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14 lü MATEMATİK DENEMESİ GENEL DENEME-3 ÇÖZÜMLERİ
1.
Cevap: B
2.
Cevap: C
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3.
Cevap: C
4.
3 4 1 yani 1 saat 1 ye karşılık gelmektedir.
08.00- 9. kahvaltı
09.00-13.00 okul
13.00-14. öğle yemeği
14.00-1 . okul (öğleden sonra)
16.00-18.00 kurs
18.00-19. akşam yemeği
Cevap: C
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5.
Cevap: D
6.
Cevap: B
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7.
Cevap: C
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8.
Cevap: B
9.
Cevap: C
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10.
Cevap: A
11.
Cevap: D
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12.
Cevap: A
13.
Cevap: B
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14.
Cevap: C
15.
Şekilde görüldüğü gibi en az 11 birim kare daha boyanırsa şekiller d doğrusuna göre simetrik olur.
Cevap: B
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16.
Cevap: A
17.
Cevap: C
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18.
Cevap: B
19.
Cevap: A
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20.
Cevap: B
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14 lü MATEMATİK DENEMESİ GENEL DENEME-4 ÇÖZÜMLERİ
1.
1 sayısının pozitif tam sayı bölenlerinin sayısı 4 1 1 1 1 1 tanedir.
144 sayısının pozitif tam sayı bölenlerinin sayısı 4 1 1 1 tanedir.
1 1 sayısının pozitif tam sayı bölenlerinin sayısı 1 1 1 1 1 1
tanedir. 1 1 sayısının pozitif tam sayı bölenlerinin sayısı 1 tanedir.
Cevap: D
2.
adet sandalye, adet tabure için 1 4 eşitliğinden 1 olup toplam
ürün sayısı x y 48 dir.
Cevap: A
3.
Cevap: A
4.
8 4 dir.
Cevap: D
5.
A) 20,45,55 üçgen eşitsizliğini sağlar
B) 30,35,55 üçgen eşitsizliğini sağlar
C) 15,50,55 üçgen eşitsizliğini sağlar
D) 20,40,60 üçgen eşitsizliğini sağlamaz.
Cevap: D
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6.
1 cm olup, 3 basamak 60 cm dir. Buna göre Barışın uzanabileceği en büyük
yükseklik cm dir.
4 1 cm dir. 1 1 4 olup, 1 4 cm dir.
En fazla 2 adet alabilir.
Cevap: B
7.
Ali 2 kalem 2 silgi uzunluk; 18 cm
Ahmet 2 kalem 1 silgi uzunluk; cm dir. Buna göre 1 silgi cm dir. Buna göre 1 kalem
1 cm dir.
Yavuz, 1 kalem 2 silgi, 1 18 cm dir. 18 48 cm dir.
Cevap: B
8.
1 ,
1 ı ı ı
olduğundan dir.
Cevap: C
9.
Cevap: D
10.
Olası durumlar; , olup bunların sayısı 14 tanedir.
Bunlardan tanesi tam karedir. Aranan olasılık ise % dir.
Cevap: C
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11.
Pazartesi k, Salı k Çarşamba k Perşembe k Cuma k olup bunların toplamı 8k dır.
4 derecedir.
Pazartesiye ait merkez açı; 4
Salıya ait merkez açı;
Çarşambaya ait merkez açı; 4
Perşembeye ait merkez açı; dir.
Cumaya ait merkez açı; dir.
Cevap: B
12.
GB
13.
a ve b pozitif tam sayı c ise bir tam sayıdır. Farklı a b ve c değerleri için
doğrusunun grafikleri çiziliyor. Buna göre doğrunun eğimi negatiftir.
Cevap: C
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14.
Cevap: B
15.
Esin ilk sınavdan 8 . sınavdan 1 aldığına göre öğretmenin vereceği not x hangi aralıkta olur?
En düşük not 18
dir.
Cevap: B
16.
Yeşil Parça, x eksenine paralel 8 birim sağa ötelersek kırmızı parçayı y eksenine göre yansıtıp sonrada x eksenine göre yansıtarak şekli tamamlarız.
