slide 2 / 222 algebra ii
TRANSCRIPT
Slide 1 / 222
Algebra II
Quadratic Functions
www.njctl.org
2014-10-14
Slide 2 / 222
Table of Contents
Explain Characteristics of Quadratic Functions
Graph Quadratic Functions
Solve Quadratic Equations by GraphingSolve Quadratic Equations by Factoring
Solve Quadratic Equations Using Square Roots
Key Terms
Application of Zero Product Property
Solve Quadratic Equations by Completing the SquareSolve Quadratic Equations using the Quadratic Formula
The Discriminant
Combining Transformations (review)
Vertex FormMore Application Problems using Quadratics
click on the topic to go to that section
Slide 3 / 222
Zero(s) of a Function: An x value that makes the function equal zero. Also called a "root," "solution" or "x-intercept"
Key Terms
Slide 7 / 222
Minimum Value: The y-value of the vertex if a > 0 and the parabola opens upward
Maximum Value: The y-value of the vertex if a < 0 and the parabola opens downward
Vertex: The highest or lowest point on a parabola.
Key Terms
Slide 8 / 222
Axis of symmetry: The vertical line that divides a parabola into two symmetrical halves
Key Terms
Slide 9 / 222
Explain Characteristics
of Quadratic Functions
Return to Table of Contents
Slide 10 / 222
Remember: A quadratic equation is any equation that can be written in the form ax2 + bx + c =0Where a, b, and c are real numbers and a ≠ 0
Question 1: Is a quadratic equation?
Question 2: Is a quadratic equation?
Characteristics of Quadratics
Slide 11 / 222
The form ax2 + bx + c = 0 is called the standard form of a quadratic equation.
The standard form is not unique.
For example,
x2 - x + 1 = 0 can also be written -x2 + x - 1 = 0.
Also, 4x2 - 2x + 2 = 0 can be written 2x2 - x + 1 = 0.
Characteristics of Quadratics
Slide 12 / 222
Practice writing quadratic equations in standard form:(Simplify if possible.)
Write 2x2 = x + 4 in standard form:
Standard Form
Slide 13 / 222
Write 3x = -x2 + 7 in standard form, if possible:
Standard Form
Slide 14 / 222
Write 6x2 - 6x = 12 in standard form and simplify, if possible:
Standard Form
Slide 15 / 222
Write 3x - 2 = 5x in standard form:
Standard Form
Slide 16 / 222
Similar to Quadratic Equations, the standard form of a Quadratic Function is y = ax2 + bx + c, where a ≠ 0.
Notice, a can be positive or negative.
Standard Form
Slide 17 / 222
When graphed, a quadratic function will make the shape of a parabola.
The parabola will open upward if a > 0 or downward if a < 0.
Graph
Slide 18 / 222
The domain of a quadratic function is all real numbers.
Domain
Slide 19 / 222
Slide 20 / 222
If the vertex is a maximum, then the range is all real numbers less than or equal to the y-value of the vertex.
The range of this quadratic is
Range
Slide 21 / 222
An axis of symmetry (also known as a line of symmetry) will divide the parabola into mirror images.
The line of symmetry is always a vertical line of the form
Axis of Symmetry
Slide 22 / 222
The x-intercepts are the points at which a parabola intersects the x-axis. These points are also known as zeros, roots or solutions and solution sets. Each quadratic function will have 0, 1, or 2 or real solutions.
2 real solutions no real solutions
1 real solution
X-Intercepts
Slide 23 / 222
1 If a parabola opens downward, the vertex is the highest value on the parabola.
True
False
Slide 24 / 222
2 If a parabola opens upward then...
A a > 0B a < 0C a = 0
Slide 25 / 222
3 The vertical line that divides a parabola into two symmetrical halves is called...
A discriminantB quadratic equationC axis of symmetryD vertexE maximum
Slide 26 / 222
Slide 27 / 222
Combining Transformations
(REVIEW)
