solution rrb 03[www.qmaths.in]

8/17/2019 SOLUTION RRB 03[Www.qmaths.in]

http://slidepdf.com/reader/full/solution-rrb-03wwwqmathsin 1/4Ph: 09555108888, 09555208888 1

2007, OUTRAM LINES, 1ST FLOOR, OPPOSITE MUKHERJEE NAGAR POLICE STATION, DELHI-110009

1. (D) After rotating the dice (i), the triangle

moves on the top the X moves to the left

side. So, O lies opposite to X.2. (B) 152 + 1 = 226

Similarly,202 + 1 = 401

3. (C) Fan can not perform it’s purpose without

wings. Similarly, wheel can not perform it

self without spokes.

4. (D) Video can’t be played without cassette,

in the same way computer can’t be run

without floppy.5. (D)

6. (A) Ink is not used directly by taking in

hand, while rest are used.7. (A) LOATHSOMENESS

After rearrangementAEEHLMNOOSSST

8. (C) 6 + 7 × 3 – 8 20 = ?After changing

6 × 7 3 + 8 – 20 = 14 + 8 – 20 = 29. (B)

The woman is the sister of Raman.10. (C)

11. (D)bag lamps

cakes

I. False II. False

12. (D)tubes cups

handles

I. False II. False

13. (D)Mangoes

Yellow Taxi

I. False II. False14. (D) In row first,

63 + 62 + 6 = 258Similarly, in row two, three and four

In row four,93 + 92 + 9 = 819

RRB MOCK TEST-3 (Solution)

15. (C)16. (D) From question,

tip singing, mot is,baj dancingcol appreciable.

17. (B) Meaningful logical order :2. Nostril

3. Wind Pipe 1. Lung

4. Blood

18. (B)19. (A)

There are four cubes in Layer I and four

cubes in Layer IV which have only oneface painted red and all other faces

unpainted. Thus, there are 8 such cubes.

20. (C) 2 2

2 2

1 1

2 2

A C E

F H J

K L M

S U W

21. (B) A = 2 Position Number × 2

Therefore,

C A B

2 + 1 + 2 = 30

Required answer = 6 × 2 = 1222. (D) First figure 21 + 37 = 58

Second figure 14 + 25 = 39

Third figure = 16 + 81 = 97

23. (A) 1

1

1

1

1

1

R Q

O N

B A

U T

S R

T S

Similarly,1

1

1

1

1

Z

X

C

M

P

Y

W

B

L

O

So, answer is YWBLO.

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24. (D) As per question :

Hence A will be uncle of D.

25. (C) Angle traced by hour hand in21

4hrs

=360 21

12 4

o

= 157

1

2

o

Angle traced by minute hand in 15 minute

=360

15

60

= 90º

Required angle =1

157 902

o

= 67

1

2

o

26. (A) Let the speed of boat in steal water is x

km/h and the speed of current of river = y

km/h.

by question,

x + y = 22 ...(1)

x - y = 16 ...(2)

Adding both equations (1) and (2)

2x = 38 x = 19 km/h.

27. (B) Let the rate = R %

By question,

1200 3 R

100

-

800 4 R

100

= 20

36R - 32R = 20 4R = 20 R = 5%

28. (A) By question,

A = 140% of B

A =140B

100

A

B =

7

5...(i)

B = 80% of C

B =80C

100

B

C =

4

5

Multiplying equation (1) and (2),

A

B ×

B

C =

7

5 ×

4

5

A

C =

28

25

A : C = 28 : 25

29. (D)1 2 3

3

x x x = 28

1 2 3 84x x x

x 1 =2

2

x

x 2 = 2x 1

x 3 = 2x

2 = 2 × 2 x

1 = 4x

1

Now.

x 1+ x

2+ x

3= 84

x 1 + 2 x

1 + 4 x

1 = 84

7 x 1 = 84

x 1=

84

7 = 12

So, x 3 = 4x , = 4 × 12 = 84

30. (B) a = 8.73, b = 4.27

Now,

3 3

2 2

a b

a ab b

=

2 2

2 2

a b a ab b a ab b

= a + b

So. answer = 8.73 + 4.27 = 13

31. (C) 1

38 = 1

332

=

13 322

= 21/2 = 2

32. (C) Let the no. of coins of 20 paise and 25

paise are x and y respectively.

x + y = 324 ...(1)

From question,

0.20x + 0.25y = 71

20x + 25y = 7100 ...(2)

From equation (1) and (2),

20x + 25y = 7100 ...(2)

x + y = 324 ...(1) × 20

20x + 25y = 7100

20x + 20y = 6480

– – – .

5y = 620

y = 124

33. (A) 8 men +12 children, work in 9 days.From question,

1 men = 2 children

6 men = 12 children.

8 men +12 children

= 8 men + 6 men = 14 men.

