std-7 sub-physics chapter 1...
TRANSCRIPT
Std-7 Sub-Physics
Chapter 1
MEASUREMENT
In this chapter you will learn
Volume and it’s unit
Vessels for measuring the volume of liquids
Measurement of volume of a liquid using
measuring cylinder and measuring beaker
Measuring the Volume of regular body
Measuring the Volume of irregular body
Area and measurement of area of regular and
irregular object
Density, it’s unit and relationship between
kg/m3 and g/cm 3
Determination of density of irregular Solid and
liquid
Introduction
Measurement is a process of comparison of unknown
quantity with a fixed known quantity of tye same kind
called the unit. The magnitude of the quantity is
expressed as,
Magnitude = Number of times the unit is contained in
the quantity × unit.
Length is the distance between two points. Its S.I.
unit is metre(symbol m). It is measured using a ruler
or a measuring tape.
Mass is the quantity of the matter contained in the
body. Its S.I. unit is kilogram(symbol kg). It is
measured using beam balance or electronic
balance.
Time is the interval of occurrence of an event. Its
S.I. unit is second(symbol s). It is measured with the
help of pendulum clock or a watch or for a short
time intervals we use stop clock or stop watch.
Temperature is a quantity which measure hotness
or coldness of a body. Its S.I. unit is kelvin(symbol)
k). Other unit are oC oF. It is measured using thermometer.
Measurement of Volume:
The space occupied by an object is called its volume.
This can be demonstrated by following activity.
S.I unit of volume:
The S.I. unit of volume is cubic metre. In short form, it is
written as m3.
One cubic metre is the volume of a cube of each side 1
metre as shown in figure below i.e., 1 m3 = 1 m × 1 m × 1
m.
Other units of volume:
• Other units of volume are units and mm3, where
1 cm3= 10-6 m3 and 1 mm3 = 10-9 m3.
• The volume of liquids is expressed in litre which is
denoted by symbol (l) and milli litre (ml).
• 1 L= 10-3 m3 = 1000cm3 and 1mL = 1 cm3
• The volume of an irregular solid is found by the
method of displacement of a liquid using a measuring
cylinder.
Relation between m3 and cm 3:
100 cm = 1 m
A cubic meter is a cube 1 meter wide, 1 meter deep and
1 meter tall.
1 m3 = 1 m x 1 m x 1 m
Substitute the conversion factor for meter to centimetre
1 m3 = (100 cm) x (100 cm) x (100 cm)
1 m3 = 1,000,000 cm3 = 106 cm3
The volume of liquid is measured generally in litre (L)
1000cm3 make one litre i.e.
1 litre= 1000cm3
Hence 1cm3= 10-3litre = 1 millilitre
Thus, 1 m3 = 1,000,000 cm3 = 106 cm3
1L= 1000 m3 = 1000mL
1mL = 1 m3 ( or 10-6 m3)
Vessels for measuring the volume of liquids
1) Measuring cylinder
It is a cylinder of generally area of cross section
of 10 cm2, made up of either glass or plastic. It
is length nearly 10cm graduated in cm3 or mL
with its zero mark at bottom and 100 marks at
the top. Thus, it is of capacity 100 cm3 (or 100
mL) as shown in figure.
The following figure(below) shows the other
kind of measuring cylinder which is used by
pharmacists to measure liquid medicines.
2) Measuring beaker:
A measuring beaker is generally used to measure
fixed volume of liquid such as milk, oil, lubricating
oil etc. Thus, they are available in different
capacities such as 50mL, 100mL, 200mL, 500mL,
1000mL. The capacity of beaker is marked on it.
