transition algebra manuel navarro and dirk hodges austin, tx may 6 th and 7 th, 2011
TRANSCRIPT
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
10. “Baseball is ninety percent mental and the other half is physical.” (percentage)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
9. “Half the lies they tell about me aren't true.” (fractions)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
8. “I knew I was going to take the wrong train, so I left early.” (distance formula)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
7. “You better cut the pizza in four pieces because I'm not hungry enough to eat six.” (fractions)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
6. “I take a two hour nap, from one o'clock to four.” (subtraction)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
5. “90% of the putts that are short don't go in.” (percentage)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
4. “You give 100 percent in the first half of the game, and if that isn't enough in the second half you give what's left.” (percentage)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
3. “The towels were so thick there I could hardly close my suitcase.” (Volume)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
2. “A nickel ain't worth a dime anymore.” (value of money)
TOP TEN QUOTES FROM THAT GREAT MATHEMATICIAN,
YOGI BERRA
1. “He hits from both sides of the plate. He's amphibious.”
(okay it’s a biology question)
Adult learners are encouraged to learn math
from a “hands on, real world” perspective -
Concrete learning.
But when they show up in the college classroom, they
encounter the world of Abstract learning – rules,
facts, theorems…
3rd Simple ruleDistributive Property
If there are parentheses in an equation, then multiply across the parentheses
distributing evenly.
Using the Distributive Property
a.) 2(x + y)
= 2x + 2y
Example: Find each product by using the distributive property to remove the parentheses.
b.) 7(x + 2y – 5z) = 7x + 14y – 35z
c.) – 4(3a – 3b – 10c) = – 12a + 12b + 40c
a.) 2(x + y)
b.) 7(x + 2y – 5z) c.) – 4(3a – 3b – 10c)
4th Simple ruleAddition Property of Equality
Collect like terms by moving variables to one side of the fence
and non-variables to the other side (making sure to change the
sign if they cross over).
Combining Like Terms
6x2 + 7x2
19xy – 30xy
13xy2 – 7x2y
13x2
– 11xy
Can’t be combined (since the terms are not like terms)
Terms Before Combining After Combining Terms
5th Simple ruleMultiplication Property of Equality
Divide (or multiply) both sides of an equation to get the variable
isolated and positive.
6th Simple ruleMultiplication Property of Inequality
If the problem is an inequality, then all rules apply with 2
exceptions:1)When dividing by a negative
number the direction of the arrow must be changed.
2)When there is a compound inequality each set of terms must
be applied.
7th Simple ruleSystems of equations
If problem has 2 variables then must substitute the value of one of the variables (which is many
times a polynomial) for the other.
Solve the following system using the substitution method.3x – y = 6 and – 4x + 2y = –8
Solving the first equation for y, 3x – y = 6
–y = –3x + 6 y = 3x – 6 Multiply both sides by – 1.)
Substitute this value for y in the second equation. –4x + 2y = –8 –4x + 2(3x – 6) = –8 Replace y with result from first equation. –4x + 6x – 12 = –8 Use the distributive property.
2x – 12 = –8 Simplify the left side.
2x = 4 Move 12 to the other side and change sign.
x = 2 Divide both sides by 2.
The Substitution Method
Continued.
Example:
Substitute x = 2 into the first equation solved for y.
y = 3x – 6 = 3(2) – 6 = 6 – 6 = 0
Our computations have produced the point (2, 0).
Check the point in the original equations.
First equation,
3x – y = 6
3(2) – 0 = 6 true
Second equation,
–4x + 2y = –8
–4(2) + 2(0) = –8 true
The solution of the system is (2, 0).
The Substitution Method
Example continued:
Solve x2 = 49
2x
Solve (y – 3)2 = 4
Solve 2x2 = 4
x2 = 2
749 x
y = 3 2
y = 1 or 5
243 y
Square Root PropertyExample:
Solve (x + 2)2 = 25
x = 2 ± 5
x = 2 + 5 or x = 2 – 5
x = 3 or x = 7
5252 x
Square Root Property
Example:
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