this is a sample test for the prealgebra–level algebra–ready placement test at the harbor...

111
This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided for each question. The review–links of all the topics may be accessed here . This is an interactive PowerPoint file. For the best viewing, download it and run it in the viewing–mode.

Upload: matthew-stevenson

Post on 13-Jan-2016

212 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

This is a sample test for the prealgebra–levelalgebra–ready placement testat the Harbor College

The solution and a link to the topic review are provided for each question. The review–links of all the topics may be accessed here.

This is an interactive PowerPoint file. For the best viewing, download it and run it in the viewing–mode.

Page 2: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

C

D

Question 1.

Answer for Question 1:

2842

The reduced form of is

67

34

47

23

Page 3: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q1

2842

The correct answer is 2/3.To reduce a fraction, we divide the numerator and the denominator by their greatest common factor (i.e. the largest number that can go into both numbers) which is 14.

=

Page 4: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q1

2842

The correct answer is 2/3.To reduce a fraction, we divide the numerator and the denominator by their greatest common factor (i.e. the largest number that can go into both numbers) which is 14.

=÷1428

42 ÷14= 2

3

Page 5: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

C

D

Question 1. 2842

The reduced form of

67

34

47

23

is

Page 6: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

C

D

Question 2.

Answer for Question 2:

56

14

=

42

512

712

1324

Page 7: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q2

56

14

=Convert into fractions with LCD = 1212

(5 x 2 – 1 x 3)

=

712

The correct answer is .

712

Page 8: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

C

D

Question 2. 56

14

=

42

512

712

1324

Page 9: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

C

D

Question 3.

Answer for Question 3:

2714

187

34

94

98

38

Page 10: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q3

2714

187

=

÷

2714 18

7x

The answer is . 34

reciprocate and multiply

Page 11: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q3

2714

187

=

÷

2714 18

7x3

22= 3

4

The answer is . 34

reciprocate and multiply

1

Page 12: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Question 3. 2714

187

Next Question

A

B

C

D

34

94

98

38

Page 13: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

C

D

Question 4.

Answer for Question 4:

42

3 143

=

3

42

1

41

1

41

3

Page 14: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Next Question

Solution to Q4

3 143

= 3 – 1 43

= 243

141=

The answer is .141

Link to review

Page 15: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

C

D

Question 4.

42

3 143

=

3

42

1

41

1

41

3

Page 16: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

C

D

Answer for Question 5:

,43

,98

32

43

98

43

98

32

98

98

43<

<

<

< 32

43

32

32

<

<

<

<

Question 5. Arrange

from the smallest to the largest.

Page 17: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q5

, 43

32

We cross multiply to compare the fractions.

The answer is B:

So 98

32

, similarly we have that

43

98<3

2<

43

<43

98< .

← larger

Page 18: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q5

, 43

32

We cross multiply to compare the fractions.

The answer is B:

So 98

32

, similarly we have that

43

98<3

2<

43

<43

98< .

← larger

43 =

Or multiply by the LCD = 36

36 x 98 =3

2=36 x 36 x

Link to reviewNext Question

9 4 12

27 32 24

the largestthe middle the smallest

Page 19: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Question 5. Arrange

from the smallest to the largest.

Correct!

Next Question

A

B

C

D

,43

,98

32

43

98

43

98

32

98

98

43

32

43

32

32

<

<

<

<

<

<

<

<

Page 20: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Question 6. A bag has 48 pieces of candies. Joe ate 7/8 of the whole bag. How many pieces of candies did Joe eat?

D

B

C

A 42

36

40

30

Answer for Question 6:

Page 21: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q6

48 x = 4287

6

The answer is 42.

Page 22: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Question 6. A bag has 48 pieces of candies. Joe ate 7/8 of the whole bag. How many pieces of candies did Joe eat?

Correct!

Next Question

42

36

40

30D

B

C

A

Page 23: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

6

4

0

–4

A

D

C

B

Question 7. –3 – (–5) – (–2) =

Answer for Question 7:

Page 24: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q7The answer is 4.

–3 – (–5) – (–2) = –3 + 5 + 2 = 4

Page 25: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

6

4

0

–4

Correct!

Next Question

Question 7. –3 – (–5) – (–2) =

A

D

C

B

Page 26: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

39

37

35

34

A

B

D

C

Question 8.

Answer for Question 8:

33 =32 x 36

Page 27: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q8

33 =32 x 36

33 38

2+6=8

The answer is 35.

Page 28: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q8.

33 =32 x 36

33 38

= 35

2+6=8 8–3=5

The answer is 35.

Page 29: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

39

37

35

34

Correct!

