siemnes palicaion de ct y tp
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Basics of
Current and Voltage Transformers
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2
1
12
N
N= II
R1jX1 jX2 R2I1 I2
Zb
S2P2 Ideal CT
S1P1 Im
N1 N2 ZmU
2
Equivalent current transformer circuit
X1 = Primary leakage reactance
R1 = Primary winding resistance
X2 = Secondary leakage reactanceZ0 = Magnetizing impedance
R2 = Secondary winding resistance
Zb = Secondary load
Note: Normally the leakage fluxes X1 and X2 can be neglected
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jX2
i2 ZBi1
1 : N2
R2
RB
i'1= i1 i21
N2
LW
L2
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N1
I1
I2
N2
Zb
I2
I1
Im
. N1N2
Current transformer:Phase displacement () and current ratio error ()
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CT classes to IEC 60044-1: 5P or 10P
Specification: 300/1 A 5P10, 30 VA
5% accuracyat I= n x In Accuracy
limit factor ALF
Rated burden
(nominal power) PNBRatio In -Prim / In -Sek.
BBPiP
NBPiPALFALF+
+='
Actual accuracy limit factor
in operation is higher as the CT
is normally underburdened :
Operating ALF: ALF
Dimension criterium:
TFK
n
I
SCIALF max'
KTF (over-dimensioning factor) considers the single sided CT over-magnetising due to the d.c.
component in short circuit current ISC.
KTF values required in practice depend on relay type and design.
Recommendations are provided by manufacturers (see Application Guides)
RCT
5 Ohm
CT2
.seci RIP =
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UKN
10 %
50 %
U2
Im
Definition of the CT knee-point voltage
IEC 60044-1 Class PX
formerly
British Standard BS3938:
Class X
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Accuracy classCurrent error
at nominal
current (In)
Angle errorat rated current
In
Total error at n x In
(rated accuracy limit)
5P
10P
1 %
5%
60 minutes 5 %
10 %
IEC 60044-1 specifies the following classes:
Current transformer, Standard for steady-state performance
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Current transformers, Standard for transient performance
IEC 60044-6 specifies four classes:
Class
Ratio error Angle error
Maximum error at
rated accuracy limit
TPX(closed iron core)
TPYwith anti-remanence
air gap
TPZlinear core
30 min
30 min
180 18 min
0,5 %
1,0 %
1,0 %
%10
only)current(a.c.
%10
%10
Error at rated current
TPSclosed iron core
Special version for high impedance protection
(Knee point voltage, internal secondary resistance)
Remanence
no limit
< 10 %
negligible
No limit
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Current transformer saturation
Steady-state saturation with AC current
Transient saturation with offset current
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S
ISC
Im
DC flux non-saturated
AC flux
Magnetising current
Short circuit current
Transient CT saturation due to DC component
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Pprimary current
TN
B
total flux
a.c. flux
transientd.c. flux
BMax
B~
t
t
d.c. component
B~
)(
1 TSt
TN
t
SN
SN
~
+= ee
TT
TT
B
B
TNTS
TS
S
NS
Max1
~
+=T
TT
B
B
N
S
NS
SN
MaxBnT
Tl
TT
TTt =
tan
1
Bi
W
S
=
+=
RR
LT
[ ]
[ ]ms10900
min
S
=TFor 50 Hz:
Course of CT-flux during off-set short-circuit current
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CT transient over-dimensioning factor KTF
KTF
TS [ms]
50 100 150 200
10
2
0
3
0
4
0
5
0
6
0
100
250
500
1000
5000
(KTF 1+TN)
Closed iron core
