web course 4
TRANSCRIPT
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ME 1303 GAS DYNAMICS
AND JET PROPULSION
Presented by
G.Kumaresan
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Flow Regime Classification
Subsonic Flow0.8 < M
Transonic Flow0.8 > M
> 1.2
Supersonic FlowM
> 1.2
Hypersonic FlowM
> 5
p
RTaRTRTTpch
conshch
and2but
1
02
2
1---------- (1)
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Cont..
01
202
max2
12
2
1
1
2
1
20
0cons
0aa0,cAt;2max
2
10cons
maxand0,0At
;2
2
1
1
2
11
2
ha
cCa
ah
ch
cchT
consCa
pah
---------- (2), using 1&2
;Therefore from (1)
---------- (3)
Therefore from (3)
---------- (4); combining all
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Problem-1
Example 1.
The jet of a gas at 593 K ( = 1.3 R = 469 J/kg K) has a Machnumber of 1.2. Determine the local and stagnation conditions
velocity of sound and enthalpy.
What is the Maximum attainable velocity of this jet ?
SolutionGIVEN:T = 593 K, = 1.3, R = 469 J / kg K, M = 1.2
For isentropic flow = 1.3, M = 1.2
T / To = 0.822 ; P / Po = 0.428
a = 601.29 m / s Ans
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Cont..T / To = 0.822 To = 593 / 0.822 = 721.41 K
= 663.21 m / s
Ans
Now C* = a* &
= 618.44 m / s
Ans
Cmax = 1712.39 m / s Ans
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Cont..
1R
pC
= ( 1.3 x 469) / 0.3 = 2032.333 Ans
ho = cp To = 3032.333 x 721.4112
= 1466.148 kJ / kg Ans
h = cp T = 2023.333 x 593
= 1205.174 kJ / kg Ans
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SONIC VELOCITYGeneral
A disturbance at a given point creates a region of compressed
molecules that is passed along to its neighboring molecules and
in so doing creates a traveling wave.
Waves are measured by the amplitude of the disturbance.
The speed at which this disturbance is propagated through the
medium is called the wave speed.
Wave speed = f ( type of medium, thermodynamic state &strength of the wave)
The stronger the wave is, the faster it moves.
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Cont..
Waves oflarge amplitude, which involve relatively large changes
in pressure and densityShock waves
Waves of very small amplitude, their speed is characteristic only
of the medium and its state- Sound waves
The presence of an object in a medium can only be felt by the
objects sending out or reflecting infinitesimal waves which
propagate at the characteristic sonic velocity.
For a compressible flow, the speed of propagation of smalldisturbances, called the sonic velocity (acoustic speed).
The ratio of the flow velocity to the sonic velocity Mach
number
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Propagation of Sound waves
Piston
dV
p+dp+d
aV= 0P
wave front Tube
p+dpP
observer at rest Unsteady flow pattern
Pressure plot
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Cont..
x
y
Moving observer Steady flow pattern
In this case the stagnant gas at pressure p on the left
appears to flow towards the right with a velocity a.
The wave can be considered as a stationary wave contained
within a control surface through which flow occurs from left
to right.
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Writing continuity and momentum equation for the control volume
Continuity
For steady 1D flow, m = AV = cons. ; but A = cons.
V = cons. ; now for c.v
a = (+d) (a-dV)
expanding, then neglecting the higher-order and solving for dV
dV =da
Cont..
.
Momentum
Shear stress effect may be neglected because of infinitesimal
thickness of C.V
The x-component momentum equation is
(1)
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ME 1303 GAS DYNAMICS
AND JET PROPULSION
Presented by
G.Kumaresan
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7/30/2019 Web Course 4
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ddP
a 2
Cont..
xxx i nVoutVmF PA ( P+dP ) A = Aa [ (a-dV) - a ] A dP = Aa dV
Cancelling the area and solving for dV, we have
dV = dP/ a (2)
By combining eqn. (1) & (2)(3)
Eqn. 3 shows that in compressible fluids in which there is a large
density change for a given pressure change the acoustic speed is
much lower compared to incompressible fluids.
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ddp
RTd
dpP
d
dpP
TRpK
a
Cont..Eqn. 3 further simplified to
Where, K Bulk modulus of elasticity
ddp
d
dp
dv
dpv
volumei nchangerelative
pr essur ei nincreaseK
2
1
w.k.t adiabatic bulk modulus, pK
(a)
( b)
comparing (a) & (b)
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Cont..
Speed of sound in different medium
Liquids Solids
where,
B- bulk modulus
E- youngs modulus
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Cont..
Conclusion:
In a given fluid, a is higher at higher temperatures
Fluids with higher values of the K have higher a
a at a given temperature is higher for lower molecular weight ofgases vice versa
From the above it suggest that M plays an important role in the
design and working of machines using higher molecular weight
fluids.
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a
CM
2
2
2
2
2;
22
2
a
C
a
C
aK
K
C
KA
AC
forceelastic
forceinert iaM
MACH NUMBER
RTV
a
VenergykinecticrandomenergykinecticdirectedM
2
2
2
2
V orCvelocity of the medium ; asonic velocity through the medium
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Problem 2The temperature, pressure and Mach number at the entry of a
flow passage are 300 K, 3 bar and 1.4 respectively. If the exit
Mach number is 3 determine for adiabatic flow of a perfect gas (= 1.4, R=287 J/kg K):
(i) stagnation temperature (ii) temperature and velocity
of gas at exit, and (iii) the flow rate per square metre of the inlet
cross-section.
Solution:
For adiabatic flow 00201 TTT 1392.101392.12)4.1(
214.112
1211
101 TTMTT
3/484.3
300287
5103
1
11;6.417300392.101 mkg
RT
pKT
Ans
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Cont..
2m-kg/s45.169306.486484.311
1
.m111
.
/06.4863002874.14.114.1111
CA
CAm
smTRaMC
smaMC
KTT
TT
MT
T
/4.73414.1492874.13222
14.1493008.2
392.1
2T011
022
1T
2T
8.22)3(
2
14.11222
11
2
02
Ans
Ans
Ans
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Wave Propagation
Q.An airplane is traveling while you are observing from the
ground. How will you know whether it is subsonic or
supersonic?
Point disturbance is at rest Moving disturbance
M = 0 ( M = u/a = 0.5)
Always stays inside the family of circularsound waves
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Wave fronts from Sonic disturbance
All the wave fronts coalesce on the left side and move along
with the disturbance.
No region upstream is forewarned of the disturbance as the
disturbance arrives at the same time as the wave front.
Zone of
Silence
Zone of action
W f f S i di b
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Wave fronts from Supersonic disturbance
The wave fronts have coalesced to form a cone with the
disturbance at the apex.
The half angle at the apex is called Mach angle ( )
Always stays outside the family ofcircular sound waves
Di t b P ti
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Disturbance PropagationIn Subsonic flow, bothRaj and Lisa can hear
Joy talking, since soundwaves travel from Joysmouth in all directions.
In Supersonic flow,sound waves (and otherdisturbances in the flow)travel only in the
downstream direction;thus, while Lisa can hearJoy talking, Raj cant.
Disturbances can nottravel upstream in asupersonic flow
P bl 3
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Problem 3A needle nose projectile traveling at a speed of M=3 passes 200m
above an observer. Find the projectiles velocity and determine
how far beyond the observer the projectile will first be heard?
200 m
M=3
xo
M
smaMV
sm
TRa
5.193
11sin
11sin
/6.1041)2.347(3
/2.347
)300)(287(4.1
mxx 565
200
tan