t wilson
TRANSCRIPT
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The Mechanistic Studies of theWacker Oxidation
Tyler W. WilsonSED Group Meeting
11.27.2007
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Introduction
• Oxidation of ethene by Pd (II) chloride solutions (Phillips, 1894)-First used as a test for alkenes (Pd black was the indicator)C2H4 + Pd(II)Cl2 + H2O → C2H4O + Pd(0) + 2HCl
• Later Smidt and co-workers employed cupric chloride toregenerate the Pd (0) catalyst (Smidt, 1962)
• What made Smidt’s process applicable to large scale production was thefinal recycling of CuCl back to Cu(II)Cl2 by air
C2H4 + Pd(II)Cl2 + H2O → C2H4O + Pd(0) + 2HCl Pd(0) + 2CuCl2 → Pd(II)Cl2 + 2CuCl
2 CuCl + 1/2 O2 + 2 HCl → 2CuCl2 + H2O
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Introduction
PdCl42- + C2H4 + H2O → Pd(0) + CH3CHO +2 HCl + 2 Cl- (1)Pd(0) + 2 CuCl2 + 2 Cl- → PdCl42- + 2 Cu(I)Cl (2)2 Cu(I)Cl + 2 HCl + 1/2 O2 → 2 Cu(II)Cl2 + H2O (3)
Net: C2H4 + 1/2 O2 → CH3CHO (4)
• Adding up the three reactions gives the Wacker Oxidation Reaction :
Wacker Oxidation Reaction
• Why is it called the Wacker Oxidation?-Smidt and co-workers discovered the reaction at Consortium Fur Elecktrochemie Industrie G.M.BH., Munich, Germany (a subsidiary of WackerChemie)
• Industrial Importance:- Plants with production capacity of 15,000 tons of acetaldehyde per yearhave been developed
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Introduction
Chloride Inhibition:
Proton Inhibition:
PdCl
Cl
OH2
H2C
CH2 PdCl
Cl
OH2
PdCl
Cl
OH2
OH
OH
H2O
PdCl
Cl
OH
H2C
CH2H
Ka
H
Slow
H2O
K
CH3CHO
Slow
Fast
PdCl42- + C2H4
K1PdCl3(C2H4)1- + Cl1-
PdCl3(C2H4)1- + H2OK2
PdCl2(C2H4)(H2O) + Cl1-
1/[Cl-] term
1/[Cl-] term
outer sphere (trans)
inner sphere (cis)
-d[olefin]
dt=
k [ PdCl4-2 ] [olefin]
[ H+ ] [ Cl - ]2Rate =
Rate Equation: -First order in Pd and alkene-Chloride squared inhibition term-Proton inhibition term
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C2D4 + PdCl42- + H2O CD3CDO + Pd(0) + 2 HCl + 2 Cl-
C2H4 + PdCl42- + H2O CH3CHO + Pd(0) + 2 HCl + 2 Cl-
kD
kH
Observed KIE = kH / kD = 1.07
+ PdCl42- + H2O
H H
D DH+
H2OC C
D D
H HOHCl2(OH2)Pd
CH2DCDO
CHD2CHOCompetitive isotope effect = kH / kD = 1.9
Early Evidence for Inner-Sphere Mechanism: KIEs
• Observed Kinetic Isotope Effects
• Competitive isotope effect:
• No deuterium incorporation is observed when reaction is run in D2O
GROUPEXERCISE
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PdCl
Cl
OH2
H2C
CH2 PdCl
Cl
OH2
PdCl
Cl
OH2
OH
OH
H2O
PdCl
Cl
OH
H2C
CH2H
Ka
H
RDS
H2O
K
CH3CHO
RDS
Fast
inner sphere (cis)
Proton Inhibition
Proton Inhibition
Early Evidence for Inner-Sphere Mechanism: KIEs