Next Question

Question 8. 33

=32 x 36

A

B

D

C

Page 30: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

2

4

6

8

A

B

C

D

Question 9. 24 ÷ 6 x 2

Answer for Question 9:

Page 31: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q9The answer is 8.

24 ÷ 6 X 2 = 4 x 2= 8

Page 32: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

2

4

6

8

A

B

C

D

Question 9. 24 ÷ 6 x 2

Page 33: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

15

–9

6

0D

B

C

A

Question 10. 6 – 3(–3) =

Answer for Question 10:

Page 34: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q10The answer is 8.

6 – 3(–3)= 6 + 9= 15

Page 35: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

Question 10. 6 – 3(–3) =

15

–9

6

0D

B

C

A

Page 36: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

C

B

Question 11. 2.3 – 0.45 + 0.08 =

Answer for Question 11:

1.93

1.83

1.73

2.03

Page 37: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q11The answer is 1.93.

2.3 – 0.45 + 0.08 = 1.85 + 0.08= 1.93

Page 38: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

Question 11. 2.3 – 0.45 + 0.08 =

1.93

1.83

1.73

2.03A

D

C

B

Page 39: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

C

D

Question 12. 1.22 x 0.5 =

Answer for Question 12:

0.36

0.6

0.24

0.72

Page 40: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q12The answer is 0.72.

1.22 x 0.5= 1.44 x 0.5= 0.72

Page 41: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

Question 12. 1.22 x 0.25 =

A

B

C

D

0.36

0.6

0.24

0.72

Page 42: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

D

B

C

A

Question 13. 0.108 ÷ 1.8 =

Answer for Question 13:

0.6

0.06

0.006

0.0006

Page 43: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q13The answer is 0.6.

0.108 ÷ 1.8= 1.08 ÷ 18= 0.6

Page 44: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

C

D

Question 13. 0.108 ÷ 1.8 =

0.6

0.06

0.006

0.0006

Page 45: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

D

Question 14.

Answer for Question 14:

–0.5

–0.8

–0.7

43

– 1.35 =

C –0.6

Page 46: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q14The answer is –0.6.

43

– 1.35

= 0.75 – 1.35= –0.6

Page 47: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

D

Question 14.

–0.5

–0.8

–0.7

43

– 1.35 =

C –0.6

Page 48: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

D

Question 15. 2.3 X 103 =

Answer for Question 15:

C

0.00023

0.023

230

2300

Page 49: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q15The answer is 230.

2.3 X 103

= 2.3 x 1,000= 2300

Page 50: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

D

Question 15. 2.3 X 103 =

C

0.00023

0.023

230

2300

Page 51: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

C

B

D

Question 16. How many grams of pure alcohol are there in 300 grams of cough syrup that is 5% alcohol?

Answer for Question 16:

A

1.5 g

150 g

15 g

0.15 g

Page 52: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q16The answer is 15 grams.

5% of 300 is

1005

x 300

Page 53: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Link to reviewNext Question

Solution to Q16The answer is 15 grams.

5% of 300 is

1005

x 300

= 15

3

Page 54: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

Question 16. How many grams of pure alcohol are there in 300 grams of cough syrup that is 5% alcohol?

C

B

D

A

1.5 g

150 g

15 g

0.15 g

Page 55: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

D

Question 17. Which of the following percentages is the closest to 2/7.

Answer for Question 17:

C 30%

20%

10%

40%

Page 56: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q17The answer is C: 30%

72

= 0.28…

Link to reviewNext Question

Page 57: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

D

Question 17. Which of the following percentages is the closest to 2/7.

C 30%

20%

10%

40%

Page 58: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

C

D

Question 18. Arrange the numbers 60%, 2/3, 0.61 from the smallest to the largest .

Answer for Question 18:

B

60%, 2/3, 0.61

60%, 0.61, 2/3,

2/3, 0.61, 60%,

0.61, 60%, 2/3,

Page 59: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q18The answer is B:

Link to reviewNext Question

60%, 0.61, 2/3,

60% = 0.60

2/3 ≈ 0.66

Page 60: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

C

D

Question 18. Arrange the numbers 60%, 2/3, 0.61 from the smallest to the largest .

B

60%, 2/3, 0.61

60%, 0.61, 2/3,

2/3, 0.61, 60%,

0.61, 60%, 2/3,

Page 61: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

B

C

D

Question 19. Joe got a raise from $15/hr to $18/hr. What is the % increase in Joe’s hourly wages?

Answer for Question 19:

A

3%,

18%,

15%,

20%,

Page 62: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q19The answer is A:

Link to reviewNext Question

20%

From $15 Joe got a of raise of 3$.

so the % increase is 3/15 = 20% .

