the role of transmitting boundaries in modeling dynamic soil-structure interaction problems
TRANSCRIPT
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The Role of Transmitting Boundaries in Modeling Dynamic Soil-Structure
Interaction ProblemsMohammed Y. Fattah
*, T. Schanz
**, Shatha H. Dawood
***
* Building and Construction Eng. Dept., University of Technology, Baghdad, Iraq
** Ruhr-Universitt Bochum, Germany***Former graduate student, Building and Construction Eng. Dept., University of Technology, Baghdad, Iraq
ABSTRACT
The objective of this paper is to investigate the validity of transmitting boundaries in dynamic analysis of soil-structureinteraction problems. As a case study, the proposed Baghdad metro line is considered. The information about the dimensionsand the material properties of the concrete tunnel and surrounding soil were obtained from a previous study. A parametric
study is carried out to investigate the effect of several parameters including the peak value of the horizontal component ofearthquake displacement records and the frequency of the dynamic load. The computer program (Mod-MIXDYN) is used for
the analysis. The numerical results are analyzed for three conditions; finite boundaries (traditional boundaries), infiniteboundaries modelled by infinite elements (5-node mapped infinite element) presented by Selvadurai and Karpurapu ,1988),and infinite boundaries modelled by dashpot elements (viscous boundaries).
It was found that the transmitting boundary absorbs most of the incident energy. The distinct reflections observed in the "fixedboundaries" case disappear in the "transmitted boundaries" case. This is true for both cases of using viscous boundaries ormapped infinite elements. The type and location of the dynamic load are two controlling factors in deciding the importance ofusing infinite boundaries. It was found that the results are greatly affected when earthquake is applied as a base motion or a
pressure load is applied at the surface ground. The horizontal displacement on the free surface increases significantly whenmodeling infinite boundaries at all values of peak displacement of the earthquake. It increases about (7.0) times the value ofusing finite elements only.
Keywords:Dynamic, soil-structure interaction, infinite element, tunnel.
1. INTRODUCTION
Many different approaches have been proposed for solving
interaction problems considering infinite media by using amechanism which irreversibly transfers energy from thenear field to the far field.
2. THE NON-REFLECTING VISCOUSBOUNDARIES TECHNIQUE
This concept was developed by Lysmer and Kuhlemeyerin 1969. It has been widely used for various dynamic soil-structure interaction problems (Genes and Kocak, 2002).
It is also often referred to as the viscous boundary, sinceits implementation involves placing viscous dashpots atthe boundary. The viscous boundary rests on the well-known observation that the stresses associated with thepassage of plane waves at a station are proportional to thevelocities there.
For example, assuming that the waves in the two-
dimensional case (Figure 1) impinge at a right angle on theartificial boundary, the exact transmitting boundarycondition is formulated as:
0 uVp (1)
0 vVs (2)
where:
: normal stress, : shear stress,
: mass density,
Vp: dilatation (compression) wave velocity =
)2( G ,
Vs: shear wave velocity = G ,
G : shear modulus )1(2E ,
)21)(1(
E
:Poisson's ratio, E: Yong's modulus
u, v: are the normal and tangential displacements.
In discretized form, it is customary to lump the distributeddampers described by Equations 1 and 2, which results in
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each node in dampers with coefficients Cn and Ct in thenormal and the tangential directions.
Cn= AVp (3)
Ct= AVs (4)
where:
A: is the applicable area.
Figure 1. Lumped viscous damper (Wolf, 1988)Viscous boundary method appears to treat both dilatational
and shear waves with sufficient accuracy in manyapplications. The viscous forces, or dashpots, do notdepend upon the frequencies of the transmitted waves. Itcan absorb both harmonic and non harmonic waves(Wong, 2004). Viscous boundaries are local in space andtime; therefore this technique is suitable for transient
analysis (Wolf, 1988).
It is commonly believed that one drawback to the viscousboundary is its inability to transmit Rayleigh waves aseffectively as it does the body wave. The use of viscousboundary for problems which involve Rayleigh wavesshould not necessarily be ruled out (Cohen, 1980).
With "Thin Layer" description, , an approachwas developed by Kausel et al. (1975) for plane or axialsymmetric layers on a rigid ground in the frequencydomain which works with exact expressions in thehorizontal directions, and the accuracy of which
corresponds to finite element method in regards of thevertical direction (Rastandi, 2003). In this method, a layer
medium over a rigid base is discretized in relatively thinlayers with respect to the wave length.Thin Layer Element
Method (TLEM) is an example of substructure approachand it is normally formulated in the frequency domain.Though time domain formulation of (TLEM) can becarried out, it was used mainly in the dynamic analysis oflayered soil and was not applied to embedded structures(Jamaa, and Shiojiri, 2000).
Another way of treating the artificial boundariesmight be by introducing infinite-elements for modeling the
far-field in soil-structure interaction problems. Theseelements were proposed by Bettess (1977) to obtain
solutions to static and steady state dynamic problems.Since then, many authors, including Medina and Penzien
(1982), Yang and Yun (1992) and Yerli et al. (1998) havesuccessfully extended the infinite element formulation to
model wave propagation problems in infinite media(Genes, and Kocak , 2002).
2.1Boundary Element Method (BEM)
It is a semi-numerical method and requires obtaining thefundamental solutions pertaining to the region, providedthat the radiation condition at infinity is satisfied (Genesand Kocak, 2002). In BEM, the differential equation istransformed to a boundary integral equation (Weber,1994). It has advantages because only surfacediscretization of the body is required which decrease the
spatial dimension by one (Genes and Kocak, 2002) whichmakes this method suitable for solving problems involvingonly homogeneous half space.