• Inner-sphere was initially proposed based on observed kinetics in combinationwith kinetic isotope effect (circa 1964)
• Outer-sphere was disfavored because RDS is after hydroxypalladationreasonable to assume a KIE would be observed• Stereochemical probe of the reaction is needed
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Pd Cl
ClHO Pd
Cl 2
C
O
O
H2O
Na2CO3
CO
H
DD
HPdCl2
2
NaOAc
CH3CNH2O
HO
PdH
D
DH
Cl
2
HO
HD
DH
COPdL3
OO
HD
DH
CO
retentiveinsertion
Trans stereochemistry confirmed by1H-NMR
coupling constant
Evidence For Outer-Spere Addition: Stille Study
• Trapping hydropalladated intermediate with CO
Problem: Sterically, syn addition would be disfavored with a chelating diolefin
Problems:-Solvent is CH3CN not water-Previous studies have shown that dimeric Pd(II)complexes were prone to anti addition-Strong CO binds Pd strongly and could preventcoordination of H2O
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H2C CH2 PdCl42-+
[Cl-] < 1M
[Cl-] > 3 M
[CuCl2] > 2.5 M
HOCl
CH3CO
CH3CO
PdCl
Cl
OH2
H2C
CH2H2O
O2
O2
Stereochemistry is lost
Stereochemistry is retained(potentially)
[CuCl2] < 1M
Evidence for Outer-Spere: Backvall Study
• Product distribution depends on chloride and CuCl2 concentrations:
• Major Assumptions:-Chlorohydrin and ethanal are formed from the same intermediate:(PdCl2(H2O)(C2H4))- Steric course of the reaction is not altered by running at higher chloride andcupric chloride concentrations
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D
D
H
H
C CD
H D
H
Pd OH2Cl
Cl
OH
HDL3Pd
D H OH
HD
Cl
HD
threo
CuCl2
LiCl
H2O
"trans"
PdCl42-
"inversion"
D
D
H
H
PdCl42- C C
D
H D
H
Pd OH
Cl
Cl OH
DH
L3Pd
D H
OH
HDCl
HD
erythro
CuCl2
LiCl
H2O
"cis""inversion"
(E)-d2-ethene
D
H
D
H
(Z)-d2-ethene erythro
D
H
D
H
(Z)-d2-ethene threo
"trans" OH
HDCl
HD
OH
HD
Cl
HD"cis"
Evidence for Outer-Spere: Backvall Study
• Stereochemical course of trans-addition (outer-sphere):
• Stereochemical course of cis-addition (inner-sphere):
Similarly,
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H
HD
D
HO
DH HgCl
HD Cl
HD
HO
HD
PdCl4-2
"retention"
CuCl2
LiCl
HO
DH PdL3
HD
Hg(NO3)2
AcOH
H2O
40% yield> 96% threo
HO
DH PdL3
HD O
D HH D
Cl
HDHO
HD
erythro
CuCl2
LiCl
Evidence for Outer-Spere: Backvall Study
• Control experiments:(1) (Z)/(E) isomerization was less than 1%(2) Confirmed cleavage of 1° palladium-carbon bond by CuCl2-LiCl proceeded with
inversion(3) Confirmed chlorohydrin was not being obtained from an epoxide intermediate
-Stereochemistry predicted for chlorohydrin via epoxide intermediate
-Independent preparation of a hydroxypalladated ethene
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DHC CHD (gas)
