traction power
DESCRIPTION
For giving motion to a train, following resistances mustbe exceeded:1. Locomotive resistance (Rl)2. Wagon resistance (Rv)3. Curve resistance (Rk)4. Slope(ramp) resistance (Rr) Total resistance R=Rl+Rv+Rr+RkTRANSCRIPT
•MARCH 2015 Research, Planning & Coordination Department 2
For giving motion to a train, following resistances must
be exceeded:
1. Locomotive resistance (Rl)
2. Wagon resistance (Rv)
3. Curve resistance (Rk)
4. Slope(ramp) resistance (Rr)
Total resistance R=Rl+Rv+Rr+Rk
TRACTION POWER
MOTION OF A TRAIN
•MARCH 2015 Research, Planning & Coordination Department 3
We symbolize traction force with F:
R>F The train can not move
R=F The train moves with a constant speed and
without any acceleration.
R<F The move with acceleration and speed
increases by the time
TRACTION POWER
MOTION OF A TRAIN
•MARCH 2015 Research, Planning & Coordination Department 4
Rl= (rl).(Gl)
rl== 0,65 + (13,15/P) + (0,00932 . V) + (0,004526 . A . V²)/(P.N)
• P = average axle load (tonnes)
• N = number of axle
• V = speed (km/h)
• A = locomotive area of view(m²)
• G L = mass of locomotive (tonnes) ifade eder.
Rl unit is Kp and rl unit is kp/tonnes
TRACTION POWER
LOCOMOTIVE RESISTANCE (Rl)
•MARCH 2015 Research, Planning & Coordination Department 5
Rv= (rv).(Gv)
Freight Wagon: r v = 2 + 0,057 . (V²/100)
Passenger Wagon: r v = 1,968 + 0,00932 . V +
0,000161. V²
• G v = mass of wagon
• V = train speed (km/h)
Rv unit is Kp and rv unit is kp/tonnes
TRACTION POWER
LOCOMOTIVE RESISTANCE (Rv)
•MARCH 2015 Research, Planning & Coordination Department 6
R k = r k . (G l + G v)
rk= 650/(R-55)
• R is the curve with minimum radius among the
all curves.
Rk unit is Kp and rk unit is kp/tonnes
TRACTION POWER
CURVE RESISTANCE (Rk)
•MARCH 2015 Research, Planning & Coordination Department 7
TRACTION POWER
SLOPE RESISTANCE (Rk)
R r = rr . (G l + G v)
rr = i
Rk unit is Kp and rk unit is kp/tonnes
•MARCH 2015 Research, Planning & Coordination Department 8
100 tonnes and 6 axle-locomotive will carry 700 tonnes burden with 40
km/h speed. What is the power of this locomotive on alignment and on
% 05, % 010, % 015, % 020, %025 slopes?
(Locomotive view area is 10 m2)
13,15 0,004526 . A . V2
r l = 0,65 + ---------- + 0,00932 . V + ------------------------------ Kp/ton
P P . N
13,15 0,004526 . 10 . 402
r l = 0,65 + ---------- + 0,00932 . V + ------------------------------ = 2,535 Kp/ton
16,66 16,66 . 6
TRACTION POWER
EXAMPLE
•MARCH 2015 Research, Planning & Coordination Department 9
R l = r l . G l
= 2,535 . 100
= 253 Kp
V2
r v = 2 + 0,057 -------- Kp/ton
100
402
r v = 2 + 0,057 -------- = 2,912 Kp/ton
100
R v = r v . G v
= 2,912 . 700
= 2038 Kp
TRACTION POWER
EXAMPLE
•MARCH 2015 Research, Planning & Coordination Department 10
•R r = rr . (G l + G v) and on alignment R r = 0
•On % 05 slope Rr = 5 . (100 + 700) = 4000 Kp
•On % 010 slope Rr = 10 . (100 + 700) = 8000 Kp
•On % 015 slope Rr = 15 . (100 + 700) = 12000 Kp
•On % 020 slope Rr = 20 . (100 + 700) = 16000 Kp
•On % 025 slope Rr = 25 . (100 + 700) = 20000 Kp
TRACTION POWER
EXAMPLE
•MARCH 2015 Research, Planning & Coordination Department 11
R = R L + R v + R r = T
On alignment R = R L + R v olur ve R = 253 + 2038 = 2291 Kp
On % 05 slope R = RL + Rv + Rr and R = 253 + 2038 + 4000 =6291 Kp
On % 010 slope R = RL + Rv + Rr and R = 253 + 2038 + 8000 = 10291 Kp
On % 015 slope R = RL + Rv + Rr and R = 253 + 2038 + 12000 = 14291 Kp
On % 020 slope R = RL + Rv + Rr and R = 253 + 2038 + 16000 = 18291 Kp
On % 025 slope R = RL + Rv + Rr and R = 253 + 2038 + 20000 = 22291 Kp
TRACTION POWER
EXAMPLE
•MARCH 2015 Research, Planning & Coordination Department 12
P=T.V/367 (kW)
On alignment P=250 kW
On % 05 slope P = 686 kW
On % 010 slope P = 1122 kW
On % 015 slope P = 1558 kW
On % 020 slope P = 1994 kW
On % 025 slope P = 2430 kW
TRACTION POWER
EXAMPLE
•MARCH 2015 Research, Planning & Coordination Department 13
%00 %05 %010 %015 %020 %025
RL (Kp) 253 253 253 253 253 253
Rv (Kp) 2038 2038 2038 2038 2038 2038
Rr (Kp) 0 4000 8000 12000 16000 20000
R = T(Kp) 2291 6291 10291 14291 18291 22291
P (KW) 250 686 1122 1558 1994 2430
TRACTION POWER
EXAMPLE