technician’s list

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Technician’s List Technician’s List Two Demonstrations:- Two Demonstrations:- Standing waves on a string (please Standing waves on a string (please leave string in the Sun or under UV leave string in the Sun or under UV Lamp) Lamp) Activity 150 D:- More complicated Activity 150 D:- More complicated standing wave (just the standing standing wave (just the standing wave on a loop please) wave on a loop please) Worksheets:- Worksheets:- AS_Unit1_Quantum_06_De_Broglie_Quest AS_Unit1_Quantum_06_De_Broglie_Quest ions ions

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Technician’s List. Two Demonstrations:- Standing waves on a string (please leave string in the Sun or under UV Lamp) Activity 150 D:- More complicated standing wave (just the standing wave on a loop please) Worksheets :- AS_Unit1_Quantum_06_De_Broglie_Questions. Wave Particle Duality. - PowerPoint PPT Presentation

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Page 1: Technician’s List

Technician’s ListTechnician’s List

Two Demonstrations:-Two Demonstrations:- Standing waves on a string (please Standing waves on a string (please

leave string in the Sun or under UV leave string in the Sun or under UV Lamp)Lamp)

Activity 150 D:- More complicated Activity 150 D:- More complicated standing wave (just the standing wave standing wave (just the standing wave on a loop please)on a loop please)

Worksheets:- Worksheets:- AS_Unit1_Quantum_06_De_Broglie_QueAS_Unit1_Quantum_06_De_Broglie_Questionsstions

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Wave Particle DualityWave Particle Duality

Quantum Physics Lesson 3Quantum Physics Lesson 3

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Today’s ObjectivesToday’s Objectives

Explain what is meant by wave-particle Explain what is meant by wave-particle duality.duality.

Describe the main points of de Broglie’s Describe the main points of de Broglie’s hypothesis that matter particles also have a hypothesis that matter particles also have a wave-like nature.wave-like nature.

State and use the equation State and use the equation λλ = h/p = h/mv = h/p = h/mv

Describe evidence for de Broglie’s hypothesis.Describe evidence for de Broglie’s hypothesis.

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Wave particle dualityWave particle duality

What evidence is there that light is a wave? What evidence is there that light is a wave? What evidence is there that light is a particle?What evidence is there that light is a particle?

Think about it yourself. Write a few sentences.

Discuss with the person next to you

Page 6: Technician’s List

Prince Louis de BrogliePrince Louis de Broglie1892-19871892-1987

Electrons should not Electrons should not be considered simply be considered simply as particles, but that as particles, but that frequency must be frequency must be assigned to them also.assigned to them also.

(1929, Nobel Prize (1929, Nobel Prize Speech)Speech)

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Prince Louis de BrogliePrince Louis de Broglie1892-19871892-1987

Louis de Broglie reasoned Louis de Broglie reasoned that if Light can behave like that if Light can behave like a wave as well as a particle a wave as well as a particle then matter can behave like then matter can behave like a wave. a wave.

He predicted that all matter He predicted that all matter also behaves like a wave. also behaves like a wave.

The wavelength of this The wavelength of this wave will be inversely wave will be inversely proportional to the object’s proportional to the object’s momentum. momentum.

The constant of The constant of proportionality is Planck’s proportionality is Planck’s Constant. Constant.

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De Broglie (1924)De Broglie (1924) Suggested that particles such as electrons Suggested that particles such as electrons

might show wave properties.might show wave properties. He summised that the He summised that the de Broglie de Broglie

wavelengthwavelength, , λλ was given by: was given by:

m = mass

v = velocity of the particle

mv

h

p

h

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Note that:-• This is a matter wave equation not electromagnetic wave• The de Broglie wavelength can be altered by changing the velocity of the particle.

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The de Broglie wavelength λ In 1923 de Broglie hypothesised:

* Matter particles have a dual wave-particle nature

* The wave like behaviour is characterised by a wavelength λ

λ = h mv

h = planks constant

m = mass

v = velocity

λ = h p

Change the by changing a particle’s speed

λ

Page 11: Technician’s List

The de Broglie wavelength λ In 1923 de Broglie hypothesised:

* Matter particles have a dual wave-particle nature

* The wave like behaviour is characterised by a wavelength λ

λ = h mv

h = Planks constant

m = mass

v = velocity

λ = h p

Change the by changing a particle’s speed

λ

Page 12: Technician’s List

The de Broglie wavelength λ In 1923 de Broglie hypothesised:

* Matter particles have a dual wave-particle nature

* The wave like behaviour is characterised by a wavelength λ

λ = h mv

h = Planks constant

m = mass

v = velocity

λ = h p

Change the by changing a particle’s speed

λ

Page 13: Technician’s List

In words...In words...

momentum

constant sPlanck'h wavelengtBroglie de

velocitymass

constant sPlanck'h wavelengtBroglie de

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The diffraction tubeThe diffraction tube

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Activity 240DActivity 240DDemonstration Demonstration

'Superposing electrons''Superposing electrons' Video of activity Video of activity

http://www.youtube.com/watch?v=pnlP-z-cZBM

http://www.youtube.com/watch?v=i0xMgsnmE4Y – With explanation – With explanation

http://www.youtube.com/watch?v=vCRNGqXBPRk&feature=channel&list=UL

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Summary of ExperimentSummary of Experiment

Beam of electrons directed at a thin Beam of electrons directed at a thin metal foil.metal foil.

