VIRINAH BINTI JOLIS-CT11210273TUTORIAL TASKInterpreting Test Scores and Item AnalysisQuestion 1-Measures of Central TendenciesCalculate the mean, median and mode of the followinga) 46,45,45,43,42,41,40,37,32,31,29,28,25,22,19(n=15)b) 45,50,60,32,67,89,56,76,90,78,45,32,45,66,56(n=15)Answer 1(a) Mean19+22+25+28+29+31+32+37+40+41+42+43+45+45+4615525 =35 15

Medianxm = x 15+1 = 16 = 8 = 37 2 2

Mode

45==================================================================== 1 (b) Mean32+32+45+45+45+50+56+56+60+66+67+76+78+89+90 15887 = 59.13 15 Medianxm = x 15+1 = 16 = 8 = 56 2 2

Mode

32, 45, 56

Question 2

Measures of Dispersion Calculate the range and standard deviation of the following scores:CANDIDATESABCDEFGHIJ

MARKS!3117131149111318

Answer

Mean13 11 7 13 11 4 9 11 13 18 110 = 11 Mean 10 10

x(x-m)2

134

110

716

134

110

449

94

110

134

1849

m = 11S ( x-m )2

6 130 = 1310

s.d = 3.6

Question 3

Quantitative Item Analysis Look at the information on the following items, item X, Y, ZOPTIONITEM XITEM YITEM Z

A B C* DA* B C DA B* C D

UPPER1 0 11 34 1 5 43 4 3 5

LOWER2 0 7 61 7 3 30 10 2 3

Find out

a) What is the difficulty level?

ITEM XITEM YITEM Z18 = 0.6 5 = 0.16 14 = 0.46 30 30 30

b) What is the discrimination index?

ITEM XITEM YITEM Z11 - 7 = 0.13 4 1 = 0.1 4 10 = - 0.2 30 30 30

c) Should this item be eliminated?Yes, these three items should be eliminated especially Item Z. They completely not discriminate as well as an item with an index of 0.6 or 0.7.

d) Should any distractor be eliminated or modified?No, because without distractor, the item will not really challenge the students abilities and instead of eliminating the distractor, teacher can minimize distractions in each item.