Linear core
TN = network time constant
(short-circuit time constant)
TS = CT secondary time constantTN [ms]
NS
S
TT
T
S
N
STF
1
+= TT
TK
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+=N
M
TFT
t-
e-1N1 TK'
N
NNTF 11
R
XTK +=+=
0 20 40 60 80 100
5
10
15
40 ms
50 ms
30 ms
10 ms
20 ms
tM
Ktd
[ ms]
Mt
14
6
CT with closed iron core,
Over-dimensioning factor KTF
for specified time to saturation (tM
)
:tM
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0 20 40 60 80 1000
20
40
60
80
100
120
140
160
180
0 20 40 60 80 1000
0.5
1
1.5
2
2.5
3
3.5
4
KTF
TN in ms
10 ms
8 ms
6 ms
4 ms
2 ms
2 ms
6 ms4 ms
8 ms
10 ms
tM
tM
(tM,TN)(el. degree)
CT over-dimensioning factor KTF (tM,TN)
in the case of short time to saturation (tM)
TN in ms
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Current transformer
magnetising and de-magnetising
P
BBMax
m
BR
t m
BMax
BR
B
t
( ) TSt
RMax.R
+= eBBBB
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Current transformer
Course of flux in the case of non-successful auto-reclosure
tF1 tDT tF2
tF1 = duration of 1st fault
tDT dead time
tF2 =duration of 2nd fault
B
t
Bmax
++
+
+=
S
F2
N
F2
SN
SNS
F2DT
S
F1
N
F1
SN
SN Tt
Tt
(
1Ttt
Tt
Tt
(
1~
maxee
TT
TTeee
TT
TT
B
B
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Current transformer
magnetising curve and point of remanence
BI II III
H = imw
I: closed iron core (TPX)
II: core with anti-remanence air-gaps (TPY)
III: Linearised core (TPZ)
up to 80%
< 10%
negligible
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Current transformers TPX und TPY
Course of the flux with non-successful auto-reclosure
tF1 tDT tF2 t
BR
BR
closed iron core (TPX)
core with anti-
remanence air-gaps (TPY)
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Standards of voltage transformers
Class
designation
5P
3P
Voltage error FU Angle error
Permissible error at 0.05 UN and 1.0 UN
3.0 %
6.0 %
120 minutes
240 minutes
Class
designation at 1.0 UN at 1.0UN
0.1
0.2
0.5
1
3
0.1
0.2
0.5
1
3
10
5
20
30
Not determined
Permissible voltage error in % Permissible angle error in minutes
VT classes to IEC 60044-2
VT classes for measurement IEC 60044-2
All 3P and 5P protection CTs must
additionally comply with one of the
below VT metering classes!
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Capacitive voltage transformer,
Equivalent circuit
ZBLF CF
RF 100 V
3
20 kV
3
400 kV
3
C1= 5 nF
C2= 95 nF
R'BLF CF
RFLTRT
CT
CE= C1+ C2
RE
LO
U*1= UP C1
C1+ C2U*2
L'B
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Legend:
UP(t) Primary voltage
US(t) Secondary voltage
(1) Fault inception
(2) Aperiodic damping of US(t)
(3) Periodic damping of US(t)
Time
Tsin ms
Ratio
Classes
3PT1
6PT1
3PT2
6PT2
3PT3
6PT3
10 --- 25 4
20 10 10 2
40 10 2 2
60 10 0.6 2
90 10 0.2 2
%100U2
)t(U
s
s
t
Measured voltage transients after fault at
voltage maximum and zero-crossing
(Example)
Recommendations to IEC 60044-5
Transient performance of CVTs,
Recommendations acc. to IEC 60044-5
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BCT
BNCT
B
BNiALF
i RR
RR
PP
PPALFALF'
+
+=
+
+=
rated CT burden: PBNinternal burden of the CT: Pi=RiI2N
2
Actual connected burden : PB= RBI2N2
RB=Rl+RR= burden resistance
Rl= resistance of connecting cables
RR= burden resistance of the relayBNCT
BCT
BNi
BALF'i
RR
RR
PP
PPALF'ALF
+
+=
+
+=
N
KOD
I
IK' ALF No saturation
for the total
short-circuit duration:N
N
N
~
Max
TF 11R
XT
B
