the gas laws learning about the special behavior of gases objective #2, begins on pg. 5 of the note...
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![Page 1: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/1.jpg)
The Gas LawsThe Gas LawsThe Gas LawsThe Gas LawsLearning about the special behavior Learning about the special behavior
of gasesof gases
Objective #2, begins Objective #2, begins on pg. 5 of the Note on pg. 5 of the Note
packpack
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Combined Gas Law:There really is no need to remember 3
different equationsA single expression , called the
combined gas lawcombined gas law, combines the three gas laws, only holding the amount of gas constant..
![Page 3: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/3.jpg)
Re-arranging the Combined Gas Law
This is not in your notes, but perhaps it should be.
You will need to be able to solve for 1 variable, when given the other 5. To do that, you will need to re-arrange the formula.
Q: How do you isolate just 1 variable?
A: Criss-cross the other variables,
that are with it, to the other side
of the equation.
![Page 4: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/4.jpg)
Example, to solve for V1…
(how to get V1 all by itself)
P1 V1 P2V2
T1 T2
Re-arranging the Combined Gas Law
![Page 5: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/5.jpg)
Example, to solve for V1…
Move the P1, to the bottom…
P1 V1 P2V2
T1 T2
Re-arranging the Combined Gas Law
![Page 6: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/6.jpg)
Example, to solve for V1…
Then move the T1, to the top…
V1 P2V2
T1 T2 P1
Re-arranging the Combined Gas Law
![Page 7: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/7.jpg)
Example, to solve for V1…
V1 P2V2T1
T2 P1
Re-arranging the Combined Gas Law
![Page 8: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/8.jpg)
Your turn…With your neighbor, please write the
formula you would use to find each of the following:
V1 = V2 =
T1 = T2 =
P1 = P2 =
![Page 9: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/9.jpg)
Your turn…With your neighbor, please write the
formula you would use to find each of the following:
V1 = V2 =
T1 = T2 =
P1 = P2 =
P2V2T1
T2P1
P2V2T1
P1V1 P2V2T1
T2V1
P1V1T2
T1P2
P1V1T2
P2V2 P1V1T2
T1V2
We can not have 1/T1 as a legitimate option, so the formula must be inverted.
![Page 10: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/10.jpg)
Example 1• The volume of a gas-filled balloon is 30.0 L at 40o
C and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure?
![Page 11: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/11.jpg)
Example 1• The volume of a gas-filled balloon is 30.0 L at 40o
C and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure?
First, determine what formula we’re going to use to find what’s missing:
![Page 12: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/12.jpg)
Example 1• The volume of a gas-filled balloon is 30.0 L at 40o
C and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure?
First, determine what formula we’re going to use to find what’s missing:
We’re finding V2 = V1 x P1 x T2
P2 x T1
![Page 13: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/13.jpg)
Example 1• The volume of a gas-filled balloon is 30.0 L at 40o
C and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure?
First, determine what formula we’re going to use to find what’s missing:
We’re finding V2 = V1 x P1 x T2
P2 x T1
Now substitute, changing the temp to Kelvin:
![Page 14: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/14.jpg)
Example 1• The volume of a gas-filled balloon is 30.0 L at 40o
C and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure?
First, determine what formula we’re going to use to find what’s missing:
We’re finding V2 = V1 x P1 x T2
P2 x T1
Now substitute, changing the temp to Kelvin:V2 =(30 L)x(153 kPa)x(273K)
(101.3kPa)x(313K)
![Page 15: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/15.jpg)
Example 1• The volume of a gas-filled balloon is 30.0 L at 40o
C and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure?
First, determine what formula we’re going to use to find what’s missing:
We’re finding V2 = V1 x P1 x T2
P2 x T1
Now substitute, changing the temp to Kelvin:V2 =(30 L)x(153 kPa)x(273K)
(101.3kPa)x(313K)
V2 = 39.5 L
![Page 16: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/16.jpg)
Example 2• A gas at 155 kPa and 25o C occupies a
container with an initial volume of 1 L. By changing the volume, the pressure of a gas increases to 605 kPa as the temperature is raised to 125o C. What is the new volume?
