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  • 7/21/2019 Solutions for Mechanics of materials assignment

    1/14

    Example.

    AbeamisloadedandsupportedasshowninFig,P0.Useh"@to

    compute

    the

    deflection:

    w

    (a)

    at

    a

    point

    midway

    between

    the

    supports

    (b)

    at

    the

    right

    end

    of

    the

    beam.

    V=yvL

    (4=u),.t)*

    tw[zL)'

    /-/q)Drtu

    ffi@

    ,.)

    M

    =

    t'vL-

    lL

    -

    wL(-

    lz

    Er

    6=

    0rL+

    gnL

    .t\

    : @tr

    2V

    ET

    +(-\M

    L'\

    Zt

    ,

    D

    Y71

    *?L+

    9Er

    L';f

    (

    ,^

    -h/Lv

    lS'a

    .P

    +

  • 7/21/2019 Solutions for Mechanics of materials assignment

    2/14

    Find

    the

    maximum

    deflection

    of

    the

    cantilever

    beam

    1.

    Using

    discontinuity

    function

    method

    2.

    Using integration

    method

    k-

    *r

    3k

    ,

    Finl{

    ru.Ldooa-t

    :

    f,l(A

    =-F

    h/L'(r

    -o7o+

    EIffr=-#t4/L''l

    +

    Vrs

    V

    4

  • 7/21/2019 Solutions for Mechanics of materials assignment

    3/14

    at

    K>c

    )

    O=ff=c

    o=

    -o+opdt

    =>

    1r=a)

    rft)

    =

    hCAurr'x'+#y3*

    %G-gL>)

    IW

    tt,*=

    4r=t

    b{-

    ft,"

    4

    -

    +

    H

    )=

    -,#

    #

    ok=r=

    b

    (-SwLz'

    ry'

    -

    ygty)r

    -

    #

    #'

  • 7/21/2019 Solutions for Mechanics of materials assignment

    4/14

    Ip

    l-

    Find

    the

    maximum

    defrection

    of

    the

    cantirever

    beam

    1.

    Using

    discontinuity

    function

    method

    2.

    Using integration

    method

    -

    t-{'-

    '

    {

    C

    F;^d

    l*=

    O

    :

    .a

    h/L

    t- ..: ,

    t

    -

    .---

    .'i:

    i

    '

    1

    t--'

    t-

    ra

    cflao

    u1-{

    ;

    */n=

    /f

    tz=

    +

    -0L+

    T

    Er

    4-Y=

    u/L*

    w=

    +:r

    f

    "tel

    ra{

  • 7/21/2019 Solutions for Mechanics of materials assignment

    5/14

  • 7/21/2019 Solutions for Mechanics of materials assignment

    6/14

    f=;^/

    /t{etk'po

    at

    a

    vn^(t/,nd,

    Ef

    ;s

    6t(ca,

    z'tog

    Uq

    l.q

    )

    ue.Sty

    t?nryQSa-h'8P'

    re

    3eo

    (

    /dftt)

    L{00

    3oo.

    (

    'l

    J)'soo'8'YzM2

    /vlr

    =

    LV0O'8

    #42

    (1;

    9l*,=

    /'rr

    l',

    =

    tttt

    ffi,

    C"\

    lvr)r-,r=

    /4,

    Y

    lt-t-N)

    =

    + '

    mL

    L"

    /

    ett6

    n=

    Vr)r,*(%)*,=

    H

    (n,pftr)=

    ,Flg

    .)

    =

    n,f,

    Gt)

    -yA.

    t$'r+')

    ETL

  • 7/21/2019 Solutions for Mechanics of materials assignment

    7/14

    W

    Determine

    the

    reaction

    force

    at

    support

    A in

    terms

    of

    p.

    P:wL/4

    (N)

    I

    Reltlo'u

    ra//er

    d*fU

    a{ tp"

    *t

    WN/m

    fuet

    lq

    6'e

    ft-r,*tdfo^

    z4r0.

    W

    R,t

    ^-*o(

    anfurd(

    w-

    #-uH

    t,=#=

    a'#)'

    u)

    W=fi+l[r+6=P ,

    -/'

    -wTM

    W=c

    n;=W=#*t=Jlt

  • 7/21/2019 Solutions for Mechanics of materials assignment

    8/14

    P(

    Forthe

    beam

    and loading

    shown,

    use

    double

    integrati^rlmethod

    to

    determine

    (a)the

    equation

    of

    the

    elastic

    curve

    for

    the

    se$ment

    AB

    of

    the

    beam,

    (b)

    the

    deflection

    midway

    betlryeen

    A

    and

    B,

    and

    (c)

    the

    slope

    at

    B.

    Assume

    that

    El is

    constant

    for

    the

    beam.

    -

    TE=Od4r-*O

    Z

    fre

    =o>>

    8"=

    ttL

    , :;P

    d

    Vn

    A

    A

    zn=Qz2

    /fi"=&

    -L

    ZA/"=O:

    /V

    lY

    =

    -W'r

    Z

    fll

    P

    *ru*-l

    +

    wb'

    -fl/c=

    74

    +

    ry'

    r-tffi=

    $*ry-V

    luffEre""''.

