semestertoets 3_2012

4
1 SEMESTERTOETS 3 / SEMESTER TEST 3 23 MEI 2012 / 23 MAY 2012 KURSUS / COURSE: MEGANIESE INGENIEURSWETENSKAPPE / MECHANICAL ENGINEERING SCIENCE TYD / TIME: 120 MIN BLADSYE / PAGES: 4 VRAESTEL / PAPER: STROMINGSLEER / FLUID DYNAMICS 3A PUNTE / MARKS: 65 BEANTWOORD AL DIE VRAE / ANSWER ALL THE QUESTIONS SAKREKENAARS WORD TOEGELAAT / CALCULATORS ARE ALLOWED _____________________________________________________________________ QUESTION 1 [20] By using the Navier-Stokes equation, determine the velocity distribution for fully developed, laminar flow in a tube with radius R 1 (See Figure 1). In the middle of the tube is a solid rod with radius R 2 . The viscosity of the fluid flowing in the annulus is μ and the pressure drop over a distance L is ΔP. [15] Determine also the position of the maximum velocity. [5] Figure 1 NOTE: Show all algebraic calculations.

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    SEMESTERTOETS 3 / SEMESTER TEST 3 23 MEI 2012 / 23 MAY 2012

    KURSUS / COURSE: MEGANIESE INGENIEURSWETENSKAPPE / MECHANICAL

    ENGINEERING SCIENCE TYD / TIME: 120 MIN BLADSYE / PAGES: 4 VRAESTEL / PAPER: STROMINGSLEER / FLUID DYNAMICS 3A PUNTE / MARKS: 65

    BEANTWOORD AL DIE VRAE / ANSWER ALL THE QUESTIONS SAKREKENAARS WORD TOEGELAAT / CALCULATORS ARE ALLOWED

    _____________________________________________________________________

    QUESTION 1 [20] By using the Navier-Stokes equation, determine the velocity distribution for fully developed, laminar flow in a tube with radius R1 (See Figure 1). In the middle of the tube is a solid rod with radius R2. The viscosity of the fluid flowing in the annulus is and the pressure drop over a distance L is P. [15] Determine also the position of the maximum velocity. [5]

    Figure 1

    NOTE: Show all algebraic calculations.

  • 2

    QUESTION 2 [15]

    Find expressions for the velocities Vr and V for a cylinder without circulation

    0cosV xr

    Make use of Bernoullis equation to find an expression for the boundary pressure around a cylinder without circulation. Refer to figure above (Figure 2). Calculate the drag and discuss the result briefly.

    Figure 2

    QUESTION 3 [10]

    The velocity potential for a certain inviscid flow field is given by:

    323 yyx

    Where has the units of m/s when x en y are in meters. Determine the pressure difference (in pa) between point 1 (1, 2) and point 2 (4, 4) where the coordinates are in meter, if the fluid is water and elevation changes are neglible. The temperature of the water is 20C.

    QUESTION 4 [5] Water approaches a device for diverting a portion of the flow. The water is moving at a speed of 3m/s and is at a temperature of 5C. At what distance from A along the horizontal part of the diverter will the laminar boundary layer be a thickness of 1.2mm? Use Blasius solution and 610519.1 v

  • 3

    QUESTION 5 [15] In the autogyro, the lift is developed by freely rotating vanes. The rotation is caused by the aerodynamic forces on the vanes themselves. Using flat-plate theory, what is the aerodynamic torque needed to overcome skin friction for an angular speed of the vanes of 50 r/min? Take each vane to be a flat plate of dimension 4.5m by 0.3m. The autogyro has 3 vanes. The air is at a temperature of 10C. Transition takes place

    at 5102.3Re cr .

    Consider as an approximation, the equation for smooth plates, low Reynolds number

    flow to be valid for the turbulent boundary layer. Take 51055.1 and p=101.404

    Pa

    FORMULA SHEET

    2

    2 2

    2 2 2 2 2

    2

    2 2 2

    1 1 2

    1 1 1 2

    r r r rr z

    r r r rr

    rr z

    v vv v v vv vt r r r z

    vv v v vpB rr r r r r r r z

    v v v v v v vv vt r r r z

    v v vpB rr r r r r r

    2

    2 2

    2 2

    2 2 2

    1 1

    r

    z z z zr z

    z z zz

    vvr z

    vv v v vv vt r r z

    v v vp rz r r r r z

    0

    zV

    yV

    xV zyx 1

    r r

    1r r

    0

    zV

    yV

    xV zyx const

    gVzp 2

    2

    g

    xV y

    yV x

    x

    Vx

    yVy

    1rV r

    rVr

    r

    V 1r r

    1r r

    V

    r

  • 4

    yx

    xy

    kx

    Vy

    VVcurl yx

    21

    0

    zV

    yV

    xV zyx

    212

    wfc U

    4.96Rexx

    0.664

    Ref xc

    2

    2

    yUyUu

    212

    fDCU A

    1.328Ref L

    C

    RDT

    A

    wdAD 15

    0.074ReRe

    fLL

    AC 2.5

    1.89 1.62logflCe

    1.328Ref L

    C

    212

    fDCU A

    w

    w dydu

    4.64

    Rexx

    crRe 300 000 500 000 610 6103 A 1050 1700 3300 8700