solving percentage of change equations pre213 a dress costs $45 but there’s a 25% off sale....

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SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A dress costs $45 but there’s a 25% off sale. What’s the new price? mes it helps to use a table to organize information Percent Real 100% Change (+/–) New Original STEP 1: set up the table. NEVER CHANGES

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SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A city’s population increases 12% from 1990 to The population was 125,000 in What was the new population? PercentReal 100%125, % 112%X Change (+/–) New Original STEP 3: fill in missing pieces. We’re asked to find the new population.

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Page 1: SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A dress costs $45 but there’s a 25% off sale. What’s the new price? Sometimes it helps to use a table to

SOLVING PERCENTAGE of CHANGE EQUATIONSPRE213

A dress costs $45 but there’s a 25% off sale. What’s the new price?

Sometimes it helps to use a table to organize information.

Percent Real

100%

Change (+/–)

New

Original

STEP 1: set up the table.NEVER

CHANGES

Page 2: SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A dress costs $45 but there’s a 25% off sale. What’s the new price? Sometimes it helps to use a table to

SOLVING PERCENTAGE of CHANGE EQUATIONSPRE213

A city’s population increases 12% from 1990 to 2000. The population was 125,000 in 1990. What was the new population?

Percent Real

100% 125,000

+12%Change (+/–)

New

Original

STEP 2: fill out table.

Page 3: SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A dress costs $45 but there’s a 25% off sale. What’s the new price? Sometimes it helps to use a table to

SOLVING PERCENTAGE of CHANGE EQUATIONSPRE213

A city’s population increases 12% from 1990 to 2000. The population was 125,000 in 1990. What was the new population?

Percent Real

100% 125,000

+12%

112% X

Change (+/–)

New

Original

STEP 3: fill in missing pieces.

We’re asked to find the new population.

Page 4: SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A dress costs $45 but there’s a 25% off sale. What’s the new price? Sometimes it helps to use a table to

SOLVING PERCENTAGE of CHANGE EQUATIONSPRE213

A city’s population increases 12% from 1990 to 2000. The population was 125,000 in 1990. What was the new population?

Change (+/–)

New

Original

STEP 4: set up a proportion.

Percent Real

100% 125,000

+12%

112% X

100112

125,000x

=

Page 5: SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A dress costs $45 but there’s a 25% off sale. What’s the new price? Sometimes it helps to use a table to

SOLVING PERCENTAGE of CHANGE EQUATIONSPRE213

A city’s population increases 12% from 1990 to 2000. The population was 125,000 in 1990. What was the new population?

STEP 4: solve the proportion.

100112

125,000x

=

112(125,000) = 100x14,000,000 = 100x

140,000 = x

The new population was 140,000!

Page 6: SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A dress costs $45 but there’s a 25% off sale. What’s the new price? Sometimes it helps to use a table to

SOLVING PERCENTAGE of CHANGE EQUATIONSPRE213

A dress costs $45 but there’s a 25% off sale. What’s the new price?

Percent Real

100%

Change (+/–)

New

Original

Answer on next slide.

Page 7: SOLVING PERCENTAGE of CHANGE EQUATIONS PRE213 A dress costs $45 but there’s a 25% off sale. What’s the new price? Sometimes it helps to use a table to

SOLVING PERCENTAGE of CHANGE EQUATIONSPRE213

A dress costs $45 but there’s a 25% off sale. What’s the new price?

Percent Real

100% $45

-25%

75% X

Change (+/–)

New

Original

10075

45x=

75(45) = 100x3375 = 100x

$33.75 = x

The new price is $33.75!