    ,-3

    iyr(g4f

    o'l

    et

    mf4

    IA,

    '

    u'u

    I

    tt"teXrate:

    Y

    -

    fi"4t^'

    Pr

    ?

    x

    z

    ffi

    -

    v,x'nY#-Ii+tt

    v

    7

    6

    7rl

    #

    +

    lr

    Y*Lz-

  • 7/21/2019 Solutions for Mechanics of materials assignment

    9/14

    bo*n/,a,,

    eooth'rtbog

    e"t

    K

    >o,

    [=o

    0

    =-0

    +C

    --O*Ct?

    +C.

    :)

    Cr:O

    shfL

    *4

    B:

    IIJ

    qt

    >c=L

    )

    [=C

    e=

    #:M'*

    wL{d'-

    &(L)'+

    c'L

    11

    -'

    '-

    w

    Lj'-,

    P

    L'

    ,/^tt;J'r)rnu4.i7,

    nwr ,- r

    wL'n

    f

    "t*;J'*nn'Ju'

    )r"

    -

    ''

    3

    U\

    Erv=

    -4':'yTr"-

    #'+

    Kt-%"fr/

    ffifl

    d*t'+ft/tY-H-

    TET

    t,^rlT ry

    '

    vvb

    Ji-

    ,?

    4

    frr'ZvEr

    , -

    tq-

    PL3

    r)r=Llz=

    -

    {Y='==

    +

    ffi'

    {rET

    )r-L

    nt wLt

    Pt

    G.

    -

    --.-

    /

    lra-

    ZV

    Ef

    DEI

  • 7/21/2019 Solutions for Mechanics of materials assignment

    10/14

    W

    2'

    [zs.ptsl.fhs

    bsam

    depicted

    below

    has

    a 2m

    area

    mome1l

    of

    inodia

    "1"

    equof

    Zl

    inch{

    and

    ic

    made

    of a

    rnaterial

    with

    e

    Young's

    modurus

    of 2g,ooo

    iai.

    -priase

    crotisnnine:

    a)

    The

    reacfion

    force

    at

    point

    c.

    $pecify

    if the

    forcs

    {s

    up

    or down

    and

    tfie

    uR[s

    userL

    b)

    Tho

    reaction

    moment

    at

    point

    A.

    Diagram

    ff it

    is

    clockwise

    or countscbdnalse

    and

    lhe

    unltg

    ussd

    c)

    The

    displacement

    et

    point

    D.

    Spacify

    if it

    is

    up

    [+vl

    or

    dswn

    [.v]

    anO

    sFsdfy

    th

    unlt*

    usad.

    (a)

    Rc

    =

    Z,l?

    /8,

    {b)

    [tlA=

    7

    v,=

    -47{F

    c'u,

    '1"

    **-rfr

    I

    7tt

    i

    1011

    Qd^*

    Ldc

    {r=

    Pd=

    Pfza)3

    /rtd

    {g

    ;;)fr,^'."hr;2,

    a,*,}

    aaftru

    /d#db

    Le

    wo,

    ...r

    Jioo(tVJt)

    J

    14=

    zooo(16'fl

    ,nPUp*slfzo,"

    ,o*-/tn

    o4*

    /afe

    #lhortr*

    *

    Ll^;u,

    f,r'o

    -

    7

    WL:

  • 7/21/2019 Solutions for Mechanics of materials assignment

    11/14

    ,futrt

    zo4/6'ft)

    wt

    Z

    /Llfi

    =C

    s),/?'*zt?o,e'

    z

    va/

    (b;1'

    ;

    )

    I,J

    /

    i

    o"*

    0",

    =

    wL

    -g

    vb\\

    W-

    tdET

    --

    P

    L.,

    7EI

    zf

    o,*:

    {,/-%}=-

    ry

    Fc

    2

    EJ

    lx,ro

    0r=

    9r*

    *

    Zcr

    *

    2cn

    ,

    :

    /?./

    a

    >

    OOO

    +1fl(7,

    Ht

    =

    st.W[hP,tt)'=

  • 7/21/2019 Solutions for Mechanics of materials assignment

    12/14

    W

    -lhr:

    sirnply

    suppcrted

    bcanr

    slxrrvn

    in

    l;ig.

    i

    consists

    uf'a

    Wl0tt

    r

    Sg

    stfucturill

    *te*l

    wide-tlangc

    shapc

    [li

    =

    200

    (ip*l

    /

    ,,

    (rti.g ,

    lt]n

    mrn'1.

    For

    rhe

    l*ading

    shrr\4rn.

    usc

    *lisco*rinuir.v

    ftutctions

    io

    compuls

    ta)

    the

    dsl'lectirlt

    ,:tlthe

    bemr

    at

    C

    and

    (b)

    thc

    dcflection

    ul'the

    lrc*nr

    ar

    J...

    /,

    Zh,=

    o=)

    Dr=

    /Z(/cu,

    0bl/

    Z

    Ft=

    ,7^

    =//

    /'4

    &u

    /t{r)

    =

    /6