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    Topic 3 Numerical Methods

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    3.1 Solutions of Non-Linear Equations

    Solve the following equations :

    1. Solve 0542 xx

    2. Solve 083 x

    3. Solve 03 xex

    So, in this subtopic we are to going discuss numerical methods in

    finding the approximate numerical solutions of such equations.

    Introduction

    Many equations cannot be solved exactly, but various methods of

    finding approximate numerical solutions exist.

    The most commonly used methods have two main parts:

    (a) finding an initial approximate value(b) improving this value by an iterative process

    Initial Values:

    The initial value of the roots of f(x) = 0 can be located

    approximately by either a graphical or an algebraic method.

    GRAPHICAL METHOD:

    Either

    (a) Plot ( or sketch ) the graph ofy =f(x).

    The real roots are the points where the curve cuts the x axis.

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    Or

    (b) Rewritef(x) = 0 in the form F(x) = G(x).

    Plot ( or sketch ) y =F(x) andy = G(x). The real roots are at

    the points where these graphs intersect.

    Example 1

    Find the approximate value of the equation 04ln xx by

    using the graphical method.

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    Example 2

    On the same axes, sketch 1 xe y and .1 xy Show that the

    equation01)1ln(

    xx has only one root .The sketch shows that there is only one point of intersection and so

    the equation 01)1ln( xx has only one root .

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    Example 3

    By sketching the graph of 3xy and 13 xy on the same

    coordinate axes, show that the equation 0133

    xx has threereal roots.

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    Algebraic Method

    Find two values a and b such that f(a) and f(b) have

    different signs.

    At least one root must lie between a and b if f(x) is

    continuous.

    If more than one root is suspected between a and b, sketch

    y =f(x).

    Example 4

    Show that the equation 043 xx has a root between 3.1x

    and 4.1x . Approximate the root to two decimal places.

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    3.2 Iterative Method

    All iterative methods follow the same basic pattern. A sequence of

    approximations ,......,,, 4321 xxxx is found, each one closer to the

    root of 0xf . Each approximation is found from the one

    before it using a specified method. The process continue until the

    required accuracy is reached.

    Iteration Method

    Rewrite the equation 0xf in the form xgx

    If the initial approximation is ,1x then calculate

    12 xgx

    23 xgx

    34 xgx

    ..

    This method fails if 1' 1 xg near the root.

    So we are looking for 1' 1 xg .

    Example 5

    Using the iteration method, find the solution of xexxf near

    5.0x correct to three decimal places.

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    Example 6

    Show that the equation 0412

    xx has a root between 0.2 and

    0.3. Taking 0.2 as the first approximation, use the iteration method

    to find the root of the equation. Give your answer correct to three

    significant figures.

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    Example 7

    Show that the equation 05.0sin xx has a root lying in the

    interval 1,2 . Using the iteration formula 5.0sin1 nn xx ,

    find the root correct to three decimal places.

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    Example 8

    Given the equation 02ln xx

    a) Show that there exist a real root between 1.5 and 1.6

    b) Find the appropriate iterative function for the equation.

    c) Hence, find the real root of the equation correct to three decimal

    places by using iterative method.

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    EXERCISE

    1. Show that the equation 03 xex has a root between 0and 1. By taking the first approximation x1 as 0.8, use

    iteration method to find the root correct to 3 decimal places.

    (Ans: 0.792)

    2. Find an approximate root of the equation .043 xx Find this root correct to 3 decimal places using iteration

    method. (Ans: 1.379)

    3. Sketch the graph of )2(ln xy where x

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    3.3 Newton-Raphson method

    Newton-Raphson Method

    If 1x is the first approximation to the root of the equation

    0xf , then second, third,. approximations are written as

    ,........,, 432 xxx and are given by the formula

    11

    12' xf

    xfxx

    Repeat this process as required

    nn

    nnxf

    xfxx

    '1

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    Example 9

    Using the Newton-Raphson Method, find the solution of xexxf

    near 5.0x correct to three decimal places.

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    Example 10

    Show that the equation 063 xx has a root between 1 and 2.

    Using the Newton-Raphson method with the starting point 1.6,

    determine an approximation to this root, giving your answer to

    three significant figures.

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    Example 11

    Use Newton-Raphson method to find an approximate value of 315

    . Give your answer correct to three decimal places.

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    Example 12

    Sketch the graph of xey and y = 2x where x < 2, on the

    same axes. Get the first approximation, 0x for the equation

    ex

    = 2 x where 0 < 0x < 1. Hence, by using Newton-Raphson

    method , solve the equation ofx

    ex

    2

    1for x < 2 to three

    decimal places.

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    Example 13

    Show that the equation 0sin2 xx has a root between 1x

    (radian) and 2x (radian). Find the root of equation by using

    a)Iteration methodb)Newton Raphson method

    giving your answer correct to two decimal places.