water and solute metabolismpeople.uncw.edu/hadleyn/549 lecture 4.pdfwater and solute metabolism...
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Water and Solute MetabolismIonic and Osmotic Regulation
In order to understand how organismsmaintain salt and water balance,
we must understand how:
• water moves• solutes (ions) move
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Water movement:
• Bulk transport (flow)
• Filtration
• Osmosis
Solute & Ion Movement
•Diffusion
•Active Transport
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Simple diffusion
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Particles move by diffusion
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If thermal motion is random, why is movement down a concentration gradient?
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Features of Simple Diffusion
• A passive process• Movement from area of higher to lower
concentration• Net movement continues until equilibrium is
reached• More rapid over short distances• Directly related to temperature• Inversely related to molecular size• Can take place in open site or across membrane
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1 mol of particles = 1 osmol
1 osmol • l -1 = 1 Osm (1osmolar )
1 Osm = 1000 mOsm
mole = gmwt of element or compd (= 6.023 x 1023
molecules)
Some Definitions
concentration = moles/liter or mmol/liter(e.g., 0.5 mol/l = 500 mmol/l)
osmotic conc = osmolarity = # of particles in solution
1 molar solution = 1 mol/l = 1 gmtw/l
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(e.g .1M NaCl = 100 mmol NaCl )
100 mmol • l -1 Cl-
= 200 mosmol • l -1 = 200 mOsm or
100 mmol • l -1 Na+
Non-electrolyte (e.g., sugar, urea):osmolarity = molar concentration
(e.g., 1 molar glucose = 1 Osm )
Electrolyte (NaCl) = dissociates in solution
.2 Osm NaCl
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Osmosis
• Movement of water across semi-permeable membrane in response to a concentration gradient
Water moves from area of high water concentration to area of lower water concentration
Water moves from an area of less concentrated solute to an area of more concentrated solute
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rigid, semipermeablemembrane
j j
j
j
j
j
j
j
out in
Cj
H2O
∆∆∆∆P
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100mMNaCl
200mMNaCl
out in
200mOsm
400mOsm
100mMNaCl
200mMsucrose
out in
200mOsm
200mOsm
100mMCaCl2
100mMNaCl
out in
300mOsm
200mOsm
hypo-osmotic hyperosmotic isosmotic
hyperosmotic hypo-osmotic
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Diffusion of Charged Particles
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Chemical Driving Forces
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Electrical Driving Forces
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mMNa+ = 150Cl- = 150
mMNa+ = 150Cl- = 130Pr- = 20
out in
electroneutrality - same # of + and - charges ina compartment.
mMNa+ = 145Cl- = 145
mMNa+ = 155Cl- = 135Pr- = 20
out in
Gibbs-Donnan Equilibrium
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Equilibrium potential
+25mV CNao
ENa = lnzNa CNa
i
+25mV 145ENa = ln
+1 155
= -1.7 mV
Calculate using the Nernst equation
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Equilibrium potential for K + = EK =
-94 mv
Membrane potential (V M) assumed to be negative
CK on outside = 3 mM
CK on inside = 130 mM
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+25mV CKo
EK = _____ ln _____zK CK
i
+25mV 3
EK = _____ ln _____
+1 130
EK = -94 mV
Equilibrium Potential of K+
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Equilibrium potential for K+ = EK = -94 mv
Membrane potential (VM) assumed to be negative
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Facilitated Diffusion
• Means by which many “polar organic compds” move across cell membranes
• Still obey favorable concentration gradients
• Hydrophilic—cannot dissolve in lipid interior
• Rely on proteins embedded in membrane
• Non-covalent, reversible bonding
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Active Transport
The net movement of a substance againstan electrochemical gradient
that is directly linked to metabolic energy.
Characteristics:
• Requires source of chemical energy
• Sensitive to metabolic poisons (e.g. CN)
• Sensitive to specific inhibitors (e.g., ouabain)
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