Measurement of volume of a liquid
1) By using measuring cylinder
For this proceed as follow-
i) Take a measuring cylinder. wash it with water
and dry it.
ii) Place the measuring cylinder on a flate surface
and then pour the given liquid completely into
measuring cylinder gently so that no liquid
splashes out of the cylinder.
iii) Wait for some time till the liquid becomes
stationary in the cylinder. You will notice that
the meniscus(upper surface) of the liquid is
curved when the liquid becomes stationary.
iv) Read the level of the liquid in the measuring
cylinder by your eye horizontally in line with
lower surface of water as shown in the figure. In
the figure the reading is 70mL.
2) By using Measuring beaker
A measuring beaker is used to measure fixed volume of
liquid from a large volume. Suppose it required to
measure 500mL of milk from the milk contained in a
bucket.
For this, take the measuring beaker of capacity 500mL.
Wash it and dry it.
Then immerse the beaker well inside the milk contained
in the bucket so that the beaker gets filled completely
with the milk.
Take out the measuring beaker from the bucket gently so
that no milk splashes out and then pour the milk from
the from the measuring beaker into another vessel.
Measuring the Volume of regular body:
The following relations are applicable-
Volume of a cuboid (V)= length(l) × breadth (b) ×
height(h)
Volume of a cube (V)= (length)3
Volume of sphere (V)= 4/3 π × (radius)3
Volume of cylinder (V)=π × (radius) × height (h)
Volume of cone (V)=π/3 × (radius)2 × height (h)
Where π = 3.14 or 22/7
Measuring the Volume of Irregular body
The volume of a solid of irregular shape can be
measured by using measuring cylinder by the method of
displacement of liquid . This method is based on the fact
that the volume of an irregular solid is equal to the
volume of water displaced by it when it is immersed in
water. When we immerse an irregular body in water, it
displaces some amount of water. The volume of
displaced water is equal to the volume of an irregular
body that displace water.
Volume of a body of irregular shape = volume of liquid
displaced by the body when it is completely immersed
into the liquid.
This method can be used to calculate the volume of
those irregular bodies which sink in water and do not
dissolve in water.
Activity: To measure the volume of a piece of stone.
Materials Required: Measuring cylinder, water, thread, a
piece of brick
Procedure-
At first, fill the measuring cylinder partially with water.
Note down the level of the water. Let it be the initial
level of water, V1. While recording the level of water,
keep the eye in the level with the bottom of the
meniscus to avoid parallax error. After this, tie the piece
of stone with the help of thread and immerse it into the
water of measuring cylinder. We can see that, the level
of water rises. Then, note down the new level of water
carefully. Let it be the final reading, V2.
Observation
Suppose V1 is 50 ml and V2 is 75 ml.
Now,
Initial volume of water in the cylinder (V1)= 50 ml
Final volume of water in the cylinder (V2)= 75 ml
∴ Volume of the water displaced (V)=V2 -V1
= 75ml - 50ml
= 25ml
∴ Volume of the Stone= Volume of water displaced
= 25ml
Area
The total space occupied by the plane surface of the
object is known as the area of that object. The SI unit of
area is the square metre (m2). Other similar units of area
are mm2, cm2, km2, etc.
1 are= 102 m2
1 hectare= 104 m2
1 km2 = 106 m2
1 cm2 = 10-4 m2
1 mm2 = 10-6 m2
Measurement of area of regular object
There are various formulae used for the measurement of
the area of the regular plane surface. Some of them are
given below,
Area of a rectangular object (A) = length(l) × breadth(b)
∴ A= l × b
Area of a circle (A)=π×(radius)2[ π = 22/7 ]
∴ A=πr2
Area of a square (A)= (side)2
Surface area of cylinder= 2 π×(radius) ×(length)
Surface area of sphere= 4 π×(radius)2
Where π = 3.14 or 22/7.
Measurement of area of irregular object
Describe the method in steps to find the area of an
irregular lamina using a graph paper.
Graph paper : It is a sheet of paper on which horizontal
and vertical lines are ruled at regular interval of 1mm.