2.2Multi-Region Boundary Element Method
It is a different BEM approach proposed by Tanrikulu et
al. (2001) who solved two-and three-dimensional layeredtype problems and underground structure problems underharmonic and transient loading. BEM decreases thecomputational mesh significantly. However, it induces anun-symmetric equation system, and its use is limited whennon-linearity is of concern (Genes and Kocak, 2002).
2.3Hybird Numerical Schemes
They combine the FEM for the structure or the near-fieldwith another numerical or analytical method for the far-field. The most widely used Hybrid model is the Coupled
Finite Element and Boundary Element Method (FEBEM)both in time and frequency domain. Two and three-dimensional problems have been solved by FEBEM forexample. This is evident in the works of Von Estroff andKausel (1989), Von Estroff and Firuziaan (2000), Yu et al.(2001). Coupled (FEBEM) analysis exploits theadvantages of the FEM and the BEM and forms arelatively small-size computational mesh, yet requiring theconversion of the system of equations into either FE or BE
form. For these reasons, FE based formulations find wider
application and they are still preferred for manyengineering problems (Genes and Kocak, 2002).
A Perfectly Matched Layer (PML)is an absorbing layermodel for linear wave equations problems that absorb,almost perfectly, propagating waves from all non-tangential angles-of incidence and of all non-zerofrequencies (Basu and Chopra, 2003). Utilizing insights
obtained with electromagnetics PMLs was first introducedby Chew et al. (1997) and Teixeira and Chew (1999).
Basu and Chopra (2003) developed displacementbased(unsplit field) PMLs for anti-plane and plane-strain motion
in visco-elastic media, for time harmonic as well astransient wave motion. These PMLs have been
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Anderson used a term of form 1/(1+r) (r is the radialdirection) in three dimensional elasticity applications.
Medina and Penzin (1982) adopted the same approach.The first explicit stated mapping was made by Beer and
Meek (1981), who used a mapping which included theterms 0:
2 ( j+ ) for < 0 (1)
2 ( j+ ) /(1- ) for > 0 (2)
They split the mapping into two parts, that from = -1 to
= 0 and from = 0 to = 1. The procedure used wasfairly complicated.
Okabe (1983) gave various possible shape functions forinfinite domains, based on what he called "Thegeneralized Lagrange family for the cube".
The form in which Zienkiewicz mapping was originallygiven was simplified and systematized by Marques and
Owen in 1984, who worked out and tabulated the mappingfunction for a large range of commonly used infiniteelements (Bettess, 1992).
4.3Selvadurai and Karpurapu MappedInfinite Elements
In 1986, Selvadurai and Karpurapu have extended the
scope of mapped type infinite elements to analyze theresponse of two-phase media such as saturated soils. The
technique based on conventional shape functions andGauss-Legendre numerical integration was used, thusmaking these elements suitable for implementation ingeneral purpose finite element programs. This kind of
elements was successfully employed for modeling manygeomechanics problems (Karpurapu, 1988). Figure 3
illustrates the composite infinite elements extended toinfinity in direction and Ttable 1 reports their mapping
functions, derivatives and shape functions.
In this study, the derivation of the mapping functions forthe infinite elements will be carried out for two differentcases:
case (a) : Infinite element extended to infinity in thenegative direction.
case (b) : Infinite element extended to infinity in thenegative direction.
Figure 4 presents the composite infinite element, whileTables 2 and 3 report the mapping functions and thederivatives for cases a and b.
Figure 3. Composite infinite elements in direction (Karpurapu, 1988)
Table 1. Mapping and shape functions for composite mapped infinite element (Karpurapu, 1988)
a. Mapping functions and derivatives
ode, i
2-noded
SuperparametricMi
5-noded
Serendipity isoparametricMi
5-nodedMi/
5-nodedMi/
1 )1()1( )1()1( 2)1()1( )1()21(
2 )1()1( )1()1( 2)1()1( )1()21(
3 )1(2)1)(1( )1()1(2 2 22 )1()1(2 )1(4
4 )1(2)1)(1( )1(2)1)(1( 2)1()1( )1(2)1(
5 )1(2)1)(1( 2)1()1( )1(2)1(
b. Shape Functions
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Node, i 2-nodedSuperparametric Ni
5-nodedSerendipity isoparametric Ni
1 4)1)(1( 4)1)(1(4)1)(1(4)1)(1( 22
2 4)1)(1( 4)1)(1(4)1)(1(4)1)(1( 22
3 2)1)(1( 2
4 2)1)(1( 2
5 2)1)(1( 2
Table 2: Mapping functions and their derivatives of the 5-noded serendipity mapped infinite element
adopted in this study for case (a)
Figure 4. The composite infinite elements adopted in this study for cases (a) and (b)
Table 3: Mapping functions and their derivatives of the 5-noded serendipity mapped infinite elements adopted in
this study for case (b).
Node, i
i i
5-nodedserendipity Mi case b
5-nodedMi/
5-nodedMi/
1 1 1 )1()1( 2)1()1( )1()21(
2 -1 1 )1()1( 2)1()1( )1()21(
3 0 1 )1()1(2 2 22 )1()1(2 )1(4
4 -1 -1 )1(2)1)(1( 2)1()1( )1(2)1(
5 1 -1 )1(2)1)(1( 2)1()1( )1(2)1(
In this paper, the 5-nodeed serendipity mapped infinite element has also been added to the finite element models
Node, ii i
5-nodedserendipity Mi case a.
