stress analysis with quickfield - quickfield support...
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![Page 1: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/1.jpg)
Vladimir Podnos,
Director of Marketing and Support,Tera Analysis Ltd.
Introduction
Stress analysis with QuickField
Alexander Lyubimtsev
Support Engineer,Tera Analysis Ltd.
QuicField live demonstration
![Page 2: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/2.jpg)
QuickField Analysis Options
Magnetic analysis suite
Magnetic Problems
Magnetostatics
AC Magnetics
Transient Magnetic
Electric analysis suite
Electric Problems
Electrostatics and DC Conduction
AC Conduction
Transient Electric field
Thermostructural analysis suite
Thermal and
mechanical
problems
Steady-State Heat transfer
Transient Heat transfer
Stress analysis
![Page 3: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/3.jpg)
Stress Analysis
• Plane stress, plane strain, axisymmetric
stress problems
• Anisotropic elastic properties
• Distributed and concentrated loadings
• Thermal stresses, magnetic and electric
forces
• Various support conditions
• Results: displacements, stress components,
principal stresses, Von Mises, Treska,
Mohr-Coulomb and Drucker-Prager criteria
![Page 4: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/4.jpg)
MultiPhysics.
Joule
Heat
Stresses &
Deformations
Thermal
Stresses
Forces
Electromagnetic
fields
Temperature
Field
Temperature
s
Magnetic state
import
![Page 5: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/5.jpg)
Open object interface
![Page 6: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/6.jpg)
MultiPhysics with ActiveField.
Joule
Heat
Stresses &
Deformations
Thermal
Stresses
Forces
Electromagnetic
fields
Temperature
Field
Temperature
s
Magnetic state
import
Deformed
shape
![Page 7: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/7.jpg)
QuickField Difference
![Page 8: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/8.jpg)
1. Cylindrical rod
2. Perforated plate.
3. Stress distribution in a long solenoid.
4. Pipe subject to temperature and pressure.
5. Bimetallic thermal control
(parametric with LabelMover).
6. Winding force
7. Stress deformed shape.
Stress analysis with QuickField
![Page 9: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/9.jpg)
Cylindrical rod
Problem specification:
Young's modulus E = 70 GPa;
Poisson's coefficient ν = 1/3
http://quickfield.com/advanced/cylindrical_bar.htm
Task:
Calculate the rod elongation
Surface force
f = Force [N] / Area [m2]
![Page 10: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/10.jpg)
Perforated plate
Problem specification:
Plate thickness 5 mm.
Force density fy = - 40 N/mm2
Young's modulus E = 20.7 GPa;
Poisson's coefficient ν = 0.3
http://quickfield.com/advanced/stress1.htm
Task:
Calculate the stress
concentration factor
![Page 11: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/11.jpg)
Stress distribution in a long solenoid
Problem specification:
Current density
j = 0.1 A/mm2;
Young's modulus
E = 107.5 GPa;
Poisson's ratio ν = 0.33.
http://quickfield.com/advanced/coupl1.htm
Task:
Calculate the stress
distribution in the solenoid
R1 = 1 cm, R2 = 2 cm
j1
Magnetic force
F ~ j1*j2 / d12
F
F
j2d12
winding
![Page 12: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/12.jpg)
Pipe subject to temperature
and pressureProblem specification:
Inner surface T1 = 100 C;
Outer surface To = 0 C;
Internal pressure P = 1 MPa;
Coefficient of thermal
expansion α = 10 -6 1/K;
Young's modulus E = 300 GPa;
Poisson's ratio ν = 0.3. R1 = 1 cm, R2 = 2 cm
Task:
Calculate the stress
distribution in the pipehttp://quickfield.com/advanced/coupl2.htm
P
P
T1
T0pipe
![Page 13: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/13.jpg)
Bimetallic thermal control
Problem specification:
Brass bar
Eb = 15·106 psi (103 GPa)
αb = 10·10-6 1/F (18·10-6 1/K)
Magnesium bar
Em = 6.5·106 psi (44.8 GPa)
αm = 14.5·10-6 1/F (26.1·10-6 1/K)
Lb = 0.75"; Lm = 1.3"; δ = 0.005"
http://quickfield.com/advanced/thermal_control.htm
Task:
Calculate the temperature
increase at which the two bars
come into contact.
![Page 14: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/14.jpg)
Winding force
http://quickfield.com/advanced/winding_force.htm
Task:
Calculate the bobbin
deformation
Problem specification:
Winding force, F = 50 N.
Hooke's law elongation
dL/L0 = F / (E·Aw)
Thermal expansion
dL/L0 = α·dT
![Page 15: Stress analysis with QuickField - QuickField support sitequickfield.com/seminar/mechanics_webinar.pdf · Director of Marketing and Support, Tera Analysis Ltd. Introduction Stress](https://reader036.vdocuments.us/reader036/viewer/2022062600/5ad87d297f8b9a5b538df339/html5/thumbnails/15.jpg)
Stress deformed shape
Problem specification:
Steel core Young's modulus
E = 200 GPa,
Air gap d = 1 mm
Force applied F= 2 kN
Model depth Lz = 80 mm
http://quickfield.com/stress_deform.htm
F
d
Calculate:
1. Core displacement.
2. Magnetic flux distribution