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Other experimental designs Randomized Block design Latin Square design Repeated Measures design

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Page 1: Stats 845 Lecture 14n

Other experimental designs

Randomized Block design

Latin Square design

Repeated Measures design

Page 2: Stats 845 Lecture 14n

The Randomized Block Design

Page 3: Stats 845 Lecture 14n

• Suppose a researcher is interested in how several treatments affect a continuous response variable (Y).

• The treatments may be the levels of a single factor or they may be the combinations of levels of several factors.

• Suppose we have available to us a total of N = nt experimental units to which we are going to apply the different treatments.

Page 4: Stats 845 Lecture 14n

The Completely Randomized (CR) design randomly divides the experimental units into t groups of size n and randomly assigns a treatment to each group.

Page 5: Stats 845 Lecture 14n

The Randomized Block Design

• divides the group of experimental units into n homogeneous groups of size t.

• These homogeneous groups are called blocks.

• The treatments are then randomly assigned to the experimental units in each block - one treatment to a unit in each block.

Page 6: Stats 845 Lecture 14n

The ANOVA table for the Completely Randomized Design

Source df Sum of Squares

Treatments t - 1 SSTr

Error t(n – 1) SSError

Total tn - 1 SSTotal

Source df Sum of Squares

Blocks n - 1 SSBlocks

Treatments t - 1 SSTr

Error (t – 1) (n – 1) SSError

Total tn - 1 SSTotal

The ANOVA table for the Randomized Block Design

( )CRij i ijy

( )RBij i j ijy

Page 7: Stats 845 Lecture 14n

Comments

The ability to detect treatment differences depends on the magnitude of the random error term

( )CRij

( )RBij

The error term, , for the Completely Randomized Design models variability in the reponse, y, between experimental units

The error term, , for the Completely Block Design models variability in the reponse, y, between experimental units in the same block (hopefully the is considerably smaller than .( )CR

ij

Page 8: Stats 845 Lecture 14n

Example – Weight gain, diet, source of protein, level of protein(Completely randomized design)

Page 9: Stats 845 Lecture 14n

Block Block 1 107 96 112 83 87 90 6 128 89 104 85 84 89 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

2 102 72 100 82 70 94 7 56 70 72 64 62 63 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

3 102 76 102 85 95 86 8 97 91 92 80 72 82 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

4 93 70 93 63 71 63 9 80 63 87 82 81 63 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

5 111 79 101 72 75 81 10 103 102 112 83 93 81 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

Randomized Block Design

Page 10: Stats 845 Lecture 14n

The Anova Table for Diet Experiment

Source S.S d.f. M.S. F p-valueBlock 5992.4167 9 665.82407 9.52 0.00000Diet 4572.8833 5 914.57667 13.076659 0.00000

ERROR 3147.2833 45 69.93963

Page 11: Stats 845 Lecture 14n

Example 1:

• Suppose we are interested in how weight gain (Y) in rats is affected by Source of protein (Beef, Cereal, and Pork) and by Level of Protein (High or Low).

• There are a total of t = 32 = 6 treatment combinations of the two factors (Beef -High Protein, Cereal-High Protein, Pork-High Protein, Beef -Low Protein, Cereal-Low Protein, and Pork-Low Protein) .

Page 12: Stats 845 Lecture 14n

• Suppose we have available to us a total of N = 60 experimental rats to which we are going to apply the different diets based on the t = 6 treatment combinations.

• Prior to the experimentation the rats were divided into n = 10 homogeneous groups of size 6.

• The grouping was based on factors that had previously been ignored (Example - Initial weight size, appetite size etc.)

• Within each of the 10 blocks a rat is randomly assigned a treatment combination (diet).

Page 13: Stats 845 Lecture 14n

• The weight gain after a fixed period is measured for each of the test animals and is tabulated on the next slide:

Page 14: Stats 845 Lecture 14n

Block Block 1 107 96 112 83 87 90 6 128 89 104 85 84 89 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

2 102 72 100 82 70 94 7 56 70 72 64 62 63 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

3 102 76 102 85 95 86 8 97 91 92 80 72 82 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

4 93 70 93 63 71 63 9 80 63 87 82 81 63 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

5 111 79 101 72 75 81 10 103 102 112 83 93 81 (1) (2) (3) (4) (5) (6) (1) (2) (3) (4) (5) (6)

Randomized Block Design

Page 15: Stats 845 Lecture 14n

Example 2:

• The following experiment is interested in comparing the effect four different chemicals (A, B, C and D) in producing water resistance (y) in textiles.

