solutions - chs science department - capi marceau - home · 2019. 9. 15. · section 18.2 questions...
TRANSCRIPT
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Solutions
Molarity Mole solute/liters solution
The molar concentration of a
solution, expressed as the number of moles of solute per liter of
solution.
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Homework & reading
! Chapter 18 ! section 18.2 Questions 8-13
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Problems
! sample molarity problems
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Molarity problems
! Find the molarity: ! 25.0 grams of NaCl mixed with
water to make 2.50 liters of solution
! Find the grams needed to make a 5.0 liter of 0.10 M solution of CaCl2
! 0.17 M
55 g CaCl2
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NaCl
! 25.0 g NaCl x 1 mole NaCl = 0.428 mol 1 58.4 g NaCl
0.428 mol 2.5 L
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Molarity problems
! What volume of 3.0 M KOH is needed to have 1.5 moles of KOH?
! 0.50 L
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Solution Dilution
! Often chemists need to dilute a stock solution (like concentrated acids)
! Once the required number of moles is known dilution is easy
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Dilution spreads out the solute particles
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Homogeneous and shades
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Dilutions
! Molaritystock x Volumestock = Molaritydilute x Volumedilute
! Ms x Vs = Md x Vd
OR
! M1 x V1 = M2 x V2
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EXAMPLE PROBLEM ! Given a stock solution of 12 M HCl mix the
following: A chemistry teacher needs 1750 mL of 0.1 M HCl solution. What volume of the stock HCl is required?
! Ms = 12 M ! Vs = X ! Vd = 1750 mL ! Md = 0.1 M ! Solve for Vs
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Vs = Md x Vd Ms
Vs = 0.1 M x 1.750 L 12 M
Vs = 0.0146 L