Page 63: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

B

C

D

Question 19. Joe got a raise from $15/hr to $18/hr. What is the % increase in Joe’s hourly wages?

A

3%,

18%,

15%,

20%,

Page 64: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

B

C

A

Question 20. Let x = 4, then 6 – 5x is

Answer for Question 20:

D –14

–4

14

4

Page 65: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q20The answer is A:

Link to reviewNext Question

–14

Set x = 4 in 6 – 5x, we get 6 – 5(4)= 6 – 20= –14

Page 66: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

B

C

A

Question 20. Let x = 4, then 6 – 5x is

D –14

–4

14

4

Page 67: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

B

C

A

Question 21. If x = 3, y = 6, then xy – x – y is

Answer for Question 21:

D 9

0

6

–3

Page 68: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q21The answer is 9.

Link to reviewNext Question

Set x = 3, y = 6 in xy – x – ywe have 3(6) – 3 – 6 = 9

Page 69: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

B

C

A

Question 21. If x = 3, y = 6, then xy – x – y is

D 9

0

6

–3

Page 70: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

B

D

A

Question 22. If 3x – 2 = 16, then x is

Answer for Question 22:

C

12

8

6

4

Page 71: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q22The answer is x = 6.

Link to reviewNext Question

3x – 2 = 16 add 2 to both sides 3x = 18 divide both sides by 3 x = 6

Page 72: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

B

D

A

Question 22. If 3x – 2 = 16, then x is

C

12

8

6

4

Page 73: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

B

D

C

Question 23. If b = 2, and a – 2b = 10 then a =

Answer for Question 23:

A 14

8

–12

6

Page 74: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q23The answer is a = 14.

Link to reviewNext Question

If b = 2, the a – 2(2) = 10 so a = 14.

Page 75: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

B

D

C

Question 23. If b = 2, and a – 2b = 10 then a =

A 14

8

–12

6

Page 76: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

C

Question 24. A medium bag of chocolates has 24 pieces and a small bag has 6 pieces. We bought 2 medium bags and 4 small bags. How many pieces of chocolates we have in total?

Answer for Question 24:

B

80

72

96

60

Page 77: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q24The answer is 72.

Link to reviewNext Question

We have 2 x 24 + 4 x 6 = 72.

Page 78: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

D

C

Question 24. A medium bag of chocolates has 24 pieces and a small bag has 6 pieces. We bought 2 medium bags and 4 small bags. How many pieces of chocolates we have in total?

B

80

72

96

60

Page 79: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

B

Question 25. From experience, it’s sunny every 5 out of 7 days at Sunny Hills. In a period of 140 days, how many sunny days are expected?

Answer for Question 25:

C

60

80

100

120

Page 80: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q25The answer is 100.

Link to reviewNext Question

We have that 75

140x=

700 = 7x or100 = x

Page 81: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

D

B

Question 25. From experience, it’s sunny every 5 out of 7 days at Sunny Hills. In a period of 140 days, how many sunny days are expected?

C

60

80

100

120

Page 82: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

D

C

B

Question 26. A bag of chocolates cost $24 and a bag of peanuts cost $6. We bought 2 bags of chocolates and 6 bags of peanuts. What is the difference between the cost for chocolates and the cost for the peanuts?

Answer for Question 26:

A $12

$10

$8

$6

Page 83: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q26The answer is $12.

Link to reviewNext Question

The chocolates cost 2 x 24 = $48,the peanuts cost 6 x 6 = $36, so the difference is 48 – 36 = $12.

Page 84: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

D

C

B

Question 26. A bag of chocolates cost $24 and a bag of peanuts cost $6. We bought 2 bags of chocolates and 6 bags of peanuts. What is the difference between the cost for chocolates and the cost for the peanuts?

A $12

$10

$8

$6 Next Question

Page 85: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

C

B

Question 27. A triangle has sides with lengths of

Answer for Question 27:

D

ft, 1½ ft and 2 ft, what’s its perimeter? 1 23

ft4 56

ft5 16

ft5 56

ft4 16

Page 86: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q27The answer is 5 1/6 ft.

Link to reviewNext Question

The perimeter is

+1 23 1 12 + 2

= 1 + 1 + 2 + 2/3 + 1/2

= 4 + 1 16= 5 16

Page 87: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

Question 27. A triangle has sides with lengths of

ft, 1½ ft and 2 ft, what’s its perimeter? 1 23

ft4 56

ft5 16

ft5 56

ft4 16C

D

Page 88: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

B

Question 28. The perimeter of a square is 16 ft, what is the area?

Answer for Question 28:

C

256 ft2

144 ft2

16 ft2

12 ft2

Page 89: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q28The answer 16 ft2.

