spm 2005 past year paper answers

SPM 2005 Past year paper answers 1 of 13 Hoo Sze Yen

The answers in this document is merely a guide and does not necessarily reflect the actual marking scheme

SPM 2005 ANSWERS Note: Items marked in red are no longer in syllabus Paper 1 1. C 2. B 3. A 4. C 5. D 6. B 7. C 8. A 9. E 10. B 11. D 12. C 13. C

14. C 15. A 16. A 17. D 18. D 19. D 20. A 21. D 22. D 23. A 24. C 25. B 26. C

27. C 28. C 29. A 30. A 31. C 32. D 33. A 34. B 35. C 36. D 37. C 38. C 39. D

40. D 41. B 42. E 43. A 44. C 45. B 46. C 47. C 48. D 49. C 50. B



Paper 2 Section B 1. (a) Current (b)

(c) 0.1 A (d) Overcome parallax error 2. (a) Waves with the same wavelength and same wave phase difference (b)

3.325.28.0 ×

==Daxλ = 0.55 m

(c) When the peak of a wave meets the peak of another wave or when the trough meets another trough

3. (a) Reflection (b) 8 m (c) 7 m (d)

(e)

4. (a) (i) Process of liquid converting into steam at any temperature below boiling

point (ii) The liquid molecules absorb heat from the skin to gain enough energy to

leave the surface of the skin. This drops the overall heat energy of the skin (b) Any two of the following:

• Movement of air (wind) • Humidity • Surface area of liquid • Atmospheric pressure

(c) Q = mL = 0.05 × 2.3 × 106 = 1.15 × 105 J 5. (a) The position of the paper in Figure 5.2 is higher (b)



(c) The higher velocity of air above the paper creates a region of low pressure whereas the lower velocity of air below the paper has higher pressure. This causes the air below the paper to exert a force upwards.

(d) (i) Higher (ii) The air pressure is lower

(e) Bernoulli’s principle (f) Bunsen burner 6. (a) 500 (b) 1. Stationary

2. Moving with uniform velocity (c) R = mg + F (d) The normal reaction is the sum of the weight and the net force (e) (i) Reading decreases

(ii) Student’s weight minus the net force acting upon the student 7. (a) (i)

(ii) 7.5 (iii) 1600 → 800 → 400 → 200 → 100 → 50 Time taken = 5 × 7.5 = 37.5 days

(b) (i) mass (ii) [ ]

[ ]HeRnRa 42

22286

22688 +→ + Energy

(iii)E = mc2 = 8.6818 × 10-34 × (3 ×108)2 = 8. (a) The level is above the maximum acceptable level

This is because some of the radiation has been absorbed by the pesticide and unable to be detected by detector S1

(b) The level is below the minimum acceptable level This is because there is no pesticide to absorb the radiation

(c) OR



(d) Truth table for P:

Truth table for Q:

(e) P (f) 1. Output for P is acceptable

2. Output for Q is not acceptable – it accepts all levels of pesticide



Essays Part B 9. (a) (i) Density is mass per unit volume (ii) The level of the boat in Figure 9.1 is low, whereas the level of the boat in

Figure 9.2 is high The volume of water displaced by the boat in Figure 9.1 is little, whereas the volume of water displaced by the boat in Figure 9.2 is high The mass of the boat and its load is the same in both Figures When the mass of the boat and its load is the same, the volume of water displaced is greater when the density of the water is low and vice versa

(iii) Archimedes’ principle (b) When water is pumped into the ballast tank, the weight of the submarine is

greater than the buoyant force acting upon it Therefore the submarine sinks

(c) Item Characteristic Explanation Stability Lead shots at the

bottom Allows hydrometer to sink partially without tipping over

Stability Big diameter cylinder at the bottom

Allows hydrometer to sink partially without tipping over

Sensitivity Small diameter stem at the top

A smaller scale can be drawn

Wider range Longer stem Able to sink more in less dense liquids

Calibration Filled with air Able to measure densities that are both greater and less than water



10. (i)

Bright spots are formed from the converging light rays that pass through the surface of the water whereas dark regions are formed from the diverging light rays.

(ii) Figure 10.2 shows parallel incident waves forming circular waves after passing through a narrow gap, where as the waves are less circular after passing through a wide gap. The wavelengths before and after passing the gaps are the same. The narrower the gap, the more circular the waves that pass through the gap, and the wavelengths remain the same.

