unit 6, lesson 3 - vectors

55
Vectors Unit SIX, Lesson 6.3 By Margielene D. Judan

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Page 1: Unit 6, Lesson 3 - Vectors

VectorsUnit SIX, Lesson 6.3By Margielene D. Judan

Page 2: Unit 6, Lesson 3 - Vectors

LESSON OUTLINE

Vector RepresentationGraphical MethodMathematical MethodPythagorean TheoremComponent Method

Page 3: Unit 6, Lesson 3 - Vectors

Various quantities in nature can be:

• Scalar quantity – magnitude only

• Vector quantity – magnitude + direction

Page 4: Unit 6, Lesson 3 - Vectors

The length of the arrow represents the magnitude while the angle where the arrow is pointed represents the direction.

Page 5: Unit 6, Lesson 3 - Vectors

Thus, a longer vector has a larger magnitude.

A B CWhich among the vectors has the largest magnitude?

Page 6: Unit 6, Lesson 3 - Vectors

Examples of Vector Representation:

• 30 km/hr East

• 20 km/hr West

• 10 km/hr North

30 km

20 km

10 km

Page 7: Unit 6, Lesson 3 - Vectors

Examples of Vector Representation:

• 50 km/hr NE

• 50 km/hr SE

50 km

50 km

Page 8: Unit 6, Lesson 3 - Vectors

Vectors can also be drawn in a Cartesian coordinate system.

West

North

East

South

Page 9: Unit 6, Lesson 3 - Vectors

Ex. A force of 80 Newtons east

= 80 N eastW

N

E

S

Page 10: Unit 6, Lesson 3 - Vectors

Ex. A velocity of 120 km/hr southwest

= 120 km/hr SW

𝜃=45 °

𝜃=45°

W

N

E

S

Page 11: Unit 6, Lesson 3 - Vectors

Ex. A displacement of 100 m 30 north of west

= 100 m 30 N of W

𝜃=30 °W

N

E

S

Page 12: Unit 6, Lesson 3 - Vectors

We use a protractor to measure the angles in degrees, and a ruler to measure the magnitude.

Page 13: Unit 6, Lesson 3 - Vectors

Vector Addition

Page 14: Unit 6, Lesson 3 - Vectors

We can add vectors using different methods. The sum of the vectors (vector sum) is called the resultant vector, denoted by R.

Page 15: Unit 6, Lesson 3 - Vectors

Vector Addition Methods

• Graphical Method or the Tip-to-Tail Method

• Mathematical Method

1. Pythagorean Theorem

2. Component Method

Page 16: Unit 6, Lesson 3 - Vectors

1. Graphical Method or Tip-to-Tail Method

Page 17: Unit 6, Lesson 3 - Vectors

Tip-to-Tail Method

Arrow 1 Arrow 2

Arrow 1

Arrow 2

Resultant

Resultant

Review from Lesson 6.1

Page 18: Unit 6, Lesson 3 - Vectors

It is called tip-to-tail because you connect the arrows from tip to tail

Correct Wrong

tiptail

tail

tiptip

tailtail

tail

tail

tip

tip

tip

Page 19: Unit 6, Lesson 3 - Vectors
Page 20: Unit 6, Lesson 3 - Vectors

We can use many arrows.

Page 21: Unit 6, Lesson 3 - Vectors

2. Mathematical Method

Page 22: Unit 6, Lesson 3 - Vectors

Look at the red line. Can you measure its exact length?

Page 23: Unit 6, Lesson 3 - Vectors

Using the graphical method is easy and convenient. However, it does not predict measurements exactly. You cannot measure 62.5213 on a protractor and 2.617 cm in a ruler exactly. Thus, we use a more exact method called the mathematical method.

Page 24: Unit 6, Lesson 3 - Vectors

Note: Right and Up (+)Left and Down (-)

Page 25: Unit 6, Lesson 3 - Vectors

Note: Right and Up (+)Left and Down (-)

Page 26: Unit 6, Lesson 3 - Vectors

3. Pythagorean Theorem

Page 27: Unit 6, Lesson 3 - Vectors

Note: The Pythagorean Theorem is used for determining the resultant of two vectors that makes a right angle to each other.The formula is given below:

Page 28: Unit 6, Lesson 3 - Vectors
Page 29: Unit 6, Lesson 3 - Vectors

Use the Pythagorean Theorem to determine the resultant vector below.

Page 30: Unit 6, Lesson 3 - Vectors

Practice A Solution:

Page 31: Unit 6, Lesson 3 - Vectors

Practice B Solution:

Page 32: Unit 6, Lesson 3 - Vectors

AssignmentAnswer Laboratory 3.2.