Link to reviewNext Question

The perimeter is 16 ft so the square is 4 ft x 4 ft with area 4 x 4 = 16 ft2

Page 90: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

D

B

Question 28. The perimeter of a square is 16 ft, what is the area?

C

256 ft2

144 ft2

16 ft2

12 ft2

Page 91: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

B

Question 29. Which of the following is the closest to the circumference of a circle with a 8–ft radius?

Answer for Question 29:

20 ft

30 ft

40 ft

50 ft

C

D

Page 92: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q29The answer D: 50 ft.

Link to reviewNext Question

The circumference of circle is 2πr where π ≈ 3.14, if r = 8 then the circumference is 16 π ≈ 16 x 3.1 ≈ 50.

Page 93: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

B

20 ft

30 ft

40 ft

50 ft

C

D

Question 29. Which of the following is the closest to the circumference of a circle with a 8–ft radius?

Page 94: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

Question 30. Which of the following pictures represents A, B and C on the real line most accurately if A = 3, B = 9 and C = 12?

Answer for Question 30:

C

B0

0

0

0

Page 95: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q30The answer is B.

Link to reviewNext Question

0 6 1293

Page 96: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

D

Question 30. Which of the following pictures represents A, B and C on the real line most accurately if A = 3, B = 9 and C = 12?

C

B0

0

0

0

Page 97: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

Question 31. The vertices of a rectangle are (1, 1), (6, 1), (1, 8), and (6, 8). What is the perimeter of this rectangle?

Answer for Question 31:

C

B

20

24

30

36

Page 98: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q31The answer is 24.

Link to reviewNext Question

We have the following 5 x 7 rectangle:

(1, 1) (6, 1)

(6, 8)(1, 8)

So the perimeter is 5 + 5 + 7 + 7= 245

7

Page 99: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question0

A

D

Question 31. The vertices of a rectangle are (1, 1), (6, 1), (1, 8), and (6, 8). What is the perimeter of this rectangle?

C

B

20

24

30

36

Page 100: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

Question 32. The vertices of a rectangle are (–1, –1), (4, –1), (–1, 3), and (4, 3). What is the area of this rectangle?

Answer for Question 32:

B

C

36

24

20

10

Page 101: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q32The answer is 20.

Link to reviewNext Question

We have the following 5 x 4 rectangle:

(–1, 1) (4, 1)

(4, 3)(–1, 3) So the area is 5 x 4= 20

5

4

Page 102: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

Next Question

A

D

Question 32. The vertices of a rectangle are (–1, –1), (4, –1), (–1, 3), and (4, 3). What is the area of this rectangle?

B

C

36

34

20

10

Page 103: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

Question 33. The following are the temperatures recorded from 1 pm to 5 pm, what is the largest difference in the temperature during this time period given this data?

Answer for Question 33:

B

C

20o

15o

10o

5o

1 pm 2 pm 3 pm

(1, 16o)

(2, 10o)

(4, 20o)

(3, 17o)

(5, 11o)

4 pm 5 pm

Page 104: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q33The answer is 100.

Link to reviewNext Question

The highest temperature is 20o and the lowest is 10o so the largest difference is 20 – 10 = 10o

Page 105: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

A

D

Question 33. The following are the temperatures recorded from 1 pm to 5 pm, what is the largest difference in the temperature during this time period given this data?

B

C

20o

15o

10o

5o

1 pm 2 pm 3 pm

(1, 16o)

(2, 10o)

(4, 20o)

(3, 17o)

(5, 11o)

4 pm 5 pm

Next Question

Page 106: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

C

D

Question 34. Given the following right triangle, what is the length of A?

Answer for Question 34:

B

A 8 ft

8 ½ ft

9 ft

9 ½ ft

10 ft

6 ft

A

Page 107: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q34The answer is 8 ft.

Link to reviewNext Question

By Pythagorean Theorem that A2 + 62 = 102

A2 + 36 = 100A2 = 64A = 8

Page 108: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Next Question

C

D

Question 34. Given the following right triangle, what is the length of A?

B

A 8 ft

8 ½ ft

9 ft

9 ½ ft

10 ft

6 ft

A

Correct!

Page 109: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

A

D

Question 35. Which of the following value is closest to √20?

Answer for Question 35:

B

C

7.5

6.5

4.5

3.5

Page 110: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Solution to Q35The answer is 4.5 ft.

Link to review

√16 < √20 < √25

4 < √20 < 5

So √20 ≈ 4.5

Page 111: This is a sample test for the prealgebra–level algebra–ready placement test at the Harbor College The solution and a link to the topic review are provided

Correct!

A

D

Question 35. Which of the following value is closest to √20?

B

C

7.5

6.5

4.5

3.5