• A strip of material, randomly selected from each bolt, is cut into four pieces (samples) the pieces are randomly assigned to receive one of the four chemical treatments.

Page 16: Stats 845 Lecture 14n

• This process is replicated three times producing a Randomized Block (RB) design.

• Moisture resistance (y) were measured for each of the samples. (Low readings indicate low moisture penetration).

• The data is given in the diagram and table on the next slide.

Page 17: Stats 845 Lecture 14n

Diagram: Blocks (Bolt Samples)

9.9 C 13.4 D 12.7 B 10.1 A 12.9 B 12.9 D 11.4 B 12.2 A 11.4 C 12.1 D 12.3 C 11.9 A

Page 18: Stats 845 Lecture 14n

Table

Blocks (Bolt Samples)

Chemical 1 2 3

A 10.1 12.2 11.9

B 11.4 12.9 12.7

C 9.9 12.3 11.4

D 12.1 13.4 12.9

Page 19: Stats 845 Lecture 14n

The Model for a randomized Block Experiment

ijjiijy

i = 1,2,…, t j = 1,2,…, b

yij = the observation in the jth block receiving the ith treatment

= overall mean

i = the effect of the ith treatment

j = the effect of the jth Block

ij = random error

Page 20: Stats 845 Lecture 14n

The Anova Table for a randomized Block Experiment

Source S.S. d.f. M.S. F p-value

Treat SST t-1 MST MST /MSE

Block SSB n-1 MSB MSB /MSE

Error SSE (t-1)(b-1) MSE

Page 21: Stats 845 Lecture 14n

• A randomized block experiment is assumed to be a two-factor experiment.

• The factors are blocks and treatments.

• The is one observation per cell. It is assumed that there is no interaction between blocks and treatments.

• The degrees of freedom for the interaction is used to estimate error.

Page 22: Stats 845 Lecture 14n

The Anova Table for Diet Experiment

Source S.S d.f. M.S. F p-valueBlock 5992.4167 9 665.82407 9.52 0.00000Diet 4572.8833 5 914.57667 13.076659 0.00000

ERROR 3147.2833 45 69.93963

Page 23: Stats 845 Lecture 14n

The Anova Table forTextile Experiment

SOURCE SUM OF SQUARES D.F. MEAN SQUARE F TAIL PROB.Blocks 7.17167 2 3.5858 40.21 0.0003Chem 5.20000 3 1.7333 19.44 0.0017

ERROR 0.53500 6 0.0892

Page 24: Stats 845 Lecture 14n

• If the treatments are defined in terms of two or more factors, the treatment Sum of Squares can be split (partitioned) into:

– Main Effects

– Interactions

Page 25: Stats 845 Lecture 14n

The Anova Table for Diet Experiment terms for the main effects and interactions between Level of Protein and Source of Protein

Source S.S d.f. M.S. F p-valueBlock 5992.4167 9 665.82407 9.52 0.00000Diet 4572.8833 5 914.57667 13.076659 0.00000

ERROR 3147.2833 45 69.93963

Source S.S d.f. M.S. F p-valueBlock 5992.4167 9 665.82407 9.52 0.00000

Source 882.23333 2 441.11667 6.31 0.00380Level 2680.0167 1 2680.0167 38.32 0.00000

SL 1010.6333 2 505.31667 7.23 0.00190ERROR 3147.2833 45 69.93963

Page 26: Stats 845 Lecture 14n

Using SPSS to analyze a randomized Block Design

• Treat the experiment as a two-factor experiment– Blocks– Treatments

• Omit the interaction from the analysis. It will be treated as the Error term.

Page 27: Stats 845 Lecture 14n

The data in an SPSS file

Variables are in columns

Page 28: Stats 845 Lecture 14n

Select General Linear Model->Univariate

Page 29: Stats 845 Lecture 14n

Select the dependent variable, the Block factor, the Treatment factor.