Page 33: Unit 6, Lesson 3 - Vectors

4. Component Method

Page 34: Unit 6, Lesson 3 - Vectors

Most of the times, the vectors given do not form right angles and the Pythagorean Theorem is not applicable.

Pythagorean Theorem applicable

Pythagorean Theorem not applicable

Page 35: Unit 6, Lesson 3 - Vectors

The Component Method is the best method to use in all vector problems which vectors do not form a right angle (Pythagorean Theorem).Using this method, vectors are broken down into its x and y components.

Page 36: Unit 6, Lesson 3 - Vectors

Given the vector (black), find its x and y components using the graphical method.

Page 37: Unit 6, Lesson 3 - Vectors

Answer: x-component (blue), y-component (red)

x-component

y-componentResultant (R

)

Page 38: Unit 6, Lesson 3 - Vectors

After breaking the vector into its x and y components, we could now apply the Pythagorean Theorem to measure the resultant.

x-component

y-componentResultant (R

)

Page 39: Unit 6, Lesson 3 - Vectors

Using the mathematical method, however, we have to apply concepts in trigonometry.

Page 40: Unit 6, Lesson 3 - Vectors

Given: 50 m, 40 N of E. Find its x and y components.

𝜃=40 °

50 m

Page 41: Unit 6, Lesson 3 - Vectors

Given: 50 m, 40 N of E. Find its x and y components.

𝜃=40 °

dx – x component dy – y component

50 m

Page 42: Unit 6, Lesson 3 - Vectors

Given: 50 m, 40 N of E. Find its x and y components.

𝜃=40 °

dx = d cos dy = d sin

50 m

Page 43: Unit 6, Lesson 3 - Vectors

Given: 50 m, 40 N of E. Find its x and y components.

𝜃=40 °

50 m

dx = d cos dx = 50 cos 40dx = 38.30 m

dy = d sin dy = 50 sin 40dy = 32.14 m

Page 44: Unit 6, Lesson 3 - Vectors

Given: 50 m, 40 N of E. Find its x and y components.

𝜃=40 °

32.14 m50 m

38.30 m

Page 45: Unit 6, Lesson 3 - Vectors

Find the Resultant Using Component Method (Steps)

1. Make a graphical model of the vectors.

2. Find the x and y components of each vector.

3. Find the sum of all x-components and all y-components.

4. Use the Pythagorean Theorem to find the magnitude of the resultant.

5. Find the direction using tan =

Page 46: Unit 6, Lesson 3 - Vectors

Example:

Arrow 1 = 3 km 30 N of EArrow 2 = 4 km 60 S of W

Page 47: Unit 6, Lesson 3 - Vectors

1. Make a graphical model of the vectors.

Arrow 1 = 3 km 30 N

Arrow 2 = 4 km 60 S of W

𝜃=30 °𝜃=60 °

Note: Right and Up (+)Left and Down (-)

+y

+x

-y

-x

Page 48: Unit 6, Lesson 3 - Vectors

2. Find the x and y components of each vector.

Arrow 13 km 30 N

Ax = d cos Ax = -3 cos 30Ax = -2.60 km

Ay = d sin Ay = -3 sin 30Ay = -1.5 km

Arrow 24 km 60 S of W

Bx = d cos Bx = 4 cos 60Bx = 2 km

By = d sin By = 4 sin 60By = 3.46 km

Negative because x is to the left

Negative because y is downward

Page 49: Unit 6, Lesson 3 - Vectors

3. Find the sum of all x-components and all y-components.

x-component total Rx = Ax + Bx

= -2.60 km + 2 km

= -0.6 km

y-component total Ry = Ay + By

= -1.5 km + 3.46 km

= 1.96 km

Page 50: Unit 6, Lesson 3 - Vectors

4. Use the Pythagorean Theorem to find the magnitude of the resultant.

(magnitude of resultant)

Page 51: Unit 6, Lesson 3 - Vectors

5. Find the direction using tan =

tan = tan = tan = -3.27To find , remove tan by typing tan-1(-3.27) in the calculator. (teacher will teach you how) = -73.00

Page 52: Unit 6, Lesson 3 - Vectors

Answer: The displacement is2.05 km, -73.00 Removing the negative sign:2.05 km, 73.00 S of E

𝜃=73 °

Page 53: Unit 6, Lesson 3 - Vectors

Whiteboard Work:

Arrow 1 = 20 km 40 S of EArrow 2 = 10 km 60 N of E

Page 54: Unit 6, Lesson 3 - Vectors

Assignment: (short coupon bond)

From Calapan City Port, the ship travels 15 km, 30 N of W and 10 km, 10 E of N before reaching Batangas City Port. Calculate the displacement between the ports. How far did the ship travel? Make an illustration by drawing. (30 pts)Note: Box your final answers.

Page 55: Unit 6, Lesson 3 - Vectors

Sources:

Science Links 7