titration (general)

25
Titrimetry A common laboratory method for chemical quantitative analysis where a titrant is slowly added until an equivalence pt is reached

Upload: reehmamendina

Post on 18-Dec-2015

243 views

Category:

Documents


3 download

DESCRIPTION

Inorganic Chemistry

TRANSCRIPT

  • Titrimetry

    A common laboratory method for chemical quantitative analysis

    where a titrant is slowly added until an equivalence

    pt is reached

  • 9/7/14

    Terms

    a. Analyte

    b. Titrant c. Equivalence pt

    d. Indicator

    e. End pt

  • Types of Titration

    a. Coulometric Titration: The Titrant is a Constant Direct Electrical Current

    b. Volumetric Titration: Based on volume of Titrant is used

    c. Gravimetric Titration: Based on weight of Titrant used

  • Coulometric Titration Au3+ + 3e Au

    e (titrant)

    Electrode

  • Volumetric Titration

    Titrant in biuret (Reagent of Known Conce.g. NaOH

    Analyte (unknown Conc)

    e.g. Acetic Acid

    CH3COOH + NaOH CH3COO- + H2O

    At Equivalence pt 1 mole CH3COOH: 1 mole NaOH

    Indicator: Phenoplthalein

    End Point: point where color changes From colorless to pink

  • Primary Reference Standard: Standards that dont need to be

    standardized1. High Purity

    2. Atmospherically Stable

    3. Non Hygroscopic

    4. Reasonable High Molar Mass

    5. Reasonable Solubility

    6. Preferably Certified by a Recognized Organization (USP, BP and NIST)

  • Secondary Reference Standard :Reagents that need to be

    Standardized against a primary reference standard

    e.g. NaOH Solutions Standardized Using KHP

  • Concentration of Standard Solutions

    a. Molarity ( moles per liter )

    b. Normality ( moles equivalents per liter)

  • Equivalents: Number of Reacting Species

    Depends on the Reaction Involved

    For Acid/ Base Reactions: H+ and OH-

    For Redox Reaction: electrons

  • Acid/Base Titrations (Reacting Species: H+ and OH- )

    Ca(OH)2 + 2HCl CaCl2 + 2H2O

    1 mole 2 mole

    2 equivalents 2 equivalents

    Reacting Species

    OH- + H+ H20

  • Acid/Base Titrations (Reacting Species: H+ and OH- )

    a. 1mole NaOH...1 moles equivalents

    b. 1mole H2SO4...2 moles equivalents

    c. 1 mole H3PO4

    ..3 moles equivalents

    d. 2 moles Ca(OH)2

    ..4 moles equivalents

    b. 0.5 moles Fe(OH)3

    ..1.5 moles equivalents

  • Acid/Base Titrations (Reacting Species: H+ and OH- )

    Molarity = moles/L

    Normality = equivalents/La. 1 molar of NaOH.....1 Normal

    b. 1 molar of H2SO4....2 Normal

    c. 1 molar of H3PO4...3 Normal

    d. 0.25 molar of Fe(OH)3..0.75 Normal

  • Acid/Base Titrations (EW = grams/mole equivalent )

    a. 1mole NaOH ...1 mole equivalents

    (MW = 40 g )(EW = ? )

    b. 1mole H2SO4...2 moles equivalents

    (MW = 98g )... (EW = ? )

    c. 1 mole H3PO4..3 moles equivalents

    (MW = 98 g) .(EW = ? g )

  • Equivalent Weight (EW)

    EW = MW/n

    n= mole equivalents / mole compound

  • Acid/Base Titrations (EW = grams/mole equivalent )

    a. 1mole NaOH ...1 mole equivalents

    (MW = 40 g )(EW = ? )

    b. 1mole H2SO4...2 moles equivalents

    (MW = 98g )... (EW = ? )

    c. 1 mole H3PO4..3 moles equivalents

    (MW = 98 g) .(EW = ? g )

  • 9/7/14

    Problem 1

    How many grams of H2SO4 is needed to Prepare a 100 ml 0.2N H2SO4 solution?

    MW H2SO4 = 98 grams/mole

  • 9/7/14

    Problem 2

    How many mole equivalents H2SO4 are in 200 ml 0.1N H2SO4 solution?

  • 9/7/14

    Problem 3

    Given a 200 ml 0.1N H3PO4 solution

    (MW = 98 g/mole)

    a. What is the molarity of the solution?b. How many equivalents of H3PO4 are there?

    c. How many grams of H3PO4 are there?

  • 9/7/14

    Problem 4

  • Normality in Redox Reactions (Based on Electrons Transferred)

    MnO4- + 5Fe2+ + 8H+

    Mn2+ + 5Fe3+ + 4 H2O

  • Determine the moles equivalents of based on the above reaction

    2 moles FeCl3

    .. 2 moles equivalents

    2 moles KMnO4

    10 moles equivalents

  • Determine the Normality of the Following Solutions based on the

    above reaction 2M FeCl3

    .. 2 N FeCl3

    5M KMnO4

    25 N KMnO4

  • Why use Normality or Molarity?

    Sometimes it is more convenient because there is no need for

    stoichiometry

    Ratio of Mole Equivalents is always 1:1

  • Problem 5

    10 ml of a 0.02 M (0.1N) solution of KMnO4- is needed to titrate a 2 grams sample containing FeCl2 (MW = 126.8 g).

    a. What is the % mass of FeCl2 in your sample?

    MnO4- + 5Fe2+ + 8H+ Mn2+ + 5Fe3+ + 4 H2O

  • Problem 6

    10 ml of a 0.02 M (0.1N) solution of KMnO4 is needed to titrate a 20 ml solution of FeCl2 (MW = 126.8 g).

    a. What is the molarity of FeCl2 in your sample? MnO4- + 5Fe2+ + 8H+ Mn2+ + 5Fe3+ + 4 H2O

    TitrimetryTermsTypes of TitrationCoulometric TitrationVolumetric TitrationPrimary Reference Standard: Standards that dont need to be standardizedSecondary Reference Standard : Reagents that need to be Standardized against a primary reference standardConcentration of Standard SolutionsEquivalents: Number of Reacting SpeciesAcid/Base Titrations (Reacting Species: H+ and OH- )Slide 11Slide 12Acid/Base Titrations (EW = grams/mole equivalent )Equivalent Weight (EW)Slide 15Problem 1Problem 2Problem 3Problem 4Normality in Redox Reactions (Based on Electrons Transferred)Determine the moles equivalents of based on the above reactionDetermine the Normality of the Following Solutions based on the above reactionWhy use Normality or Molarity?Problem 5Problem 6