SULIT

BK 9

3

MARK SCHEME FOR ADDITIONAL MATHS. – BK 9

PAPER 1

No. Mark Scheme ΣΣΣΣ Marks

1 (a) 3

2− 1

(b) 3 1

2

2

1− 2

f(x) = 2 – 3x atau 2

13

q−= B1

2

3

15x2 - 2x – 1 = 0 atau setara 3

1

m +

1

n =

2

15

m n

mn

+= atau

1 1

m n

=1 1

15mn= − B2

m + n = - 2 dan m (n) = - 15 B1

3

4

-3 < p < 3 3

P B2

( -6)2 – 4(p)(p) > 0 B1

3

5

(a) 4 1

(b) x = 4 1

(c) ( 4, -3 ) 1

3

6

10 3

3

( 2) 2(1 )2

+ = − −x x B2

13( 2)

2(1 )23 3x

x+

− −= B1

3

−3 3 −3 3

SULIT

BK 9

4

7

1

4p = 3

2

21 3

=−

p

p B2

2

2log 1

1 3

=

−

p

p B1

3

8

(a) 4 1

(b) 2 2

6 − 4 or 10 – 2(4) B1 for using S2 in T2 = S2 – S1 or

S2 – 2S1

3

9 (a) a = 64 and r = 1

2 2

3 8ar = or 3 4 12ar ar+ = or 8 + 8r = 12 B1

(b) 128 2

64

11

2

∗

∗

−

B1 ( * follow through from the value of a and r )

4

10

p = −3 ,q = 1

2 (both) (3)

p = −3or q = 1

2 B2

1 1px

y q= − +

m = 3 or c = 2 B1

3

SULIT

BK 9

5

11

k = −4 dan h = 1

3− 3

k = −4 atau h = 1

3− B2

23

2−=

−k atau 3h = (k – 2) + 5 B1

3

12

14.25 3

1

1(40) 7

410.5 108

Q

−

= +

B2

L =10.5 or F =7 and f = 8 B1

3

13

(a) k = 3 1

(b) m = 6 2

3(m – 2) = 12 B1

3

14

(a) 8

8 6 or 6

i j

+ % %

2

2 23

5 9

− −

or 3(2 5 ) ( 2 9 )i j i j+ − − +% %% %

B1

(b) 4 3

5

i j+% % 2

2 28 6+ @ 10 B1

4

SULIT

BK 9

6

15

(a) 13

12− 2

1

cos A B1

(b) 16

63− 2

5 3

12 4

5 31

12 4

+ −

− −

B1

4

16

(a) 4

5 P = 120 1

(b) 72 2

1

3

3

4PP × atau 4 x 3 x 2 x 3 B1

3

17

.

(a) 2

5

3

6CC × = 200 1

(b) 281 2

2

5

3

6CC × + 1

5

4

6 CC × + 0

5

5

6CC × B1

3

18

(a) θ = 1.5 radian 2

21

(8)2

(θ ) = 48 B1

(b) 12 cm 2

8(1.5) B1

4

SULIT

BK 9

7

19

(a) 30 60x + 1

(b) − 60 2

for 0dy

dx= @ x = −2 B1

3

20

56

p 3

( )1

2 28r pδ π

π= × B2

2 or 28dA

r rdr

π= = B1

3

21

9

8− 3

( )

+−−

+ 221)1(2

1

)1)1(2(

1 B2

1

1

2)12(

3

3

1

−

+x B1

3

22 (a)

2

1 2

p(6) – 3 = 0 B1

(b) 834

2

+−= xx

y 2

cxx

y +−= 34

2

B1

4

23

.

(a) 0.063 1

(b) 0.91 2

0.7 + 0.7 x 0.3 B1

3

SULIT

BK 9

8

24

(a) 0.1014 2

3 5

8

3

5 3

8 8C

B1

(b) 0.8649 // 0.8650 2

P(X ≥ 2) = 1 −

0 8 1 7

8 8

0 1

3 5 3 5

8 8 8 8C C

−

B1

4

25

(a) 6.6 2

15

3.52.4

µ−= B1

(b) 0.5662 2

*7 6.6

2.4z

−≤ B1

4

END OF MARK SCHEME