section 2.1 functions

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Section 2.1 Functions

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Section 2.1 Functions. A relation is a correspondence between two sets. If x and y are two elements in these sets and if a relation exists between x and y , then we say that x corresponds to y or that y depends on x , and we write x → y. FUNCTION. - PowerPoint PPT Presentation

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Page 1: Section 2.1 Functions

Section 2.1

Functions

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Page 3: Section 2.1 Functions

A relation is a correspondence between two sets.

If x and y are two elements in these sets and if a relation exists between x and y, then we say that x corresponds to y or that y depends on x, and we write x → y.

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FUNCTION

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Determine if the following relations represent functions. If the relation is a function, then state its domain and range.

Yes, it is a function. The domain is {No High School Diploma, High School Diploma, Some College, College Graduate}. The range is {3.4%, 5.4%, 5.9%, 7.7%}.

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Yes, it is a function. The domain is {410, 430, 540, 580, 600, 750}. The range is {19, 23, 24, 29, 33}. Note that it is okay for more than one element in the domain to correspond to the same element in the range.

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No, not a function. Each element in the domain does not correspond to exactly one element in the range (0.86 has two prices assigned to it).

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Determine whether each relation represents a function. If it is a function, state the domain and range.

b) {(–2, 3), (4, 1), (3, –2), (2, –1)}

c) {(4, 3), (3, 3), (4, –3), (2, 1)}

a) {(2, 3), (4, 1), (3, –2), (2, –1)}No, it is not a function. The element 2 is assigned to both 3 and –1.

Yes, it is a function because no ordered pairs have the same first element and different second elements.

No, it is not a function. The element 4 is assigned to both 3 and –3.

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Determine if the equation defines y as a function of x.

13

2y x

Yes, this is a function since for any input x, when you multiply by –1/2 and then subtract 3, you would only get one output y.

Page 12: Section 2.1 Functions

Determine if the equation defines y as a function of x.

2 1x y

No, this it not a function since for values of x greater than 1, you would have two outputs for y.

2 1 Solve for yx y

2 1y x 1y x

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FUNCTION MACHINE

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For the function f defined by f x 3x2 2x, evaluate:

22 13 233 3)a f

22 2) ( ) 3 2 33 3 3 232 2 1b f x f x x x x

2 2) 3 2 3 2d x x xf x x

2 2) 3 3 3 2 9 6c f x x x xx

Page 17: Section 2.1 Functions

For the function f defined by f x 3x2 2x, evaluate:

2 23 3) 3 2 3 6 9 23 6g f x x x x x x

2 2) 3 2 3 7 63 23x x xf f x x

2 2) 3 2 3 2e f x x xx x

23 16 21x x

Page 18: Section 2.1 Functions

For the function f defined by f x 3x2 2x, evaluate:

2 23 2 3 2( ))

x h x xf f xh

h

h h

x hx

2 2 23 2 2 2 3 2x xh h x h x x

h

2 2 23 6 3 2 3x xh h h x

h

( 6 3 2)h x h

h

6 3 2x h

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(a) For each x in the domain of f, there is exactly one image f(x) in the range; however, an element in the range can result from more than one x in the domain.

(b) f is the symbol that we use to denote the function. It is symbolic of the equation that we use to get from an x in the domain to f(x) in the range.

(c) If y = f(x), then x is called the independent variable or argument of f, and y is called the dependent variable or the value of f at x.

SummaryImportant Facts About Functions

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Page 23: Section 2.1 Functions

2

4(a)

2 3

xf x

x x

2(b) 9g x x

(c) 3 2h x x

2

The denominator 0 so find values

where 3 2 0.x x

3 1 0x x 3, 1x x x

The set of all real numbers

Only nonnegative numbers have real

square roots so 3 2 0.x 3 3

or ,2 2

x x

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A rectangular garden has a perimeter of 100 feet. Express the area A of the garden as a function of the width w. Find the domain.

wA

A(w) = w(50 – w )

Domain: 0 < w < 50

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2 3For the functions 2 3 4 1

find the following:

f x x g x x

424 23 xx

224 23 xx

31228 325 xxx

2

3

2 3

4 1

x

x

2 32 3 4 1x x

2 32 3 4 1x x 2 3(2 3)(4 1)x x

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