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UNIT FOUR UNIT FOUR Wave Motion Wave Motion and Optics and Optics Wave Wave motion motion describes describes phenomena phenomena ranging from ranging from the the familiar... familiar... Ocean Ocean waves... waves...

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Page 1: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

UNIT FOURUNIT FOUR

Wave MotionWave Motion

and Opticsand Optics

WaveWave motionmotiondescribesdescribesphenomenaphenomenaranging fromranging fromthethefamiliar...familiar...

OceanOceanwaves...waves...

Page 2: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

SoundSound

waves...waves...

Page 3: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

LightLight

waves...waves...... to the... to theless familiarless familiarrealm ofrealm ofatomicatomicphysics...physics...

Page 4: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

...even...evenQuantumQuantumPhysicsPhysics(matter(matterwaves)...waves)...

Page 5: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

... and Relativity... and Relativity

(gravity waves)(gravity waves)..

Page 6: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

Chapter 15Chapter 15

Making WavesMaking Waves

Page 7: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

What isactuallymoving?

Water seems to move toward theshore, but no water accumulates on

the beach.

Do the wavescarry

energy?

Page 8: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

Wave Pulses and

Periodic Waves

A Slinky isideal forstudying

simplewaves.

Page 9: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! If a Slinky is laid out on a smooth table with one end heldmotionless, you can easily produce a single traveling pulse:" With the Slinky slightly stretched, move the free end back and forth

once along the axis of the Slinky.

" You will see a disturbance (the wave pulse) move from the free end ofthe Slinky to the fixed end.

! What is actually moving?" The pulse moves through the Slinky, and portions of the Slinky move

as the pulse passes through it.

" After the pulse dies out, the Slinky is exactly where it was before thepulse began.

Page 10: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! Moving one end of the Slinky back and forth created a localcompression where the rings of the spring are closer togetherthan in the rest of the Slinky." This region of compression moves along the Slinky and constitutes the

pulse.

" The wave or pulse moves through the medium (here, the Slinky), butthe medium goes nowhere.

" What moves is a disturbance within the medium which may be a localcompression, a sideways displacement (like a wave on a rope), etc.

! The speed of the pulse may depend on factors such astension in the Slinky and the mass of the Slinky.

Page 11: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! Energy is transferred through the Slinky as the pulse travels." The work done in moving one end of the Slinky increases both the

potential energy of the spring and the kinetic energy of individualloops.

" This region of higher energy then moves along the Slinky and reachesthe opposite end.

" There, the energy could be used to ring a bell or perform other types ofwork.

! Energy carried by water waves does substantial work overtime in eroding and shaping a shoreline.

Page 12: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! The pulse we have been discussing is alongitudinal wave: the displacement ordisturbance in the medium is parallel to thedirection of travel of the wave or pulse.

! Sound waves arelongitudinal.

Page 13: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! By moving your hand up and down, you couldalso produce a transverse wave, in whichthe displacement or disturbance isperpendicular to the direction the wave istraveling.

! Waves on a rope andelectromagnetic wavesare transverse.

! Polarization effects areassociated withtransverse waves butnot longitudinal waves.

! Water waves haveboth longitudinal andtransverse properties.

Page 14: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! If instead of moving your hand back and forth just once, youcontinue to produce pulses, you will send a series oflongitudinal pulses down the Slinky." If equal time intervals separate the pulses, you produce a periodic

wave.

" The time between pulses is the period T of the wave.

" The number of pulses or cycles per unit of time is the frequency f = 1/T.

" The distance between the same points on successive pulses is thewavelength !.

" A pulse travels a distance of one wavelength in a time of one period.

" The speed is then the wavelength divided by the period:

!

v ="

T= f "

Page 15: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A longitudinal wave traveling on a Slinky has aperiod of 0.25 s and a wavelength of 30 cm.

What is the frequency of the wave?

a) 0.25 Hzb) 0.30 Hzc) 0.83 Hzd) 1.2 Hze) 4 Hz

!

T = 0.25 s

f =1

T=

1

0.25 s= 4 Hz

Page 16: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A longitudinal wave traveling on a Slinky has aperiod of 0.25 s and a wavelength of 30 cm.

What is the speed of the wave?

a) 0.25 cm/sb) 0.30 cm/sc) 1 cm/sd) 7.5 cm/se) 120 cm/s

!

v = f "

= 4 Hz( ) 30 cm( )

=120 cm/s

Page 17: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

Waves on a Rope

! A snapshot of a single transverse pulsemoving along a rope is like a graph of thevertical displacement of the rope plottedagainst the horizontal position.

#At some later time

the pulse will be

farther down the

rope at a different

horizontal position.

#The shape remains

basically the same.

