stoichiometry

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Stoichiometry

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Stoichiometry. Stoichiometry. Is the study of the relative quantities of reactants and products in chemical reactions  the mole ratio. How can you get to the moon?. You need ROCKET FUEL!. 2N 2 H 4 (l) + N 2 O 4 (l)  3N 2 (g) + 4H 2 O(g) + ENERGY - PowerPoint PPT Presentation

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Page 1: Stoichiometry

Stoichiometry

Page 2: Stoichiometry

Stoichiometry

•Is the study of the relative quantities of reactants and products in chemical reactions

the mole ratio

Page 3: Stoichiometry

How can you get to the moon?

You need ROCKET FUEL!

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

(hydrazine) (dinitrogen tetroxide)

If 1000 tonnes of N2O4 is to be used, how much N2H4 should be used?

Page 4: Stoichiometry

Ratios in Balanced Chemical Equations

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

This equation means:

2 molecules of N2H4 react with 1 molecules of N2O4

• 200 molecules of N2H4 react with ______ molecules of N2O4100

• 4 molecules of N2H4 react with ______ molecules of N2O42

• 16 million molecules of N2H4 react with _________ molecules of N2O48 million

OR 2 moles of N2H4 react with 1 mole of N2O4

Page 5: Stoichiometry

• The reactants and products in a balance chemical equation will always be related by ratios established by the coefficients in the equation.

Page 6: Stoichiometry

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

a.) How many moles of N2H4 are required to react with 8 moles of N2O4?

2 mols of N2H4 = x mols of N2H4 1 mols of N2O4 8 mols of N2O4

x mols of N2H4 X 1 mols of N2O4 = 2 mols of N2H4 X 8 mols ofN2O4

Cross multiply!

x mols of N2H4 = 16 mols of N2H4

x mols of N2H4 = 2 mols of N2H4 X 8 mols ofN2O4

1 mols of N2O4

Step 1: Check the equation is balanced

Step 2: Set up mole ratio 2 mols of N2H4

1 mols of N2O4

Step 3: set equal to given and unknown

Page 7: Stoichiometry

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

b.) How many moles of N2H4 are required to react with 17 moles of N2O4?

x mols of N2H4 = 2 mols of N2H4 17 mols of N2O4 1 mols of N2O4

x mols of N2H4 = 2 mols of N2H4 X 17 mols of N2O4

1 mols of N2O4

= 34 mols of N2H4

Page 8: Stoichiometry

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

c.) How many moles of N2H4 are required to react with 0.23 moles of N2O4?

x mols of N2H4 = 2 mols of N2H4 0.23 mols of N2O4 1 mols of N2O4

x mols of N2H4 = 2 mols of N2H4 X 0.23 mols of N2O4

1 mols of N2O4

= 0.46 mols of N2H4

Page 9: Stoichiometry

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

d.) How many moles of H2O are produced from 8 moles of N2H4?

x mols of H2O = 4 mols of H2O

8 mols of N2H4 2 mols of N2H4

x mols of H2O = 4 mols of H2O X 8 mols of N2H4

2 mols of N2H4

= 16 mols of H2O

Page 10: Stoichiometry

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

e.) How many moles of N2 are produced from 11 moles of N2O4?

x mols of N2 = 3 mols of N2

11 mols of N2O4 1 mols of N2O4

x mols of N2 = 3 mols of N2 X 11 mols of N2O4

1 mols of N2O4

= 33 mols of N2

Page 11: Stoichiometry

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

f.) If 0.55 moles of H2O are produced, How much N2H4 reacted?

x mols of N2H4 = 2 mols of N2H4

0.55 mols of H2O 4 mols of H2O

x mols of N2H4 = 2 mols of N2H4 X 0.55 mols of H2O

4 mols of H2O

= 0.28 mols of N2H4

Page 12: Stoichiometry

2N2H4 (l) + N2O4 (l) 3N2(g) + 4H2O(g) + ENERGY

g.) If 0.55 moles of H2O are produced, How much N2 is produced?

x mols of N2 = 3 mols of N2

0.55 mols of H2O 4 mols of H2O

x mols of N2 = 3 mols of N2 X 0.55 mols of H2O

4 mols of H2O

= 0.41 mols of N2

Page 13: Stoichiometry

Phosphorus can be combined with oxygen gas to form diphosphorus trioxide. How many molecules of diphosphorus trioxide can be made from 5 moles of phosphorus?

• Write out balanced chemical equation

4P(s) + 3O2(g) 2P2O3(s)

x mols of P2O3 = 2 mols of P2O3

5 mols of P 4 mols of P

x mols of P2O3 = 2 mols of P2O3 X 5 mols of P

4 mols of P

= 2.5 mols of P2O3

Molecules of P2O3 = 2.5 mols of P2O3 X 6.022 X 1023 molecules/mols of P2O3

= 1.5 x 1024 molecules of P2O3

Page 14: Stoichiometry

Assignment : Practice Problems pages 237-238 #1-7, page 240 #9, 10