5-nodedMi/
5-nodedMi/
1 1 1 )1()1( 2)1()1( )1()21(
2 1 -1 )1()1( 2
)1()1(
)1()21(
3 1 0 )1()1(2 2 22 )1()1(2 )1(4
4 -1 -1 )1(2)1)(1( 2)1()1( )1(2)1(
5 -1 1 )1(2)1)(1( 2)1()1( )1(2)1(
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of the computer program (Mod-MIXDYN).
4.4Computer Program
The computer program called MIXDYN (Owen andHinton, 1980) was modified to (Mod-MIXDYN) by
implementing the mapped infinite elements to it; i.e., 5-noded coding of the mapped infinite element extendedfrom that presented by Selvadurai and Karpurapu in 1988.The program Mod-MIXDYN is coded in Fortran languageand implemented on a Pentium-IV personal computer.
5. Description of the Case Study
The proposed Baghdad metro line consists of two routes of32 km long and 36 stations designed as fortified shelters,as a first stage. The tunnel of reinforced concrete has acircular cross section with 5.0 m inner diameter (Diam.)and a 0.45 m lining thickness. The reinforcement details
and the method of construction were not known. A typicalgeological section for a specified position which is
characterized by a tunnel axis depth of 18 m is shown inFigure 5. This figure also illustrates the soil properties of
the three layers that characterize the investigated section.The properties of the materials involved in the problemsare detailed in Table 5.
5.1Modeling and Boundary Conditions
Case 1A finite element mesh with traditional boundaries (Figure6) is adopted to model the Baghdad metro line section.
Isoparametric quadrilateral eight-nodded elements are usedto model the concrete tunnel and the surrounding soil. Theboundary side nodes are restrained laterally (only vertical
displacements are possible), while the lower end nodes ofthe entire boundary mesh are restrained vertically (only
horizontal displacements are possible).
Figure 5. Geological profile of the investigated Baghdad
metro line section.
Case 2:
The 5-node mapped infinite elements presented by
Selvadurai and Karpurapu (1988) extends to infinity to theright with the other two mapped infinite elements (wheninfinite direction extends to the left and down), derived inthis study, are added to the mesh of case 1 as shown inFigure 7.
Case 3:A finite element mesh (as in case 1) with dashpot elementsis considered to model the viscous boundaries as shown in
Figure 8
Figure 6. Case 1 - Finite element mesh with traditional boundaries.
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Table 4 summarizes the general information about thefinite, infinite and dashpot elements meshes for cases 1, 2
and 3. The material properties for the problem are shownin table 5.
Table 4. General information about the mesh adopted for the three different cases.
Type of information
Case (1)
Finiteelements
only
Case (2)Finite and infinite
elements
Case (3)Finite and dashpot
elements
No. of nodes 544 581 618
No. of finite elements 160 160 160
No. of infinite elements - 20 -
No. of dashpot elements - - 50
No. of restrained nodes 37 37 50
Analysis type Plane strain, Large displacement
Damping parameters 0.00075
0
Figure 7. Case 2 - The finite element mesh with infinite boundary elements
Table 5: Material properties
PropertyConcrete
lining
Soil layers
(1)
Silty clay
(2)
Sand to siltysand
(3)
Sand
Modulus of elasticity, E (MPa) 20000 80 180 150
Poissons ratio, 0.15 0.333 0.263 0.284
Friction angle o - 30o 40o 37o
Cohesion, c (MPa) - 0.2 0.15 0Density , (kg/m
3) 2400 1950 1970 2000
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6. LOADING
Tunnels may be subjected to different types of dynamicloads such as earthquakes, impact loads resulting fromtraffic accidents if they serve as metro lines or traffictunnels, external blast loads coming from direct or indirect
hits and the internal blast loads resulting from theexplosions of demolitions charges caused by sabotage
works. In this study, two types of loads are considered:
6.1Time-History Displacement
The earthquake load is applied as base displacementmotion. The earthquake record of El-Centro in California,which hit on 18
th May 1940 has been used. It is
characterized by a s magnitude equal to 6.7 on Richterscale and a peak acceleration of 0.35g. This earthquakewas scaled to get three different values of peak
accelerations: 0.045, 0.065 and 0.13g, which were giventransformed to peak displacements Ao: 0.035, 0.05 and 0.1m by means of the fast Fourier transform. The ground
motion displacement time-history of El-Centro earthquakeis shown in Figure 9.
6.2Surface Pressure Load
A sinusoidal pressure load P(t) acting at the free surface
above the tunnel was adopted.
It can be represented by the following equation:
P(t) = 380 * sin(4.18879**t) kN/m2
for 0 < t =< 1.5 sec.
= 0.0kN/m2, for 1.5 < t < 3.0 sec.
where: = Angular frequency (rad./sec.).
f = Cyclic frequency (Hz). = /2
T = period (sec./rad.). = 1/f
Figure 8. Case 3Finite element mesh with viscous boundaries
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Figure 9. The ground motion displacement time-history of El-Centro earthquake
Three different frequencies f: 0.16, 0.24, 0.32 Hz ( = 1.0,
1.5, 2.0 rad./sec.) were considered for the acting sinusoidal
pressure load, as shown in Figure 10.
(a)
(b)
(c)
Figure 10: Pressure load - time history for the three values of .
7. PARAMETRIC STUDY
7.1Effect of Peak Displacement
The horizontal component of El-Centro earthquake wasscaled to have three different values of peak displacement
to study its effect on the
behavior of the tunnel and soil.