Page 18: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! If you repeat a series of identical pulses at regular timeintervals, you might produce a periodic wave such as shown." The wavelength ! is the distance covered by one complete cycle of the

wave.

" This wave pattern moves to the right along the rope, retaining itsshape.

" The shape depends on the exact motion of the hand or other oscillatorgenerating the wave.

! When the leading edge of the wave reaches the fixed end ofthe rope, it will be reflected and start to move back to the left." The reflected wave will interfere with the wave still traveling to the

right.

Page 19: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! If you move your hand up and down smoothly in simpleharmonic motion, the displacement of this end of the rope willvary sinusoidally with time." The resulting periodic wave will also have a sinusoidal form.

" Such a wave is called a harmonic wave.

" The individual segments of rope tend to move with simple harmonicmotion, because the restoring force pulling the rope back toward thecenter line is proportional to its distance from the center line.

! Any periodic wave can be represented as a sum of harmonicwaves with different wavelengths and frequencies." The process of breaking a complex wave down into its simple

harmonic components is called Fourier, or harmonic analysis.

Page 20: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A wave on a rope is shown below.What is the wavelength of this wave?

a) 1/6 m b) 1 m c) 2 m d) 3 m e) 6 m

In 6 m, the wave goes through 2 complete cycles.

The wavelength (length of one complete cycle) is (6 m)/2 = 3 m.

Page 21: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

If the frequency of the wave is 2 Hz,what is the wave speed?

a) 1/6 m/s b) 2/3 m/s c) 2 m/s d) 3 m/s e) 6 m/s

!

v = f" = 2 s-1( ) 3 m( ) = 6 m/s

Page 22: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! As the raised portion of a pulse approaches a given point onthe rope, the tension in the rope acquires an upwardcomponent.

" The resulting upward forcecauses this next segmentto accelerate upward, andso on down the rope.

! The speed of the pulsedepends on how fastsucceeding segments can be started moving (accelerated).

#By Newton’s second law, this is proportional to the force and

inversely proportional to the mass of the segment:

#A larger tension produces a larger acceleration.

#The speed of the pulse will increase with the

tension and decrease with the mass per unit

length of the rope:

!

v =F

µ

where µ =m

L

!

a =F

m

Page 23: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A rope has an overall length of 10 m and a total massof 2 kg. The rope is stretched with a tension of 50N. One end of the rope is fixed, and the other is

moved up and down with a frequency of 4 Hz.What is the speed of waves on this rope?

a) 5.0 m/s b) 7.07 m/s c) 15.8 m/s d) 50 m/s e) 250 m/s

!

µ =m

L=

2 kg

10 m= 0.2 kg/m

" =F

µ=

50 N

0.2 kg/m= 250 m2 /s2 =15.8 m/s

Page 24: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A rope has an overall length of 10 m and a total massof 2 kg. The rope is stretched with a tension of

50 N. One end of the rope is fixed, and the other ismoved up and down with a frequency of 4 Hz.

What is the wavelength?

a) 0.20 m b) 3.95 m c) 10 m d) 15.8 m e) 25 m/s

!

" = f # $

# =v

f=

15.8 m/s

4 Hz= 3.95 m

Page 25: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

Interference and

Standing Waves

! When a wave on a rope reaches the fixedend of the rope, it is reflected and travels inthe opposite direction back toward your hand.

" If the wave is periodic, the reflected waveinterferes with the incoming wave.

" The resulting pattern becomes more complex andconfusing.

" This process, in which two or more wavescombine, is called interference.

Page 26: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! Imagine a rope consisting of two identical segments splicedtogether to form a single rope of the same mass per unitlength as the two original segments.

" Identical waves traveling onthe two identical segmentswill combine to form a largerwave on the single joinedrope.

" At all points, the height of theindividual waves will addtogether to form a wave withthe same frequency andwavelength but twice theheight of the initial two waves.

#Principle of Superposition:

When two or more waves combine, the resulting

disturbance or displacement is equal to the sum of the

individual disturbances.

Page 27: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! When the two waves are moving the same way at the sametime, they are in phase." The resulting combined wave will be larger (have a greater height).

! If one wave is movingupward when the otherwave is moving downward,the two waves arecompletely out of phase." If the two waves have the

same height, the resultingcombined displacement willbe zero.

" No wave is propagated beyond the junction.

! The result of adding two waves together depends on theirphases as well as on their height or amplitude.

! When waves are in phase, we have constructive interference.

! When waves are out of phase, we have destructiveinterference.

Page 28: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! When two or more waves are traveling in the same direction,the difference in phase determines whether the interferencewill be constructive, destructive, or somewhere in between.

! When two waves are traveling in opposite directions, suchas when a wave is reflected back on itself, the principle ofsuperposition can be applied at different points on the string." At point A, the two waves cancel each other at all times.

