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    Taking the Mystery out of Spiral Curvesby Jim Coan

    "Formanysurveyors, thelast time theyhad to calculatea spiral curvewas in college,

    Part 1Quite often I am contacted by Land Surveyorsand asked to help them with the calculation orinterpretation of a spiral curve. These curvesare usually on some historic record with a mini-mum of information. In order to figure out whatwas done the spiral curve needs to be recon-structed (re-calculated).Spiral curves are no harder than many otherthings a surveyor calculates. In fact, they aremuch easier than a lot of things we are askedto do on a daily basis. The reason some sur-veyors have such a hard time with spiral curvesis because we very seldom deal with them. Formany surveyors, the last time they had to cal-culate a spiral curve was in college, if at all. Ifeel if a surveyor understands how a spiral isconstructed and has the proper formulas, theywill have little trouble with this type of curve.First, it must be stated that there are two com-mon types of spiral curves, Arc Spirals, andChord Spirals. Arc Spirals are used in road workwith the design of highways. Many states don'tuse spiral curves at all, instead opting to use ra-dial curves with longer radiuses. Other states useto design highways with spirals but have stoppedthe practice. There are a few states that still usespirals. Chord spiral curves are typically found inrail road work. For the purpose of this paper arcspiral curves will be discussed.A spiral curve is just the modification of asimple horizontal curve. First an appropriatecurve is placed between two tangent lines. Thiscurve is designed with respect to the designspeed of the road, the delta angle between thetangent, and many other factors.

    \DELTA ANGLE)

    Once the radius (or in many cases the degreeof curve), the design speed, and the geom-etry of the cross section (hOWmany lanes) are

    known, the length of the spiral portion ocurve can be found in highway design tabThe simple curve now changes from one cto a curve complex with three parts. Theythe spiral in, the central curve, and the sout. In many cases the spiral portion ocurve is also the super elevation transitiothe curve complex.First, the radial curve is reduced from itsnal delta angle to a delta angle that is smThen the radial curve is offset towards thdius point, but the radius stays the samethe original curve. The difference betweenoriginal delta angle and the reduced delta ais two times the delta angle of the spiraltion. That is

    Where ~= the delta angle of the overall ccomplex, ~c = the delta angle of the redcurve, and ~s = the delta angle of the sThe ~s is calculated by the following form~s = 90 Ls OR ~=LsD- - --t R 200

    D ISTANCE ' THE CURI S O FF SE TO R IG IO N A L H O R IZ O N TACURVE

    S PIR AL C UR

    H O RI ZO N TA L'M TH R ED UC E

    P IR AL

    When this is done, the curve is transforform a simple horizontal curve to a spiral cThere are now several new parts to the cThe point where the curve complex starcalled the Tangent to Spiral (TS). Thewhere the spiral in meets the horizontaltion of the curve is called the Spiral to C(SC). Where the horizontal curve meetsspiral out, the point is called Curve to S(CS), and where the spiral out meets thegent line is called the Spiral to Tangent (S

    (Continued on pag

    Fall 2005 Evergreen State Surveyor

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    Taking the Mystery (continued)

    The geometry of a spiral curve is complex. Most parts of thecurve can be calculated once it is understood where they areon the spiral. See the following figure

    Ts is the Spiral Tangent. This is the distance from the PI of theoverall curve complex to where the spiral begins (TS). The for-mula to calculate this distance is:~Ts=(R+P)Tan-+q2

    X is a distance, measured along the tangent from the TS to apoint at right angles to the SC. The formula to calculate thisdistance is:

    This can become a very complicated formula in a hurry, how-ever, I have found that if only the first two terms inside the brack-ets are used the answer will be accurate to the 0.01 feet. Whenthis is done the formula will look like this.