Select Model.

Page 30: Stats 845 Lecture 14n

Select a Custom model.

Page 31: Stats 845 Lecture 14n

Put in the model only the main effects.

Page 32: Stats 845 Lecture 14n

Tests of Between-Subjects Effects

Dependent Variable: WTGAIN

10564.033a 14 754.574 10.834 .000

437418.8 1 437418.8 6280.442 .000

4594.683 5 918.937 13.194 .000

5969.350 9 663.261 9.523 .000

3134.150 45 69.648

451117.0 60

13698.183 59

SourceCorrected Model

Intercept

DIET

BLOCK

Error

Total

Corrected Total

Type IIISum of

Squares dfMean

Square F Sig.

R Squared = .771 (Adjusted R Squared = .700)a.

Obtain the ANOVA table

If I want to break apart the Diet SS into components representing Source of Protein (2 df), Level of Protein (1 df), and Source Level interaction (2 df) - follow the subsequent steps

Page 33: Stats 845 Lecture 14n

Replace the Diet factor by the Source and level factors (The two factors that define diet)

Page 34: Stats 845 Lecture 14n

Specify the model. There is no interaction between Blocks and the diet factors (Source and Level)

Page 35: Stats 845 Lecture 14n

Tests of Between-Subjects Effects

Dependent Variable: WTGAIN

10564.033a 14 754.574 10.834 .000

437418.8 1 437418.8 6280.442 .000

5969.350 9 663.261 9.523 .000

904.033 2 452.017 6.490 .003

2680.017 1 2680.017 38.480 .000

1010.633 2 505.317 7.255 .002

3134.150 45 69.648

451117.0 60

13698.183 59

SourceCorrected Model

Intercept

BLOCK

SOURCE

LEVEL

SOURCE * LEVEL

Error

Total

Corrected Total

Type IIISum of

Squares dfMean

Square F Sig.

R Squared = .771 (Adjusted R Squared = .700)a.

Obtain the ANOVA table

Page 36: Stats 845 Lecture 14n

Repeated Measures Designs

Page 37: Stats 845 Lecture 14n

In a Repeated Measures Design

We have experimental units that• may be grouped according to one or several

factors (the grouping factors)Then on each experimental unit we have• not a single measurement but a group of

measurements (the repeated measures)• The repeated measures may be taken at

combinations of levels of one or several factors (The repeated measures factors)

Page 38: Stats 845 Lecture 14n

Example In the following study the experimenter was interested in how the level of a certain enzyme changed in cardiac patients after open heart surgery.

The enzyme was measured

• immediately after surgery (Day 0),

• one day (Day 1),

• two days (Day 2) and

• one week (Day 7) after surgery

for n = 15 cardiac surgical patients.

Page 39: Stats 845 Lecture 14n

The data is given in the table below.

Subject Day 0 Day 1 Day 2 Day 7 Subject Day 0 Day 1 Day 2 Day 7 1 108 63 45 42 9 106 65 49 49 2 112 75 56 52 10 110 70 46 47 3 114 75 51 46 11 120 85 60 62 4 129 87 69 69 12 118 78 51 56 5 115 71 52 54 13 110 65 46 47 6 122 80 68 68 14 132 92 73 63 7 105 71 52 54 15 127 90 73 68 8 117 77 54 61

Table: The enzyme levels -immediately after surgery (Day 0), one day (Day 1),two days (Day 2) and one week (Day 7)

after surgery

Page 40: Stats 845 Lecture 14n

• The subjects are not grouped (single group).

• There is one repeated measures factor -Time – with levels– Day 0, – Day 1, – Day 2, – Day 7

• This design is the same as a randomized block design with – Blocks = subjects

Page 41: Stats 845 Lecture 14n

The Anova Table for Enzyme Experiment

Source SS df MS F p-valueSubject 4221.100 14 301.507 32.45 0.0000Day 36282.267 3 12094.089 1301.66 0.0000ERROR 390.233 42 9.291

