stoichiometry. the haber process hydrogen gas and nitrogen gas combine to form ammonia gas skeleton...

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Stoichiometry

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Page 1: Stoichiometry. The Haber Process hydrogen gas and nitrogen gas combine to form ammonia gas Skeleton equation: N 2 (g) + H 2 (g) -> NH 3 (g) Balanced equation:

Stoichiometry

Page 2: Stoichiometry. The Haber Process hydrogen gas and nitrogen gas combine to form ammonia gas Skeleton equation: N 2 (g) + H 2 (g) -> NH 3 (g) Balanced equation:

The Haber Process hydrogen gas and nitrogen gas

combine to form ammonia gas

QuickTime™ and aTIFF (Uncompressed) decompressorare needed to see this picture.

Skeleton equation:

N2 (g) + H2 (g) -> NH3 (g)Balanced equation:

N2 (g) + 3H2 (g) -> 2NH3 (g)

Page 3: Stoichiometry. The Haber Process hydrogen gas and nitrogen gas combine to form ammonia gas Skeleton equation: N 2 (g) + H 2 (g) -> NH 3 (g) Balanced equation:

QuickTime™ and aTIFF (Uncompressed) decompressor

are needed to see this picture.

Page 4: Stoichiometry. The Haber Process hydrogen gas and nitrogen gas combine to form ammonia gas Skeleton equation: N 2 (g) + H 2 (g) -> NH 3 (g) Balanced equation:

1. How many grams of hydrogen would we need to convert 10.0 g of nitrogen into ammonia?

2. How many grams of ammonia can be made?

N2 (g) + 3H2 (g) -> 2NH3 (g)

QuickTime™ and aTIFF (Uncompressed) decompressor

are needed to see this picture.

ON RAMP: change grams of what you have into moles

BRIDGE: change moles of one material into moles of another

OFF RAMP: change moles of what you want back into grams

Page 5: Stoichiometry. The Haber Process hydrogen gas and nitrogen gas combine to form ammonia gas Skeleton equation: N 2 (g) + H 2 (g) -> NH 3 (g) Balanced equation:

N2 (g) + 3H2 (g) -> 2NH3 (g) 10.0 g ?

ON RAMP: change grams of what you have into moles

OFF RAMP: change moles of what you want back into grams

BRIDGE: change moles of one material into moles of another

= 2.16 g H2 needed to react with 10.0 g N2

10.0 g N2 x 1 mole N2

28.0 g N2

x 3 mol. H2

1 mol. N2

x 2.02 g H2

1 mol. H2

How many grams of hydrogen would we need to convert 10.0 g of nitrogen into ammonia?

Page 6: Stoichiometry. The Haber Process hydrogen gas and nitrogen gas combine to form ammonia gas Skeleton equation: N 2 (g) + H 2 (g) -> NH 3 (g) Balanced equation:

How many grams of ammonia can be made from 10.0 g nitrogen?

N2 (g) + 3H2 (g) -> 2NH3 (g) 10.0 g ?

ON RAMP: change grams of what you have into moles

OFF RAMP: change moles of what you want back into grams

BRIDGE: change moles of one material into moles of another

= 12.1 g NH3 can be made with 10.0 g N2

10.0 g N2 x 1 mole N2

28.0 g N2

x 2 mol. NH3

1 mol. N2

x 17.0 g NH3

1 mol. NH3

Page 7: Stoichiometry. The Haber Process hydrogen gas and nitrogen gas combine to form ammonia gas Skeleton equation: N 2 (g) + H 2 (g) -> NH 3 (g) Balanced equation:

Check your answer using Conservation of Mass.

N2 (g) + 3H2 (g) -> 2NH3 (g)

10.0 g N2 + 2.16 g H2 =12.1 g NH3 ?

12.16 g =12.1 g ?

yes, to within + 0.1 g

QuickTime™ and aTIFF (Uncompressed) decompressor

are needed to see this picture.