![Page 17: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/17.jpg)
Example 2• A gas at 155 kPa and 25o C occupies a
container with an initial volume of 1 L. By changing the volume, the pressure of a gas increases to 605 kPa as the temperature is raised to 125o C. What is the new volume?
First, determine what formula we’re going to use to find what’s missing:
![Page 18: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/18.jpg)
Example 2• A gas at 155 kPa and 25o C occupies a
container with an initial volume of 1 L. By changing the volume, the pressure of a gas increases to 605 kPa as the temperature is raised to 125o C. What is the new volume?
First, determine what formula we’re going to use to find what’s missing:
We’re finding V2 = V1 x P1 x T2
P2 x T1
![Page 19: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/19.jpg)
Example 2• A gas at 155 kPa and 25o C occupies a
container with an initial volume of 1 L. By changing the volume, the pressure of a gas increases to 605 kPa as the temperature is raised to 125o C. What is the new volume?
First, determine what formula we’re going to use to find what’s missing:
We’re finding V2 = V1 x P1 x T2
P2 x T1
Now substitute, changing the temp to Kelvin:
![Page 20: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/20.jpg)
Example 2• A gas at 155 kPa and 25o C occupies a
container with an initial volume of 1 L. By changing the volume, the pressure of a gas increases to 605 kPa as the temperature is raised to 125o C. What is the new volume?
First, determine what formula we’re going to use to find what’s missing:
We’re finding V2 = V1 x P1 x T2
P2 x T1
Now substitute, changing the temp to Kelvin:V2 =(1L)x(155kPa)x(398K)
(605kPa)x(298K)
![Page 21: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/21.jpg)
Example 2• A gas at 155 kPa and 25o C occupies a
container with an initial volume of 1 L. By changing the volume, the pressure of a gas increases to 605 kPa as the temperature is raised to 125o C. What is the new volume?
First, determine what formula we’re going to use to find what’s missing:
We’re finding V2 = V1 x P1 x T2
P2 x T1
Now substitute, changing the temp to Kelvin:V2 =(1L)x(155kPa)x(398K)
(605kPa)x(298K)
V2 = 0.342 L
![Page 22: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/22.jpg)
Example 3• A 5 L air sample at a temperature of – 50o
C has a pressure of 107 kPa. What will be the new pressure if the temperature is raised to 102o C and the volume expands to 7 L?
![Page 23: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/23.jpg)
Example 3• A 5 L air sample at a temperature of – 50o C has
a pressure of 107 kPa. What will be the new pressure if the temperature is raised to 102o C and the volume expands to 7 L?
First, determine what formula we’re going to use to find what’s missing:
![Page 24: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/24.jpg)
Example 3• A 5 L air sample at a temperature of – 50o C has
a pressure of 107 kPa. What will be the new pressure if the temperature is raised to 102o C and the volume expands to 7 L?
First, determine what formula we’re going to use to find what’s missing:
We’re finding P2 = V1 x P1 x T2
V2 x T1
![Page 25: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/25.jpg)
Example 3• A 5 L air sample at a temperature of – 50o C has
a pressure of 107 kPa. What will be the new pressure if the temperature is raised to 102o C and the volume expands to 7 L?
First, determine what formula we’re going to use to find what’s missing:
We’re finding P2 = V1 x P1 x T2
V2 x T1
Now substitute, changing the temp to Kelvin:
![Page 26: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/26.jpg)
Example 3• A 5 L air sample at a temperature of – 50o C has
a pressure of 107 kPa. What will be the new pressure if the temperature is raised to 102o C and the volume expands to 7 L?