Figures 11 and 12 show the deflected shape of axes a-aand b-b (shown in Figure 8) respectively at time when the
peak displacement occurs along them for both cases (1 and3), at three different values of peak displacement (Ao =0.035m, 0.05m and 0.1m).
It can be noticed that the horizontal displacement alongaxis a-a increases when modeling infinite boundaries in
Peak value =0.035 m @2.04 sec.
-0.045
-0.030
-0.015
0.000
0.015
0.030
0.045
0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
Time (sec.)
Gr
ounddisplacement(m)
= 1.0 rad. / sec.
-570
-380
-190
0
190
380
570
0 0.5 1 1.5 2 2.5 3
Time (sec.)
P(t)(kN
/m
2)
= 1.5 rad. / sec.
-570
-380
-190
0
190
380
570
0 0.5 1 1.5 2 2.5 3
Time (sec.)
P(t)(
kN/m
2)
= 2.0 rad. / sec.
-570
-380
-190
0
190
380
570
0 0.5 1 1.5 2 2.5 3
Time (sec.)
P(t)(kN/m
2)
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case 3, this increase becomes larger near the groundsurface about (7.0) times the value of case 1 at equal times.
On the other hand, the peak value of vertical displacementdecreases along axis b-b to about 0.2 the value of case 1 at
about the same time.
Figures 13 and 14 show the time history of horizontal
displacement at node B (shown in Figure 8), for both cases1 and 3 respectively for the three different values of (Ao).
It can be concluded from these figures that the horizontaldisplacement on the tunnels boundary decayssignificantly when using viscous boundaries (case 3) for
all the considered peak displacements. This trend may beattributed to the absorption of the reflected waves made by
using viscous boundaries which is faster than do theinfinite elements. Figures 15 to 20 show the normal
stresses xandytime- history, and the shear stress xyatnode B (shown in Figure 8) for the three different values
of the peak horizontal displacement Ao for both cases 1and 3.
A summary of the comparison between the peak values ofdisplacements and stresses predicted at the selectedlocations are listed in Table 6 below.
Table 6. Comparison of results
(a) Comparison between case 3 and case 1 for peak values of displacements and their times for axes a-a , b-b and nodes B and F at
three different values of the parameter (Ao).
Case(3)/Case(1)
Location Displacement Ao (m) Displ. ratio Time ratio
axis a-a Ux
0.035 1.00 1.00
0.05 1.00 1.00
0.1 1.00 1.00
axis b-b Uy
0.035 -0.21 0.97
0.05 0.21 0.97
0.1 0.21 0.97
Node BUx
0.035 -1.10 0.43
0.05 -1.10 0.43
0.1 -1.10 0.43
Node F Ux0.035 -0.54 0.730.05 -0.54 0.73
0.1 -0.54 0.73
(b) Comparison between case 3 and case 1 peak values of normal stresses x, yand shear stress xy at node B for three differentvalues of parameter (Ao).
Case(3)/Case(1)
Stresses Ao (m) Stress ratio Time ratio
x
0.035 0.83 1.87
0.05 0.83 1.870.1 0.84 1.87
y
0.035 -0.92 1.84
0.05 -0.92 1.84
0.1 -0.92 1.84
xy
0.035 0.85 0.09
0.05 0.85 0.09
0.1 0.85 0.09
7.2Effect of the Frequency of the SurfacePressure Load
By applying sinusoidal pressure load P(t), the effect of the
angular frequency () is studied. The pressure load isapplied at the surface.
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Figures 21 and 22 show the deflected shape of the axes a-aand b-b respectively, at the time when the peak
displacement occurs along them for the three cases 1, 2
and 3 at three different values of angular frequency (=1.0, 1.5, 2.0 rad./sec.).
The deflected shape of axis a-a has a harmonic (sinusoidal)shape for the three cases. The deflected shape of axis a-a
for case 2 is close to that of case 1 when = 1.0 rad./sec.,
while it is close to that of case 3 when = 2.0 rad./sec.
It is clear that the presence of viscous boundaries leads to
inverse the deflected shape of the axis b-b when = 2.0rad./sec., while the peak value of the vertical displacement
along axis b-b for case 3 is close to that in case 2 when = 2.0 rad./sec. but at opposite direction.
The effect of the surface pressure load frequency () onthe vertical displacement at node A is shown in Figures 23
and the horizontal displacement at node F is shown inFigure 24 for cases 1, 2 and 3. The peak value of thevertical displacement at node A increases as the frequencyincreases for cases 1 and 2 while it decreases for case 3.
The vertical and horizontal displacements at nodes A and
F respectively in case 3 decays rapidly compared to cases1 and 2.
The presence of viscous boundary in case 3 causes anincrease of the peak value of vertical displacements atnode A in the amount of about 2.1 times the value of case
1 when (= 1.0 rad./sec), while it decreases in amount of
about 0.89 times the value for case 1 when ( = 2.0rad./sec). On the other hand , in case 3 the verticaldisplacement at node A reaches the peak value at timegreater of about 1.8 times than the time measured for case
1 when (= 1.0 rad./sec).
Figures 25 to 30 trace the time-history of the normal
stresses x , yandshear stress xyat nodesB and D forthe three different values of frequency for cases 1 and 3,respectively.
A summary of the comparison between the peak values ofdisplacements and stresses of Figures 21 to 30 is listed inTable 7.