The Subject Source of variability is modelling the variability between subjects

The ERROR Source of variability is modelling the variability within subjects

Page 42: Stats 845 Lecture 14n

Analysis Using SPSS- the data file

The repeated measures are in columns

Page 43: Stats 845 Lecture 14n

Select General Linear model -> Repeated Measures

Page 44: Stats 845 Lecture 14n

Specify the repeated measures factors and the number of levels

Page 45: Stats 845 Lecture 14n

Specify the variables that represent the levels of the repeated measures factor

There is no Between subject factor in this example

Page 46: Stats 845 Lecture 14n

The ANOVA table

Tests of Within-Subjects Effects

Measure: MEASURE_1

36282.267 3 12094.089 1301.662 .000

36282.267 2.588 14021.994 1301.662 .000

36282.267 3.000 12094.089 1301.662 .000

36282.267 1.000 36282.267 1301.662 .000

390.233 42 9.291

390.233 36.225 10.772

390.233 42.000 9.291

390.233 14.000 27.874

Sphericity Assumed

Greenhouse-Geisser

Huynh-Feldt

Lower-bound

Sphericity Assumed

Greenhouse-Geisser

Huynh-Feldt

Lower-bound

SourceTIME

Error(TIME)

Type IIISum of

Squares dfMean

Square F Sig.

Page 47: Stats 845 Lecture 14n

Example :

(Repeated Measures Design - Grouping Factor)

• In the following study, similar to example 3, the experimenter was interested in how the level of a certain enzyme changed in cardiac patients after open heart surgery.

• In addition the experimenter was interested in how two drug treatments (A and B) would also effect the level of the enzyme.

Page 48: Stats 845 Lecture 14n

• The 24 patients were randomly divided into three groups of n= 8 patients.

• The first group of patients were left untreated as a control group while

• the second and third group were given drug treatments A and B respectively.

• Again the enzyme was measured immediately after surgery (Day 0), one day (Day 1), two days (Day 2) and one week (Day 7) after surgery for each of the cardiac surgical patients in the study.

Page 49: Stats 845 Lecture 14n

Table: The enzyme levels - immediately after surgery (Day 0), one day (Day 1),two days (Day 2) and one week (Day 7)

after surgery for three treatment groups (control, Drug A, Drug B)

Group Control Drug A Drug B Day Day Day

0 1 2 7 0 1 2 7 0 1 2 7 122 87 68 58 93 56 36 37 86 46 30 31 112 75 55 48 78 51 33 34 100 67 50 50 129 80 66 64 109 73 58 49 122 97 80 72 115 71 54 52 104 75 57 60 101 58 45 43 126 89 70 71 108 71 57 65 112 78 67 66 118 81 62 60 116 76 58 58 106 74 54 54 115 73 56 49 108 64 54 47 90 59 43 38 112 67 53 44 110 80 63 62 110 76 64 58

Page 50: Stats 845 Lecture 14n

• The subjects are grouped by treatment– control, – Drug A, – Drug B

• There is one repeated measures factor -Time – with levels– Day 0, – Day 1, – Day 2, – Day 7

Page 51: Stats 845 Lecture 14n

The Anova Table

There are two sources of Error in a repeated measures design:

The between subject error – Error1 and

the within subject error – Error2

Source SS df MS F p-value

Drug 1745.396 2 872.698 1.78 0.1929

Error1

10287.844 21 489.897Time 47067.031 3 15689.010 1479.58 0.0000Time x Drug 357.688 6 59.615 5.62 0.0001

Error2

668.031 63 10.604

Page 52: Stats 845 Lecture 14n

Tables of means

Drug Day 0 Day 1 Day 2 Day 7 Overall

Control 118.63 77.88 60.50 55.75 78.19

A 103.25 68.25 52.00 51.50 68.75

B 103.38 69.38 54.13 51.50 69.59

Overall 108.42 71.83 55.54 52.92 72.18

Page 53: Stats 845 Lecture 14n

Time Profiles of Enzyme Levels

40

60

80

100

120

0 1 2 3 4 5 6 7Day

Enz

yme

Lev

el

Control

Drug A

Drug B

Page 54: Stats 845 Lecture 14n

Example : Repeated Measures Design - Two Grouping Factors

• In the following example , the researcher was interested in how the levels of Anxiety (high and low) and Tension (none and high) affected error rates in performing a specified task.

• In addition the researcher was interested in how the error rates also changed over time.