Area of one big square is 1 cm × 1cm = 1 cm2
Procedure : First, place the lamina over a graph paper
and draw its boundary line on the graph paper with a
pencil. remove the lamina and count and note the
number of complete squares as well as the number of
squares more than half within the boundary line (only
the squares less than half, are left while counting). The
area of lamina is equal to the sum of the area of
complete squares and the area of squares more than
half. Let n be the total number of complete and more
than half or half squares within the boundary of lamina.
Since area of one big square is 1 cm × 1cm = 1 cm2, so
the area of lamina will be n x 1cm2 or n cm2.
Density
Each body has certain mass and a definite volume.
Experimentally it is observed that
1) Equal masses of different substance have
different volume 1kg of iron and 1 kg of cotton
will have different volume and
2) Equal volume of different substance have
different masses e.g. cubes of iron and wood(1
cm × 1cm × 1cm) will weigh differently.
Definition of density
Density is defined as its mass per unit volume. It is,
essentially, a measurement of how tightly matter is
crammed together.
The symbol for density is the Greek letter ρ (called rho).
The formula for density is ρ = M/V, where ρ is density, M
is mass, and V is volume.
For better understanding-
https://youtu.be/SimFy9wOMXY
Unit of density
The SI unit of density is kilogram per cubic meter (kg/m3).
It is also frequently represented in the C.G.S. unit of
grams per cubic centimetre (g/cm3).
The relationship between S.I. and C.G.S. units
The SI unit of density is kg/m3.
The CGS unit of density is g/cm3.
Conversion from C.G.S. to S.I.
In C.G.S. unit of density = g/cm3
= 10-3kg/10-6 m3
Relationship between kg/m3 and g/cm 3
Determination of density of regular solids
The density of the solid can be determined using the
formula D = M/V.
We proceed as follows:
1) Using beam balance, measure the mass M of the
solid.
2) Using the metre ruler, measure length, breadth and
height of the regular solid and find the volume using
the relation V = length(l) × breadth (b) × height(h)
Determination of density of irregular solid
To find the density of a solid, its mass and volume are
required. The mass (M) of the solid is determined using a
physical balance. To find the volume of the solid, a
measuring cylinder with a fixed volume of water is taken
and the volume of water is noted. Let the volume of
water be V1. The solid is tied to a string and is lowered
into the measuring cylinder such that it is completely
immersed in water. The new level of water (V2) is noted.
The difference in the levels of water V = V2 – V1 gives
the volume of the solid. Knowing the mass and volume of
the solid, the density of the solid can be determined
using the formula D = M/V.
Determination of a density of a liquid:
To determine the density of solid follow the procedure
below:
1) Take a beaker. Measure the mass of empty beaker
using a common beam balance. Let the mass be
M1 gram.
2) Now take a measuring cylinder and pour milk into
to a certain level say 50mL.Thus, volume of milk,
V=50 cm3
3) Transfer the milk into empty beaker. Measure its
mass again, lets its mass be M2 gram.
4) The difference between M1 and M2 will give the
mass M of the milk. This mass of the milk M= (M2-
M1) gram. Let M=51.5 gram.
5) Calculate the density of milk using the formula:
D = M/V.
= 51.5/50 = 1.03 g/cm3
Densities of some common substances
Speed
Speed is the rate of change of position of an object with
time. The average speed of an object in an interval of
time is the distance travelled by the object divided by the
duration of the interval Hence,
Units of speed:
In S.I. system distance is measured as metre and time is
measured as second, so the S.I. unit of speed is metre
per second and sometimes it is measured in kilometre
per hour.
Relationship between km h-1 and ms-1
1 km = 1000m
1 h = 3600 s
So 1km/h = 1000/3600
or 1km/h = 1/3.6 ms-1
or 3.6 km/h = 1 ms-1
Table below gives approximate speed of some common objects
For better understanding of whole chapter:
https://youtu.be/z5LAyppdzM8
To refer textbook go through the
following pictures: