sch4c kool aid
DESCRIPTION
by Steve Hall.TRANSCRIPT
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Man, on a hot summer's day, don't you just LOVE, Kool-Aid? OH YEAH! But I hate how you have tomake a whole pitcher out of one of those little packets of drink crystals! There must be an easierway to just get one glass of it!
THANKS TO CHEMISTRY, THERE IS!It's simple! All we need to do is use our equation:
Instructions on the Packet: What We Need To Remember!What you Need: 1. Measurement units must always be in -2L of water -1 cup of sugar 2. “Little I” stands for INITIAL, meaning -Pack of Kool-Aid crystalsMix these three, and enjoy! 3. “Little F” is your FINAL PRODUCT!
1. LET'S START OUR CHEMISTRY!
when all we want is a simple glass, all we need to do is DILUTE our solution in water,and enjoy!
*Background Info – 1 cup of sugar is equal to 200 grams of sugar
204 divided by 2000=
Ci x V
i = C
f x V
f
grams or litres. ALWAYS!
what you're STARTING OFF WITH
What we want to do is make a stock solution of Kool-Aid. This will help us because
A pack of Kool-Aid crystals is 4 grams Total weight of solid ingredients – 204 grams.
Now let's find our ratio. We know that H2O mLs are equal to grams. So we have a
ratio of 2000g/H2O : 204g/sucrose, meaning our percentage of concentration is:
0.10%
Concentrated
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2. MAKING OUR STOCK SOLUTION!First, lets find our givens.Givens:“Nickname” “Value”
0.10%
2.2L
? What we need to find!
50mL (0.05L) We have decided on our own that we want our stocksolution to be 50mL. (0.05L)
=
The Math: These 2 “Vf”s cancel out.
= Cf
= Cf
4.40% = Cf
Therefore, our stock solution of 50mL has a concentration of 4.4% Kool-Aid3. ENJOY A SINGLE GLASS!
Let's find our givens again!Givens:“Nickname” “Value”
4.40% Our stock solution concentration.
? How much solution we need to dilute with water.
0.10% The original Kool-Aid concentration.
300mL (0.3L) How much we want to drink.
=
These 2 “Ci”s cancel out.The Math:
x1000mL = ViHow much water do weneed?
x1000mL = Vi300mL – 6.8mL = ?300mL – 6.8mL = 293.2
6.8mL = Vi
Therefore, to enjoy 1 glass of refreshing Kool-Aid on a hot day, we need to add 6.8mLof our stock solution to 293.2mL of water!
3 Steps! How easy was that!? by Steve Hall, 2013
Ci
Vi
Cf
Vf
To find Cf, our equation is:
Ci
Vi
Cf
Vf
To find Cf, our equation is:
Ci x ViVf
Cf x VfVf
0.10% x 2.2L0.05L
0.220.05L
0.10% x 0.3L4.40%
0.034.40%
Ci x ViCi
Cf x VfCi