thomas jefferson national accelerator facility page 1 clas12 computing requirements g.p.gilfoyle...

Thomas Jefferson National Accelerator Facility

CLAS12 Computing Requirements

G.P.Gilfoyle

University of Richmond



Assume October, 2014 start date.Present major assumptions and results for:Data acquisitionCalibrationSimulationReconstructionReconstruction studiesPhysics analysis.



Data Acquisition

Assumptions: Event rate = 10 kHz Weeks running = 35Event size = 10 kBytes 24-hour duty factor = 60%

Data Rate = Event Rate x Event Size = 100 Mbyte/s

Average 24-hour rate = Data Rate x 24-hour duty factor = 60 Mbyte/s

Events/year = Event Rate x Weeks Running x 24-hour duty factor= 1.3x1011 Events/year

Data Volume/year = Events/year x Event size = 1270 TByte/year



Calibration

Assumptions: CPU-time/event = 155 ms Data fraction = 5%Data Passes = 5 Core efficiency = 90%

CPU-time/year = Events/year x CPU-time/event-core x Data fraction x Data passes

= 4.9x109 s

Calibration Cores = (CPU-time/year)/(year in seconds x Core efficiency)= 173 cores



Reconstruction - 1Assumptions: CPU-data-time/event = 155 ms Output/input size = 2

Data passes = 2 Fraction to disk = 10%Event size = 10 kBytes Events/year = 1.3 x 1011

Data volume/year = 1.3 Pbytes/year Core efficiency = 90%

CPU time/year = Data-events/year x CPU-data-time/event xData passes

= 3.9 x 1010 CPU-s/year

Reconstruction Cores = CPU-time/year/(year in seconds x Core efficiency) = 1387 cores

Cooked data to tape = Data volume/year x Data passes x Output/input size

= 5080 TByte/year



Reconstruction - 2

Assumptions CPU-data-time/event = 155 ms Output/input size = 2 and Results: Data passes = 2 Fraction to disk = 10%

Event size = 10 kBytes Events/year = 1.3 x 1011

Data volume/year = 1.3 Pbytes/year Core efficiency = 90%

Disk Storage = Cooked data to tape x Fraction to disk= 508 TByte

Average bandwidth = Event size x (1 + Output/input size) x Cores/(CPU-data-time/event)

= 268 Mbyte/s



Simulation -1

Assumptions: CPU-sim-time/event = 485 ms Events/year = 1.3 x 1011

Electron fraction = 50% Simulated/data events = 10 Analyzed fraction = 50% Multiplicity = 1.5 Core efficiency = 90%

Sim-events/year = Events/year x Electron fraction x Analyzed fraction x Simulated/data events

= 3.2 x 1011

CPU-sim-time/year = CPU-sim-time/event x Sim-events/year x Multiplicity = 2.3 x 1011 CPU-s/year

Simulation Cores = (CPU-sim-time/year)/(year in seconds x Core efficiency)= 8,139 cores



Simulation - 2

Assumptions CPU-sim-time/event = 485 ms Fraction to disk = 2% and Results: Sim-events/year = 3.2x1011 Fraction to tape = 10%

Simulation Cores = 8,139 Multiplicity = 1.5Output event size = 50 kBytes

Work Disk = Sim-events/year x Output event size x Fraction to Disk= 318 TBytes

Tape storage = Sim-events/year x Output event size x Fraction to Tape

= 1,588 TBytes/year

Average Bandwidth = (Output event size x Simulation cores)/CPU-sim-time/event

= 839 MBytes/s



Reconstruction Studies

Assumptions: CPU-data-time/event = 155 ms Fraction to disk = 5%Data passes = 10 Core efficiency = 90%

CPU-time/year = Fraction to disk x Events/year x Data passes CPU-data-time/event

= 3.4 x 1010 s

Cores = CPU-time/year/(year in seconds x Core efficiency)= 1,214 cores



Physics Analysis

CPU-time/year = Fraction to disk x Events/year x Data passes x CPU-data-time/event

= 1.7 x 1010 CPU-s/year

Cores = CPU-time/year/(year in seconds x Core efficiency)= 607 cores

Assumptions CPU-data-time/event-core = 8 ms Fraction of events = 50%Data passes = 10 Core efficiency = 90%



Summary

Cores Disk (TByte) Tape (TByte/yr)

DAQ 1,270

Calibration 173

Reconstruction 1,387 508 5,080

Simulation 8,139 318 1,558

Reconstruction Studies 1,214 508

Physics Analysis 607 889

Sum 11,520 2,223 7,938

thomas jefferson national accelerator facility page 1 clas12 computing requirements g.p.gilfoyle...

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