Return to Table of Contents
Slide 31 / 222
Slide 32 / 222
Let the graph of f(x) be
Graph y = 2f(.5x+1) - 2
Combining Transformations
Slide 33 / 222
Let the graph of f(x) be
Graph y =(-1/2 )f(2x + 1) + 2
Combining Transformations
Slide 34 / 222
Let the graph of f(x) be
Graph y = 3f(-.5x - 2) + 1
Combining TransformationsA
nsw
er
Slide 35 / 222
Let the graph of f(x) be
Graph y = (-1/2)f(-x + 2) +1
Combining Transformations
Slide 36 / 222
Consider the graph y = x 2 and the rules for stretches and shrinks,
Graph
Graph the Transformation
Slide 37 / 222
7 Given the graph of h(x), which of the following graphs is y = 2h(-x+1) - 3?
A B
C D
Slide 38 / 222
8 Given the graph of h(x), which of the following graphs is y = -0.5h(2x - 1) + 2?
A B
C D
Slide 39 / 222
Graph Quadratic Functions
Return to Table of Contents
Slide 40 / 222
Graph by Following Five Steps:
Step 1 - Find Axis of Symmetry
Step 2 - Find Vertex
Step 3 - Find y-intercept
Step 4 - Locate another point
Step 5 - Reflect and Connect
Slide 41 / 222
Slide 42 / 222
Slide 46 / 222
9 What is the axis of symmetry for y = x 2 + 2x - 3 (Step 1)?
A x = 1B x = -1C x = 2D x = -3
Slide 47 / 222
10 What is the vertex for y = x 2 + 2x - 3 (Step 2)?
A (-1, -4)
B (1, -4)
C (-1, -6)
D (1, -6)
Slide 48 / 222
11 What is the y-intercept for y = x 2 + 2x - 3 (Step 3)?
A (0 , -3)
B (0 , 3)
Slide 49 / 222
Practice: Graph
Graph
Slide 50 / 222
Practice: Graph
Graph
Slide 51 / 222
Practice: Graph
Graph
Slide 52 / 222
Solve Quadratic Equations by
Graphing
Return to Table of Contents
Slide 53 / 222
When asked to solve a quadratic equation, there are several ways to do so.
One way to solve a quadratic equation in standard form is to find the zeros of the related function by graphing.
A zero is the point at which the parabola intersects the x-axis.
A quadratic function may have one, two or no zeros.
Solve by Graphing
Slide 54 / 222
How many zeros do the parabolas have? What are the values of the zeros?
No zeroes 2 zeroes; x = -1 and x=3
1 zero;x=1clickclick click
Solve by Graphing
Slide 55 / 222
Every quadratic function has a related quadratic equation.
A quadratic equation is used to find the zeroes of a quadratic function. When a function intersects the x-axis its y-value is zero.
y = ax2 + bx + c Quadratic Function
0 = ax2 + bx + c
ax2 + bx + c = 0 Quadratic Equation
When writing a quadratic function as its related quadratic equation, you replace y with 0.So y = 0.
Vocabulary
Slide 56 / 222
One way to solve a quadratic equation in standard form is to find the zeros or x-intercepts of the related function.
Solve a quadratic equation by graphing:
Step 1 - Write the related function.
Step 2 - Graph the related function.
Step 3 - Find the zeros (or x-intercepts) of the related function.
Solve by Graphing
Slide 57 / 222
2x2 - 18 = 0
2x2 - 18 = y y = 2x2 + 0x - 18
Step 1 - Write the Related Function
Solve by Graphing
Slide 58 / 222
Use the same five-step process for graphing
The axis of symmetry is x = 0.The vertex is (0, -18).The y-intercept is (0, -18).Since the vertex is the y-intercept, locate two other points by substituting values for x. We'll use (2,-10) and (3,0)Graph these points and use reflection across the axis of symmetry. Connect all points with a smooth curve.
Step 2 - Graph the Function
y = 2x2 + 0x – 18
Solve by Graphing
Slide 59 / 222
(3,0) #
x = 0
(2,-10) #
(0,-18)#
#
#
Step 2 - Graph the Function
y = 2x2 + 0x – 18
Solve by Graphing
Slide 60 / 222
The zeros appear to be 3 and -3.
(3,0) #
x = 0
(2,-10) #
(0,-18)#
#
#
Step 3 - Find the zeros
y = 2x2 + 0x – 18
Solve by Graphing
Slide 61 / 222
The zeros are 3 and -3.
Substitute 3 and -3 for x in the quadratic equation.
