SPM QUESTION FORM 4 SOLUTION OF TRIANGLESSPM 2003 P2 Q15 Diagram 5 shows a tent VABC in the shape of a pyramid with triangle ABC as the horizontal base. V is the vertex of the tent and the angle between the inclined plane VBC and the base is .

Given that VB=VC=2.2 m and AB=AC=2.6 m , calculate (a) The length of BC if the area of the base is 3 , [3 marks] [3 marks] [4 marks]

(b) The length of AV if the angle between AV and the base is (c) The area of triangle VAB

SPM 2004 P2 Q13. Diagram 6 shows a quadrilateral ABCD such that ABC is acute.

(a) Calculate (i) ABC (ii) ADC, (iii) The area , in , of quadrilateral ABCD. [8 marks]

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SPM QUESTION FORM 4 SOLUTION OF TRIANGLES(b) A triangle A B C has the same measurements as those given for triangle ABC , that is, A C = 12.3

cm, C B = 9.5 cm and B A C = 40. (i) Sketch the triangle A B C , (ii) State the size of A B C SPM 2005 P2 Q12

, but which is different in shape to triangle ABC. [2 marks]

A Rajah 7 menunjukkan sebuah segitiga ABC. 20 cm

B

65 o15 cm CRAJAH 7

(a) Hitungkan panjang, dalam cm, AC.

[2 markah]

(b) Suatu sisiempat ABCD dibentuk dengan keadaan AC ialah pepenjuru, ACD ! 40 o dan AD = 16 cm. Hitungkan dua nilai yang mungkin bagi ADC . (c) Dengan menggunakan ADC yang tirus dari (b), hitungkan (i) panjang, dalam cm, CD, (ii) luas, dalam cm 2 , sisiempat ABCD itu. [6 markah] [2 markah]

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SPM QUESTION FORM 4 SOLUTION OF TRIANGLES

SPM 2006 P2 Q13 Rajah 5 menunjukkan sebuah sisiempat ABCD. D 5 cm

40 o

C 6 cm

B A 9 cmRAJAH 5

Luas segitiga BCD ialah 13 cm 2 dan BCD ialah tirus. Hitung (a) BCD , (b) panjang, dalam cm, bagi BD, (c) ABD , (d) luas, dalam cm 2 , sisiempat ABCD. [2 markah] [2 markah] [3 markah] [3 markah]

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SPM QUESTION FORM 4 SOLUTION OF TRIANGLES

SPM 2007 P2 Q15 Diagram 7 shows quadrilateral ABCD .

(a) Calculate (i) The length , in cm , of AC (ii) ACB (b) Point A lies on AC such that A B = AB (i) Sketch ( A BC (ii) Calculate the area , in , of ( A BC

[4 marks]

[6 marks]

SPM 2008 P2 Q14 In Diagram 14, ABC is a triangle . ADFB, AEC and BGC are straight lines. The straight line FG is perpendicular to BC.

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SPM QUESTION FORM 4 SOLUTION OF TRIANGLES

It is given that BD = 19 cm , DA = 16cm , AE = 14 cm, DAE =

and FBG =

.

(a) Calculate the length , in cm , bagi (i) DE (ii) EC [5 marks] (b) The area of triangle DAE is twice the area of triangle FBG. Calculate the length , in cm , of BG. [4 marks] (c) Sketch triangle A B C which has a different shape from triangle ABC such that A B = AB , A C = AC and A B C = ABC. [1 marks]

SPM 2009 P2 Q12 Diagram 12 shows a trapezium KLMN. KN is parallel to LM and LMN is obtuse.

Find (a) The length , in cm , of LN (b) The length , in cm , of MN (c) LMN (d) The area , in , of triangle LMN. [2 marks] [3 marks] [3 marks] [2 marks]

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SPM QUESTION FORM 4 SOLUTION OF TRIANGLES

SPM 2010 P2 Q13 Solution by scale drawing will not accepted Diagram 13 shows triangle ABC and triangle CDE where BCE and ACD are straight lines.

(a) Calculate the length , in cm , of (i) BC (ii) DE (b) Point C lies on BE such that AC =AC (i) Sketch triangle AC B (ii) Find AC B (iii) Calculate the area , in , of triangle AC B.

[5 marks]

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