14 men complete a work in 9 days.

1 man complete a work in 14 × 9 days

12 men complete a work in14 9

12

days

=21

2 = 10

1

2 days

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34. (D) n(E) = 50 (No. of fail in English)

n(M) = 30 (No. of fail in math)

n(E M) = 12 (No. of fail in both)

Total no. of fail students = n(E M)

n(E M) = n (E) + n(M) - n(E M)

= 50 + 30 – 12 = 68 Total no. of pass students = 100 - 68 = 32

35. (A) D

A E B

C20 m

15 m

Area of ABCD =1

2(sum of parallel sides) ×

height

480 =1

2(AB + DC) × DE

480 =

1

2 (AB + 20) × 15

1

2(AB + 20) =

480

15= 32

AB + 20 = 32 × 2 = 64

AB = 64 - 20 = 44 metre

36. (B) Number of women = (100 – 55)% of 64100

= 64100 ×45

100 = 28845

37. (D) Circumference of circular park = 2 r = Distance covered in one revolution

Required distance = 3 × 2 r

= 6 ×22

7 × 14 = 264 metre

38. (B) 4 2403 600.75

24

030

28

20

20

×

39. (D) The length of the train = speed × timetaken of cross the signal

= 90 ×5

18× 10 = 5 × 5 × 10 = 250 m

40. (B) Let the fraction isx

y .

By question,

30×150

x

y =

9

20

x

y

=9

20

×150

30

=9

4

41. (D) Let the breadth of hall = x mLength = 5x m,

Area of hall = 500 m2

l × b = 500 m2

5x × x = 500

5x 2 = 500

x 2 = 100 x = 10 m

length = 5x = 5 × 10 = 50 m42. (C) 72 is L.C.M of options (a), (b) and (c)

but 36, 24 in option (c) is biggest values.

required values of a and b are 36 and 24.

43. (C)1

1 x

×

11

1 x

11

2 x

11

3 x

= 1 x

x

×

1 1

1

x

x

×

2 1

2

x

x

×

3 1

3

x

x

= 1 x

x

×

2

1

x

x

×

3

2

x

x

×

4

3

x

x

=4 x

x

44. (A) Preeti's savings = 2,00,000 ×70

100 ×

60

100

×75

100 = 20 × 7 × 6 × 75 = ` 63,000

45. (D) Only sequence of discounts is changed. equivalent discounts will be same.

20%, 5%, 10% = 5%, 10%, 20% = 10%,20%, 5%

all are equal.

46. (B) P = ` 8000, r =8%

2 half yearly = 4% half-

yearly and n = 2 × 2 half-years = 4 half-years

C.I. = P 1 1100

n

r

= 8000

4

1041

100

= 8000

4

261

25

= 8000

4569761

390625

= 8000 ×

66351

390625 =` 1358.86

47. (C) Sum of 15 numbers = 25 × 15 = 375 The new sum = 375 - 15 × 4= 375 – 60 = 315

The new mean =315

15 = 21

48. (C) Difference % = 26% – 6% = 20%

20 % of 6500 = 1300

49. (D) Required % =26-18

18 × 100 = 44.44%

44%50. (C) 18% + 13% + 6% = 37%

37 % of 6500 = 2405

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1. (D)2. (B)

3. (C)

4. (D)

5. (D)

6. (A)

7. (A)

8. (C)

9. (B)

10. (C)

11. (D)

12. (D)

13. (D)

14. (D)

15. (C)

16. (D)

17. (B)

18. (B)

19. (A)

20. (C)

21. (B)

22. (D)

23. (A)

24. (D)

25. (C)

RRB MOCK TEST-3 (ANSWER KEY)

26. (A)27. (B)

28. (A)

29. (D)

30. (B)

31. (C)

32. (C)

33. (A)

34. (D)

35. (A)

36. (B)

37. (D)

38. (B)

39. (D)

40. (B)

41. (D)

42. (C)

43. (C)

44. (A)

45. (D)

46. (B)

47. (C)

48. (C)

49. (D)

50. (C)

51. (D)52. (A)

53. (B)

54. (B)

55. (C)

56. (C)

57. (C)

58. (C)

59. (A)

60. (A)

61. (A)

62. (B)

63. (C)

64. (A)

65. (A)

66. (B)

67. (B)

68. (C)

69. (D)

70. (A)

71. (B)

72. (B)

73. (A)

74. (B)

75. (A)

76. (C)77. (B)

78. (D)

79. (A)

80. (C)

81. (B)

82. (A)

83. (A)

84. (B)

85. (B)

86. (A)

87. (B)

88. (A)

89. (C)

90. (C)

91. (C)

92. (A)

93. (D)

94. (C)

95. (A)

96. (B)

97. (C)

98. (D)

99. (A)

100. (C)

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solution rrb 03[www.qmaths.in]

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