Check 2x2 – 18 = 0
2(3)2 – 18 = 0 2(9) - 18 = 0 18 - 18 = 0 0 = 0 #
Step 3 - Find the zeros
y = 2x2 + 0x – 18
2(-3)2 – 18 = 0 2(9) - 18 = 0 18 - 18 = 0 0 = 0 #
Solve by Graphing
Slide 62 / 222
12
A
B
C y = -2x2 + 12x - 18
Solve the equation by graphing the related function and identifying the zeros.
-12x + 18 = -2x2
Step 1: Which of these is the related function?
y = 2x2 - 12x - 18
y = -2x2 - 12x + 18
Slide 63 / 222
13 What is the axis of symmetry?
Formula: -b 2a
y = -2x2 + 12x - 18
A x = -3
B x = 3
C x = 4
D x = -5
Slide 64 / 222
14
What is the vertex?
y = -2x2 + 12x - 18
A (3,0)
B (-3,0)
C (4,0)
D (-5,0)
Slide 65 / 222
15
What is the y-intercept?
y = -2x2 + 12x - 18
A (0,0)
B (0, 18)
C (0, -18)
D (0, 12)
Slide 66 / 222
16
A B
C D
If two other points are (5, -8) and (4, -2), what does the graph of y = -2x2 + 12x - 18 look like?
Slide 67 / 222
17
Find the zero(s)
y = -2x2 + 12x - 18
A -18B 4C 3 D -8
Slide 68 / 222
Solve Quadratic Equations by
Factoring
Return to Table of Contents
Slide 69 / 222
In addition to graphing, there are additional ways to find the zeros or x-intercepts of a quadratic. This section will explore solving quadratics using the method of factoring.
A complete review of factoring can be found in the Fundamental Skills of Algebra (Supplemental Review) Unit.
Fundamental Skills of Algebra (Supplemental Review)
Click for Link
Solve by Factoring
Slide 70 / 222
Review of factoring - Factoring is simply rewriting an expression in an equivalent form which uses multiplication. To factor a quadratic, ensure that you have the quadratic in standard form: ax2+bx+c=0
Tips for factoring quadratics:· Check for a GCF (Greatest Common Factor). · Check to see if the quadratic is a Difference of Squares or other special binomial product.
Solve by Factoring
Slide 71 / 222
Examples:
Quadratics with a GCF:
3x2 + 6x in factored form is 3x(x + 2)
Quadratics using Difference of Squares:
x2 - 64 in factored form is (x + 8)(x - 8)
Additional Quadratic Trinomials:
x2 - 12x +27 in factored form is (x - 9)(x - 3)2x2 - x - 6 in factored form is (2x + 3)(x - 2)
Solve by Factoring
Slide 72 / 222
Practice: To factor a quadratic trinomial of the form x2 + bx + c, find two factors of c whose sum is b.
Example - To factor x2 + 9x + 18, look for factors of 18 whose sum is 9.(In other words, find 2 numbers that multiply to 18 but also add to 9.)
Factors of 18 Sum
Solve by Factoring
Slide 73 / 222
Practice:
Factor x2 + 4x - 12, look for factors of -12 whose sum is 4.(in other words, find 2 numbers that multiply to -12 but also add to 4.)
Factors of -12 Sum
Solve by Factoring
Slide 74 / 222
Zero Product Property
= 0x? ?
Imagine this: If 2 numbers must be placed in the boxes and you know that when you multiply these you get ZERO, what must be true?
Slide 75 / 222
Zero Product Property
For all real numbers a and b, if the product of two quantities equals zero, at least one of the quantities equals zero.
If a b = 0 then a = 0 or b = 0
Slide 76 / 222
Example: Solve x2 + 4x - 12 = 0
1. Factor the trinomial.2. Using the Zero Product Property, set each factor equal to zero.3. Solve each simple equation.
Now... combining the 2 ideas of factoring with the Zero Product Property, we are able to solve for the x-intercepts (zeros) of the quadratic.
Solve by Factoring
Slide 77 / 222
Example: Solve x2 + 36 = 12x
Remember: The equation has to be written in standard form (ax2 + bx + c).