• Four groups of three subjects diagnosed in the four Anxiety-Tension categories were asked to perform the task at four different times patients in the study.

Page 55: Stats 845 Lecture 14n

The number of errors committed at each instance is tabulated below.

Anxiety Low High

Tension None High None High

subject subject subject subject 1 2 3 1 2 3 1 2 3 1 2 3

18 19 14 16 12 18 16 18 16 19 16 16 14 12 10 12 8 10 10 8 12 16 14 12 12 8 6 10 6 5 8 4 6 10 10 8 6 4 2 4 2 1 4 1 2 8 9 8

Page 56: Stats 845 Lecture 14n

The Anova Table

Source SS df MS F p-value

Anxiety 10.08333 1 10.08333 0.98 0.3517Tension 8.33333 1 8.33333 0.81 0.3949

AT 80.08333 1 80.08333 7.77 0.0237

Error1

82.85 8 10.3125

B 991.5 3 330.5 152.05 0BA 8.41667 3 2.80556 1.29 0.3003BT 12.16667 3 4.05556 1.87 0.1624

BAT 12.75 3 4.25 1.96 0.1477

Error2

52.16667 24 2.17361

Page 57: Stats 845 Lecture 14n

Latin Square Designs

Page 58: Stats 845 Lecture 14n

Latin Square Designs Selected Latin Squares

3 x 3 4 x 4A B C A B C D A B C D A B C D A B C DB C A B A D C B C D A B D A C B A D CC A B C D B A C D A B C A D B C D A B

D C A B D A B C D C B A D C B A 

5 x 5 6 x 6A B C D E A B C D E FB A E C D B F D C A EC D A E B C D E F B AD E B A C D A F E C BE C D B A E C A B F D

F E B A D C

Page 59: Stats 845 Lecture 14n

A Latin Square

Page 60: Stats 845 Lecture 14n

Definition

• A Latin square is a square array of objects (letters A, B, C, …) such that each object appears once and only once in each row and each column. Example - 4 x 4 Latin Square.

A B C DB C D AC D A BD A B C

 

Page 61: Stats 845 Lecture 14n

In a Latin square You have three factors:

• Treatments (t) (letters A, B, C, …)

• Rows (t)

• Columns (t)

The number of treatments = the number of rows = the number of colums = t.The row-column treatments are represented by cells in a t x t array.The treatments are assigned to row-column combinations using a Latin-square arrangement

 

Page 62: Stats 845 Lecture 14n

Example

A courier company is interested in deciding between five brands (D,P,F,C and R) of car for its next purchase of fleet cars.

• The brands are all comparable in purchase price. • The company wants to carry out a study that will

enable them to compare the brands with respect to operating costs.

• For this purpose they select five drivers (Rows). • In addition the study will be carried out over a

five week period (Columns = weeks).

Page 63: Stats 845 Lecture 14n

• Each week a driver is assigned to a car using randomization and a Latin Square Design.

• The average cost per mile is recorded at the end of each week and is tabulated below:

Week 1 2 3 4 5 1 5.83 6.22 7.67 9.43 6.57 D P F C R 2 4.80 7.56 10.34 5.82 9.86 P D C R F

Drivers 3 7.43 11.29 7.01 10.48 9.27 F C R D P 4 6.60 9.54 11.11 10.84 15.05 R F D P C 5 11.24 6.34 11.30 12.58 16.04 C R P F D

Page 64: Stats 845 Lecture 14n

The Model for a Latin Experiment

kijjikkijy

i = 1,2,…, t j = 1,2,…, t

yij(k) = the observation in ith row and the jth column receiving the kth treatment

= overall mean

k = the effect of the ith treatmenti = the effect of the ith row

ij(k) = random error

k = 1,2,…, t

j = the effect of the jth column

No interaction between rows, columns and treatments

Page 65: Stats 845 Lecture 14n

• A Latin Square experiment is assumed to be a three-factor experiment.

• The factors are rows, columns and treatments.

• It is assumed that there is no interaction between rows, columns and treatments.

• The degrees of freedom for the interactions is used to estimate error.