0.033 M PdCl2 (aq.)
2.7 M CuCl2 (aq.),
3.3 M LiCl (aq.)
5 kg/cm2 , 20-40 h, 20 °C ClOH
D
D(E or Z)
6 M NaOH
O
D D
O
D D
And/or
Evidence for Outer-Spere: Backvall Study
Model for anti addition predicts: (E)-ethene-d2 → (Z)-ethylene oxide-d2
(Z)-ethene-d2 → (E)-ethylene oxide-d2
• Results clearly indicate that under these reactions conditions an outer-sphere mechanismis operative
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PdCl
Cl
OH2
H2C
CH2 PdCl
Cl
OH2
OH
H2O HK3 OH
PdCl
OH2
RDS
14 e- complex
fast
PdCl
H
OH2
CH2
OH
PdCl
H
OH2
CH2
OH
Cl
16 e- complex
18 e- complex!"Hydride Elimination
RDS
X
OH2
PdCl
OH
Me
O
H CH3
2 3
4
PdCl42- C2H4
H2O - 2 [Cl-] 1
Evidence for Outer-Spere: Backvall Study
• Backvall Outer-Sphere Mechanism:
Experimental observations1. Chloride inhibition2. Proton inhibition3. Very low KIE4. No D-incorporation
from D2O
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Reevaluation of Inner and Outer Sphere Mechansims
• Kinetically, the main difference between the mechanisms is the position of therate-determining step:
-Outer-sphere: Trans-hydroxypalladation is in equilibrium (proton inhibition) and RDSoccurs downstream of this step-Inner-sphere: Proton inhibition results from Acid/Base equilibrium prior to cis-hydroxypalladation and the RDS is the hydroxypalladation
PdCl
Cl
OH2
H2C
CH2 PdCl
Cl
OH2
PdCl
Cl
OH2
OH
OH
H2O
PdCl
Cl
OH
H2C
CH2H
Ka
H
H2O
K
CH3CHO
RDS
Fast
outer sphere (anti)
inner sphere (syn)
RDS
• Distinguishing the mechanisms requires an olefin that will undergo anexperimentally observable change if the hydroxypalladation is in equilibrium
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OHD
D H HPdCl4
-2 H2O
HO
D D
Pd(II)
OH
H H
HO H
HDDPdCl4
-2H2O
1a 1b
k2
k1
k-1
k1
k-1
Oxidation Products
H
Evidence for Inner-Sphere: Isomerization of Allylic Alcohol
• Isomerization of deuterated allyl alcohol
Inner-sphere mechanism:• k2 >> k-1
• At early conversion very littleisomerization will be observed
Outer-sphere mechanism:• k2 << k-1
• At early conversionisomerization will be observed
Experimental Predictions
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Evidence for Inner-Sphere: Isomerization of Allylic Alcohol
OH
Me PdCl42-
PdCl42-
Me
O
Me OMe
H
90% 10%(Markovnikov) (Anti-Markovnikov)
O
H
OHMe
O
OH
40%12%
Me OH
Me OH
PdII
OH
Me OH
OH
PdII
PdCl42-
Me
O
OH
OMe
OH H
Me
O
OH
2.6%
49% 39%
(Markovnikov) (Anti-Markovnikov)
• Directing influence of hydroxyl group
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OHD
D H HPdCl4
-2 H2O
[H+] =0.4 M[Cl-] = 0.4 M
Oxidation Productsstd. kinetic rxn
conditionsHenry, P. M. et. al. J. Mol. Cat. 1982, 16, 81-87
Less 3% isomerization observered in recoverd starting material after
oxidation had preceeed to 50% conversion
Evidence for Inner-Sphere: Isomerization of Allylic Alcohol
Control Experiments:-No detectable isomerization observed in the absence of Pd (II)-Kinetic study revealed that the oxidation of allyl alcohol obeyed the samerate expression as observed for ethene (eqn 1)
Initial Result:
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Evidence for Inner-Sphere: Isomerization of Allylic Alcohol
Kinetic Data for Isomerization
Oxidation rate is 2xisomerization rateIsomerization rate is5x Oxidation rate
OHD
D H HPdCl4
-2
1a
-d[olefin]
dt=
kox [ PdCl4-2 ] [olefin]
[ H+ ] [ Cl - ]2(1)Rate =
-d[olefin]
dt=
ki [ PdCl4-2 ] [olefin]
[ Cl - ](2)Rate =
[ LiCl] = 0.2-3.3 M[HClO4] = 0.2- 2.0 M[PdCl4
2-] = 0.01-0.10 M
Quinone, H2O
HO H
HDD
O
H OH
Me
isomerization oxidation
Rate expresion for oxidation
Rate expresion for isomerization
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Evidence for Inner-Sphere: Isomerization of Allylic Alcohol
• Question: Why is isomerization the predominate process at high [Cl-]?