Solve by Factoring
Slide 78 / 222
18 Solve
A x = -7B x = -5C x = -3D x = -2E x = 2
F x = 3
G x = 5
H x = 6
I x = 7
J x = 15
Slide 79 / 222
19 Solve
A m = -7B m = -5C m = -3D m = -2E m = 2
F m = 3
G m = 5
H m = 6
I m = 7
J m = 15
Slide 80 / 222
20 Solve
A h = -12B h = -4C h = -3D h = -2E h = 2
F h = 3G h = 4H h = 6
I h = 8
J h = 12
Slide 81 / 222
21 Solve
A d = -7B d = -5C d = -3D d = -2E d = 0
F d = 3G d = 5H d = 6
I d = 7
J d = 37
Slide 82 / 222
Berry Method to factor
Step 1: Calculate ac.
Step 2: Find a pair of numbers m and n, whose product is ac, and whose sum is b.
Step 3: Create the product .
Step 4: From each binomial in step 3, factor out and discard any common factor. The result is the factored form.
Example: Solve
When a does not equal 1, check first for a GCF, then use the Berry Method.
Berry Method to Factor
Slide 83 / 222
Use the Berry Method.a = 8, b = 2, c = -3
-4 and 6 are factors of -24 that add to +2
Solve
Step 1
Step 2
Step 3
Step 4 Discard common factors
Berry Method to Factor
Slide 84 / 222
Use the Zero Product Rule to solve.
Solve
Berry Method to Factor
Slide 85 / 222
Solve
Use the Berry Method.a = 4, b = -15, c = -25
Berry Method to Factor
Slide 86 / 222
Use the Zero Product Rule to solve.
Solve
Berry Method to Factor
Slide 87 / 222
Solve
Berry Method to Factor
Slide 88 / 222
Application of the Zero Product Property
In addition to finding the x-intercepts of quadratic equations, the Zero Product Property can also be used to solve real world application problems.
Return to Table of Contents
Slide 89 / 222
Example: A garden has a length of (x+7) feet and a width of (x+3) feet. The total area of the garden is 396 sq. ft. Find the width of the garden.
Application
Slide 90 / 222
22 The product of two consecutive even integers is 48. Find the smaller of the two integers.
Hint: Two consecutive integers can be expressed as x and x + 1. Two consecutive even integers can be expressed as x and x + 2.
Slide 91 / 222
23 The width of a rectangular swimming pool is 10 feet less than its length. The surface area of the pool is 600 square feet. What is the pool's width?
Slide 92 / 222
24 A science class designed a ball launcher and tested it by shooting a tennis ball straight up from the top of a 15-story building. They determined that the motion of the ball could be described by the function: , where t represents the time the ball is in the air in seconds and h(t) represents the height, in feet, of the ball above the ground at time t. What is the maximum height of the ball? At what time will the ball hit the ground? Find all key features and graph the function. Students type their answers here
Problem is from:
Click link for exact lesson.
Slide 93 / 222
25 A ball is thrown upward from the surface of Mars with an initial velocity of 60 ft/sec. What is the ball's maximum height above the surface before it starts falling back to the surface? Graph the function. The equation for "projectile motion" on Mars is:
Students type their answers here
Slide 94 / 222
Solve Quadratic Equations Using
Square Roots
Return to Table of Contents
Slide 95 / 222
Slide 96 / 222
Slide 97 / 222
What if x2 has a coefficient other than 1?
Example: Solve 4x2 = 20 using the square roots method.
Solve Using Square Roots
Slide 98 / 222
26 When you take the square root of a real number,
your answer will always be positive.
True
False
Slide 99 / 222
27 If x2 = 16, then x =
A 4B 2C -2D 26E -4
Slide 100 / 222
28 Solve using the square root method.
A 5B 20C 4D -2
E -5F 2G -4H -20
Slide 101 / 222
29 If y2 = 4, then y =
A 4B 2C -2D 26E -4
Slide 102 / 222
Challenge: Solve (2x - 1)² = 20 using the square root method.
Solve Using Square Roots
Slide 106 / 222
33 A physics teacher put a ball at the top of a ramp and let it roll toward the floor. The class determined that the height of the ball could be represented by the equation, ,where the height, h, is measured in feet from the ground and time, t, in seconds. Determine the time it takes the ball to reach the floor.
Students type their answers here
Problem is from:
Click link for exact lesson.
Slide 107 / 222
34 A rock is dropped from a 1000 foot tower. The height of the rock as a function of time can be modeled by the equation: . How long does it take for the rock to reach the ground?