Table 7. Comparison between the results
(a) A comparison between cases 2, 3 and case 1 peak values of displacements and their times for axes a-a , b-b and nodes A and F at
three different values of (
).
Case(2)/Case(1) Case(3)/Case(1)
Location Displacementw
rad./sec.Displ.ratio Time ratio Displ. ratio
Timeratio
axis a-a Ux
1 -0.51 0.29 1.35 1.08
1.5 0.49 0.93 1.38 1.56
2 0.57 3.48 1.18 1.39
axis b-b Uy
1 0.77 0.80 1.05 1.22
1.5 0.87 4.50 0.95 0.23
2 -0.95 2.55 -0.80 0.40
Node A Uy
1 0.42 0.50 2.09 1.78
1.5 0.70 0.89 1.31 1.15
2 -0.99 1.90 -0.89 0.55
Node F Ux
1 0.52 0.81 1.35 1.08
1.5 0.49 0.93 1.38 1.56
2 0.57 3.48 1.18 1.39
(b) A comparison between case 3 and case 1 peak values of normal stresses x, yand shear stress xy for nodes B and D at three
different values of
.
Case(3)/Case(1)
Node Stresses
rad./secStress ratio Time ratio
B x
1 -0.52 3.20
1.5 0.55 0.20
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2 -0.45 0.41
D x
1 0.11 0.35
1.5 0.13 0.37
2 -0.13 0.20
B y
1 -0.97 3.14
1.5 -5.20 0.202 -0.91 0.43
D y
1 -0.49 3.20
1.5 0.85 0.77
2 -0.42 0.40
B xy
1 2.04 0.99
1.5 -1.74 0.35
2 1.52 1.67
D xy
1 -2.15 3.00
1.5 -2.07 0.35
2 1.96 1.67
8. CONCLUSIONS
A dynamic finite-element analysis is carried out for a soil-structure interaction problem considering transmitting
boundaries. Two types of boundaries are considered inaddition to the traditional boundaries: viscous boundaries
and mapped infinite elements. The following conclusionsare drawn
i. The transmitting boundary absorbs most of theincident energy. The distinct reflections observed for
the "fixed boundaries" disappear by using "transmittedboundaries". This is true for both cases of using
viscous boundaries or mapped infinite elements.
ii. The type and location of the dynamic load representtwo controlling factors in deciding the importance ofusing infinite boundaries. It was found that the resultspresent significant differences when earthquake isapplied as a base motion or a pressure load is appliedat the surface ground.
iii. The horizontal displacement on the free surface
increases significantly when modeling infinite
boundaries for all values of the earthquake peakdisplacement. It increases about 7.0 times the valueobtained by using finite elements only.
iv. The peak value of the vertical displacement at nodesA, B, E and F (located at the tunnels crown and sidewalls, and at the surface above the tunnel and at thesurface 6.5 m away from tunnels centre respectively)
increases with the frequency of the surface pressureload for both cases 1 and 2 (traditional boundaries andmapped infinite elements respectively) while itdecreases for case 3 (viscous boundaries).
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[4] Bettess, P., Infinite Elements, International Journalfor Numerical Methods in Engineering, Vol. 11, 1977.
[5] Chew, W. C., Jin, J. M., and Michielssen, E.,Complex Coordinate Stretching as a Generalized
Absorbing Boundary Condition., Microwave andOptical Technology Letters, 15(6), 1997.
[6] Cohen, M., "Silent Boundary Methods for Transient
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[7] Engquist, B. and Majda, A., Radiation BoundaryConditions for Acoustic and Elastic Wave
Calculations, Communications on Pure and AppliedMathematics, Vol. 32, pp. 313-357, 1979.
[8] Feltrin, G., Absorbing Boundaries for Time-DomainAnalysis of Dam-Reservoir-Foundation Systems,Swiss Federal Institute of Technology Zurich, Nov.1997.
[9] Genes, M. C. and Kocak, S., "A Combined FiniteElement Based Soil Structure", Engineering
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Structures, Elsevier Science Ltd. 2002. (Websitewww.elsevier.com/locate/engstruct )
[10]Jamaa, S. B. and Shiojiri, H., A Method for Three
Dimensional Interaction Analysis of Pile-Soil Systemin Time Domain, Transactions of JSCES, Paper No.20000013, 2000.
[11]Karpurapu, G. R.,Composite Infinite ElementAnalysis of Unbounded Two-Phase Media,
Computational Mechanics Publications / Adv. Eng.Software, Vol.10, No. 4, 1988.
[12]Kausel, E., Roesset, J. M. and Waas, G., DynamicAnalysis of Footing on Layered Media, Journal ofEngineering Mechanics, Vol. 101, 1975.
[13]Lysmer, J. and Kuhlemeyer, R. L., Finite DynamicModel for Infinite Media, Journal of Engineering
Mechanics, ASCE, 95(EM4), 1969.
[14]Medina, F., and Penzien, J., Infinite Elements forElastodynamics., Earthquake Eng Struct Dynamics,Vol. 10, 1982.
[15]Okabe, M., Generalized Lagrange Family for theCube with Special Reference to Infinite DomainInterpolations, Comp. Meth. Appl. Mech. Eng.,
38(2), pp. 153-168, 1983.
[16]Okamoto, S., Introduction on EarthquakeEngineering, University of Tokyo,1973.
[17]Owen, D. R. J. and Hinton, E., "Finite Elements inPlasticity: Theory and Practice", Pineridge PressLimited, 1980.