Page 66: Stats 845 Lecture 14n

The Anova Table for a Latin Square Experiment

Source S.S. d.f. M.S. F p-value

Treat SSTr t-1 MSTr MSTr /MSE

Rows SSRow t-1 MSRow MSRow /MSE

Cols SSCol t-1 MSCol MSCol /MSE

Error SSE (t-1)(t-2) MSE

Total SST t2 - 1

Page 67: Stats 845 Lecture 14n

The Anova Table for Example

Source S.S. d.f. M.S. F p-value

Week 51.17887 4 12.79472 16.06 0.0001

Driver 69.44663 4 17.36166 21.79 0.0000

Car 70.90402 4 17.72601 22.24 0.0000

Error 9.56315 12 0.79693

Total 201.09267 24

Page 68: Stats 845 Lecture 14n

Example

In this Experiment the we are again interested in how weight gain (Y) in rats is affected by Source of protein (Beef, Cereal, and Pork) and by Level of Protein (High or Low).

There are a total of t = 3 X 2 = 6 treatment combinations of the two factors.

• Beef -High Protein• Cereal-High Protein• Pork-High Protein• Beef -Low Protein• Cereal-Low Protein and • Pork-Low Protein

Page 69: Stats 845 Lecture 14n

In this example we will consider using a Latin Square design

Six Initial Weight categories are identified for the test animals in addition to Six Appetite categories.

• A test animal is then selected from each of the 6 X 6 = 36 combinations of Initial Weight and Appetite categories.

• A Latin square is then used to assign the 6 diets to the 36 test animals in the study.

Page 70: Stats 845 Lecture 14n

In the latin square the letter

• A represents the high protein-cereal diet• B represents the high protein-pork diet• C represents the low protein-beef Diet• D represents the low protein-cereal diet• E represents the low protein-pork diet and • F represents the high protein-beef diet.

Page 71: Stats 845 Lecture 14n

The weight gain after a fixed period is measured for each of the test animals and is tabulated below:

Appetite Category 1 2 3 4 5 6 1 62.1 84.3 61.5 66.3 73.0 104.7 A B C D E F 2 86.2 91.9 69.2 64.5 80.8 83.9 B F D C A E

Initial 3 63.9 71.1 69.6 90.4 100.7 93.2 Weight C D E F B A

Category 4 68.9 77.2 97.3 72.1 81.7 114.7 D A F E C B 5 73.8 73.3 78.6 101.9 111.5 95.3 E C A B F D 6 101.8 83.8 110.6 87.9 93.5 103.8 F E B A D C

Page 72: Stats 845 Lecture 14n

The Anova Table for Example

Source S.S. d.f. M.S. F p-value

Inwt 1767.0836 5 353.41673 111.1 0.0000

App 2195.4331 5 439.08662 138.03 0.0000

Diet 4183.9132 5 836.78263 263.06 0.0000

Error 63.61999 20 3.181

Total 8210.0499 35

Page 73: Stats 845 Lecture 14n

Diet SS partioned into main effects for Source and Level of Protein

Source S.S. d.f. M.S. F p-value

Inwt 1767.0836 5 353.41673 111.1 0.0000

App 2195.4331 5 439.08662 138.03 0.0000

Source 631.22173 2 315.61087 99.22 0.0000

Level 2611.2097 1 2611.2097 820.88 0.0000

SL 941.48172 2 470.74086 147.99 0.0000

Error 63.61999 20 3.181

Total 8210.0499 35

Page 74: Stats 845 Lecture 14n

Graeco-Latin Square Designs

Mutually orthogonal Squares

Page 75: Stats 845 Lecture 14n

DefinitionA Greaco-Latin square consists of two latin squares (one using the letters A, B, C, … the other using greek letters , , , …) such that when the two latin square are supper imposed on each other the letters of one square appear once and only once with the letters of the other square. The two Latin squares are called mutually orthogonal.Example: a 7 x 7 Greaco-Latin Square

A B C D E F GB C D E F G A

C D E F G A BD E F G A B CE F G A B C DF G A B C D EG A B C D E F

Page 76: Stats 845 Lecture 14n

Note:

At most (t –1) t x t Latin squares L1, L2, …, Lt-1 such that any pair are mutually orthogonal.

It is possible that there exists a set of six 7 x 7 mutually orthogonal Latin squares L1, L2, L3, L4, L5, L6 .