Students type their answers here
Ans
wer
Slide 108 / 222
Solving Quadratic Equations by
Completing the Square
Return to Table of Contents
Slide 109 / 222
In algebra, "Completing the Square" is a technique for changing a quadratic expression from standard form: ax2 + bx + c to the vertex/graphing form: a(x + h)2 + k.
It can also be used as a method for solving quadratic equations.
Completing the Square
Slide 110 / 222
Slide 111 / 222
37 Find (b/2)2 if b = -12.
Slide 115 / 222
38 Complete the square to form a perfect square trinomial.
x2 + 18x + ?
Slide 116 / 222
39 Complete the square to form a perfect square trinomial.
x2 - 6x + ?
Slide 117 / 222
Step 1 - Write the equation in the form x2 + bx = c.
Step 2 - Find (b ÷ 2)2.
Step 3 - Complete the square by adding (b ÷ 2)2 to both sides of the equation.
Step 4 - Factor the perfect square trinomial.
Step 5 - Take the square root of both sides.
Step 6 - Write two equations, using both the positive and negative square root and solve each equation.
Completing the Square
Slide 118 / 222
Let's look at an example to solve:x2 + 14x -15 = 0
Step 1 - Rewrite Equation
Step 2 - Find (b/2)2
Step 3 - Add the result to both sides
Step 4 - Factor & Simplify
Step 5 - Take Square Root of both sides
Step 6 - Write 2 Equations & Solve
How can you check your solutions?
Completing the Square
Slide 119 / 222
Let's look at an example to solve:
Step 1 - Rewrite Equation
Step 2 - Find (b/2)2
Step 3 - Add the result to both sides
Step 4 - Factor & Simplify
Step 5 - Take Square Root of both sides
Step 6 - Write 2 Equations & Solve
How can you check your solutions?
Completing the Square
x2 - 2x - 2 = 0
Slide 120 / 222
40 Solve the following by completing the square :
x2 + 6x = -5
A -5B -2C -1D 5E 2
Slide 121 / 222
41 Solve the following by completing the square :
x2 - 8x = 20
A -10B -2C -1D 10E 2
Slide 122 / 222
Slide 123 / 222
Challenge:
Step 1 - Rewrite Equation
Step 2 - Find (b/2)2
Step 3 - Add the result to both sides
Step 4 - Factor & Simplify
Step 5 - Take Square Root of both sides
Step 6 - Write 2 Equations & Solve
Completing the Square
3x2 - 10x = -3 *Note: There is no GCF to factor out like the previous example.
Slide 124 / 222
Challenge:
Step 1 - Rewrite Equation
Step 2 - Find (b/2)2
Step 3 - Add the result to both sides
Step 4 - Factor & Simplify
Step 5 - Take Square Root of both sides
Step 6 - Write 2 Equations & Solve
Completing the Square
4x2 - 17x + 4 = 0 *Note: There is no GCF to factor out.
Slide 125 / 222
Challenge:Completing the Square
-6x2 - 25x - 25 = 0 *Note: There is no GCF to factor out.
Slide 126 / 222
43 Solve the following by completing the square :
A
B
C
D
E
Slide 127 / 222
Return to Table of Contents
Solve Quadratic Equations by Using
the Quadratic Formula
Slide 128 / 222
At this point you have learned how to solve quadratic equations by:
Today we will be given a tool to solve ANY quadratic equation, and it ALWAYS works!
Many quadratic equations may be solved using these methods. Though completing the square works for any quadratic equation, it can be cumbersome to repeatedly use the algorithm.
· graphing· factoring· using square roots and · completing the square
Solving Quadratics
Slide 129 / 222
Now try Completing the Square on the standard form of a quadratic equation.
Completing the Square
Step 1 - Rewrite Equation
Step 2 - Find (b/2)2
Step 3 - Add the result to both sides
Step 4 - Factor & Simplify
Step 5 - Take Square Root of both sides
Step 6 - Write 2 Equations & Solve
Slide 130 / 222
Steps 2 and 3 - Find (b/2)2 , Add the result to both sides, simplify
Step 1 - Rewrite Equation and factor out a
Step 4 - Factor & Simplify
Step 5 - Take Square Root of both sides
Step 6 - Solve for x
Completing the Square
Slide 131 / 222
Slide 132 / 222
Example 1: Solve 2x2 + 3x - 5 = 0
a = 2 b = 3 c = -5
Once you identify the values of a, b, and c, simply substitute into the quadratic formula and simplify as much as possible.