    This formula ismuch easier to use.It must a ls o be n ote d th athe above tw o form ulas are used the.6.s m ust be in radianAnother way to find a value for "X" is to use an approximformula. If the length of the spiral is treated like a straigthen the "X" and the "Y" can be calculated by using thelas of a right triangle. This will only be an approximatiomight be precise enough for a particular job.For example, given a length of spiral (Ls) of 200.00 feet,delta spiral of 0349'11" (0.0666666 radians based on aof 1500.00 feet)The "X" value, using the series formula will be 199.91 feThe "X" value, using the right angle approximationwill be 199Y is the right angle distance from the tangent to the Sformula to calculate this distance is:

    As with the "X" value, the formula for the "Y" value can bplified to the two terms inside the brackets. The above fthen becomes

    Y = Ls ( ~ s _ : ; s )Again, the .6.s m ust be in rad ians!Just likethe "X"value you can also use a right angle approximExample: USing the same parameters as the example forvalue the "Y" value using the series formula is4.44 feet. Usright angle approximation the "Y" value is also 4.44 feet.LT is the long tangent (spiral). It is the distance from thethe spiral point of intersection (SPI) as measured alotangent line.The formula to find the LT is:

    2ilsLCSin-- 3LT=-----Sin (1800- . 6 . . 1 ' )

    In this formula the ~s does not need to be changed to raST is the short tangent (spiral). It is the straight line difrom the SPI to the spiral to curve (SC). The formula is:

    2~sLCSin-- 3ST=-----Sin (1800 - L~ . s )

    34 Evergreen State Surveyor Fall 2005

    (Continued on pa

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    Taking the Mystery (continued)Ls is the arc length of the spiral, it is a function of the radius (ordegree of curve), the design speed of the road, and how manylanes the road is designed for. The Ls can be determined fromhighway design tables such as the one shown below.

    In the above table the value of "D' in the left hand column standsfor degree of curve the e is for the maximum rate ofsuperelevation around a curve, and the L is for the length ofthe spiral (Ls) in feet for a given design speed.LC is the chord length of the spiral. This is a straight line dis-tance from the TS to the SC. Given the value of "X" and "Y" theLC can be found by using right triangle formulasLC = V X 2 + y2q is the distance along the tangent to a point at right angles to theghost PC Gust less than Ls+2). The formula for finding "q" is:q = X R Sin L is

    P is the distance the curve is offset. The formula to find "P" is:p = Y R (l - Cos ~s)At this point it should be stated that .6.sand 2~s are approximate3 3values, but very good approximate values. For most spiral curvesthese values will be exact to the nearest one second of a de-gree. When ~s is as large as 210 (which is very rare) the cor-rection to ~s is approximately 30".'3

    In part two of our discussion we will talk about the partsspiral curve.LOOK FOR PART 2 IN THE COMING WINTER ISSUE.

    S u r v e y i n g - G e o m a t i c sT e c h n o lo g y .Study at Peninsula College in beautiful Port Angele

    Washington where you can earn- An AAS degree in Surveying-Geomatics Technology

    or An AAS-T degree in Pre-Geomatics Transfers to Oreg

    Institute of Technology at Klamath Falls, Oregon.Our Surveying-Geomatics Department offers-

    A dedicated computer lab AutoCAD, MicroSurvey, Star*Net, and more Total station and Trimble GPS-equippedContact:Jon Purnell, PLSPeninsula College1502 East Lauridsen Blvd.Port Angeles, WA 98362

    [email protected](360) 417-63841-877-452-9277 toll-free inwww.pc.ctc.edu/survtech

    ~PENINSULAnCOLLEGEFall 2005 Evergreen State Surveyor

    mailto:[email protected]://www.pc.ctc.edu/survtechhttp://www.pc.ctc.edu/survtechmailto:[email protected]
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    Taking The Mystery Out Of Spiral Curves-Part 2(see the Fall Issue for Part 1)By Jim Coan, Renton Technical College

    PARTS OF A SPIRAL CURVEAn example of calculating all parts of a spiral curve is as follows.

    Given:A four lane road with a design speed of 70mph; a degree of curve of 0300'00"; a DeltaAngle of 6000'00". With the above information a radius will be calculated at 1909.86feet. From table 10.4a (above) the length of the spiral curve will be 300.00 feet.With this information all parts of the spiral curve can be calculated.First, from the above information Ds, and Dc can be calculated. To calculate Ds we use

    90 L 90 300 0the formula ~ s = - _ _ _ _ , for our curve .6.s = - = 04 30' 00 " and1 C R 1 C 1,909.86

    .6.c=.6.- 2.6.s, again, for our curve ~c = 6000'00"- 2(0430'00") = 5 l'Ou'Ou''

    Now that Ds has been calculates, "X" and "Y" can be found. First we will calculate "X"using the formula:X=Ls(l- .6./), for our curve X =300.00'(1- (0.078539816)2)=299.815'10 ' 10*Remember in this formula as well as the formula to find "Y" Ds must be in radians.To find "Y" we will use the formula:Y-L (.6.s .6./) c. Y_30000,(0.078539816 (0.078539816)3)_7851'- s --- , lor our curve - . - - .3 ~ 3 ~