" At this point, the string will not oscillate at all; this is called a node.

"At point B, both waves willbe in phase at all times.

"The two waves always add,producing a displacementtwice that of each wave byitself.

"This is called an antinode.

Page 29: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! This pattern of oscillation is called a standing wave." The waves traveling in opposite directions interfere in a

way that produces a standing or fixed pattern.

" The distance between adjacent nodes or adjacentantinodes is half the wavelength of the original waves.

" At the antinodes, the string is oscillating with a largeamplitude.

" At the nodes, it isnot moving at all.

" At points betweenthe nodes andantinodes, theamplitude hasintermediatevalues.

Page 30: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! Guitars, pianos, and other stringed instrumentsproduce music using standing waves on strings." The frequency of the sound wave equals the string’s

frequency of oscillation and is related to the musical pitch.

" A higher frequency represents a higher-pitched sound.

Page 31: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! For a string fixed at both ends, the simplest standingwave, the fundamental or first harmonic, hasnodes at both ends and an antinode in the middle.

#The wavelength is determined bythe length of the string.

#Since the distance betweennodes is half the wavelength, thewavelength must be twice thelength of the string.

#The wave speed is determinedby the tension in the string andthe mass per unit length of thestring.

#The frequency can then be foundusing the relationship v = f !:

!

f =v

"=v

2L

Page 32: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! A string with a longer length L will result in a lowerfrequency." The effective length can also be shortened by placing your

finger firmly on the string,producing a higher-pitchedtone.

! Other patterns of oscillationmay also be produced.

#The second harmonic has a nodeat the midpoint of the string, and awavelength equal to L.

#This wavelength is half thefundamental, so its frequency istwice the fundamental.

#Musically, this pitch would be anoctave above the fundamental.

Page 33: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! A string with a longer length L will result a lowerfrequency." The effective length can also be shortened by placing your

finger firmly on the string,producing a higher-pitchedtone.

! Other patterns of oscillationmay also be produced.

#The third harmonic has fournodes (counting the ones at theends) and three antinodes, and awavelength equal to two-thirds L.

#The resulting frequency is threetimes the fundamental and 3/2that of the second harmonic.

#Musically, this is called a fifthabove the second harmonic.

Page 34: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A guitar string has a mass of 4 g, a length of74 cm, and a tension of 400 N. These values

produce a wave speed of 274 m/s.What is its fundamental frequency?

a) 1.85 Hzb) 3.70 Hzc) 185 Hzd) 274 Hze) 370 Hz

!

L = 74 cm = 0.74 m

v = 274 m/s

" = 2L

f1

=v

"1

=v

2L

=274 m/s

1.48 m

=185 Hz

Page 35: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A guitar string has a mass of 4 g, a length of74 cm, and a tension of 400 N. These values

produce a wave speed of 274 m/s.What is the frequency of the second

harmonic?

a) 92.5 Hzb) 123 Hzc) 185 Hzd) 370 Hze) 740 Hz

!

L = 74 cm = 0.74 m

v = 274 m/s

" = L

f2

=v

"2

=v

L

=274 m/s

0.74 m

= 370 Hz

Page 36: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

Sound Waves! Sound waves may be generated in many ways in

addition to an oscillating string.

! Since sound waves reach our ears, they must beable to travel through air.

The bassstring hasbeenplucked,producing ablur near themiddlewhere theamplitude isgreatest.

Page 37: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! A sound wave consists of pressure variations in air.

" The diaphragm of a speaker oscillates back and forth, producingregions of higher pressure and lower pressure.

" These regions propagate through the air as variations in air pressureand density, forming a longitudinal sound wave.

Page 38: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! We can show these pressure variations in a graph of pressureplotted against position.

! The factors that determine the speed of sound are related tohow rapidly one air molecule transmits changes in velocity tonearby molecules to propagate the wave.

" In room temperature air, soundwaves travel with a speed of340 m/s or 750 MPH.

" For gases other than air, thespeed also depends on themasses of the molecules oratoms.

" Sound waves can also travelthrough liquids and solids, oftenwith higher speeds.

Page 39: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! Interference phenomena such as standing waves can beobserved in sound waves." Many musical instruments produce standing waves in a tube or pipe.

" If the tube is closed at one end, such as a bottle, there is adisplacement node at the closed end.

" At the open end, there is a displacement antinode.

! The frequency of the standingwave can be found from thespeed of sound in air and thewavelength:

where the wavelength isdetermined by the length ofthe tube.

!

f =v

"=

340 m/s

"

Page 40: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! The standing-wave patterns for the first threeharmonics for a tube open at one end and closed atthe other are represented as follows:

#The first harmonic orfundamental has a wavelengthfour times longer than thelength of the tube.

#The wavelength of the secondharmonic is equal to four-thirdsof the length of the tube.