PdCl Cl
Cl
CH2OH
PdCl Cl
Cl CH2OH
HOH2C
PdCl Cl
Cl CH2OHH2O H2O
+ H+
2- 1-1-
PdCl
Cl
OH2
H2C
CH2 PdCl
Cl
OH2
PdCl
Cl
OH2
OH
OH
H2O
PdCl
Cl
OH
H2C
CH2
H
SlowH2O
K
1- 1-
1-
CH3CHO
CH3CHO
Labile coordination site
Pd
Cl
Cl CH2OH
HOH2C 1-
Cl-
Unfavorable at high [Cl-]
• Compare to proposed wacker intermediates that lead to oxidation
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Evidence for Inner-Sphere: Kinetic Probe
• Design a kinetic probe in which RDS is hydroxypalladation
Assumption:-Exchange is completely symmetric then k1 = k-1’ and k-1 = k-1’, then the rate ofisomerization only depends on the rate of formation of 3, not on its equilibrium conc.
Prediction:-Kinetics will follow rate equation (1) if syn hydroxypalladation is operative (b/c protonequilibrium is prior to RDS)-Kinetics will follow rate equation (3) if trans hydroxypalladation is operative
O16HF3C
CH3 CF3
CD3PdCl4
-2 H218O
H16O
H3C CF3
Pd(II)18OH
CF3
CD3
H18O CD3
CF3CH3F3C
PdCl4-2H2
16O
k1
k-1
k1'
k-1'H
=ki [ PdCl4
-2 ] [olefin]
[ Cl - ]2 [H + ]
2a 2b
3
Rate (1) =ki [ PdCl4
-2 ] [olefin]
[ Cl - ]2Rate (3)
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Evidence for Inner-Sphere: Kinetic Probe
Results:Kinetic Data
-Kinetic data shows clear inversedependence on [H+]-The value of ki was calculated fromeqn 1 and remains fairly constant overrange of Pd, Cl and H concentrations
=ki [ PdCl4
-2 ] [olefin]
[ Cl - ]2 [H + ]Rate (1)
=ki [ PdCl4
-2 ] [olefin]
[ Cl - ]2Rate (3)
• Kinetic data is consistent with syn hydoxypalladation, what about stereochemistry ofisomerization
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Evidence for Inner Sphere: Kinetic Probe
• Prediction on stereochemical outcome of the isomerization
-Syn should lead to inversion and Anti should give retention
Isomerization Results:
• Stereochemistry of isomerzation is alsoconsistent with a syn hydroxypalladation• Downside this alkene is not a goodmodel of an actual Wacker substrate
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Evidence for Inner Sphere: Transfer of Chirality
• Chirality Transfer to study modes of addition
• Study stereochemistry of products at both high and low chlorideconcentrations• Anti-addition at low chloride will give the opposite absolutestereochemistry
C CC
H
R
H
H
R2
HO PdII
X
R
S H
R2 H
C
X
R1
H
(S)-(E)-1a
R
O X
R1
H
(S)-5, 5' or 5''
or
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C CC
H
Me
H
H
Me
HO(R)-Z-3a(53% ee)
MeOH
Li2PdCl4, NEt3CuCl2, PhHgCl
Me
O
Ph
Me H
(R)-2
Low Chloride84% yield30% ee
Me PhMe H
(S)-Z-3a''High Chloride
70% yield68% ee
(S)-Z-3a(74% ee)
Similarily,
Evidence for Inner Sphere: Transfer of Chirality
Controls:
1. Test a nucleophile whose mode of addition is known to be syn regardless ofchloride concentration
Results:
• Results suggest a syn hydroxypalladation at low chloride concentrations and an antihydroxypalladation at high chloride concentrations
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Computational Study of the Wacker Oxidation
• Combined catalytic cycles of the Wacker Oxidation
Wacker Conditions:LL conditions (Industria): Low[Cl-] (< 1M) and low [CuCl2](< 1M) yield only aldehyde viainternal syn addition (rate eqn 1)HH conditions: high [Cl-] (> 3 M)and high [CuCl2] (> 2.5M) yieldboth aldehyde and chlorohydrinvia external anti addition (rateeqn 2)HL conditions: yield no oxidationproductsLH conditions: yield syn and antiproducts, and obey a combinedrate law
• Employed computational models (hybrid density functional theory andimplicit solvation methods) to investigate relevant steps in cycle
Goddard, W. A. et. al. J. Am. Chem. Soc. 2007, 129, 12342-12343
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Computational Study of the Wacker Oxidation
