section prop 5610

2
Prepared by: D.A.Childs B.Sc., C.Eng., M.I.C.E. Internet Version: Not to be used for commercial purposes unless verified by the user as being correct. http://www.childs-ceng.demon.co.uk SECTION : Main Girder Sheet No. Units : N & mm 508.0 Holes in tension zone Compact Section Check 38.0 Flange Web: 2286.0 BS 5400-3:2000 Clause 9.3.7.2: 9.0 24 63 508.0 24 180 BD 56/10 Clause 9.3.8.2: 38.0 192.0 Web Flange: Lh comp 102.0 Clause 9.3.7.3.1 t(h) 14.0 24 96 Lv comp 102.0 t(v) 14.0 Hence Section : Lh tension 102.0 Non-Compact t(h) 14.0 Lv tension 102.0 Cl. 9.4 Effective t(v) 14.0 230 Area 69822 59827 X-X Axis Y-Y Axis 1.181E+3 8.53696E+8 1.181E+3 1.181E+3 7.83544E+8 1.181E+3 1.2798E+3 1.10575E+2 1.55559E+3 1.0822E+3 1.14441E+2 8.06406E+2 7.42704E+10 6.84562E+7 6.48479E+10 5.88148E+7 5.99222E+7 5.06705E+7 13527 kNm Cl. 9.7.2 L 17068.0 8668.0 h 0.94 . 9.7.1 Support to compression f 0.849 c) Intermediate lateral restraints are 0.500 17068 2.483 0.000 0.935 58.49 Cl. 9.8 11654 kNm 43.7 Annex G.8 (Fig. 11b) BS5400 b > 30 0.0944 Annex G.8 (Fig. 11b) BD56 0.048 0.882 (BS5400) ¦ Cl. 9.9.1.2 8898 kNm (BS5400) 9432 kNm (BD56) Bfc Bf comp tfo tfo comp dw hole f bR Compression angle Lh x Lv x t tw (34tw/m)*(355/syw) 0.5 = 1188 < dwe (2082) dw . Bf tension tw . tfo tension 28tw(355/syw) 0.5 = 313 < d1 (768) bfo Tension angle Lh x Lv x t dh hole f dh 7tfo(355/syf) 0.5 = 330 > bfo( tfo bR Bft / tw)(syw / 355) 0.5 = sy Web thickness twe = A gross = A net = Zpe ytgross = Iyygross = ytgross = ycgross = Iyynet = ycgross = ytnet = rygross = ytnet = ycnet = rynet = ycnet = Ixxgross = Zpe gross = Ixxnet = Zpe net = Zxcnet = Zxtnet = Mpe = Zpe net sy = lLT =le k4 h u / ry le k4 = [{4Z 2 pe(1-Iy/Ix)}/A 2 h 2 ] 1/4 = i = Ic/(Ic+It) = lw = lF = (lw/ry)(tf/D) = yi = 0.8(2i-1) = = [{4i(1-i)+0.05lF 2 +yi 2 } 0.5 +yi] -0.5 lLT = Mult = Zxtnet sy = b = lLT[(syc/355)(Mult/Mpe)] 0.5 = = 0.0035lw/le(b-30) = h = 0.0035(b-30) = MR/Mult = 0.5[{1+(1+h)5700/b 2 }-{(1+(1+h)5700/b 2 ) 2 -22800/b 2 } 0.5 ] = At ULS MD = MR / gmgf3 = MR / (1.1*1.05) = Angle Dimensions: Lh = length of horizontal leg Lv = length of vertical leg t = thickness of leg

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Page 1: Section Prop 5610

Prepared by:D.A.Childs B.Sc., C.Eng., M.I.C.E.

Internet Version:Not to be used for commercial purposes unless verified by the user as being correct.

http://www.childs-ceng.demon.co.uk

SECTION : Main Girder Sheet No. 1Units : N & mm

508.0 Holes in tension zone Compact Section Check

38.0 Flange Web:

2286.0 BS 5400-3:2000 Clause 9.3.7.2: m = 0.32

9.0 24 63

508.0 24 180 BD 56/10 Clause 9.3.8.2:

38.0

192.0 Web Flange:

Lh comp 102.0 Clause 9.3.7.3.1t(h) 14.0 24 96

Lv comp 102.0t(v) 14.0 Hence Section :

