why does the spoon appear broken?. refraction 23 september 2015 objectives be able to select and...

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Why does the spoon appear broken?

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Page 1: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Why does the spoon appear broken?

Page 2: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Refraction

19 April 2023

ObjectivesBe able to select and apply Snell’s Law.

HSW: AF2 – Understanding the applications and implications of science

Used before in: lesson 3 Will use again in: lesson 5

PLTS: Team workers – Work collaboratively with others.

Used before in: lesson 3 Will use again in: lesson 5

Keywordsfrequency, speed, time, distance, Hertz, sonar, A-Scan, echo

Page 3: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Outcomes• ALL MUST be able to carry out a practical

safely

• MOST SHOULD calculate the refractive index of glass

• SOME COULD be able to apply the refraction equation to different situations

Page 4: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Refraction revision

• What can you remember?

• In groups make a mind map of everything you can remember about refraction.

– When does it happen?– Can you draw diagrams to describe it?– Explain what apparent depth is.

Page 5: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Revision:

Refraction occurs when a wave changes speed as it passes from one region to another.

This speed change usually causes the wave to change direction.

Water waves slow down as they pass over from a deeper to a shallower region.

Light slows down as it passes from air into glass, perspex or water.

Page 6: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Refraction experimentTypical results:

angle of incidence / °

angle of refraction / °

deviation / °

0 0 0

15 10 5

30 19 11

45 28 17

60 35 25

75 40 35

No deviation occurs when the angle of incidence is zero.

Increasing the angle of incidence increases the deviation.

Page 7: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Refraction of light at a plane surface(a) Less to more optical dense transition (e.g. air to glass)

angle of incidence

normal

AIR GLASS

angle of refraction

Light bends TOWARDS the normal.

The angle of refraction is LESS than the angle of incidence.

Page 8: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

(b) More to less optical dense transition (e.g. water to air)

angle of refraction

angle of incidence

normal

WATER AIR

Light bends AWAY FROM the normal.

The angle of refraction is GREATER than the angle of incidence.

Page 9: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

object at the bottom of a pool

AIR

WATER

Why a pool appears shallow

image

normals

observer

Page 10: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Complete the paths of the RED light rays:

A

B

C

D

E

F

Page 11: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

The refraction equationWhen a light ray passes from one medium to another:

n = sin i sin r

where:i is the angle of incidence in the first mediumr is the angle of refraction in the second mediumn is a constant number called the refractive index.

r

i

Page 12: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

An experiment to find the refractive index (n) of glass

1. Set up the equipment as shown in the diagram opposite

2. For an initial angle of incidence, i of 30º trace the path of the light ray.

3. Measure the angle refraction, r.4. Calculate the refractive index using

the formula: n = sin (i) / sin (r).5. Repeat for a range of angles

between 10º and 80º.6. Calculate the average value of n.

i/º sin(i/º) r/º sin(r/º) n

Average n

Page 13: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Question 1Calculate the refractive index when light passes from air to glass if the angle of incidence is 30° and the angle of refraction 19º.

n = sin i / sin r

= sin (30º) / sin (19º)

= 0.500 / 0.326

refractive index , n = 1.53

Page 14: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Question 2Calculate the angle of refraction when light passes from air to perspex if the angle of incidence is 50° and the refractive index, n = 1.50.

n = sin i / sin r

1.50 = sin (50º) / sin (r )

becomes: sin (r ) = sin (50º) / 1.50

= 0.766 / 1.50

sin (r ) = 0.511

angle of refraction = 30.7º

Page 15: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Question 3Calculate the angle of incidence when light passes from air to water if the angle of refraction is 20° and the refractive index, n = 1.33.

n = sin i / sin r

1.33 = sin (i) / sin 20º

becomes: sin (i) = 1.33 x sin (20º)

= 1.33 x 0.342

sin (i) = 0.455

angle of incidence = 27.1º

Page 16: Why does the spoon appear broken?. Refraction 23 September 2015 Objectives Be able to select and apply Snell’s Law. HSW: AF2 – Understanding the applications

Complete:medium 1 medium 2 n i r

air water 1.33 50o 35.2o

glass air 0.67 30o 48.6o

water glass 1.13 59.8o 50o

air diamond 2.40 50o 18.6o

air unknown 1.53 50o 30o

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