[18]Park, S. H. and Tassoulas, J. L., "A Discontinuous
Galerkin Method for Transient Analysis of WavePropagation in Unbounded Domains.", ComputerMethods in Applied Mechanics and Engineering, 191,3983-4011, 2002.
[19]Park, S. H. and Antin, N., "A Space TimeDiscontinuous Galerkin Method for Seismic Soil-
Structure Interaction Analysis", 16th ASCEEngineering Mechanics Conference, University of
Washington, July 2003.
[20]Pissanetsky, S., A Simple Infinite Element, Compel,3, No. 2, Boole Press, Dublin, pp107-114, 1984.
[21]Rastandi, I. J., Modelization of Dynamic Soil-Structure Interaction Using Integral Transform-FiniteElement Coupling, Technician University Munchen,2003.
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[27]Von Estorff, O., and Firuziaan, M., CoupledBEM/FEM Approach for Non-linear Soil-StructureInteraction.,Eng Anal Boundary Elements, 24, 2000.
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a a
b b
c
c
Figure 11. Deflected shape of axis a-a at time of peak
value of horizontal displacement for three different values
of (Ao)cases (1 and 3)
Figure 12. Deflected shape of axis b-b at time of peak
value of vertical displacement for three different values of
(Ao)cases (1 and 3)
Ao = 0.035 m
0
5
10
15
20
25
30
-0.1 -0.075 -0.05 -0.025 0 0.025
Horizontal Displacement (m)
VerticalDistance
(m
)
Ux-Case1 Ux-Case3
Ao = 0.035 m
-0.15
-0.1
-0.05
0
0.05
0.1
0.15
0 5 10 15 20 25
Horizontal Distance (m)
VerticalDisplacement(m
)
Uy-Case1 Uy -Case3
Ao = 0.05 m
0
5
10
15
20
25
30
-0.1 -0.075 -0.05 -0.025 0 0.025
Horizontal Displacement (m)
VerticalDistance
(m)
Ux-Case1 Ux-Case3
Ao = 0.05 m
-0.15
-0.1
-0.05
0
0.05
0.1
0.15
0 5 10 15 20 25
Horizontal Distance (m)
VerticalDisplacement(m)
Uy-Case1 Uy -Case3
Ao = 0.1 m
0
5
10
15
20
25
30
-0.1 -0.075 -0.05 -0.025 0 0.025
Horizontal Displacement (m)
VerticalDistance
(m)
Ux-Case1 Ux-Case3
Ao = 0.1 m
-0.15
-0.1
-0.05
0
0.05
0.1
0.15
0 5 10 15 20 25
Horizontal Distance (m)
V
erticalDisplacement(m)
Uy-Case1 Uy -Case3
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a a
b b
c c
Figure 13. Horizontal displacement - time history at node
B for three different values of (Ao) - case (1).
Figure 14. Horizontal displacement - time history at node
B for three different values of (Ao) - case (3).
Ao = 0.035 m
-0.02
-0.01
0.00
0.01
0.02
0 5 10 15 20 25 30Time (sec.)
HorizontalDisplacement(m
Ux -Case1
Ao = 0.035 m
-0.02
-0.01
0.00
0.01
0.02
0 5 10 15 20 25 30Time (sec.)
HorizontalDisplacement(m
Ux -Case3
Ao = 0.05 m
-0.03
-0.02
-0.01
0.00
0.01
0.02
0.03
0 5 10 15 20 25 30Time (sec.)
HorizontalDisplacement(m
Ux -Case1
Ao = 0.05 m
-0.03
-0.02
-0.01
0.00
0.01
0.02
0.03
0 5 10 15 20 25 30Time (sec.)
HorizontalDisplacement(m
Ux -Case3
Ao = 0.1 m
-0.06-0.05
-0.04
-0.03
-0.02
-0.01
0.00
0.01
0.02
0.03
0.04
0.05
0.06
0 5 10 15 20 25 30Time (sec.)
HorizontalDisplacement(m
Ux -Case1
Ao = 0.1 m
-0.06-0.05
-0.04
-0.03
-0.02
-0.01
0.00
0.01
0.02
0.03
0.04
0.05
0.06
0 5 10 15 20 25 30Time (sec.)
HorizontalDisplacement(m
Ux -Case3
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a a
b b
c c
Figure 15. Normal stressx- time history at node B for
three different values of (Ao) - case (1)
Figure 16. Normal stressx- time history at node B for
three different values of (Ao) - case (3)
Ao = 0.035 m
-200
-150
-100
-50
0
50
100
150
200
0 5 10 15 20 25 30Time (sec.)
x(kN/
m2)
Sx -Case1
Ao = 0.035 m
-200
-150
-100
-50
0
50
100
150
200
0 5 10 15 20 25 30Time (sec.)
x(kN/
m2)
Sx -Case3
Ao = 0.05 m
-300
-200
-100
0
100
200
300
0 5 10 15 20 25 30Time (sec.)
x(kN/m
2)
Sx -Case1
Ao = 0.05 m
-300
-200
-100
0
100
200
300
0 5 10 15 20 25 30Time (sec.)
x(kN/m
2)
Sx -Case3
Ao = 0.1 m
-600
-400
-200
0
200
400
600
0 5 10 15 20 25 30Time (sec.)
x(kN/m
2)
Sx -Case1
Ao = 0.1 m
-600
-400
-200
0
200
400
600
0 5 10 15 20 25 30Time (sec.)
x(kN/m
2)
Sx -Case3
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a a
b b
c c
Figure 17. Normal stressy- time history at node B for
three different values of (Ao) - case (1).
