thevenin - norton equivalents and maximum power transfer

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Circuit Theorems: Thevenin and Norton Equivalents, Maximum Power Transfer Dr. Mustafa Kemal Uyguroğlu

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Page 1: Thevenin - Norton Equivalents and Maximum Power Transfer

Circuit Theorems:Thevenin and Norton Equivalents,

Maximum Power Transfer

Dr. Mustafa Kemal Uyguroğlu

Page 2: Thevenin - Norton Equivalents and Maximum Power Transfer

Thevenin’s Theorem

Any circuit with sources (dependent and/or independent) and resistors can be replaced by an equivalent circuit containing a single voltage source and a single resistor.Thevenin’s theorem implies that we can replace arbitrarily complicated networks with simple networks for purposes of analysis.

Page 3: Thevenin - Norton Equivalents and Maximum Power Transfer

Independent Sources (Thevenin)

Circuit with independent sources

RTh

VTh

Thevenin equivalent circuit

+–

Page 4: Thevenin - Norton Equivalents and Maximum Power Transfer

No Independent Sources

Circuit without independent sources

RTh

Thevenin equivalent circuit

Page 5: Thevenin - Norton Equivalents and Maximum Power Transfer

Thevenin Equivalent Circuit

Basic steps to determining Theveninequivalent are– Find vTh RTh

VTh+–

i = 0 i = 0

+

Voc

-

+

Voc

-

Linear

Two-terminal circuit

Voc = VTh

Page 6: Thevenin - Norton Equivalents and Maximum Power Transfer

Thevenin Equivalent Circuit

- Compute the Thevenin equivalent resistance, RTh

(a) If there are only independent sources, then short circuit all the voltage sources and open circuit the current sources (just like superposition).

RTh

Linear circuit with all independent sources set equal to zero.

Rin = RTh

RinRin

Page 7: Thevenin - Norton Equivalents and Maximum Power Transfer

Thevenin Equivalent Circuit

(b) If there are only dependent sources, then must use a test voltage or current source in order to calculate

RTh = VTest/Itest

RTh

Linear circuit with dependent sources

Itest

+

Vtest

-

Linear circuit with dependent sources

Vtest

+

-

Itest

Page 8: Thevenin - Norton Equivalents and Maximum Power Transfer

Thevenin Equivalent Circuit

(c) If there are both independent and dependent sources, then compute(i) RTh = VTest/Itest (all independent sources set equal to zero)(ii) compute RTh from VOC/ISC.

RTh

+–

Linear

Two-terminal circuit

i = isc i = iscVTh

isc = VTh / RTh

Page 9: Thevenin - Norton Equivalents and Maximum Power Transfer

Example

Page 10: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.

Page 11: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.

Ref.

5 3 5.52 2oc oc

ocV V V V−

+ = ⇒ =KCL at Voc :

Page 12: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.

Page 13: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.

Page 14: Thevenin - Norton Equivalents and Maximum Power Transfer

Problem: for the following circuit , determine the Thevenin equivalent circuit.

Page 15: Thevenin - Norton Equivalents and Maximum Power Transfer

Solution:Step 1: In this circuit, we have a dependent source. Hence, we start by finding the open circuit voltage Voc = Vab. KCL at node C (5 - Voc)/2 + Voc/4 = 0 Voc = 10 V

Page 16: Thevenin - Norton Equivalents and Maximum Power Transfer

Step 2: We obtain the short circuit current Isc by shorting nodes a-b and finding the current through it.

5 = 2 Isc + 3 Isc => Isc = 5/5 Isc = 1 A

Page 17: Thevenin - Norton Equivalents and Maximum Power Transfer

Step 3: Find the equivalent Thevenin Voltage and Resistance Vth = Voc = Vab = 10V Rth = Voc/Isc => Rth = 10/1 ΩVth = 10VRth = 10 Ω

Page 18: Thevenin - Norton Equivalents and Maximum Power Transfer

Norton Equivalent Circuit

Any Thevenin equivalent circuit is in turn equivalent to a current source in parallel with a resistor [source transformation].A current source in parallel with a resistor is called a Norton equivalent circuit.

Page 19: Thevenin - Norton Equivalents and Maximum Power Transfer

Norton Equivalent Circuit

Finding a Norton equivalent circuit requires essentially the same process as finding a Thevenin equivalent circuit.

VTh

RTh

IN RN

Th N NV R I= ThN

Th

VIR

=

+–

Th NR R=

Page 20: Thevenin - Norton Equivalents and Maximum Power Transfer

Thevenin/Norton Analysis

1. Pick a good breaking point in the circuit (cannot split a dependent source and its control variable).

2. Thevenin: Compute the open circuit voltage, VOC.Norton: Compute the short circuit current, ISC.

If there is not any independent source then both VOC=0 and ISC=0 [so skip step 2]

Page 21: Thevenin - Norton Equivalents and Maximum Power Transfer

Thevenin/Norton Analysis

3. Calculate RTh(RN) = Voc / Isc4. Thevenin: Replace circuit with VOC in series with RTh

Norton: Replace circuit with ISC in parallel with RTh

Note: for circuits containing no independent sources the equivalent network is merely RTh , that is, no voltage (or current) source.

Only steps 2 & 4 differ from Thevenin & Norton!

Page 22: Thevenin - Norton Equivalents and Maximum Power Transfer

Maximum Power Transfer

I

Page 23: Thevenin - Norton Equivalents and Maximum Power Transfer

Maximum Power Transfer

Power delivered to the load as a function of RL.

Page 24: Thevenin - Norton Equivalents and Maximum Power Transfer

Maximum Power Transfer

Page 25: Thevenin - Norton Equivalents and Maximum Power Transfer

Maximum Power Transfer

Page 26: Thevenin - Norton Equivalents and Maximum Power Transfer

Example

Page 27: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.

Page 28: Thevenin - Norton Equivalents and Maximum Power Transfer

Example

Page 29: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.

17 6 5 172 2 33 2 6 3

6 32 64 12.85 3 5

Th ThTh

Th

V V V

V V

+ ++ = − ⇒ = − − −

− = = − = −

KCL at the supernode:

Page 30: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.

Page 31: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.

Page 32: Thevenin - Norton Equivalents and Maximum Power Transfer

Example cont.