section prop 5610
TRANSCRIPT
Prepared by:D.A.Childs B.Sc., C.Eng., M.I.C.E.
Internet Version:Not to be used for commercial purposes unless verified by the user as being correct.
http://www.childs-ceng.demon.co.uk
SECTION : Main Girder Sheet No. 1Units : N & mm
508.0 Holes in tension zone Compact Section Check
38.0 Flange Web:
2286.0 BS 5400-3:2000 Clause 9.3.7.2: m = 0.32
9.0 24 63
508.0 24 180 BD 56/10 Clause 9.3.8.2:
38.0
192.0 Web Flange:
Lh comp 102.0 Clause 9.3.7.3.1t(h) 14.0 24 96
Lv comp 102.0t(v) 14.0 Hence Section :
Lh tension 102.0 Non-Compactt(h) 14.0
Lv tension 102.0 Cl. 9.4 Effective Section
t(v) 14.0 105.6
230 6.9
Area
69822
59827
X-X Axis Y-Y Axis
1.181E+3 8.53696E+8 1.181E+3
1.181E+3 7.83544E+8 1.181E+3
1.2798E+3 1.10575E+2 1.55559E+3
1.0822E+3 1.14441E+2 8.06406E+2
7.42704E+10 6.84562E+7
6.48479E+10 5.88148E+7
5.99222E+7
5.06705E+7 13527 kNm
Cl. 9.7.2L 17068.0
8668.0h 0.94 Cl. 9.7.1 Support to compression flange for lw
0.849 c) Intermediate lateral restraints are not fully effective
0.500 17068
2.483
0.000
0.935
58.49Cl. 9.8
11654 kNm
43.7
Annex G.8 (Fig. 11b) BS5400 b > 30 0.0944Annex G.8 (Fig. 11b) BD56 0.048
0.882 (BS5400) ¦ 0.935 (BD56)Cl. 9.9.1.2
8898 kNm (BS5400)9432 kNm (BD56)
Bfc Bf comp
tfo tfo comp bfo dw hole f bR
Compression angle Lh x Lv x t tw
(34tw/m)*(355/syw)0.5 = 1188 < dwe (2082) : Non-Compact
dw . Bf tension d1/dw = 0.34
tw . tfo tension 28tw(355/syw)0.5 = 313 < d1 (768) : Non-Compact
bfo
Tension angle Lh x Lv x t
dh hole f dh
7tfo(355/syf)0.5 = 330 > bfo(192) : Compact
tfo
bR
Bft
(yc / tw)(syw / 355)0.5 =
sy Web thickness twe =
A gross =
A net =
Zpe
ytgross = Iyygross = ytgross =
ycgross = Iyynet = ycgross =
ytnet = rygross = ytnet =
ycnet = rynet = ycnet =
Ixxgross = Zpe gross =
Ixxnet = Zpe net =
Zxcnet =
Zxtnet = Mpe = Zpe net sy =
lLT = le k4 h u / ry le
k4 = [{4Z2pe(1-Iy/Ix)}/A2h2]1/4 =
i = Ic/(Ic+It) = lw =
lF = (lw/ry)(tf/D) =
yi = 0.8(2i-1) =
u = [{4i(1-i)+0.05lF2+yi
2}0.5+yi]-0.5
lLT =
Mult = Zxtnet sy =
b = lLT[(syc/355)(Mult/Mpe)]0.5 =
h = 0.0035lw/le(b-30) =h = 0.0035(b-30) =
MR/Mult = 0.5[{1+(1+h)5700/b2}-{(1+(1+h)5700/b2)2-22800/b2}0.5] =
At ULS MD = MR / gmgf3 = MR / (1.1*1.05) =
Angle Dimensions:Lh = length of horizontal legLv = length of vertical legt = thickness of leg