vocab factoring day 2 simple trinomials · factoring day 2 simple trinomials practice and exit...
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6.1 Solving Quadratic Equations
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I will be able to solve quadratic equations
Vocab
Factoring Day 2 simple trinomials
Practice and exit question
6.1 Solving Quadratic Equations
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6.1 Solving Quadratic Equations
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6.1 Solving Quadratic Equations
Quadratic Relation: y = ax2 + bx + c
Quadratic Equation: ax2 + bx + c = 0
6.1 Solving Quadratic Equations
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The basic principle behind solving quadratic equations is... (dun dun dun...)
If two numbers (_________________) have a product of zero, then
either one or both ______
Steps to Solve Quadratic Equations
1) Make sure all the numbers and variables are on one side of the equal sign so that the polynomial is equal to zero (should look like ax2 + bx + c = 0)
2) Factor (use common factors, difference of squares, trinomial or decomposition)
3) Set each factor equal to zero and solve for the variable
6.1 Solving Quadratic Equations
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x2 6x + 8 = 0
6.1 Solving Quadratic Equations
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6.1 Solving Quadratic Equations
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Whiteboard Questions
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6.1 Solving Quadratic Equations
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6.1 Solving Quadratic Equations
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6.1 Solving Quadratic Equations
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6.1 Solving Quadratic Equations
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6.1 Solving Quadratic Equations
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Practice: Page 320 # 4ae, 6cf, 7cd, 8a, 9b, 10, 14,13 (challenge)