two port networks unit ii
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TRANSCRIPT
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An Introduction ToTwo – Port Networks
The University of TennesseeElectrical and Computer Engineering
Knoxville, TN
wlg
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Two Port Networks
Generalities: The standard configuration of a two port:
The NetworkInputPort
Output Port
+
_ _
+V1 V2
I1 I2
The network ?
The voltage and current convention ?
* notes
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Two Port Networks
Network Equations:
V1 = z11I1 + z12I2
V2 = z21I1 + z22I2
I1 = y11V1 + y12V2
I2 = y21V1 + y22V2
V1 = AV2 - BI2
I1 = CV2 - DI2
V2 = b11V1 - b12I1
I2 = b21V1 – b22I1
V1 = h11I1 + h12V2
I2 = h21I1 + h22V2
I1 = g11V1 + g12I2
V2 = g21V1 + g22I2
ImpedanceZ parameters
AdmittanceY parameters
TransmissionA, B, C, D
parameters
HybridH parameters
* notes
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Two Port Networks
Z parameters:
1
111 I
Vz
02I
2
112 I
Vz
01I
1
221 I
Vz
02I
2
222 I
Vz
01I
z11 is the impedance seen looking into port 1 when port 2 is open.
z12 is a transfer impedance. It is the ratio of the voltage at port 1 to the current at port 2 when port 1 is open.
z21 is a transfer impedance. It is the ratio of the voltage at port 2 to the current at port 1 when port 2 is open.
z22 is the impedance seen looking into port 2 when port 1 is open.
* notes
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Two Port Networks
Y parameters:
1
111 V
Iy
02V
2
112 V
Iy
01V
1
221 V
Iy
02V
2
222 V
Iy
01V
y11 is the admittance seen looking into port 1 when port 2 is shorted.
y12 is a transfer admittance. It is the ratio of the current at port 1 to the voltage at port 2 when port 1 is shorted.
y21 is a transfer impedance. It is the ratio of the current at port 2 to the voltage at port 1 when port 2 is shorted.
y22 is the admittance seen looking into port 2 when port 1 is shorted.
* notes
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Two Port Networks
Z parameters: Example 1
Given the following circuit. Determine the Z parameters.
8
2 0 2 0
1 0
+
_
+
_
V 1 V 2
I1 I2
Find the Z parameters for the above network.
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Two Port Networks
Z parameters: Example 1 (cont 1)
For z11:
Z11 = 8 + 20||30 = 20
For z22:
For z12:
Z22 = 20||30 = 12
2
112 I
Vz
01I
8
2 0 2 0
1 0
+
_
+
_
V 1 V 2
I1 I2
22
1 83020
2020xI
xxIV
Therefore:8
8
2
212
I
xIz = 21z
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Two Port Networks
Z parameters: Example 1 (cont 2)
The Z parameter equations can be expressed inmatrix form as follows.
2
1
2
1
128
820
I
I
V
V
2
1
2221
1211
2
1
I
I
zz
zz
V
V
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Two Port Networks
Z parameters: Example 2 (problem 18.7 Alexander & Sadiku)
You are given the following circuit. Find the Z parameters.
1
1
4
2
2 V x
+
-
Vx
+ +
__
V 1 V 2
I1 I2
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Two Port Networks
Z parameters: Example 2 (continue p2)
1
111 I
Vz
02I
1
1
4
2
2 V x
+
-
Vx
+ +
__
V 1 V 2
I1 I2
6
26
6
2
11xxxxxx VVVVVV
I
2
31
xVI ; but 11 IVVx
Substituting gives;
2
3 111
I VI
or
3
511
1
1 zI
V
Z21 = -0.667
Z12 = 0.222
Z22 = 1.111
Other Answers
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Two Port Networks
Transmission parameters (A,B,C,D):
The defining equations are:
2
2
1
1
I
V
DC
BA
I
V
2
1
V
VA
I2 = 0 2
1
I
VB
V2 = 0
2
1
V
IC
I2 = 0 2
1
I
ID
V2 = 0
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Two Port Networks
Transmission parameters (A,B,C,D):
Example Given the network below with assumed voltage polarities andCurrent directions compatible with the A,B,C,D parameters.
+
_
+
_
R 1
R 2V 1 V 2
I1 -I2
We can write the following equations.
V1 = (R1 + R2)I1 + R2I2
V2 = R2I1 + R2I2
It is not always possible to write 2 equations in terms of the V’s and I’s Of the parameter set.
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1
1R
2
1
R
2
21
R
RR
Two Port Networks
Transmission parameters (A,B,C,D):
Example (cont.)
V1 = (R1 + R2)I1 + R2I2
V2 = R2I1 + R2I2
From these equations we can directly evaluate the A,B,C,D parameters.
2
1
V
VA
I2 = 02
1
I
VB
V2 = 0
2
1
V
IC
I2 = 0 2
1
I
ID
V2 = 0
=
=
=
=
Later we will see how to interconnect two of these networks together for a final answer
* notes
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Two Port Networks
Hybrid Parameters: The equations for the hybrid parameters are:
2
1
2221
1211
2
1
V
I
hh
hh
I
V
1
111 I
Vh
V2 = 02
112 V
Vh
I1 = 0
1
221 I
Ih
V2 = 0 2
222 V
Ih
I1 = 0
* notes
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Two Port Networks
Hybrid Parameters: The following is a popular model used to representa particular variety of transistors.
