section 9.1 – inverse functions. does an inverse function exist? if yes, you can find the inverse...
DESCRIPTION
The Existence of the Inverse of f(x) IF for every x there is at most one y (function) AND IF for every y there is at most one x (one-to-one) then an inverse function of f(x) exists. The inverse function is denoted byTRANSCRIPT
Section 9.1 – Inverse Functions
DOES an inverse function exist?
IF YES, you can find the inverse function.
The Existence of the Inverse of f(x)
IF for every x there is at most one y (function)
AND
IF for every y there is at most one x (one-to-one)
then an inverse function of f(x) exists.
The inverse function is denoted by 1f x
Graphical Existence of InversePasses BOTH vertical and horizontal line test.
Inverse Exists No Inverse Exists(1, 1), (-1, 1)
No Inverse Exists(1, 0), (0, 0)
Inverse Exists No Inverse Exists(3, 0.9), (7, 0.9)
Inverse Exists Inverse Exists
No Inverse Exists(-3, 2), (0, 2)
Inverse Exists
JanuaryFebruaryMarchJuly
WinterSpringSummer
t 0 1 2 3f(t) 5 2 2 4
Does an inverse exist?
FordBushCarterClinton
PresidentVice-President
2, 4 , 3, 2 , 1, 5
6, 5 , 8, 1 , 6, 3
No Inverse Exists(Jan, Winter), (Feb, Winter)
No Inverse Exists(1, 2), (2, 2)
Inverse Exists
No Inverse Exists(Ford, President),
(Ford, Vice-President)No Inverse Exists
(6, 5), (6, 3)
Algebraic Existence of Inverse
2y x 6x 4 2x y x y 7
2x y 4 2 2x y 16
No Inverse Exists(-4, -12), (-2, -12)
No Inverse Exists(4, 2), (4, -2)
Inverse Exists
No Inverse Exists(0, 2), (0, -2)
No Inverse Exists(4, 0), (-4, 0)
FINDING the inverse which exists
2. Switch the x and the y.
3. (Algebraically) Solve for y.
4. Replace y with 1f x
1. Determine if inverse function exists. If yes, proceed to #2.
Finding the inverse function GRAPHICALLY
Finding the Inverse Function TABULARLY
x -2 3 5 7 8 9f(x) 0 -1 4 9 -3 2
x 0 -1 4 9 -3 2-2 3 5 7 8 9 1f x
x 2 3 4 5 6 7f(x) -7 -1 3 4 8 4
x 2 3 4 5 6 7f(x) -7 -1 3 4 8 4
No Inverse Exists(5, 4), (7, 4)
Finding the Inverse ANALYTICALLY
x y 7
y 7x y 7 x
1f 7x x
f x 2x 3 x 2 3y
x y32
1 xx 32
f
f x x 1
x 1y 2x 1y
2x y1
12 xx 1 f
3f x x 3 3x 3y 3x y3
3 1 xx 3 f
3f x x 4 3x 4y
3x y4
3x y4
3 1 x4x f