Lh tension 102.0 Non-Compactt(h) 14.0

Lv tension 102.0 Cl. 9.4 Effective Section

t(v) 14.0 105.6

230 6.9

Area

69822

59827

X-X Axis Y-Y Axis

1.181E+3 8.53696E+8 1.181E+3

1.181E+3 7.83544E+8 1.181E+3

1.2798E+3 1.10575E+2 1.55559E+3

1.0822E+3 1.14441E+2 8.06406E+2

7.42704E+10 6.84562E+7

6.48479E+10 5.88148E+7

5.99222E+7

5.06705E+7 13527 kNm

Cl. 9.7.2L 17068.0

8668.0h 0.94 Cl. 9.7.1 Support to compression flange for lw

0.849 c) Intermediate lateral restraints are not fully effective

0.500 17068

2.483

0.000

0.935

58.49Cl. 9.8

11654 kNm

43.7

Annex G.8 (Fig. 11b) BS5400 b > 30 0.0944Annex G.8 (Fig. 11b) BD56 0.048

0.882 (BS5400) ¦ 0.935 (BD56)Cl. 9.9.1.2

8898 kNm (BS5400)9432 kNm (BD56)

Bfc Bf comp

tfo tfo comp bfo dw hole f bR

Compression angle Lh x Lv x t tw

(34tw/m)*(355/syw)0.5 = 1188 < dwe (2082) : Non-Compact

dw . Bf tension d1/dw = 0.34

tw . tfo tension 28tw(355/syw)0.5 = 313 < d1 (768) : Non-Compact

bfo

Tension angle Lh x Lv x t

dh hole f dh

7tfo(355/syf)0.5 = 330 > bfo(192) : Compact

tfo

bR

Bft

(yc / tw)(syw / 355)0.5 =

sy Web thickness twe =

A gross =

A net =

Zpe

ytgross = Iyygross = ytgross =

ycgross = Iyynet = ycgross =

ytnet = rygross = ytnet =

ycnet = rynet = ycnet =

Ixxgross = Zpe gross =

Ixxnet = Zpe net =

Zxcnet =

Zxtnet = Mpe = Zpe net sy =

lLT = le k4 h u / ry le

k4 = [{4Z2pe(1-Iy/Ix)}/A2h2]1/4 =

i = Ic/(Ic+It) = lw =

lF = (lw/ry)(tf/D) =

yi = 0.8(2i-1) =

u = [{4i(1-i)+0.05lF2+yi

2}0.5+yi]-0.5

lLT =

Mult = Zxtnet sy =

b = lLT[(syc/355)(Mult/Mpe)]0.5 =

h = 0.0035lw/le(b-30) =h = 0.0035(b-30) =

MR/Mult = 0.5[{1+(1+h)5700/b2}-{(1+(1+h)5700/b2)2-22800/b2}0.5] =

At ULS MD = MR / gmgf3 = MR / (1.1*1.05) =

Angle Dimensions:Lh = length of horizontal legLv = length of vertical legt = thickness of leg

S7
Holes in flange assumed to be symmetrical about Y-Y axis. Input holes to one side of Y-Y axis only.
T12
Start with holes nearest tension flange and work towards compression flange.
O31
Section Properties about horizontal axis, i.e. parallel to flange plates.
R31
Section Properties about the vertical axis. Girder is assumed to be symmetrical about the vertical axis at the centre of the web.
U31
Plastic Modulus about X-X Axis
O52
Depth to neutral axis of gross section from outer face of tension flange.
R52
Second moment of area of gross section.
U52
Distance to equal area line of gross section from tension face
O53
Depth to neutral axis of gross section from outer face of compression flange.
R53
Second moment of area of net section.
U53
Distance to equal area line of gross section from compression face
O54
Depth to neutral axis of net section from outer face of tension flange.
R54
Radius of gyration of gross section about Y-Y axis
U54
Distance to equal area line of net section from tension face
O55
Depth to neutral axis of net section from outer face of compression flange.
R55
Radius of gyration of net section about Y-Y axis
U55
Distance to equal area line of net section from compression face
O56
Second moment of area of gross section.
U56
Plastic modulus of gross section.
O57
Second moment of area of net section.
U57
Plastic modulus of net section.
O58
Elastic modulus with respect to extreme compression fibre of net section.
O59
Elastic modulus with respect to extreme tension fibre of net section.
T87
Distance between lateral restraints at support
T88
Effective length shall be determined in accordance with Clause 9.6 making appropriate adjustment (if necessary) for flexiibilty of restraining system if requirements of Clause 9.12.4.1 cannot be met.
T89
A value less than 1.0 may be obtained from Fig. 10(a) or 10(b) if bending moment varies between points of lateral support.
Q96
Slenderness Parameter