simple u-tube manometer

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SIMPLE U-TUBE MANOMETER Example 1 A U-tube manometer similar to that shown in below is used to measure the gauge pressure of water (mass density ρ = 1000 kg /m 3 ). If the density of mercury is 13.6 × 10 3 kg /m 3 , what will be the gauge pressure at A if h 1 = 0.45 m and D is 0.7 m above BC. Mercury, Hg Water It is a manometer that has a fluid reservoir and the end open to atmosphere. It is common to have two different type of fluids within the manometer, one fluid in the reservoir, and another type of fluid within the U.

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It is a manometer that has a fluid reservoir and the end open to atmosphere. It is common to have two different type of fluids within the manometer, one fluid in the reservoir, and another type of fluid within the U. Example 1 - PowerPoint PPT Presentation

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Page 1: Simple U-TUBE Manometer

SIMPLE U-TUBE MANOMETER

Example 1A U-tube manometer similar to that shown in below is used to measure the gauge pressure of water (mass density ρ = 1000 kg /m3). If the density of mercury is 13.6 × 103kg /m3, what will be the gauge pressure at A if h1 = 0.45 m and D is 0.7 m above BC.

Mercury, Hg

Water

It is a manometer that has a fluid reservoir and the end open to atmosphere. It is common to have two different type of fluids within the manometer, one fluid in the reservoir, and another type of fluid within the U.

Page 2: Simple U-TUBE Manometer

SOLUTION :Considering

the pressure at left-hand limb;PB = Pressure, at A + Pressure due to depth, of fluid P

33 /106.13 mkgQ

33 /100.1 mkgP

mh 45.01

mh 7.02

= 1hp PA

= 1ghp PA

the pressure at right-hand limb;

Cp = Pressure Dp at D + Pressure due to depth 2h of liquid Q

Cp = 20 hQ

= 20 ghQ

Since CB pp

21 ghghp QPA

12 ghghp PQA

45.081.9100.17.081.9106.13 33 2/7.88976 mN

23 /1097.88 mN

Page 3: Simple U-TUBE Manometer

EXAMPLE 2.5

A U-tube manometer similar to that shown below is used to measure the gauge pressure of a fluid P of density ρ = 1000 kg/m3. If the density of the liquid Q is 13.6 × 103kg/m3, what will be the gauge pressure at A if h1 = 0.15 m and h2 = 0.25 m above BC. Take into consideration patm = 101.3 kN/m2.

Page 4: Simple U-TUBE Manometer

SOLUTIONPutting ,

ρQ = 13.6 310 ρP = 1000 kg/m3

h1 = 0.15 m h2 = 0.25 m

pressure at left-hand limb;

Bp = Pressure Ap at A + Pressure due to depth 1h of fluid P + Pressure due to

depth 2h of liquid Q

= 21 hhp QPA

= 21 ghghp QPA

pressure at right-hand limb;

Cp = Pressure Dp at D

Dp = Atmospheric pressure

Cp = atmp

CB pp

DQPA pghghp 21

21 ghghpp QPBA

25.081.9100015.081.91036.133.101

2/1.70835 mN2/84.70 mkN

,

Since

Page 5: Simple U-TUBE Manometer

ACTIVITY

The U-tube manometer measures the pressure of water at A which is below the atmospheric pressure. If the specific weight of mercury is 13.6 times that of water and the atmospheric pressure is 101.3 kN/m2, find what is the absolute pressure at A when h1 = 10 cm, h2 = 25 cm and the specific weight of water is 9.81×103N/m3.

Page 6: Simple U-TUBE Manometer

SOLUTION

21 hhpp mercuryairAB

2/3.101 mkNpp atmC

CB pp

atmmercuryairA phhp 21

21 hhpp mercuryairatmA

25.06.1398101.09810103.101 3 Ap

2/66965 mN

2/965.66 mkN

Page 7: Simple U-TUBE Manometer

SELF ASSESSMENT

2.3 Assuming that the atmospheric pressure is 101.3 kN/m2 find the absolute pressure at A in the figure below when

a) Fluid P is water, fluid Q is mercury ω = 13.6, a = 1 m and h = 0.4 m.

b) Fluid P is oil ω = 0.82, fluid Q is brine ω = 1.10, a = 20 cm and h = 55 cm.