Figure 18. Normal stressy- time history at node B for
three different values of (Ao) - case (3).
Ao = 0.035 m
-2500
-2000
-1500
-1000
-500
0
500
1000
1500
2000
2500
0 5 10 15 20 25 30Time (sec.)
y(kN/
m2)
Sy -Case1
Ao = 0.035 m
-2500
-2000
-1500
-1000
-500
0
500
1000
1500
2000
2500
0 5 10 15 20 25 30Time (sec.)
y(kN/
m2)
Sy -Case3
Ao = 0.05 m
-3000
-2000
-1000
0
1000
2000
3000
0 5 10 15 20 25 30Time (sec.)
y(kN/m
2)
Sy -Case1
Ao = 0.05 m
-3000
-2000
-1000
0
1000
2000
3000
0 5 10 15 20 25 30Time (sec.)
y(kN/m
2)
Sy -Case3
Ao = 0.1 m
-6000
-4000
-2000
0
2000
4000
6000
0 5 10 15 20 25 30Time (sec.)
y(kN/m
2)
Sy -Case1
Ao = 0.1 m
-6000
-4000
-2000
0
2000
4000
6000
0 5 10 15 20 25 30Time (sec.)
y(kN/m
2)
Sy -Case3
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a a
b b
c c
Figure 19. Shear stressxy- time history at node B for
three different values of (Ao) - case (1).
Figure 20. Shear stressxy- time history at node B for
three different values of (Ao) - case (3).
Ao = 0.035 m
-1000
-500
0
500
1000
0 5 10 15 20 25 30Time (sec.)
xy(kN
/m
2)
Sxy -Case1
Ao = 0.035 m
-1000
-500
0
500
1000
0 5 10 15 20 25 30Time (sec.)
xy(kN
/m
2)
Sxy -Case3
Ao = 0.05 m
-1500
-1000
-500
0
500
1000
1500
0 5 10 15 20 25 30Time (sec.)
xy(kN/m
2)
Sxy -Case1
Ao = 0.05 m
-1500
-1000
-500
0
500
1000
1500
0 5 10 15 20 25 30Time (sec.)
xy(kN/m
2)
Sxy -Case3
Ao = 0.1 m
-3000-2500
-2000
-1500
-1000
-500
0
500
1000
1500
2000
2500
3000
0 5 10 15 20 25 30Time (sec.)
xy(kN/m
2)
Sxy -Case1
Ao = 0.1 m
-3000-2500
-2000
-1500
-1000
-500
0
500
1000
1500
2000
2500
3000
0 5 10 15 20 25 30Time (sec.)
xy(kN/m
2)
Sxy -Case3
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a a
b b
c c
Figure 21. Deflected shape of axis a-a at time of peak
value of horizontal displacement for three different values
of ( - cases (1, 2 and 3).
Figure 22. Deflected shape of axis b-b at time of peak
value of vertical displacement for three different values of
() - cases (1, 2 and 3).
= 1.0 rad /sec.0
5
10
15
20
25
30
-0.005 -0.0025 0 0.0025 0.005
Horizontal Displacement (m)
VerticalDista
nce
(m)
Ux-Case1 Ux-Case3Ux-Case2
= 1.0 rad /sec.
-0.05
-0.0375
-0.025
-0.0125
0
0 5 10 15 20 25
Horizontal Distance (m)
VerticalDisplace
ment(m)
Uy-Case1 Uy -Case3Uy -Case2
= 1.5 rad /sec.0
5
10
15
20
25
30
-0.005 -0.0025 0 0.0025 0.005
Horizontal Displacement (m)
VerticalDistance
(m)
Ux-Case1 Ux-Case3Ux-Case2
= 1.5 rad /sec.
-0.05
-0.0375
-0.025
-0.0125
0
0 5 10 15 20 25
Horizontal Distance (m)
VerticalDisplacement(m)
Uy-Case1 Uy -Case3Uy -Case2
= 2.0 rad /sec.0
5
10
15
20
25
30
-0.005 -0.0025 0 0.0025 0.005
Horizontal Displacement (m)
VerticalDistance
(m)
Ux-Case1 Ux-Case3Ux-Case2
= 2.0 rad /sec.
-0.05
-0.0375
-0.025
-0.0125
0
0.0125
0.025
0.0375
0.05
0.0625
0 5 10 15 20 25
Horizontal Distance (m)
VerticalDisplacement(m)
Uy-Case1 Uy -Case3Uy -Case2
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a a
b b
c c
Figure 23. Vertical displacement - time history at node A
for three different values of (
) - cases (1, 2 and 3).
Figure 24. Horizontal displacement - time history at node
F for three different values of (
) - cases (1, 2 and 3).
= 1.0 rad / sec.
-0.02
-0.01
0.00
0.01
0.02
0 0.5 1 1.5 2 2.5 3Time (sec.)
VerticalDisplac
ement(m)
Uy -Case1 Uy -Case3Uy -Case2
= 1.0 rad / sec.
-0.008
-0.006
-0.004
-0.002
0.000
0.002
0.004
0.006
0.008
0 0.5 1 1.5 2 2.5 3Time (sec.)
HorizontalDispla
cement(m
Ux -Case1 Ux -Case3Ux -Case2
= 1.5 rad / sec.
-0.02
-0.01
0.00
0.01
0.02
0 0.5 1 1.5 2 2.5 3Time (sec.)
VerticalDisplacement(m)
Uy -Case1 Uy -Case3Uy -Case2
= 1.5 rad / sec.