(iii) Diffraction (b) Item Characteristic Explanation

Design and structure Strong and rigid materials

Will not break under strong waves

Design and structure Has a small hole in the retaining wall

To allow diffraction for dissipation of energy

Design and structure Wider at the base of the retaining wall

To withstand water pressure

Location Bay Calmer waves, less likely to break

Size or energy of the waves

Bay Calmer waves due to refraction



Part C 11. (a) (i) Power is the inverse of the focal length of a lens in meters. (ii) Long focal length

Bigger diameter (able to catch more light rays) (iii)

(iv) Magnification = 41040

eyepiece theoflength Focallens objective theoflength Focal

==

(b) (i) Y It has both converging and diverging lenses The converging lens enables near objects to be focused on the retina The diverging lens enables far objects to be focused on the retina

(ii) X does not allow far objects to be focused on the retina Z does not allow near objects to be focused on the retina

(iii) High index glass Angle of refraction will be too near normal

12. (a) (i) Potential energy → kinetic energy → electrical energy (ii) Ensures continual supply of electricity

Able to use another network if one network is down Overall cost of producing electricity is lowered Power can be controlled and adjusted when needed

(b) (i)

(ii) Laminated soft iron core

To prevent eddy currents Easily magnetise and demagnetize

(iii) Copper Low resistance Less heat or power loss

(c) (i)

3024

==RVI =0.8 A

(ii) Power loss = I2R = 0.82(30) = 19.2 W



Paper 3 Section A 1. (a) (i) Distance of compression of the spring (ii) Final velocity of trolley (iii)Mass of trolley / spring constant / angle of incline of ramp (b) Distance of compression, e

(cm) Length of ticker tape, x

(cm) Velocity, v

(cm s-1) 2.0 5.5 27.5 3.0 7.5 37.5 4.0 11.3 56.5 5.0 12.8 64.0 6.0 15.5 77.5

(c)

(d) v is directly proportional to e



2.

(a) R is inversely proportional to d2

(b) 2

1d

= 0.41 mm-2

d = 1.56 mm (c)

(i) Gradient, m = 25.05.03.061.0

−− = 12.4 Ω mm2

(ii)

(d)

(e) Ensure that the connections are tight



Section B Question 3 Inference: The pressure of the air in the tyre increases because the temperature of the air in the tyre has increased Hypothesis: When the temperature of air increases, the pressure increases if the mass and volume is constant Aim: To investigate the relationship between the pressure and the temperature of gas Variables: Manipulated: Air temperature Responding: Air pressure Constant: Mass and volume of the trapped air Apparatus and Materials: Round-bottomed flask, mercury thermometer, Bourdon gauge, Bunsen burner, tripod, wire gauze, retort stand, stirrer, ice Set up:

Procedure: 1. Apparatus is set up as per the diagram. 2. The round-bottomed flask is submerged in water and the water bath with ice is stirred

continuously until the temperature of the water bath is stable. 3. The temperature of the water is taken from the thermometer. 4. The reading from the Bourdon gauge is read at temperatures 30, 40, 50, 60, 70 and 80

°C. Results: Temperature, θ (°C) 30 40 50 60 70 80Air pressure, P (Pa)



Analysis: • A graph of P against θ is plotted. • A linear graph is obtained. • When extrapolated, pressure P = 0 occurs when gas temperature, θ = -273 °C

• When the Celsius scale is replaced with the Kelvin scale, a linear graph that goes

through origin is obtained.



Question 4 Inference: As the magnet moves through the coil faster, the magnitude of the current or the brightness of the light bulb increases Hypothesis: The faster the relative movement of the magnet with the solenoid, the higher the induced current Aim of the experiment: To study the relationship between the speed of the movement of the magnet with the solenoid and the induced current Variables: Manipulated: Height of the magnet bar (this determines the speed of the magnet) Responding: Galvanometer reading Constant: Number of turns on the solenoid Apparatus/Materials: Insulated copper wire, galvanometer, magnet bar, ruler, retort stand Setup:

Procedure: 1. The apparatus is setup as above. 2. The height of the magnet bar is placed at 20.0 cm and dropped through the solenoid.

The reading of the galvanometer is recorded. 3. The experiment is repeated with the height of the magnet bar at 30.0 cm, 40.0 cm,

50.0 cm and 60.0 cm. Analysis A graph of galvanometer reading, I against the height of the magnet bar is drawn.

It is observed that the higher the magnet bar, i.e. the higher the speed of the magnet bar moving through the solenoid, the higher the galvanometer reading.

Galvanometer reading, I

Height of magnet bar

spm 2005 past year paper answers

Documents

actual marking

hoo sze yen

bourdon gauge

bottomed flask

truth table

necessarily

magnet bar

galvanometer