Page 77: Stats 845 Lecture 14n

The Greaco-Latin Square Design - An Example

A researcher is interested in determining the effect of two factors

• the percentage of Lysine in the diet and • percentage of Protein in the diet

have on Milk Production in cows.

Previous similar experiments suggest that interaction between the two factors is negligible.

Page 78: Stats 845 Lecture 14n

For this reason it is decided to use a Greaco-Latin square design to experimentally determine the two effects of the two factors (Lysine and Protein).

Seven levels of each factor is selected• 0.0(A), 0.1(B), 0.2(C), 0.3(D), 0.4(E), 0.5(F), and

0.6(G)% for Lysine and • 2(a), 4(b), 6(c), 8(d), 10(e), 12(f) and 14(g)% for

Protein ). • Seven animals (cows) are selected at random for

the experiment which is to be carried out over seven three-month periods.

Page 79: Stats 845 Lecture 14n

A Greaco-Latin Square is the used to assign the 7 X 7 combinations of levels of the two factors (Lysine and Protein) to a period and a cow. The data is tabulated on below:

P e r i o d 1 2 3 4 5 6 7

1 3 0 4 4 3 6 3 5 0 5 0 4 4 1 7 5 1 9 4 3 2 ( A ( B ( C ( D ( E ( F ( G 2 3 8 1 5 0 5 4 2 5 5 6 4 4 9 4 3 5 0 4 1 3 B ( C ( D ( E ( F ( G ( A 3 4 3 2 5 6 6 4 7 9 3 5 7 4 6 1 3 4 0 5 0 2 ( C ( D ( E ( F ( G ( A ( B

C o w s 4 4 4 2 3 7 2 5 3 6 3 6 6 4 9 5 4 2 5 5 0 7 ( D ( E ( F ( G ( A ( B ( C 5 4 9 6 4 4 9 4 9 3 3 4 5 5 0 9 4 8 1 3 8 0

( E ( F ( G ( A ( B ( C ( D

6 5 3 4 4 2 1 4 5 2 4 2 7 3 4 6 4 7 8 3 9 7

( F ( G ( A ( B ( C ( D ( E

7 5 4 3 3 8 6 4 3 5 4 8 5 4 0 6 5 5 4 4 1 0 ( G ( A ( B ( C ( D ( E ( F

Page 80: Stats 845 Lecture 14n

The Model for a Greaco-Latin Experiment

klijjilkklijy

i = 1,2,…, t j = 1,2,…, t

yij(kl) = the observation in ith row and the jth column receiving the kth Latin treatment and the lth Greek treatment

k = 1,2,…, t l = 1,2,…, t

Page 81: Stats 845 Lecture 14n

= overall mean

k = the effect of the kth Latin treatment

i = the effect of the ith row

ij(k) = random error

j = the effect of the jth column

No interaction between rows, columns, Latin treatments and Greek treatments

l = the effect of the lth Greek treatment

Page 82: Stats 845 Lecture 14n

• A Greaco-Latin Square experiment is assumed to be a four-factor experiment.

• The factors are rows, columns, Latin treatments and Greek treatments.

• It is assumed that there is no interaction between rows, columns, Latin treatments and Greek treatments.

• The degrees of freedom for the interactions is used to estimate error.

Page 83: Stats 845 Lecture 14n

The Anova Table for a Greaco-Latin Square Experiment

Source S.S. d.f. M.S. F p-value

Latin SSLa t-1 MSLa MSLa /MSE

Greek SSGr t-1 MSGr MSGr /MSE

Rows SSRow t-1 MSRow MSRow /MSE

Cols SSCol t-1 MSCol MSCol /MSE

Error SSE (t-1)(t-3) MSE

Total SST t2 - 1

Page 84: Stats 845 Lecture 14n

The Anova Table for Example

Source S.S. d.f. M.S. F p-value

Protein 160242.82 6 26707.1361 41.23 0.0000

Lysine 30718.24 6 5119.70748 7.9 0.0001

Cow 2124.24 6 354.04082 0.55 0.7676

Period 5831.96 6 971.9932 1.5 0.2204

Error 15544.41 24 647.68367

Total 214461.67 48