Rows of atoms cause the electron Rows of atoms cause the electron beam to be diffracted in certain beam to be diffracted in certain directions only.directions only.

We observe rings due to electrons We observe rings due to electrons being diffracted by the same amount being diffracted by the same amount from grains of different orientations, at from grains of different orientations, at the same angle to the incident beam.the same angle to the incident beam.

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What we should seeWhat we should see

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Electron diffractionElectron diffraction 1927: Davisson & Gerner confirmed 1927: Davisson & Gerner confirmed

this prediction with experiments this prediction with experiments using electron beams.using electron beams.

They actually used a nickel target They actually used a nickel target instead of a carbon one (we used)instead of a carbon one (we used)

The wavelength they measured The wavelength they measured agreed with de Broglieagreed with de Broglie

There is a relationship between the There is a relationship between the accelerating voltage V and the k.e. of accelerating voltage V and the k.e. of the particlesthe particles

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Diffraction effects have been shown forDiffraction effects have been shown for

Hydrogen atomsHydrogen atomsHelium atomsHelium atoms

Neutrons Neutrons

Neutron diffraction is an excellent way Neutron diffraction is an excellent way of studying crystal structures.of studying crystal structures.

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ACTIVITY 300SACTIVITY 300SSOFTWARE BASED SOFTWARE BASED 'ELECTRONS 'ELECTRONS INTERFERING ONE BY INTERFERING ONE BY ONE' ONE'

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Energy Levels ExplainedEnergy Levels Explained

Two Demonstrations:-Two Demonstrations:- Standing waves on a stringStanding waves on a string Activity 150 D:- More complicated Activity 150 D:- More complicated

standing wave (just the standing wave standing wave (just the standing wave on a loop please)on a loop please)

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mv

h

p

h

What is the wavelength of a human being, assuming he/she weighs 70 kg, and is running at 25 m/s?

De Broglie WavelengthDe Broglie Wavelength

In 1932, De In 1932, De Broglie Broglie discovered that discovered that all particles with all particles with momentum have momentum have an associated an associated wavelength.wavelength.

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Practice QuestionsPractice Questions 1.Find the wavelength of an electron of 1.Find the wavelength of an electron of

mass 9.00 × 10mass 9.00 × 10-31-31 kg moving at 3.00 × 10 kg moving at 3.00 × 1077 m m ss-1-1

2.  Find the wavelength of a cricket ball of 2.  Find the wavelength of a cricket ball of mass 0.15 kg moving at 30 m smass 0.15 kg moving at 30 m s-1-1..

3.  It is also desirable to be able to calculate 3.  It is also desirable to be able to calculate the wavelength associated with an electron the wavelength associated with an electron when the accelerating voltage is known. when the accelerating voltage is known. There are 3 steps in the calculation. There are 3 steps in the calculation. Calculate the wavelength of an electron Calculate the wavelength of an electron accelerated through a potential difference of accelerated through a potential difference of 10 kV.10 kV.

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Step 1: Kinetic energy Step 1: Kinetic energy

EEKK = = eVeV = 1.6 × 10 = 1.6 × 10-19-19 × 10000 = 1.6 × 10 × 10000 = 1.6 × 10-15-15 J J

Step 2: Step 2:

EEKK = ½ mv = ½ mv22 = ½m (mv) = ½m (mv) 22 = p = p22 / 2m, / 2m, so momentumso momentum

pp = √2m = √2mEEkk = √2 × 9.1 × 10 = √2 × 9.1 × 10-31-31 × 1.6 × 10 × 1.6 × 10-15-15 = 5.4 × 10= 5.4 × 10-23-23 kg m s kg m s-1-1

Step 3: Wavelength Step 3: Wavelength λλ = h / p = 6.63 × 10 = h / p = 6.63 × 10-34-34 / 5.4 × 10 / 5.4 × 10-23-23 = 1.2 × = 1.2 ×

1010-11-11 m m = 0.012 nm.= 0.012 nm.

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Slits

Laser

Screen 1

L1

Slit spacing, dWavelength, Distance to screen, LFringe spacing, x

Screen 2L2

d1d2

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EndEnd