+ +
_ _
V 1 V 2
+
_
K 1
K 4K 3V 1K 2V 2
I1 I2
We can write the following equations:
D
VCII
BVAIV
212
211
* notes
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4
1
K
K2
K3
K1
Two Port Networks
Hybrid Parameters:
D
VCII
BVAIV
212
211
We want to evaluate the H parameters from the above set of equations.
1
111 I
Vh
V2 = 0 2
112 V
Vh
I1 = 0
1
221 I
Ih
V2 = 02
222 V
Ih
I1 = 0
=
=
=
=
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2
1
R
1
- 1
1R
Two Port Networks
Hybrid Parameters: Another example with hybrid parameters.
Given the circuit below.
+
_
+
_
R 1
R 2V 1 V 2
I1 -I2The equations for the circuit are:
V1 = (R1 + R2)I1 + R2I2
V2 = R2I1 + R2I2
The H parameters are as follows.
1
111 I
Vh
2
112 V
Vh
1
221 I
Ih
2
222 V
Ih
V2=0
V2=0
I1=0
I1=0
=
=
=
=
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Two Port Networks
Modifying the two port network:
Earlier we found the z parameters of the following network.
8
2 0 2 0
1 0
+
_
+
_
V 1 V 2
I1 I2
2
1
2
1
128
820
I
I
V
V
* notes
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Two Port Networks
Modifying the two port network:
We modify the network as shown be adding elements outside the two ports
8
2 0 2 0
1 0
+
_
+
_
V 1 V 2
I1 I2
+
_1 0 v
6
4
We now have:
V1 = 10 - 6I1
V2 = - 4I2
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Two Port Networks
Modifying the two port network:
We take a look at the original equations and the equations describingthe new port conditions.
2
1
2
1
128
820
I
I
V
V V1 = 10 - 6I1
V2 = - 4I2
So we have,
10 – 6I1 = 20I1 + 8I2
-4I2 = 8I1 + 12I2
* notes
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-0.2273
0.4545
0
10
168
826
Two Port Networks
Modifying the two port network:
Rearranging the equations gives,
2
1
I
I
1
2
1
I
I
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Two Port Networks
Y Parameters and Beyond:
Given the following network.
+
_
+
_
V 1 V 2
I1I2
s
1
1
1
s
(a) Find the Y parameters for the network.
(b) From the Y parameters find the z parameters
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Two Port Networks
1
111 V
Iy
02V
2
112 V
Iy
01V
1
221 V
Iy
02V 2
222 V
Iy
01V
I1 = y11V1 + y12V2
I2 = y21V1 + y22V2
+
_
+
_
V 1 V 2
I1I2
s
1
1
1
s
To find y11
12
2)
12
2(
111 sI
ssIV so = s + 0.5
1
111 V
Iy
02V
We use the above equations toevaluate the parameters from thenetwork.
Y Parameter Example
short
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Two Port Networks
Y Parameter Example
1
221 V
Iy
02V +
_
+
_
V 1 V 2
I1
s
1
1
1
s
I2
212IV
We see
= 0.5 S
1
221 V
Iy
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Two Port Networks
Y Parameter Example
+
_
+
_
V 1 V 2
I1
s
1
1
1
s
I2
2
112 V
Iy
01V
21
12 V
Iy
122IV
We have
= 0.5 S
short
2
222 V
Iy
01V
We have
)2(
222
s
sIV s
y1
5.022
To find y12 and y21 we reverse things and short V1
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Two Port Networks
Y Parameter Example
Summary:
Y =
s
s
yy
yy
15.05.0
5.05.0
2221
1211
Now suppose you want the Z parameters for the same network.
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Two Port Networks
Going From Y to Z Parameters
For the Y parameters we have:
VYI
For the Z parameters we have:
IZV
From above; IZIYV 1
Y
y
Y
yY
y
Y
y
zz
zzYZ
1121
1222
2221
12111 YY
det
Therefore
where
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Two Port Parameter Conversions:
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Two Port Parameter Conversions:
To go from one set of parameters to another, locate the set of parametersyou are in, move along the vertical until you are in the row that containsthe parameters you want to convert to – then compare element for element
22
11 hz H
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Interconnection Of Two Port Networks
Three ways that two ports are interconnected:
* Parallel
* Series
* Cascade
ba
yyy
ba
zzz
ba
TTT
ya
yb
za
zb
Ta Tb
parametersY
parametersZ
parametersABCD
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Interconnection Of Two Port Networks
Consider the following network:
R 1
R 2
R 1
R 2T1 T2
Referring to slide 13 we have;
+
_
+
_
V1 V2
I1 I2
1
2
V
VFind
2
2
2
121
2
12
21
1
1
11
11
2
I
V
R
RR
RR
R
RR
RR
I
V
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2
2
2
121
2
12
21
1
1
11
11
2
I
V
R
RR
RR
R
RR
RR
I
V
Interconnection Of Two Port Networks
Multiply out the first row:
)(
2112
212
2
1
2
2
211
IRRR
RRV
R
R
R
RRV
Set I2 = 0 ( as in the diagram)
22211
22
1
2
32
RRRR
R
V
V
Can be verified directly
by solving the circuit
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End of Lesson
Basic Laws of Circuits
Two-Port Networks