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Slide 16 1. Disjoint 2. Not disjoint 3. Disjoint 4. Not disjoint 5. Disjoint Slide 18

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Page 1: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 16

1. Disjoint

2. Not disjoint

3. Disjoint

4. Not disjoint

5. Disjoint

Slide 18

Page 2: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 25

Since P(E)+P(Ē) = 1

P(E) = 1-P(Ē)

Slide 26 This is a different question, but it is really similar.

Slide 27

Page 3: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 28

Page 4: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 29

Slide 30

Page 5: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 34

Slide 36

Page 6: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 40

Slide 41

Page 7: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 43

Slide 46

The set of all possible realizations is called the SUPPORT or RANGE of X

Slide 47

Page 8: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 51

Slide 53

a. P(2≤x≤4) = P(1<x≤4) = F(4)-F(1) = 16/36 – 1/36 = 15/36

b. P(4≤x≤6) = P(3<x≤6) = F(6)-F(3) = 36/36 – 9/36 = 27/36

c. P(2<x≤5) = F(5)-F(2) = 25/36 – 4/36 = 21/36

Slide 56

Page 9: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 57

Page 10: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

Slide 60

Slide 67

Page 11: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible

E[X] = 1(1/36) + 2(3/36) + 3(5/36) + 4(7/36) + 5(9/36) + 6(11/36)

= 161/36

Slide 71 (5.1 and 5.2 is proof, it’s up to you if you want to go over those)

Page 12: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible
Page 13: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible
Page 14: Slide 16 Disjoint - Quantitative Sciences Course Unionqscu.org/wp-content/uploads/2019/10/STAT-230-Midterm...answer: p(8) = 0. We can describe a random variable by listing its possible