#The wavelength of the thirdharmonic is equal to four-fifthsof the length of the tube.

#etc.

!

f =v

"=

340 m/s

"

Page 41: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

The Doppler Effect

!A moving source of sound, such as a car horn,seems to change pitch depending on itsmotion relative to the listener.

#As a car passes a

stationary observer,

the horn’s pitch

changes from a higher

pitch to a lower pitch.

Page 42: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

The Doppler Effect

!Comparing the wavefronts for a stationary carhorn and for a moving car horn illustrates whythe pitch changes.

#When the car isapproaching theobserver, thewavefronts reaching theobserver are closertogether.

#When the car ismoving away from theobserver, thewavefronts reaching theobserver are fartherapart.

Page 43: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

The Physics of Music

$ Why do certain combinations of notes(chords) sound better than others?

$ Musical notes actually have a mix of higherharmonics along with the fundamental frequency.

$ The relationships between these differentfrequencies explain why some notes soundharmonious together, and others do not.

$ An analysis of the mixture of frequencies is calledharmonic or frequency analysis.

Page 44: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! When a guitar string is plucked in the usual position, thesecond and third harmonics often dominate the harmonicspectrum.

" f1 is the frequency of the first harmonic.

" Since the string is usually plucked right where the second harmonic(f2 = 2f1) has an antinode, the second harmonic is stronglystimulated.

" The body of the guitaralso determines whichharmonics will bereinforced.

Page 45: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! When a guitar string is plucked near the bridge, many higher harmonicsare present in the harmonic spectrum.

" This results in a twangy sound.

" The pitch still sounds the same, but the tone quality depends on the mixtureof harmonics present.

! Different instruments generate different harmonic mixes, so they havedifferenttones.

" A trumpet produces alot of higher harmonicsso it sounds “bright”or “brassy”.

" A flute can produce atone dominated by thefundamental frequency,with almost none of thehigher harmonics, sothe tone sounds “pure”.

Page 46: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

! When discussing musical notes, we describe the differencein frequencies in terms of musical intervals.

! Musical scales and intervals are based upon the ratiosbetween the higher harmonics in the notes.

" The frequency of the second harmonic is twice that of the firstharmonic. This interval is an octave, and corresponds to theinterval from one note C to the next higher C (the first and eighthnotes in the scale).

" The frequency of the third harmonic is 3/2 that of the secondharmonic. This interval isa fifth, between the firstand fifth notes in the scale(C and G).

" The frequency of the fourthharmonic is 4/3 that of thethird harmonic. Thisinterval is a fourth,between the first andfourth notes (C and F).

Page 47: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

" The frequency of the fifth harmonic is 5/4 that of the fourthharmonic. This interval is a major third, between the first and thirdnotes (C and E).

! Just tuning involves tuning an instrument so that in onekey, all the intervals have simple frequency ratios." In a different key, the tuning may not sound correct.

! Equally-tempered tuning is a compromise so that theratios are all approximately correct, but not perfect.

" The ratios betweenadjacent half steps onthe scale are all identical,so the scales soundcorrect regardless ofwhat key you are in.

Page 48: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A C-major scale begins with do on middle Chaving a frequency of approximately 264 Hz.Assuming that they have been tuned to theperfect ratios for the intervals in question,what should the frequency be for sol (G)?

a) 88 Hzb) 132 Hzc) 176 Hzd) 396 Hze) 528 Hz

!

sol is a fifth above do with a ratio of 3 2 :

f =3

2264 Hz( ) = 396 Hz

Page 49: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A C-major scale begins with do on middle Chaving a frequency of approximately 264 Hz.Assuming that they have been tuned to theperfect ratios for the intervals in question,what should the frequency be for fa (F)?

a) 176 Hzb) 198 Hzc) 352 Hzd) 440 Hze) 528 Hz

!

fa is a fourth above do with a ratio of 4 3 :

f =4

3264 Hz( ) = 352 Hz

Page 50: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

A C-major scale begins with do on middle Chaving a frequency of approximately 264 Hz.Assuming that they have been tuned to theperfect ratios for the intervals in question,what should the frequency be for do at the

top of the scale (high C)?a) 88 Hzb) 198 Hzc) 352 Hzd) 440 Hze) 528 Hz

!

From do to the next higher do is an octave,

which doubles the frequency :

f = 2 264 Hz( ) = 528 Hz

Page 51: Wave motion UNIT FOUR describes Wave Motion …dristle/ppt_ch_15.pdf · by the tension in the string and the mass per unit length of the string. #The frequency can then be found using

" Combinations of notes sound harmonious when the higherharmonics overlap.

" When two notes are too close in pitch, beats can produce adissonant buzz.

" The two waves come in and out of phase as time progresses.