    Next we will calculate the length of the spiral chord (LC) using the formula:LC= ~X2 + y2 , for our curve LC= ~299.8152 + 7.85e = 299.918'With the information we have calculated so far we can now calculate the long tangent(LT), and the short tangent (ST). To find the LT we will use the formula:

    LC. Sin 2.6.s 299.918. Sin 2(0430'00")LT = 3 for our curve LT = 3 = 200.060'Sin(180 -.6.s) , Sin(180' -0430'00")To find the ST we will use the formula:

    LC. Sin ~s 299.918'. Sin 0430'00"ST= 3 forourcurveST= 3 =100.064'Sin(180 -.6. s) , Sin (180 - 0430' 00")

    (Continued on paWinter 2005 Evergreen State Surveyo

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    Spiral Curve (cont inued)Next, "P" and "q" need to be calculated. The formula to find "P" is:p = Y - R(l- Cos.6.J ' for our curve P = 7.851-1,909.86(1- Cos04'30'00") = 1.964'The formula to find "q" is:q =X - R. Sin.6.s , for our curve q =299.815 -1, 909.86(Sin0430 '00") 149.969'

    Finally, after all calculations have been done the spiral tangent can be found by using theformula:

    Ll . 60'00'00"Ts =(R+P)Tan2+q .for our curve Ts = (1,909.86 + 1.964)Tan 2 +149.969=1,253.761'The final results are:

    x = 299.815'Dc= = iDs = 0430'00" LT =200.060'De =0300'00" ST = 100.064'R = 1,909.860' P = l.964'Ls = 300.000' q = 149.969'LC =299.918' Ts = 1,253.761'

    Y 7851'

    Now that the entire spiral has been calculated the next step is to make the necessarycalculations to layout the spiral. In order to get the necessary information two parts mustbe calculated, the deflection angle and the chord distance for intermediate points on thespiral.

    First, the chord distance needs to be determined. There are many ways to accomplish thisbut the best way is to use the arc distance as a chord distance. This will create an errorbecause chord distances are always shorter than arc distances, but for the precision of0.01 feet the error is very small if at all and it is very complicated to calculate a truechord distance. The following table illustrates the error of the chord to spiral over a 300foot spiral curve.

    Station Arc Distance Chord DistanceTS = 0+00 0.00' 0.00'

    0+50 50.00' 50.00'1+00 100.00' 100.00'1+50 150.00' 150.00'2+00 200.00' 199.99'2+50 250.00' 249.97'

    SC=3+00 300.00' 299.92'(Continued on pa

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    Spiral Curve (continued)This is based on a 300.00 foot spiral with a ~s of 0430'00". Because the LC has already beencalculated, the largest error of 0.08 feet at 3+00 (SC) can be dismissed leaving the largestpractical error of 0.03 feet. For layout this should be accurate enough. If more precision isneeded there several programs available such as TDS or Land Development Desktop that do avery good job of calculating spiral chord distances.Next, the deflection angle is calculated. In order to do this we will use the formula

    as = ( _ ! _ J 2 ~s where "I" is the length on the spiral to the point being staked. Ls is the lengthi; 3of the spiral (300.00feet), and ~s is the delta spiral (0430'00")Exampie:

    Station Distance Deflection AngleTS =0+00 0.00' 0000'00"

    0+50 50.00' 0002'30"1+00 100.00' 0010'00"1+50 150.00' 0022'30"2+00 200.00' 0040'00" ,2+50 250.00' 0102'30"

    SC = 3+00 300.00' 0130'00"

    Again, these deflection angles are not perfect because ~ S is not perfect but it is more than3adequate for the surveying precision needed to layout a spiral curve.The next step, now that all of the calculations are done, is to layout the curve complex. This willconsist of laying out the spiral in, the center curve and the spiral out.If you asked ten different surveyors how to layout a spiral curve complex you would probablyget ten deferent answers, and this surveyor is no different. I will explain my preferred procedure.There are many other ways and the best way is the one the surveyor responsible for the work iscomfortable with.First, ifpossible the P.I. of the entire curve complex should be occupied. Once this is done theback tangent can be sited and the TC as well as the SPI of the spiral in can be set. While still atthe P.I. the delta angle can be turned as a deflection angle and the SPI and ST can be set alongthe ahead tangent.

