stoichiometry
DESCRIPTION
Stoichiometry. http://www.unit5.org/chemistry/Stoichiometry.html. 1 mol = molar mass. 1 mole = 22.4 L @ STP. 1 mol = 6.02 x 10 23 particles. Welcome to Mole Island. Stoichiometry Island Diagram. Known Unknown Substance A Substance B. M. - PowerPoint PPT PresentationTRANSCRIPT
Stoichiometry
http://www.unit5.org/chemistry/Stoichiometry.html
Welcome to Mole Island
1 mole = 22.4 L @ STP
1 mol = molar mass
1 mol = 6.02 x 1023 particles
Stoichiometry Island Diagram
Mass
Particles
Volume Mole Mole
Mass
Known UnknownSubstance A Substance B
Stoichiometry Island Diagram
Volume
Particles
M
V
P
Mass Mountain
Liter Lagoon
Particle Place
Mole Island
Stoichiometry Island Diagram
Mass
Particles
Volume Mole Mole
Mass
Volume
Particles
Known Unknown
Substance A Substance B
Stoichiometry Island Diagram
1 mole = molar mass (g) Use coefficientsfrom balanced
chemical equation1 mole = 22.4 L @ STP
1 mole =
6.022 x
1023 partic
les
(atoms o
r molecu
les)
1 mole = 22.4 L @ STP
1 mole = 6.022 x 10 23 particles
(atoms or molecules)
1 mole =
molar m
ass (g
)
(gases) (gases)
Stoichiometry Island Diagram
Mass
Particles
Volume Mole Mole
Mass
Known UnknownSubstance A Substance B
Stoichiometry Island Diagram
Volume
Particles
M
V
P
Mass Mountain
Liter Lagoon
Particle Place
?
Visualizing a Chemical Reaction
Na + Cl2 NaCl
___ mole Cl2 ___ mole NaCl___ mole Na
2
10 5 10
2
10 5 10
___ mole NaCl10
Visualizing a Chemical Reaction
Na + Cl2 NaCl
___ mole Cl2___ mole Na
2
10 5
2
Proportional Relationships
I have 5 eggs. How many cookies can I make?
3/4 c. brown sugar1 tsp vanilla extract2 eggs2 c. chocolate chipsMakes 5 dozen cookies.
2 1/4 c. flour1 tsp. baking soda1 tsp. salt1 c. butter3/4 c. sugar
5 eggs 5 doz.
2 eggs= 12.5 dozen cookies
Ratio of eggs to cookies
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150 cookies
Proportional Relationships
• StoichiometryStoichiometry– mass relationships between substances in a chemical
reaction– based on the mole ratio
• Mole RatioMole Ratio– indicated by coefficients in a balanced equation
2 Mg + O2 Mg + O22 2 MgO 2 MgO
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Stoichiometry Steps1. Write a balanced equation.2. Identify known & unknown.3. Line up conversion factors.
– Mole ratio - moles moles– Molar mass - moles grams– Molarity - moles liters soln– Molar volume - moles liters gas
Core step in all stoichiometry problems!!
– Mole ratio - moles moles
4. Check answer.Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
1 mol of a gas=22.4 Lat STP
Molar Volume at STP
Standard Temperature & Pressure0°C and 1 atm
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Molar Volume at STP
Molar Mass(g/mol)
6.02 1023
particles/mol
MASSIN
GRAMSMOLES
NUMBEROF
PARTICLES
LITERSOF
SOLUTION
Molar Volume (22.4 L/mol)
LITERSOF GASAT STP
Molarity (mol/L)
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How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas?
9 mol O2 2 mol KClO3
3 mol O2
= 6 mol KClO3
2KClO3 2KCl + 3O2 ? mol 9 mol
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O2 KClO3
x mol KClO3 = 9 mol O2 = 6 mol KClO3
2 mol KClO3
3 mol O26 mol
How many grams of KClO3 are required to
produce 9.00 L of O2 at STP?
? g 9.00 L
Stoichiometry Problems
2KClO3 2KCl + 3O2
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O2 KClO3
x g KClO3 = 9.00 L O2 22.4 L O2
= 32.8 g KClO3
1 mol O2 2 mol KClO3
3 mol O2
122.55 g KClO3
1 mol KClO3
32.8 g
How many grams of KClO3 are required to
produce 9.00 L of O2 at STP?
