vector

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Dyn11 Phas e ref Applied volts(volt) 1U1V 400 1V1W 403 1W1U 402 Measured volts(volt) 1U2N 9.12 1V2N 390 1W2w 385 1W2v 401 1V2W 386.4 1V2V 386.2 Short 1U – 2u Apply 3 Phase Volts to 1U, 1V, 1W Condition : 1. 1U1V=2u2n+2n1V ie: 400=9.12+390=399.12 2. 1W2W < 1W2V ie: 385 < 401 3. 1V2W = 1V2V ie: 386.4 = 386.2 So Vector group is Dyn 11 YNd1 Phase ref Applied volts(volt) Vector diagram Short 1U – 2u , Apply 3 Phase Volts to 1U, 1V, 1W Condition : 1. 1U1N=1U2v+2v1N=> 239.9= 34.33+205.7≈240.0 2. 1W2w =1W2v=>378.1=378.6 1U1V 432 1V1W 422 1W1U 411 Measured volts(volt) 1U1N 239.9 1V1N 255.2 1W1N 230.8 1U2v 34.33 2v1N 205.7 1W2w 378.1 1W2v 378.6 1V2v 393.7

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Page 1: Vector

Dyn11Phase ref

Applied volts(volt)

1U1V 4001V1W 4031W1

U402

Measured volts(volt)1U2N 9.121V2N 3901W2

w385

1W2v 4011V2W 386.41V2V 386.2

Short 1U – 2u Apply 3 Phase Volts to 1U, 1V, 1W Condition :

1. 1U1V=2u2n+2n1V ie: 400=9.12+390=399.12

2. 1W2W < 1W2V ie: 385 < 401

3. 1V2W = 1V2V ie: 386.4 = 386.2

So Vector group is Dyn 11

YNd1Phase ref Applied volts(volt)

Vector diagram

Short 1U – 2u , Apply 3 Phase Volts to 1U, 1V, 1W Condition : 1. 1U1N=1U2v+2v1N=> 239.9= 34.33+205.7≈240.0 2. 1W2w =1W2v=>378.1=378.6 3. 1V2w>1V2v=>419>393.7 So Vector group is YNd1

1U1V 4321V1W 4221W1U 411 Measured volts(volt)1U1N 239.91V1N 255.21W1N 230.8

1U2v 34.33

2v1N 205.7

1W2w 378.1

1W2v 378.6

1V2v 393.7

1V2w 419

Page 2: Vector

DZn0Phase

refApplied volts(volt)

1U1V 4191V1W 4211W1U 420

Measured volts(volt)1V3V 402.21W3

W402.8

3U3V 16.283U3W 16.301V3N 394.21W3N 394.61V3W 402.41W3V 402.3

Short 1U – 3U, Apply 3 Phase Volts to 1U, 1V, 1W Condition:

1. 1V3V=1W3W 402.2=402.82. 1V3W=1W3V 402.4=402.33. 1W3N=1V3N 394.6 =394.24. 1U1V = 3U3V+3V1V

419 = 16.28 +402.25. 1U1W = 3U3W+3W1W

420 = 16.30 + 402.8

D(+7.5)yn11

Phase ref Applied volts(volt)1U1V 4201V1W 4201W1U 419

Phase ref Measured volts(volt)1U3n 14.751V3n 4041W3w 3911W3v 4011V3w 3901V3v 389

Short 1U – 3U, Apply 3 Phase Volts to 1U, 1V, 1W Condition: 1.1V3w=1V3v 390=389

2. 1W3w<1W3v 391<401 3.1U1V=1U3N+3N1V

420=14.75+404=418.75

Page 3: Vector

D(+7.5)d0Phase ref Applied volts(volt)

1U1V 4201V1W 4201W1U 419

Phase ref Measured volts(volt)1U2w 25.502w1w 394.122w2v 25.411W1V 4192U2V 26.122V1V 394.2

Short 1U – 2U, Apply 3 Phase Volts to 1U, 1V, 1W Condition: 1. 1W1U=1U2w+2w1W 419=25.50+394.12=419.62 2.1U1V = 2U2V + 2V1V 420 = 26.12+394.2 = 420.3 3. 2w1W=2v1V

394.12=394.2So Vector Group Is D(+7.5)d0yn11

YNd111U1V : 417

1V1W :426

1U1W :426

Measured Volts : 1U2U 2W 2V

1N

1W 1V

1U1N : 242.6 1W2V : 4242W1N :200.7 1V2V : 383.5 2W2U :41.9 1V2W : 383.9 1W2W :385.4

Inference :1U1N = 2W1N + 2W2U

(i.e.) 242.6 = 200.7+ 41.9 = 242.61W2W < 1W2V (i.e.) 385.4< 4241V2V = 1V2W (i.e.) 383.5 ~ 383.9