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Jan has 90% probability to eat breakfast and Dave has a 30% probability to eat breakfast. What’s the probability that either Jennifer or David (not both of them) eats breakfast tomorrow morning? 90% × (1 − 30%) + (1 − 90%) × 30% = 66% Avg:$3301 Median:3,466 sd: 1,297 monthly Find the 95% Confidence Interval for monthly salary: 3301 ± 2 × 1297 Find the probability for a monthly salary btwn $3,301 and $5,895. If a BBA student decides to accept an intern offer immediately if salary that is among the top 16% of all accepted intern offers, what would be the least amount of monthly salary that will make him/her accept the offer immediately? If you take a random sample of 16 BBA interns would the distribution of salary be the same as the distribution of the monthly salary of a BBA intern?

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Jan has 90% probability to eat breakfast and Dave has a 30% probability to eat breakfast.Whats the probability that either Jennifer or David (not both of them) eats breakfast tomorrow morning?90% (1 30%) + (1 90%) 30% = 66%

Avg:$3301 Median:3,466 sd: 1,297 monthlyFind the 95% Confidence Interval for monthly salary: 3301 2 1297Find the probability for a monthly salary btwn $3,301 and $5,895.

If a BBA student decides to accept an intern offer immediately if salary that is among the top 16% of all accepted intern offers, what would be the least amount of monthly salary that will make him/her accept the offer immediately?

If you take a random sample of 16 BBA interns would the distribution of salary be the same as the distribution of the monthly salary of a BBAintern?

Regression = Total - ResidualR square = Regression/TotalChoose b0 and b1 to minimize Residual or Standard Error