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    PH0101 UNIT 1 LECTURE 3 1

    PH0101 UNIT 1 LECTURE 3

    Bending of Beams

    Bending moment of a BeamUniform Bending (Theory and Experiment)

    Worked Problem

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    PH0101 UNIT 1 LECTURE 3 2

    Bending of Beams

    A beam is a rod or bar of uniform crosssection(circular or rectangular) whose length is verymuch greater than its thickness as shown inFigure

    A beam is considered to be made up of a largenumber of thin plane layers called surfacesplaced one above the other.

    AB

    MN

    DC

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    PH0101 UNIT 1 LECTURE 3 3

    Consider a beam to bebent into an arc of acircle by the applicationof an external couple

    as shown Figure Taking the longitudinal

    section ABCD of thebent beam ,the layers

    in the upper half areelongated while thosein the lower half arecompressed.

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    PH0101 UNIT 1 LECTURE 3 4

    In the middle there is a layer (MN) which is notelongated or compressed due to bending of the

    beam.

    This layer is called theneutral surfaceand the

    line (MN) at which the neutral layer intersects the

    plane of bending is called the neutral axis.

    It is obvious that the length of the filamentincreases or decreases in proportion to its distanceaway from the neutral axis MN.

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    PH0101 UNIT 1 LECTURE 3 5

    The layers below MN are compressed and thoseabove MN are elongated and there will be such

    pairs of layers one above MN and one below

    MN experiencing same forces of elongation and

    compression due to bending and each pairforms a couple.

    The resultant of the moments of all these

    internal couples are called the in ternal bend ing

    momentand in the equilibrium condition, this is

    equal to the external bending moment.

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    PH0101 UNIT 1 LECTURE 3 6

    Bending Moment of a Beam

    Consider the section PBCP, the extended filaments

    lying above the neutral axis MN are in state oftension and exert an inward pull on the filamentadjacent to them towards the fixed end of the beam.

    M

    N

    C

    B

    P

    D

    AP

    Load

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    PH0101 UNIT 1 LECTURE 3 7

    In the same way the shortened filaments lying below theneutral axis MNare in a state of compression and exertan outward push on the filaments adjacent to themtowards the loaded end of the beam.

    As a result tensile and compressive stresses develop inthe upper and lower halves of the beam respectively andform a couple which opposes to bending of the beam.

    The moment of this couple is called the moment of the

    resistance.

    When the beam is in equilibrium position the bendingmoment and restoring moment or moment of resistanceshould be equal.

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    PH0101 UNIT 1 LECTURE 3 8

    To find an expression for

    the moment of therestoring couple considera fiber DCat a distance rfrom the neutral axis MNas shown in Figure

    Let the radius ofcurvature be Rand bethe angle subtended by itat the centre of curvature.In unstrained position ofthe beam, the length ofthe fiber DC= MN = R.

    In the strained positionthe length of the fibre,

    C

    A

    M

    B

    D

    N

    DC= (R + r)

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    PH0101 UNIT 1 LECTURE 3 9

    Strain in the fiber DC, =

    or

    lengthOriginal

    lengththeinChange

    R

    r

    R

    RrR

    Strain

    )(

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    PH0101 UNIT 1 LECTURE 3 10

    i.e., strain is proportional to the distance from the

    neutral axis.

    Let the area of the fiber beAand its neutral axis

    be at a distance r from neutral axis of the beam

    and the strain produced be r/R. We haveStress = Yx Strain = Y r / R

    Hence, force on the areaA

    F = Y(r/R) xA

    Therefore the moment of this force about MN

    = Y(r/R) xAx r= Y Ar2/ R

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    PH0101 UNIT 1 LECTURE 3 11

    As the moment of the forces acting on both the upper andlower halves of the section are in the same direction, thetotal moment of the forces acting on the filaments due tostraining

    gIR

    YarR

    Y

    R

    raY

    22

    where Igis the geometrical moment of inertia and

    is equal to AK2

    , A being the total area of thesection and Kbeing the radius of gyration of the

    beam

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    PH0101 UNIT 1 LECTURE 3 12

    gIRY

    gIR

    Y

    :. moment of the forces

    In equilibrium, bending moment of the beam is equal and

    opposite to the moment of bending couple due to the loadon one end.

    :. Bending moment of the beam =

    The quantity YIg (=YAK2) is called the flexural rigidity of the

    beam. Flexural r igid i ty is defined as the bending moment

    required to produce a unit radius of curvature.

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    PH0101 UNIT 1 LECTURE 3 13

    Uniform Bending The beam is loaded

    uniformly on its both ends,

    the bent beam forms an

    arc of a circle. An elevation

    in the beam is produced.

    This bending is calleduni form bending.

    Consider a beam (or bar)

    AB arranged horizontally

    on two knife edges C

    and D symmetrically so

    that AC = BD = a ,as

    shown in Figure

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    PH0101 UNIT 1 LECTURE 3 14

    The beam is loaded with equal weights W and Wat the ends A and B.

    The reactions on the knife edges at C and D areequal to W and W acting vertical upwards.

    The external bending moment on the part AF ofthe beam is

    = W x AFW x CF = W (AFCF)= W x AC = W x a

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    PH0101 UNIT 1 LECTURE 3 15

    R

    YIWa

    g

    Internal bending moment =where

    Y - Youngsmodulus of the material of the bar

    Ig - Geometrical moment of inertia of the cross-

    section of beamR - Radius of curvature of the bar at F

    In the equilibrium position,

    external bending moment = internal bending

    moment

    R

    YIg

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    PH0101 UNIT 1 LECTURE 3 16

    Since for a given value of W, the values of a, Y and

    Igare constants, R is constant so that the beam isbent uniformly into an arc of a circle of radius R.

    CD = l and yis the elevation of the midpoint E of the

    beam so that y= EF

    D

    F

    C

    O

    y

    R

    l/2 E

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    PH0101 UNIT 1 LECTURE 3 17

    EF (2REF) = (CE)2

    y(2Ry) =

    y2R = (y2is negligible)

    y=

    2

    l

    R8

    2

    l

    4

    2

    l

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    PH0101 UNIT 1 LECTURE 3 18

    or

    Wa =

    or

    g2 I8 Yy

    2

    8R1

    ly

    yIalWY

    g8

    2

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    PH0101 UNIT 1 LECTURE 3 19

    If the beam is of rectangular cross-section,

    , where b is the breath and d is the

    thickness of beam. If M is the mass, the

    corresponding weight W = Mg

    12

    3bd

    Ig

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    PH0101 UNIT 1 LECTURE 3 20

    Hence

    ybd

    aMglY

    3

    2

    2

    3

    from which Y the Youngs modulus of thematerial of the bar is determined.

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    PH0101 UNIT 1 LECTURE 3 21

    Exper iment

    A rectangular beam (or bar) AB of uniformsection

    is supported horizontally on two knife edges A

    and B as shown in Figure

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    PH0101 UNIT 1 LECTURE 3 22

    Two weight hangers of equal masses aresuspended from the ends of the beam.

    A pin is arranged vertically at the mid-pointof the beam.

    A microscope is focused on the tip of the pin.

    Initial reading of the microscope in thevertical scale is noted.

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    PH0101 UNIT 1 LECTURE 3 23

    Equal weights are added to both hangerssimultaneously and the reading of the

    microscope in the vertical scale in noted.

    The experiment is repeated for decreasing

    order of magnitude of the equal masses.

    The observations are then tabulated and the

    mean elevation (y) at the mid point of the bar

    is determined.

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    PH0101 UNIT 1 LECTURE 3 24

    Load in Kg

    Microscope reading elevation Meanelevation(y)

    for

    a load of M.

    Load

    increasing

    Load

    decreasingMean

    WW+50 gms

    W+100 gms

    W+150 gms

    W+200 gms

    W+250 gms

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    PH0101 UNIT 1 LECTURE 3 25

    The length of the bar between the knifeedges lis measured.

    The distance of one of the weight hangersfrom the nearest knife edge p is measured.

    The breadth (b) and thickness (d) of the barare measured using vernier calipers andscrew gauge.

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    PH0101 UNIT 1 LECTURE 3 26

    The youngs modulus of the material of the

    beam is determined by the relation

    Nm-2

    ybd

    lagMY

    3

    2

    2

    3

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    PH0101 UNIT 1 LECTURE 3 27

    THANK YOU

    THANK YOU