How can you check your answers?
Quadratic Formula
Slide 133 / 222
Example 2: Solve: 2x = x2 - 3
To use the Quadratic Formula, the equation must be in standard form (ax2 + bx +c = 0).
Identify a, b, and c, then substitue into the formula and simplify.
Don't forget to check your results!
Quadratic Formula
Slide 134 / 222
44 Solve the following equation using the quadratic formula:
A -5B -4C -3D -2E -1
F 1
G 2
H 3
I 4J 5
Slide 135 / 222
45 Solve the following equation using the quadratic formula:
A -5B -4C -3D -2E -1
F 1
G 2
H 3
I 4J 5
Slide 136 / 222
46 Solve the following equation using the quadratic formula:
A -5B -4C -3D -2E -1.5
F 1.5
G 2
H 3
I 4J 5
Slide 137 / 222
Example 3: Solve using the quadratic formula, and simplify the result. x2 - 2x - 4 = 0
Quadratic Formula
Slide 138 / 222
47 Find the larger solution to the equation.
Slide 139 / 222
48 Find the smaller solution to the equation.
Slide 140 / 222
Work in small groups to solve the quadratic equation using the following different methods.
Factoring Quadratic Formula
Completing the Square
Graphing
Which Method
Slide 141 / 222
Factoring Quadratic Formula
Completing the Square
Graphing
Work in small groups to solve the quadratic equation using the following different methods.
Which Method
Slide 142 / 222
The Discriminant
Return to Table of Contents
Slide 143 / 222
2 real solutions no real solutions
1 real solution
Recall what it means to have 0, 1, or 2 solutions/zeros/roots
Solutions
Slide 144 / 222
At times, it is not necessary to solve for the zeros or roots of a quadratic function, but simply to know how many roots exist (zero, one, or two).
The quickest way to determine how many solutions a quadratic has, algebraically, is to calculate what's called the discriminant.
It may look familiar, as the discriminant is a part of the quadratic formula.
The Discriminant
Slide 145 / 222
Slide 146 / 222
Other important tips before practice:
· The square root of a positive number has two solutions.
· The square root of zero is 0.
· The square root of a negative number has no real solution.
The Discriminant
Slide 147 / 222
Slide 148 / 222
If b2 - 4ac > 0 (POSITIVE) the quadratic has two real solutions
If b2 - 4ac = 0 (ZERO) the quadratic has one real solution
If b2 - 4ac < 0 (NEGATIVE) the quadratic has no real solutions
CONCLUSION:
The Discriminant
click to reveal
Slide 149 / 222
49 What is the value of the discriminant of 2x2 - 2x + 3 = 0 ?
Slide 150 / 222
50 Use the discriminant to find the number of solutions for 2x2 - 2x + 3 = 0
A 0
B 1
C 2
Slide 151 / 222
51 What is the value of the discriminant of x2 - 8x + 4 = 0 ?
Slide 152 / 222
52 Use the discriminant to find the number of solutions for x2 - 8x + 4 = 0
A 0
B 1
C 2
Slide 153 / 222
Vertex Form
Return to Table of Contents
Slide 154 / 222
Vertex Form
A quadratic equation in vertex form:
So far, we have been using quadratics in standard form. However, sometimes when graphing, it is more useful to write them in Vertex Form.
Slide 155 / 222
Vertex Form shows the location of the vertex (h , k).The a still tells the direction of opening.And the axis of symmetry is x = h.
Example: Find the vertex, direction of opening and the axis of symmetry for the graph of:
A quadratic function written in vertex form:
Vertex Form
Slide 156 / 222
Find the vertex, direction of openness and the axis of symmetry for each.
A.
B.
C.
Vertex Form
Slide 157 / 222
D.
E.
Vertex FormFind the vertex, direction of openness and the axis of symmetry for each.