Cevap: B
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17.
ve olup iki kare farkından ve dir.
Cevap: D
18.
Şekle göre aşağıda açınımı verilen zarı elde ederiz. Bu da at yüzde noktanın olması demektir.
Cevap: D
19.
A’nın taban çevresi 18 cm
B’nin taban çevresi 4 cm
C’nin taban çevresi cm
D’nin taban çevresi 1 cm
Bunlardan üçünün toplamı 1 . . cm yi veren üçlü 18 1 dur.
Cevap: B
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20.
1 eşitliğinden bulunur.
Cevap: C
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14 lü MATEMATİK DENEMESİ GENEL DENEME-5 ÇÖZÜMLERİ
1.
5 1 15 olduğundan 5 i 5 parçaya ayırmak için 4 kesim 1 yi 8 parçaya ayırmak
için kesim yapılacaktır. Bu da
4 1
5
1 1 5 5 5 TL demektir.
Cevap: B
2.
sayısının pozitif tam sayı bölen sayısı 9 tanedir.
4 sayısının pozitif tam sayı bölen sayısı 8 tanedir.
48 sayısının pozitif tam sayı bölen sayısı 1 tanedir.
5 sayısının pozitif tam sayı bölen sayısı 8 tanedir.
Cevap: C
3.
1. aracın tükettiği yakıt miktarı 4 -27=13 lt
. aracın tükettiği yakıt miktarı 5 -16=34 lt
. aracın tükettiği yakıt miktarı 48-32=16 lt
4. aracın tükettiği yakıt miktarı 5 -25=31 lt
Cevap: B
4.
A’nın alabileceği en küçük değer 1000 dir.
Cevap: C
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5.
1 18, 1 1 18, 1 9 18, 18 5 19 dir.
Cevap: D
6.
91 9 9 94 95 9 9 98 99 sayıları 1 a yakındır. 9 tane futbolcu 1 ’ar gol
atarlar geriye kalan futbolcu da şer gol atarlar ve en çok gol sayısı 9 18 1 8 olur. Yani 110
olamaz.
Cevap: D
7.
0 - arasında 1,2,9,16 yani 4 tane tam kare sayı
10 - arasında 1 5 yani tane tam kare sayı
20 -4 arasında 5 yani tane tam kare sayı
30 -5 arasında 49 yani tane tam kare sayı
Cevap: A
8.
• Taban genişliği arttıkça yakıt tüketimi artar.
• Yanak yüksekliği arttıkça yakıt tüketimi azalır.
• Jant çapı arttıkça yakıt tüketimi artar.
T model araçta Yanak yüksekliği büyük ve taban genişliği ile Jant çapı küçük olduğundan daha
azdır.
Cevap: D
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9.
5. sınıflar 5 kişi olup grafikte temsil ettiği merkez açı 5 derece olduğundan bir öğrenciyi
derece temsil etmektedir.
. sınıflar kişi olup A 1 dur.
. sınıflar 15 kişi olup C 5 tir.
8. sınıflar 5 kişi olup B 5 tir. Buna göre A B-C=35-5=30 dur.
Cevap: A
10.
Kitabın eni x olsun. Buna göre 4 1 eşitliğinden 1 dur.
Cevap: A
11.
dir.
Cevap: B
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12.
Kartlarda yazan dört ardışık sayı 1 4 olması durumunda 11 1 için durum sağlanır ve n 1
olur?
Cevap: C
13.
Cevap: B
14.
Ayhan saatte 18 km ve Yakup saatte 10 km yol giymektedir. Buradan 18 11 1
eşitliğinden x 14 bulunur.
Cevap: B
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15.
Şekilde görüldüğü gibi en büyük benzerlik oranı tür.
Cevap: C
16.
5 5 eşitsizliğinden 5 11 ve den 1 dir.
Cevap: C
17.
Pisagor teoreminden karenin bir kenarı 8 birimdir. 5 4 1 birimkaredir.
Cevap: B
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18.
A A’B’C’D 1 .1 1 birim karedir.