BK' +=+==
+=
S
M
N
M
SN
SN
T
t
T
t
(
1 eeTT
TTTFK ''
No saturation for
the specified time tM:mTFODKKK
Re
100
Remanence%1
1K mRe
=
with
CT dimensioning
Theory:
Practice:
TFKODK =
Remanence only considered in extra high voltage systems (EHV)
KTF-values acc. to relay manufacturers guides
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Practical CT requirements
Transient over-dimensioning factors KTF
(AR not considered)
5KTF
Distance
7SA6 and 7SA522 30ms)Tif1(2K NTF >setting/ IN, at least 207SJ56
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CT dimensioning for
Example differential protection (1)
1. Calculation of fault currents
Net
IL IL IT
F1 F2 F3 F4
7UT617SD61
Impedances related to 20 kV:
[ ]
0.13
3000
220
MVA''SCS
2kV2NU
N Z:Net ==
=
[ ][ ]
1.2100
%12
40
220
100
%
MVAT-NP
2kV2NU
T Z:Transf. ==
= Tu
[ ] [ ] 3,20,48/km'LzkmlL Z:Line ===
Impedances related to 110 kV:
[ ]
4.03
3000
2110
MVA''SCS
2kV2NU
N Z:Net ==
=
110 kV, 3 GVA
110/20 kV
40 MVA
uT=12%OH-line:
l = 8 km,zL= 0,4 /km
300/1A 1200/1A 200/1A 200/1A
[ ][ ]
36.3100
%12
40
2110
100
%
MVAT-NP
2kV2NU
T Z:Transf. ==
= Tu
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F1 kA17.34.03
3110kV/1.1
NZ
3/NU1.1F1I =
=
=
kA1.7336.34.03
3110kV/1,1
TZNZ
3/NU1.1F2I =
+
=
+
= kA2.83.21.20.13
320kV/1,1
LZTZNZ
3/NU1.1F4I =
++=
++=F2
Dimensioning of the 110 kV CTs for the transformer differential protection:
Manufacturer recommends for relay 7UT61: 1) Saturation free time 4ms for internal faults2) Over-dimensioning factor KTF 1,2
for through flowing currents (external faults)The saturation free time of 3 ms
corresponds to KTF 0,75See diagram, page 59
Criterion 1) therefore reads:
43300
173000,75
NI
F1ITFKALF' == 7
300
17301,2
NI
F2ITFKALF' ==
For criterion 2) we get:
kA9.551.20.13
320kV/1.1
ZZ
3/U1.1I
TN
NF3 =
+
=
+
=F3
F4
The 110 kV CTs must be dimensioned according to criterion 1).
CT dimensioning for
Example differential protection (2)
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CT dimensioning for
Example differential protection (3)
We try to use a CT type: 300/1, 10 VA, 5P?, internal burden 2 VA.
1.1643102
5.22' =+
+=
+
+ ALF
ratedP
iP
operationPiPALF
Specification of the CTs at the 20 kV side of the transformer:
Chosen, with a security margin : 300 /1 A, 5P20, 10 VA, R2 2 Ohm (Pi 2VA)
It is good relaying practice to choose the same dimensioning as for the CTs on the 110 kV side:
1200/1, 10 VA, 5P20, R2 2 Ohm (Pi 2VA)
Dimensioning of the 20 kV CTs for line protection:
For relay 7SD61, it is required: 1) Saturation free time 3ms for internal faults
2) Over-dimensioning factor KTF 1.2for through flowing currents (external faults)
24200
95500.5
NI
F3ITFKALF' == 8.16==
200
28001.2
I
IKALF'
N
F4TF
The 20 kV line CTs
must be dimensioned
according to criterion 1).
(Connected burden estimated to about 2.5 VA)
The saturation free time of 3 ms corresponds
to KTF 0.5See diagram, page 59
Criterion 1) therefore reads: For criterion 2) we get:
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For the 20 kV line we have considered the CT type: 200/5 A, 5 VA, 5P?, internal burden ca. 1 VA
8245111' =++=
++ ALF
ratedPiPoperationPiPALF
Specification of line CTs:
We choose the next higher standard accuracy limit factor ALF=10 :
Herewith, we can specify: CT Type TPX, 200/5 A, 5 VA, 5P10, R2 0.04 Ohm ( Pi 1 VA)
(Connected burden about 1 VA)
CT dimensioning for
Example differential protection (4)