-0.008
-0.006
-0.004
-0.002
0.000
0.002
0.004
0.006
0.008
0 0.5 1 1.5 2 2.5 3Time (sec.)
HorizontalDisplacement(m
Ux -Case1 Ux -Case3Ux -Case2
= 2.0 rad / sec.
-0.02
-0.01
0.00
0.01
0.02
0 0.5 1 1.5 2 2.5 3Time (sec.)
VerticalDisplacement(m)
Uy -Case1 Uy -Case3Uy -Case2
= 2.0 rad / sec.
-0.008
-0.006
-0.004
-0.002
0.000
0.002
0.004
0.006
0.008
0 0.5 1 1.5 2 2.5 3Time (sec.)
HorizontalDisplacement(m
Ux -Case1 Ux -Case3Ux -Case2
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a a
b b
c c
Figure 25. Normal stressx- time history at node B for
three different values of (
) - cases (1 and 3).
Figure 26. Normal stressx- time history at node D for
three different values of (
) - cases (1 and 3).
= 1.0 rad / sec.
-300
-200
-100
0
100
200
300
0 0.5 1 1.5 2 2.5 3Time (sec.)
x(kN/
m2)
Sx -Case1 Sx -Case3
= 1.0 rad / sec.
-75
-60
-45
-30
-15
0
15
30
45
60
75
0 0.5 1 1.5 2 2.5 3Time (sec.)
x(kN/
m2)
Sx -Case1 Sx -Case3
= 1.5 rad / sec.
-300
-200
-100
0
100
200
300
0 0.5 1 1.5 2 2.5 3Time (sec.)
x(kN/m
2)
Sx -Case1 Sx -Case3
= 1.5 rad / sec.
-75
-60
-45
-30
-15
0
15
30
45
60
75
0 0.5 1 1.5 2 2.5 3Time (sec.)
x(kN/m
2)
Sx -Case1 Sx -Case3
= 1.5 rad / sec.
-300
-200
-100
0
100
200
300
0 0.5 1 1.5 2 2.5 3Time (sec.)
x(kN/m
2)
Sx -Case1 Sx -Case3
= 2.0 rad / sec.
-75
-60
-45
-30
-15
0
15
30
45
60
75
0 0.5 1 1.5 2 2.5 3Time (sec.)
x(kN/m
2)
Sx -Case1 Sx -Case3
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a a
b b
c c
Figure 27. Normal stressy- time history at node B for
three different values of (
) - cases (1 and 3).
Figure 28. Normal stressy - time history at node D for
three different values of (
) - cases (1 and 3).
= 1.0 rad / sec.
-1000
-800
-600
-400
-200
0
200
400
600
800
1000
0 0.5 1 1.5 2 2.5 3Time (sec.)
y(kN/
m2)
Sy -Case1 Sy -Case3
= 1.0 rad / sec.
-100
-80
-60
-40
-20
0
20
40
60
80
100
0 0.5 1 1.5 2 2.5 3Time (sec.)
y(kN/
m2)
Sy -Case1 Sy -Case3
= 1.5 rad / sec.
-1000
-800
-600
-400
-200
0
200
400
600
800
1000
0 0.5 1 1.5 2 2.5 3Time (sec.)
y(kN/m
2)
Sy -Case1 Sy -Case3
= 1.5 rad / sec.
-100
-80
-60
-40
-20
0
20
40
60
80
100
0 0.5 1 1.5 2 2.5 3Time (sec.)
y(kN/m
2)
Sy -Case1 Sy -Case3
= 2.0 rad / sec.
-1200-1000
-800
-600
-400
-200
0
200
400
600
800
1000
1200
0 0.5 1 1.5 2 2.5 3Time (sec.)
y(kN/m
2)
Sy -Case1 Sy -Case3
= 2.0 rad / sec.
-120
-100
-80
-60
-40
-20
0
20
40
60
80
100
120
0 0.5 1 1.5 2 2.5 3Time (sec.)
y(kN/m
2)
Sy -Case1 Sy -Case3
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a a
b b
c c
Figure 29. Shear stressxy- time history at node B for
three different values of (
) - cases (1 and 3).
Figure 30. Shear stressxy- time history at node D for
three different values of (
) - cases (1 and 3).
= 1.0 rad / sec.
-80
-60
-40
-20
0
20
40
60
80
0 0.5 1 1.5 2 2.5 3Time (sec.)
xy(kN
/m
2)
Sxy -Case1 Sxy -Case3
= 1.0 rad / sec.
-30
-20
-10
0
10
20
30
0 0.5 1 1.5 2 2.5 3Time (sec.)
xy(kN
/m
2)
Sxy -Case1 Sxy -Case3
= 1.5 rad / sec.
-80
-60
-40
-20
0
20
40
60
80
0 0.5 1 1.5 2 2.5 3Time (sec.)
xy(kN/m
2)
Sxy -Case1 Sxy -Case3
= 1.5 rad / sec.
-30
-20
-10
0
10
20
30
0 0.5 1 1.5 2 2.5 3Time (sec.)
xy(kN/m
2)
Sxy -Case1 Sxy -Case3
= 2.0 rad / sec.
-80
-60
-40
-20
0
20
40
60
80
0 0.5 1 1.5 2 2.5 3Time (sec.)
xy(kN/m
2)
Sxy -Case1 Sxy -Case3
= 2.0 rad / sec.
-30
-20
-10
0
10
20
30
0 0.5 1 1.5 2 2.5 3Time (sec.)
xy(kN/m
2)
Sxy -Case1 Sxy -Case3