Slide 158 / 222
53 Find the vertex for the graph of
A
B
C
D
Slide 159 / 222
54 Find the direction of opening for the graph of
A up
B down
C left
D right
Slide 160 / 222
Slide 161 / 222
Slide 162 / 222
57 Give the direction of opening for the graph of
A up
B down
C left
D right
Slide 163 / 222
58 Give the axis of symmetry for the graph of
Slide 164 / 222
Slide 165 / 222
60 Give the direction of openness of
A up
B down
C left
D right
Slide 166 / 222
61 The axis of symmetry for the graph of is ______ .
Slide 167 / 222
Slide 168 / 222
Slide 169 / 222
Slide 170 / 222
Converting from Standard Form to Vertex Form
To convert from standard form to vertex form, we need to recall the method for completing the square.
Step 1 - Write the equation in the form y = x2 + bx + ___ + c - ___
Step 2 - Find (b ÷ 2)2
Step 3 - Write the result from Step 2 in the first blank and in the second blank.
Step 4 - Rewrite the first three terms as a perfect square.
Slide 171 / 222
Slide 175 / 222
Slide 176 / 222
Compare the following functions based on information from the equations. What do the graphs have in common? How are they different? Sketch both graphs to confirm your conclusions.
Comparing Functions
Slide 177 / 222
Write two different quadratic equations whose graphs have vertices at (3.5, -7).
Two Functions
Slide 178 / 222
What if "a" does not equal 1?
Step 1 - Write the equation in the form y = ax2 + bx +__+ c - __
Step 2 - Factor: y = a(x2 + (b/a)x +__)+ c - __
Step 3 - Find (b/a ÷ 2)2
Step 4 - Put your answer from Step 3 in the first blank and multiply Step 3 by a to fill in the second blank.
Step 5 - Write trinomial as perfect square.
Standard Form to Vertex Form
Slide 179 / 222
Slide 180 / 222
Slide 184 / 222
Geometric Definition of a Parabola
A parabola is a locus* of points equidistant from a fixed point, the focus, and a fixed line, the directrix.
*locus is just a fancy word for set.
Every parabola is symmetric with respect to a line through the focus and perpendicular to the directrix. The vertex of the parabola is the "turning point" and is on the axis of symmetry.
Slide 185 / 222
Axis of Symmetry
Directrix
Focus
L1
L2
L1=L2
Focus and Directrix of a Parabola
Every point on the parabola is the same distance from the directrix and the focus.
Slide 186 / 222
ParabolasThe parts are the same for all parabolas,regardless of the direction
in which they open.
Directrix
Axis of Symmetry
Vertex
Focus
y=ax2+bx+c
Vertex
Focus
Directrix
Axis of Symmetry
x=ay2+by+c
Slide 187 / 222
Slide 188 / 222
Genera l Form y= ax2 + bx + c x= ay2 +by + c
Vertex Form y= a(x - h)2 +k x= a (y - k)2 + h
Opens a>0 opens upa<0 opens down
a>0 opens to the righta<0 opens to the le ft
Axis of Symmetry x = h y = k
Vertex (h , k) (h , k)
Directrix
Focus
Parabola Summary
Slide 189 / 222
71 What is the vertex of ?
A (-3, 2)
B (-3, -2)
C (2, 3)
D (-2, -3)
Slide 190 / 222
72 What is the vertex of ?
A (3, 2)
B (-3, -2)
C (2, 3)
D (-2, -3)
Slide 191 / 222
Slide 192 / 222
Slide 196 / 222
Slide 197 / 222
78 What is the vertex of y= x2 - 8x +21?
A (4, 5)
B (-4, 5)
C (-5, 4)
D (5, 4)
Slide 198 / 222
79 What is the equation of the directrix for the following equation?
A y = 2B y = -4
C x = 3
D x = -5
Slide 199 / 222
80 Where is the focus for the following equation?
A (-3 , 5)B (3 , 5)
C (5 , 3)
D (5 , -3)
Slide 200 / 222
Slide 201 / 222
82 What is the equation of the parabola with vertex (2,3) and directrix y = 4?
A y = 4(x - 2)2 + 3
y = -1/4(x - 2)2 + 3
x = 4(y - 2)2 + 3
x = 1/4(y - 2)2 + 3
B
C
D
Slide 202 / 222
More Application Problems Using
Quadratics
Return to Table of Contents
Slide 203 / 222
Quadratic Functions in the Real WorldClick on the bike to learn more.
