solutions a solution is a homogenous mixture whose component substances cannot be distinguished. ...
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Solutions
A solution is a homogenous mixture whose component substances cannot be distinguished.
Eg: Salt water, Gatorade, tap water, vodka, Kool-Aid.
SOLUTION
Made up ofMade up of
SOLUTE SOLVENT
The substance dissolved, usually a
solid
The substance dissolved, usually a
solid
The liquid the solute is dissolved in (Ex.
water)
The liquid the solute is dissolved in (Ex.
water)
Common Solutions in the world…..
http://www.nrprcd.org/photo_gallery/rcd_03/coordinator_breakfast/images/orange_juice.jpghttp://www.nrprcd.org/photo_gallery/rcd_03/coordinator_breakfast/images/orange_juice.jpg
Chocolate Milk
Solute: chocolate powder
Solvent: milk
Chocolate Milk
Solute: chocolate powder
Solvent: milk
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Salt Water
Solute: salt
Solvent: water
Salt Water
Solute: salt
Solvent: water
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Orange Juice
Solute: orange concentrate
Solvent: water
Orange Juice
Solute: orange concentrate
Solvent: water
Aqueous Solution
An aqueous solution is one in which the solvent is water
Solubility
The maximum amount of solute that can be dissolved in a certain volume of solvent Solubility of solids increases with
temperature (eg. Think of dissolving sugar in hot coffee)
Solubility of gases decreases with temperature.
Measurement of the amount of solute that is dissolved in a given amount of solution
Mass of solute (g)Mass of solute (g)
Volume of solution (L)Volume of solution (L)
(C)(C)
C = M
Vg/Lg/L
1 L = 1000ml
C = M
V
A solution with concentration of 10 g/L will have 10 grams of solute for every
1 L (1000ml) of solution
When comparing solutions be sure to have the same unit of measurement (grams/litre)
NOTE: To ensure you always have the correct units for concentration (grams/litre) we will the change the formula slightly:
C = g
L
Concentration
2 scoops1 scoop
1 litre of solvent 1 litre of solvent
What is the concentration of a solution that has volume of 500ml and contains 40 g of solute?
C = ?
G = 40 g
L = 0.5 L
C = 40 g
0.5 L0.5 L
C = 80g/L
C = g
1 L
C = M
V
You have a 5 g/L of a salt solution with a volume of 50 ml. What is the amount of solute (salt) in this solution?
GIVEN INFORMATION
C = 5 g/L
G = ?
L = 0.05 L
50 ml = 0.05 L
C g
1 L
5 g
1 0.05
g = 0.25 grams
Cross multiply
C=M V
C=g L
Each can contains sugar ( ) and water. Which can has the strongest concentration?
Water (50ml)Water (50ml) Water (0.25 L)Water (0.25 L)Water (25 ml)Water (25 ml) Water (125ml)Water (125ml)
Remember…Keep the units the same!!= 1 particle
(1g)
= 1 particle (1g)
C = 100 g/LC = 100 g/L C = 80 g/L C = 80 g/L C = 28 g/LC = 28 g/L C = 32 g/LC = 32 g/L
How much solute is there in a 50g/L solution if it has a volume of 250ml?
C = 50 g/L
G = ?
L = 250ml .25L
50 = ?
0.25 L0.25 L
G = 12.5 g
C = g
L
You have a solution that has a concentration of 22 g/L. There is 30 grams of solute in this solution. What is the volume in milliliters of the solution?
GIVEN INFORMATION
C = 22 g/L
G = 30
L = ?
C g
1 L
22 30
1 L
V = 1.36 L or 1360 ml
Cross multiply
C=M V
The volume of the solution is 1360 ml.
Place about half the amount of solvent (liquid) into container
Add the solute Dissolve by shaking or swirling Add the rest of the solvent (liquid)
to reach the desired volumeDO NOT put all of the
solvent and solute together at once…inaccurate results!
DO NOT put all of the solvent and solute together at once…inaccurate results!
Find out you how much grams you need.
Describe the procedure that would be used to prepare 250 ml of a sugar solution that has a concentration of 13 g/L.
BE SPECIFIC……
0.250
g13 grams25.3g
Write out procedure using a step by step method!
1. Pour half the required volume of solvent (125 ml) into a volumetric flask
2. Add the solute (3.25 g of sugar) to the flask 3. Mix them together by swirlling. 4. Add more solvent (liquid) until you reach the desired final volume of 250 ml.
C=g L
o Concentration Formula C =M/V (C=g/L)
o To Prepare a Solution You….-pour half of required amount of solvent in beaker-Add desired amount of solute-Mix-Add solvent (liquid) till your beaker reaches the required amount
Study guide, Module 3, page 14 Text book page 351 # 5, 6, 7 Worksheet # 4