    (Continued on pagWinter 2005 Evergreen State Surveyor 27

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    Spiral Curve (continued)Once these points are set the SPI of the back tangent can be occupied, the instrument canbe sited along the back tangent, the spiral delta angle can be turned as a deflection angle,and the SC as well as the CPl can be set. Next occupy the CPl, backsite the SPl that wasjust occupied, tum the delta angle of the interior curve as a deflection angle and set theCS. At this point the surveyor should also be looking at the SPl that was set for the aheadtangent when the PI was occupied (here is your check).

    This is a "best case" scenario and will not always fit the conditions in the field.Regardless of the conditions, if the control points can be put in first the surveyor willkeep better control over the spiral curve complex.Once the control is in, the TS can be occupied, the tangent line can be sited as thebacksite, the deflection angles turned, the distances measured and the spiral in can besurveyed.The center curve can be surveyed as any horizontal curve would be staked out. Thisprocedure is well known to surveyors and will not be discussed further.The spiral out can be stakes backwards (or back stations), that is, the instrument can beset up on the ST the ahead tangent can be used as a backsite and the angles that arealready calculated can be turned as angles left, or subtracted from 3600 and turned asangles right.There is another way that a spiral can be surveyed. This can be accomplished byoccupying the CS and staking out the spiral to the ST. This involves dividing the spiralinto even segments. For example our 300 foot spiral can be divided into 6 even 50 footstations. Each part of the spiral will be given a number beginning with 0 at the ST andgoing to 6 at the CS. These numbers will be referred to as Chord Point Numbers (CPN)

    (Continued on pa

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    Spiral Curve (cont inued)

    The deflection angles can be calculated by using the formula;a~C e ~ ;n2

    Where "C" is a constant calculated by the formula C = ( n f + 2nt ) ( n t - n f ). In thisequation nl is the CPN of the point being staked, and n, = n = the number where theinstrument is set up. Another way to find "C" is by the following table

    "C" VALUES CONSTANT FOR SPIRAL CURVESDEFLECTION INSTRUMENT AT CHORD POINT NUMBER (n) DEFLECTIONTOCPN TOCPN

    0 1 2 3 4 5 6 7 8 9 100 0 2 8 18 32 50 7 98 128 162 200 01 1 0 5 14 27 44 6 90 119 152 189 12 4 -4 0 8 20 36 5 80 108 140 176 23 9 -10 -7 0 11 26 4~ 68 95 126 161 34 IV -v - V - IV V '''' 32 54 80 110 144 45 25 -28 -27 -22 -13 0 17 38 63 92 125 56 36 -40 -40 -36 -28 -16 0 20 44 72 104 6

    -7 49 -54 -55 -52 -45 -34 19 0 23 50 81 7

    - -8 64 -70 -72 -70 -64 -54 40 22 0 26 56 8- -9 81 -88 -91 -90 -85 -76 63 46 -25 0 29 9- - - - - - -10 100 108 112 112 108 100 88 72 -52 -28 0 10

    (Continued on pag

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    Spiral Curve (continued)In the above table, if the instrument is at CPN 6 and the deflection angle for CPN 4 isbeing calculated, the "C" value for the formula will be 32. When the "C" value isacquired either by calculation or by the table the absolute value should be used.This procedure can work on the spiral in as well as the spiral out. The trick is dividingthe spiral into even sections.Example:STATION I CPN C DEF. ANGLE DISTANCECS = 10+00 6 0 0 0

    10+50 ! 5 17 0042'36" 50.00'11+00 4 32 0120'00" 100.00'11+50 3 45 0152'30" 150.00'12+00 2 56 0220'00" i 200.00'12+50 1 65 0242'30" 250.00'

    ST = 13+00 : 0 72 0300'00" I 300.00'In the above example the deflection angle for the last station (13+00) is the sameas 2LlS again, this is your check. The distances are the station distance (arc distance) as

    3previously explained.

    As previously stated, this is but one common way to calculate a spiral curve complex.Hopefully this discussion has taken the mystery out of spiral curves, their parts, and thecalculations involved. Granted, there are numerous steps in the process, but no equationsare too complex for a surveyor. Once all parts are calculated the surveyor can usewhatever they need to accomplish their job. Ifmore information is required, there areseveral books on route surveying or highway design manuals readily available.

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