Slide 204 / 222
Quadratic Equations and ApplicationsA sampling of applied problems that lend themselves to being solved by quadratic equations:
Number Reasoning
Free Falling Objects
Geometry: Dimensions
Distances
Business:Interest Rate
Height of a Projectile
Slide 205 / 222
PLEASE KEEP THIS IN MIND.
When solving applied problems that lead to quadratic equations, you might get a solution that does not satisfy the physical constraints of the problem.
For example, if x represents a width of a garden and the two solutions of the quadratic equations are -9 and 1, the value -9 is rejected since a width must be a positive number. We call this an extraneous solution.
Quadratic Equations and Applications
Slide 206 / 222
The product of two consecutive negative integers is 1122. What are the numbers?
Applications
Slide 207 / 222
Applications
Two cars left an intersection at the same time, one heading north and one heading west. Some time later, they were exactly 100 miles apart. The head headed north had gone 20 miles farther than the car headed west. How far had each car traveled?
Slide 208 / 222
The product of two consecutive odd integers is 1 less than four times their sum. Find the two integers.
Applications
Slide 209 / 222
The length of a rectangle is 6 inches more than its width. The area of the rectangle is 91 square inches. Find the dimensions of the rectangle.
Applications
Slide 210 / 222
83 The product of a number and a number 3 more than the original is 418. What is the smallest value the original number can be?
Slide 211 / 222
84 The product of two consecutive positive even integers is 168. Find the larger of the numbers.
Slide 212 / 222
85 Two cars left an intersection at the same time, one heading north and the other heading east. Some time later they were 200 miles apart. If the car heading east traveled 40 miles farther, how far did the northbound car go?
Slide 213 / 222
86 A square's length is increased by 6 units and its width is increased by 4 units. The result of this transformation is a rectangle with an area of 195 square units. Find the area of the original square.
Slide 214 / 222
87 In the accompanying diagram, the width of the inner rectangle is represented by x - 3 and its length by x + 3. The width of the outer rectangle is represented by 3x + 4 and the length by 3x - 4. Express the area of the pink shaded region as a polynomial in terms of x.
Students type their answers here
Problem is from:
Click link for exact lesson.
Step 1: Write an expression to represent the area of the larger rectangle.Step 2: Write an expression to represent the area of the smaller rectangle.Step 3: Subtract the polynomial to get your final answer.
Use the the next page for space to solve.
Application ProblemsApplication Problems
Slide 215 / 222
Step 1: Write an expression to represent the area of the larger rectangle.
Step 2: Write an expression to represent the area of the smaller rectangle.
Step 3: Subtract the polynomial to get your final answer.
Ans
wer
Slide 216 / 222
88 A large painting in the style of Rubens is 3 ft. longer than it is wide. If the wooden frame is 12 in. wide, the area of the picture and frame is 208 ft2 , find the dimensions of the painting. (Draw a diagram.)
Students type their answers here
Ans
wer
Slide 217 / 222
89 The rectangular picture frame below is the same width all the way around. The photo it surrounds measures 17" by 11". The area of the frame and photo combined is 315 sq. in. What is the length of the outer frame?
17 x x 11
x
x Ans
wer
Slide 218 / 222
90 Two mathematicians are neighbors. Each owns a separate rectangular plot of land that shares a boundary and have the same dimensions. They agree that each has an area of square units. One mathematician sells his plot to the other. The other wants to put a fence around the perimeter of his new combined plot of land. How many linear units of fencing will he need? Write your answer as an expression of x. Students type their answers here
Problem is from:
Click link for exact lesson.
Note: This question has two correct approaches and two different
correct solutions. Can you find them both? Hint: Start by factoring.
Slide 219 / 222
91 Part A
An expression is given. x2 - 8x + 21 Determine the values of h and k that make the expression (x - h)2 + k equivalent to the given expression.
Input your answer for h =
From PARCC sample test
Slide 220 / 222
92 Part A
An expression is given. x2 - 8x + 21 Determine the values of h and k that make the expression (x - h)2 + k equivalent to the given expression.
Input your answer for k =
From PARCC sample test
Slide 221 / 222
93 Part B
An equation is given.
x2 - 8x + 21 = (x - 4)2 + 3x - 16
Find the one value of x that is a solution to the given equation.
From PARCC sample test
Slide 222 / 222