vector presentation
DESCRIPTION
This is a brief introduction to vector addition.TRANSCRIPT
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Vectors
Glenbrook South High School Physics
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A scalar is a quantity with magnitude only
1.6 m
34 m/s
A vector is a quantity with magnitude and direction
0.9 m @ 35° N of E
21 m @ 65° E of N
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Method 1: Graphical Method
N
S
W E
You travel 6 m @ 35° E of N
And then go 8 m due E
A = 6 m @ 35° E of N
B = 8 m due E
Scale: 1 cm = 1 m
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Method 1: Graphical Method
N
S
W E
You travel 6 m @ 35° E of N
And then go 8 m due E
A = 6 m @ 35° E of N
B = 8 m due E
Scale: 1 cm = 1 m35°
![Page 5: Vector Presentation](https://reader036.vdocuments.us/reader036/viewer/2022062405/55622cdcd8b42ad44d8b5716/html5/thumbnails/5.jpg)
Method 1: Graphical Method
N
S
W E
You travel 6 m @ 35° E of N
And then go 8 m due E
A = 6 m @ 35° E of N
B = 8 m due E
Scale: 1 cm = 1 m35°
Sketch a new coordinate axis to make vector B
A
B
![Page 6: Vector Presentation](https://reader036.vdocuments.us/reader036/viewer/2022062405/55622cdcd8b42ad44d8b5716/html5/thumbnails/6.jpg)
Method 1: Graphical Method
N
S
W E
You travel 6 m @ 35° E of N
And then go 8 m due E
A = 6 m @ 35° E of N
B = 8 m due E
Scale: 1 cm = 1 m
23°
A
B
R = 12.5 m @ 23⁰ N of E
E of N 23 @ 5.12 om
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Method 2: Component
Method
N
S
W E
A = 6 m @ 35° E of N
B = 8 m due E 35°
A
Ax
Vector X-component
Y-component
A 3.44 m 4.91 m
B
Total
Ay
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Method 2: Component
Method
N
S
W E
A = 6 m @ 35° E of N
B = 8 m due E 35°
A
Ax
Vector X-component
Y-component
A 3.44 m 4.91 m
B
Total
Ay
mmAA
xx 44.3)6)(35(sin
6m35sin
mmAA
xy 91.4)6)(35(cos
6m35cos
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Method 2: Component
Method
N
S
W E
A = 6 m @ 35° E of N
B = 8 m due E 35°
A
B
Vector X-component
Y-component
A 3.44 m 4.91 m
B 8.00 m 0.00 m
Total
mBx 8
mBy 0
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Method 2: Component
Method
N
S
W Eθ
Rx = 11.44m
Vector X-component
Y-component
A 3.44 m 4.91 m
B 8.00 m 0.00 m
Total 11.44 m 4.91 m
Ry = 4.91m
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Method 2: Component
Method
N
S
W Eθ
Rx = 11.44m
Ry = 4.91m
mmmR 45.12)91.4()44.11( 22
o
m
m2.23)
44.11
91.4(tan 1
E of N 2.23 @ 45.12 om