Cevap: C
19.
EKOK 8 4 9 olup Berra’nın yaptığı kulenin hacmi en çok 9 9 59 olur.
Cevap: A
20.
Yanal alanı lan küpün bir ayrıtının uzunluğu 4 5 cm olur.
olamaz.
Cevap: B
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14 lü MATEMATİK DENEMESİ GENEL DENEME-6 ÇÖZÜMLERİ
1.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1
Geriye 16 öğrenci kalır.
Cevap: C
2.
35 in bölenleri satır ve sütun olarak yazıldıktan sonra satıra yazılan sayılarun bölenleri altlarına
yazılıyor.
Cevap: D
3.
Üçgenin enkısa kenarı birde en uzun kenarı olursa telle çevirme işi ucuza mal edilir. Üçgen
eşitsizliğinden, 1,16,16 veya 2, 15, 16 -8,9,16 olması durumlarını inceleyelim.
1.16+16.8+16.4=208, 2.16+15.8+16.4=216, 8.16+9.8+16.4=264 TL demek ki 2. 208=416 TL
en ucuz maliyettir.
Cevap: B
4.
İki masa arasındaki açıklık x olsun
11 5 1 12 11 1 denkleminden x=80 cm bulunur.
Cevap: B
5.
Her yolcuda 1 zeytin tasarruf, altı ayda 24 zeytin demektir.
2 =320 000 TL
kazanç demektir.
Cevap: A
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6.
4 6 ise bir ayrıtın uzunluğu 4 5 cm
1 6 1 ise bir ayrıtın uzunluğu 6 5 cm
1 2 6 2 ise bir ayrıtın uzunluğu 5 cm dir. Tarık, İbrahim’den en çok 5 4 5
4 5 cm uzundur.
Cevap: D
7.
16 çarpımdan 4 tanesi
den küçük demektir. Tabloda tane sayı
den küçüktür. nin en az
olması için , A=2 ve B=2 olmalıdır.
Buna göre, 2 tir.
Cevap: B
8.
EKOK(4,5) 2 olduğundan, 12 14 veya 12 14 olmalıdır.
Cevap: C
9.
2 , 2 ve ü 12 dir. Buna göre,
4 , 25 ve ü 16 dir. k 1 için a b c 45 şeklinde en az değeri alır.
Cevap: D
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10.
Pisagor teoreminden ,15,17 üçgeni için x 17 cm sağlar.
Cevap: C
11.
V=(2 2 ) 4 ( ) dir.
Cevap: C
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12.
Çilekli kalan
yani
4 2
Kestaneli kalan
yani
45 6
Çikolatalı kalan
yani
6 45
Muzlu kalan
yani
45 6 226
Muzlu çilekli kestaneli çikolatalı
Cevap: B
13.
Kapının uzun kenarı 6 2 yüksekliği 5 2 olup alanı 6 metre karedir.
Cevap: C
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14.
LPG 500 km 200 TL ise 3000 km de 6.200=1200 TL, benzin 200 km 120 TL ise 3000 km de
15.120=1800 TL olup fark 1800-1200=600 TL dir.
Cevap: A
15.
Deponun hacmi; 4 4 72 metreküp olup, 72/6 62 dakika demektir.
Cevap: B
16.
olduğundan
dir. 5 ise 2 5 olmalıdır. O halde aranan nokta
K dir.
Cevap: A
17.
Konide verilen TOB dik üçgeninde Pisagor teoreminden 4 ve kare dik prizmanın
hacmi 4 256 bulunur.
Cevap: B
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18.
Ortak alan 9 birim karedir.
Cevap: D
19.
1,2 m 12 cm olup 12, cm lik ayrıtı yan yana olacak şekilde 1 sıra,
2,56 m 256 cm olup 2 cm lik ayrıtı üst üste olacak şekilde sıra,
5,12 m 512 cm olup 6,4 cm lik ayrıtı yan yana olacak şekilde sıra
Toplam 1 64 adet koli konabilir demektir.
Cevap: D
20.
( ) ( )
2 olur.
Cevap: C