table of contents graphing quadratic functions – general form it is assumed that you have...
DESCRIPTION
Table of Contents Sketch the Graph of a Quadratic in Standard Form Face Up Face Down Vertex Axis of symmetry x-int: f (x) = 0 and solve for x y-int: x = 0 and solve for y Draw the parabolaTRANSCRIPT
Table of Contents
Graphing Quadratic Functions – General Form
• It is assumed that you have already viewed the previous three slide shows titled
Graphing Quadratic Functions – ConceptGraphing Quadratic Functions – Standard FormGraphing Quadratic Functions – Converting
General Form To Standard Form
• The next three pages are summaries from those shows, and are important to understanding this module.
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2( )f x ax bx c
General Form of a Quadratic Function
Standard Form of a Quadratic Function
2( )f x a x h k
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2( ) ( )f x a x h k
Sketch the Graph of a Quadratic in Standard Form
0a Face Up
0a Face Down
Vertex ( , )V h k
Axis of symmetry
x h
x-int: f (x) = 0 and solve for x
y-int: x = 0 and solve for y
Draw the parabola
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Vertex - General Form
2bxa
2( )f x ax bx c
• Given the general form of a quadratic function …
…the x-value of the vertex is given by
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2bxa
• There are two other helpful concepts for graphing a quadratic function that is in general form.
We already know that the x-value of the vertex is given by …
• Concept 1:
To find the y-value of the vertex, just plug the x-value into the function …
2bfa
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Thus, the vertex of the graph of the quadratic function in general form is given by
• Concept 2:
,2 2b bV fa a
The a of the general form is the same value as the a in the standard form.
This means that the a in the general form can be used to determine the face up/face down behavior, just as it did in the standard form.
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Summary for Graphing Quadratics in General Form
0a Face Up
0a Face Down
2( )f x ax bx c
Axis of symmetry 2
bx
a
,2 2b b
V fa a
x-int: f (x) = 0 and solve for x
y-int: x = 0 and solve for y
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• Example:
Sketch the graph of the given quadratic function.
2( ) 3 12 9f x x x
3a Face down
Vertex:2bxa
12
2 3
126
2
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2( ) 3 12 9f x x x 2x
2( 2) 3 2 12 2 9f
3 4 12 2 9
12 24 9 3Vertex 2,3V
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Axis of Symmetry: x = x-value of vertex
2x
2,3V
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x-intercepts
2( ) 3 12 9f x x x
2
2
3 12 9 0
3 4 3 0
3 1 3 0
x x
x x
x x
3, 1x
3,0 1,0
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y-intercept
2( ) 3 12 9f x x x
0, 9
2(0) 3 0 12 0
9
f
0x
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Summary:
Face down
2,3V
2x Axis:
Function: 2( ) 3 12 9f x x x
x-intercepts
3,0 1,0
y-intercept
0, 9
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Plot the vertex 2,3V
2x Plot the axis:
Plot the point: 1,0
-5
4
2
-2
-4
-5
4
2
-2
-4
-5
4
2
-2
-4
Draw the branch of the parabola on the right side of the axis. -5
4
2
-2
-4
Use symmetry to draw the left branch.
-5
4
2
-2
-4Label
-5
4
2
-2
-4
(-1,0)
x=-2
(-2,3)
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