slide 1 of 41 what happens to produce? all males are mutant, but all females are wild-type? all...

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Slide 1 of 41 What happens to produce? All males are mutant, but all females are wild-type? All females are wild type, but only 50% of males are? 50% are wild-type, 50% are mutant?

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Page 1: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 1 of 41

What happens to produce?

All males are mutant, but all females are wild-type?

All females are wild type, but only 50% of males are?

50% are wild-type, 50% are mutant?

Page 2: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 2 of 41

What happens to produce? (Answers)

All males are mutant, but all females are wild-type? Wild-type dad + Mutant mom (homozygous recessive)

All females are wild type, but only 50% of males are? Wild-type dad + Heterozygous Mom

50% are wild-type, 50% are mutant for both genders? Mutant dad + Heterozygous Mom

Page 3: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 3 of 41

Think about it…

IF the mother is homozygous dominant, then sons are

IF the mother is heterozygous, then sons are

IF the mother is homozygous recessive, then sons are

Page 4: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 4 of 41

Think about it… (Answers)

IF the mother is homozygous dominant, then sons are 100% wild-type

IF the mother is heterozygous, then sons are 50% wild-type

IF the mother is homozygous recessive, then sons are 0% wild-type

Page 5: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 5 of 41

Think about it… (Page 2)

IF the father is wild-type, then daughters are

IF the father is mutant, then daughters are

So mothers determine ______ &

wild type fathers produce ______ daughters

Page 6: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 6 of 41

Think about it… (Page 2) (Answers)

IF the father is wild-type, then daughters are 100% Wild-type

IF the father is mutant, then daughters are Follow the mother’s type

So mothers determine sons &

wild type fathers produce wild-type daughters

Page 7: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 7 of 41

Sex-linked Disorders?

Which gender do you think is afflicted at a higher rate?

Why?

Page 8: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 8 of 41

Sex-linked Disorders? (ANSWER)

Which gender do you think is afflicted at a higher rate? Males

Why? Biologically inferior? XY means what they inherit from mom determines

whether sons are diseased or not XX gets an allele from mom and another from dad

So two chances to get the normal allele, and the normal allele is dominant to the disease allele

Page 9: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 9 of 41

What should have happened?

What should have been the ratio if the characters were inherited via a Mendelian pattern?

How do the recombinants form?

Page 10: Slide 1 of 41 What happens to produce?  All males are mutant, but all females are wild-type?  All females are wild type, but only 50% of males are?

Slide 10 of 41

What should have happened?

What should have been the ratio if the characters were inherited via a Mendelian pattern? 1:1:1:1

How do the recombinants form? Parental and recombinant types are equally likely

according to a typical Mendelian inheritance pattern