Key Results (Syn pathway):1. For the syn manifold, the calculated barrier
for the deprotonation from 3 (5.8 kcal/mol)to 4 (15.3 kcal/mol) is plausible under thestandard conditions (pH 0-2)
2. The calculated barrier for 4 to 5 is ΔG** =33.4 kcal/mol and is far to high to befeasible for the Wacker process (ΔG**expt =22.4 kcal/mol)
Overall for syn: 1→ 2 → TS-ALE1 → 3 → TS-INT → 10 → TS-ISO (RDS) → 6 → product
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Computational Study of the Wacker OxidationKey Results (anti-pathway):
-Overall for anti: 1→ 2 → TS-EXT (RDS) → 9-H → TS-ALE2 → 10 → TS-ISO → 6 →product-Since anti obeys rate equation 2 there is no proton inhibition so TS-EXT being the RDSis consistent with rate law
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Computational Study of Wacker Oxidation
Results: Role of CuCl2
Stabilizing Interactions:CuCl2 stabilizes both TS-ISO (by -6.0 kcal/mol) and TS-EXT (by -1.9 kcal/mol)Destabilizing Interactions:CuCl2 destabilizes TS-ALE1 (by + 2.7 kcal/mol)-Predicts at HH anti pathway is strongly favored
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Conclusions
• Mechanism of the Wacker oxidation is dependent on the reaction conditionsand is best described by two competing processes
Inner-SpereHydroxypalladation
-Occurs at low [Cl-] andlow [CuCl2]-Rate is best describedby eqn 1-RDS is still debated
Outer-SphereHydroxypalladation
-Occurs at high [Cl-] andhigh [CuCl2]-Rate is best describedby eqn 2-RDS is still debated
• Kinetic and stereochemical models have been well studied and future workmay need to relay more heavily on computational models
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References
Excellent Reviews:(1) P. M. Henry, Palladium Catalyzed Oxidation of Hydrocarbons; D. Reidel, Dordrecht:
Holland, 1980, p. 41.(2) P. M. Henry, In Handbook of Organopalladium Chemistry for Organic Synthesis;
Negishi, E., Ed.; Wiley & Sons: New York, 2001; p. 209Initial Kinetic Studies:(1) Smidt, J. et. al. Angew. Chem. Int. Ed. 1962, 1, 80-88(2) Henry, P. M. J. Am. Chem. Soc. 1964, 86, 3246-3250.Backvall Study:(1) Backvall, J. E. et. al. J. Am. Chem. Soc. 1979, 101, 2411-2416Computational Studies:(2) Goddard, W. A. et. al. J. Am. Chem. Soc. 2007, 129, 12342-12343(3) Siegbahn, E. M. J. Phys. Chem. 1996, 100, 14672-14680
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Additional Comments/Questions
http://en.wikipedia.org/wiki/Patrick_Henry
Patrick Henry“Give me liberty or give me death”
Updated Version“Give me syn or give me death”
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Group Exercise
Group Exercise
Given that (1) is an intermediate the reaction, write a mechanism thataccounts for the formation acetaldehyde observed in the KIE studies
C2D4 + PdCl42- + H2O CD3CDO + Pd(0) + 2 HCl + 2 Cl-
C2H4 + PdCl42- + H2O CH3CHO + Pd(0) + 2 HCl + 2 Cl-
kD
kH
Observed KIE = kH / kD = 1.07
+ PdCl42- + H2O
H H
D DH+
H2OC C
D D
H HOHCl2(OH2)Pd
CH2DCDO
CHD2CHOCompetitive isotope effect = kH / kD = 1.9
PdCl
Cl
OH2
OH
CH3CHO?
Reaction run in D2O shows no incorporation
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Solution for Group Exercise
PdH2O
Cl H
CH2
OH
PdCl
Cl
OH2
OHPd
H2O
ClOH
Cl-
PdH2O
Cl
OH
CH3
H3C
O
H
• Recent computational workquestions ability to undergo β-Hydride elimination from -OH(see Goddard, W. A. JACS,2006, 128, 3132 and referencetherein)
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Backup: Ruling out π-Allyl Pathway
Rate of isomerization isequal to 1/2 rate ofexchange
Rate of exchange isequal to rate ofisomerization
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Backup: Schematic for Industrial Wacker Process