First, determine what formula we’re going to use to find what’s missing:
We’re finding P2 = V1 x P1 x T2
V2 x T1
Now substitute, changing the temp to Kelvin:P2 =(5L)x(107kPa)x(375K)
(7L)x(223K)
![Page 27: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/27.jpg)
Example 3• A 5 L air sample at a temperature of – 50o C has
a pressure of 107 kPa. What will be the new pressure if the temperature is raised to 102o C and the volume expands to 7 L?
First, determine what formula we’re going to use to find what’s missing:
We’re finding P2 = V1 x P1 x T2
V2 x T1
Now substitute, changing the temp to Kelvin:P2 =(5L)x(107kPa)x(375K)
(7L)x(223K)
P2 = 128.52 kPa
![Page 28: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/28.jpg)
Example 4A given mass of air has a volume of 6 L at 101 kPa.
What volume will it occupy at 25 kPa if the temperature does not change?
![Page 29: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/29.jpg)
Example 4A given mass of air has a volume of 6 L at 101 kPa.
What volume will it occupy at 25 kPa if the temperature does not change?
First, determine what formula we’re going to use to find what’s missing. Since temp doesn’t change, T1 and T2 cancel each other out:
![Page 30: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/30.jpg)
Example 4A given mass of air has a volume of 6 L at 101 kPa.
What volume will it occupy at 25 kPa if the temperature does not change?
First, determine what formula we’re going to use to find what’s missing. Since temp doesn’t change, T1 and T2 cancel each other out:
We’re finding V2 = V1 x P1 x T2
P2 x T1
![Page 31: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/31.jpg)
Example 4A given mass of air has a volume of 6 L at 101 kPa.
What volume will it occupy at 25 kPa if the temperature does not change?
First, determine what formula we’re going to use to find what’s missing. Since temp doesn’t change, T1 and T2 cancel each other out:
We’re finding V2 = V1 x P1 x T2
P2 x T1
Now substitute, changing the temp to Kelvin:V2 = (6L)x(101kPa)
(25kPa)
![Page 32: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/32.jpg)
Example 4A given mass of air has a volume of 6 L at 101 kPa.
What volume will it occupy at 25 kPa if the temperature does not change?
First, determine what formula we’re going to use to find what’s missing. Since temp doesn’t change, T1 and T2 cancel each other out:
We’re finding V2 = V1 x P1 x T2
P2 x T1
Now substitute, changing the temp to Kelvin:V2 = (6L)x(101kPa)
(25kPa)
V2 = 24.24L
![Page 33: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/33.jpg)
A Word of Caution!!When we’re trying to find an unknown
Temp., like T2…
P1 V1 P2V2
T1 T2
=
![Page 34: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/34.jpg)
A Word of Caution!!When we’re trying to find an unknown
Temp., like T2…
P1 V1 P2V2
T1 T2
=
![Page 35: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/35.jpg)
A Word of Caution!!When we’re trying to find an unknown
Temp., like T2…
P1 V1 P2V2 So we have P1 V1 1
T1 T2 P2 V2 T1 T2
This doesn’t work, to have 1/T2
= =
![Page 36: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/36.jpg)
A Word of Caution!!When we’re trying to find an unknown
Temp., like T2…
P1 V1 P2V2 So we have P1 V1 1
T1 T2 P2 V2 T1 T2
To fix this, we need to invertinvert both sides:
= =
![Page 37: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/37.jpg)
A Word of Caution!!When we’re trying to find an unknown
Temp., like T2…
P1 V1 P2V2 So we have P1 V1 1
T1 T2 P2 V2 T1 T2
To fix this, we need to invert both sides:
P2 V2 T1 T2
P1 V1
=
=
=
![Page 38: The Gas Laws Learning about the special behavior of gases Objective #2, begins on pg. 5 of the Note pack](https://reader030.vdocuments.us/reader030/viewer/2022032707/56649e4e5503460f94b44d68/html5/thumbnails/38.jpg)
•Practice…•Practice…•Practice!!
Now you know how to do MOST of Objective
#2 (we’ll do the rest a little later…)
Next part is “Collecting a gas over water”