9.00 LO2
1 molO2
22.4 L O2
= 32.8 g KClO3
2 molKClO3
3 molO2
122.55g KClO3
1 molKClO3
? g 9.00 L2KClO3 2KCl + 3O2
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
O2 KClO3
x g KClO3 = 9.00 L O2 22.4 L O2
= 32.8 g KClO3
1 mol O2 2 mol KClO3
3 mol O2
122.55 g KClO3
1 mol KClO3
32.8 g
How many grams of silver will be formed from 12.0 g copper?
12.0g Cu
1 molCu
63.55g Cu
= 40.7 g Ag
Cu + 2 AgNO3 2 Ag + Cu(NO3)2
2 molAg
1 molCu
107.87g Ag
1 molAg
12.0 g ? g
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Cu Ag
x g Ag = 12.0 g Cu63.55 g Cu
= 40.7 g Ag1 mol Cu 2 mol Ag
1 mol Cu107.87 g Ag
1 mol Ag40.7 g
2 Na + Cl2 2 NaCl2 grams 1 gram 2 grams W R O N G
Violates Law of Conservation of Matter
2 atoms 1 molecule 2 molecules*
*Better name would be “formula unit”
2 moles 1 mole 2 moles
100 g x L x g
Na Cl2
x L Cl2 = 100 g Na23 g Na
= 49 L Cl21 mol Na 1 mol Cl2
2 mol Na22.4 L Cl21 mol Cl2
48.69 L
Right side of room…calculate how many grams of NaCl will be produced from 100 g of Na.
Left side of room…calculate how many grams of NaCl will be produced from 48.69 L of Cl2.
Na NaCl
x g NaCl = 100 g Na23 g Na
= 254 g NaCl1 mol Na 2 mol NaCl
2 mol Na58.5 g NaCl1 mol NaCl
Cl2 NaCl
x g NaCl = 48.69 L Cl2 22.4 L Cl2= 254 g NaCl
1 mol Cl2 2 mol NaCl1 mol Cl2
58.5 g NaCl1 mol NaCl
Stoichiometry
KClO3 KCl + O232 2500 g x g x L
KClO3 O2
x L O2 = 500 g KClO3 122.5 g KClO3
= 137 L O2
1 mol KClO3 3 mol O2
2 mol KClO3
22.4 L O2
1 mol O2
KClO3 KCl
x g KCl = 500 g KClO3 122.5 g KClO3
= 304 g KCl1 mol KClO3 2 mol KCl
2 mol KClO3
74.5 g KCl1 mol KCl
(304 g)
(196 g)
x g O2 = 137 L O2 22.4 L O2
= 196 g O2
1 mol O2 32 g O2
1 mol O2
137 L
Stoichiometry
2 TiO2 + 4 Cl2 + 3 C CO2 + 2 CO + 2 TiCl4
4.55 molx mol
C Cl2
x mol Cl2 = 4.55 mol C3 mol C
= 6.07 mol C4 mol Cl2
C TiO2
x molecules TiCl4 = 115 g TiO2 80 g TiO2
= 8.66x1023 molecules TiCl4
1 mol TiO2 2 mol TiCl42 mol TiO2
6.02x1023 molecules TiCl41 mol TiCl4
x g TiO2 = 4.55 mol C3 mol C
= 243 g TiO2
2 mol TiO2 80 g TiO2
1 mol TiO2
How many moles of chlorine will react with 4.55 moles of carbon?
How many grams of titanium (IV) oxide will react with 4.55 moles of carbon?
x g
How many molecules of TiCl4 will react with 115 g TiO2?
TiO2 TiCl4
x molecules115 g
6.02x1023 atoms H2O6.02x1023 molecules H2O
Which has more atoms: 30 g aluminum metal or 18 mL distilled water?
x atoms Al = 30 g Al27 g Al
= 6.69x1023 atoms Al1 mol Al 6.02x1023 atoms Al
1 mol Al
How many atoms of aluminum are in 30 g of aluminum?
Al
x atoms Al = 30 g Al27 g Al
= 6.69x1023 atoms Al6.02x1023 atoms Al
Al
x atoms = 18 mL H2O 1000 mL H2O
= 1.45x1021 atoms
1 L H2O 1 mol H2O22.4 L H2O
How many atoms are in 18 mL of water? H2O
x atoms = 18 mL H2O 1 mL H2O
= 1.81x1024 atoms
1 g H2O 1 mol H2O 18 g H2O
How many atoms are in 18 mL of water?
1 mol H2O3 atoms
1 molecule H2O
1 moL H2O6.02x1023 molecules H2O 3 atoms
1 molecule H2O
W R O N GW R O N G
Recall, density of water
LITERS is ONLY used for GASES @ STPLITERS is ONLY used for GASES @ STP